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2.1 General equation of displacement relative to force in translation and rotation

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(1)

Chapter 2

Modeling and static analysis

First, a mathematical formulation derivied for each translating and rotating degree of freedom in a EPFHM is based on the characteristic of static mechanism, the design fundamental, stiffness estimation, and the functional experiment of a EPFHM. It leads to easily decompose the force and bending moment of the designated EPFHM into force components in X,Y, Z-axis and bending moment components in X,Y,Z-axis. Eventually, the stiffness of each axis is derived from the following methodology.

2.1 General equation of displacement relative to force in translation and rotation

Six degrees of freedom in translation/rotation are respectively defined as X, Y, Z, A, B and C-axis. The characteristics of the design fixture need to be defined as shown in Fig. 4 for illustrating the behavior of X,Y and Z axes translation.

(2)

Fig. 4 Schematic diagram of X-Y-Z translation

The force definitions of piezoelectric EPFHM for finding translation and rotation stiffness are derived as follows.

K λ U

F= (1) where,

[

Fx Fy Fz

]

=

F is the force of X,Y and Z axes.

[

x y z

]

=

U is the displacement of X,Y and Z axes.

=

z y x

λ λ λ

0 0

0 0

0 0

λ , and λxyz are respectively calibrated

functions of material property in X,Y and Z axes. It proves that the EPFHM material has probable non-isotropy property by the experiment. If the λ is constant proved by the experiment, the translation axial material property is regarded as linear inclination.

F F

K K C C

U U

(3)

=

z y x

K K K

0 0

0 0

0 0

K , and Kx , Ky , Kz are the ratio of force

z y

x F F

F , , and its corresponding displacement ∆x,∆y,∆z in X,Y and Z axes respectively.

Kx,Ky,Kz are evaluated by FEA. Eq.(1) is defined as

Trans

S U

F= (2)

Trans

S is defined as a characteristic matrix of a EPFHM translation to help matrix operation and coordinate transformation.

=

z z y y x x

Trans

K K

K

λ λ

λ

0 0

0 0

0 0

S

And, the displacement of characteristic matrix is derived from the following formula.

S 1

F

U= Trans (3) The relationship of bending moments, stiffness and angular displacement in A, B, and C axes, is shown as below.

R R

R F θχ K

r

M= × = (4) Among,

[

Mx My Mz

]

=

M , Mx,My,Mz are respectively bending moment in A,B and C axes.

[

Rx Ry Rz

]

R = F F F

F , which is the force applied to the proper position of a EPFHM results in bending moment components of A, B and C axes.

(4)

=

Rz Ry Rx

χ χ χ

0 0

0 0

0 0

χ , χRxRyRz are respectively calibrated

functions of material property in X, Y and Z rotational axes. It also proves that the EPFHM material has probable non-isotropy property by the experiment. If the χ is constant proved by the experiment, the rotation axial material property is regarded as linear inclination.

[

∆θx ∆θy ∆θz

]

=

θ is the angular displacement vector of X,Y and Z rotational axes.

=

Rz Ry Rx

R

K K K

0 0

0 0

0 0

K , andKRx,KRy,KRz are the ratio of bending

moment Mx,My,Mz to its corresponding angular displacement

z y

x θ θ

θ ∆ ∆

∆ , , in X,Y and Z axis respectively.

According to the design method, KRx,KRy,KRzare evaluated by FEA. Eq.(4) is defined as

Rot

R θS

F = (5)

SRot is defined as a characteristic rotation matrix of a EPFHM to help matrix operation and coordinate transformation.

=

Rz Rz Rz Ry Ry Ry Rx Rx Rx

Rot

r K r

K r

K

χ χ

χ

0 0

0 0

0 0

S

And, the angular displacement vector is derived as given by S 1

F

θ= R Rot (6) In fact, FRx,FRy,FRz results in the translation effect of a fixture and which is

(5)

S 1

F

U= R Tran (7) Combining Eq.(3) with Eq. (7) results in

S 1

F F

U=( + R) Trans (8)

Therefore, the displacement from FR is compensated by F.

2.2 General equation of displacement relative to voltage in translation and rotation

The force of PZT is expressed as l

K

FPiezoPiezo Piezo∆ (9) And, λPiezo is defined as Eq.(1).

The relationship of displacement and voltage is )

(V f l=

∆ (10) so, the relationship of PZT force and voltage is

) (V f K

FPiezoPiezo Piezo (11) The stiffness value of varied PZT is

) / ( 4000

~

4 N m

KPeizo ≈ µ (12) The displacement of a EPFHM is occurred due to KPiezo >>KFixture. Correspondingly, the translation and rotation effects are caused by the input displacement of a PZT.

The contact with a PZT and EPFHM causes varied friction instead of backlash error of a mechanism. The forces F and FR of Eq.(7)(8) cause the displacement without the consideration of energy loss. According to the mentioned derivation, adding the PZT

(6)

[

Px Py Pz

]

P = F F F

F , is the PZT force, which leads to the

translation of X, Y, and Z axes.

[

PRx PRy PRz

]

PR = F F F

F , is the PZT force, which leads to the

bending moment of X, Y, and Z axes.

From Eq.(8), S 1

η F η F

U=( P + PR R) Trans (13) Among,

=

z y x

η η η

0 0

0 0

0 0

η ,

=

Rz Ry Rx

R

η η η

0 0

0 0

0 0 η

About the contact problem by the FEA simulation, it reveals that the output displacement will just linearly increase along the input force; however, it will not correspondingly reflect to the same result of experiment. Therefore, η and ηR must be the transfer functions between EPFHM force F,FR and PZT force FP,FPR.

And,

P

P QK

F =

PR R

PR Q K

F = (14) Among,

[

fx(Vx) fy(Vy) fz(Vz)

]

=

Q is the displacement function vector,

which is occurred by the translation of three PZTs with different voltage in X,Y, and Z axes.

(7)

[

Rx( Rx) Ry( Ry) Rz( Rz)

]

R = f V f V f V

Q is also the function vector and

the displacement, which is occurred by the bending moment of a PZT with the voltage in X,Y, and Z axes.

⎥⎥

⎢⎢

=

z Piezo y

Piezo x

Piezo

P

K K

K

0 0

0 0

0 0

K Among, KPiezox , KPiezoy and KPiezoz

are respectively the stiffness of three PZTs which create translations in X,Y, and Z axes.

⎥⎥

⎢⎢

=

Rz Piezo Ry

Piezo Rx

Piezo

PR

K K

K

0 0

0 0

0 0

K Among, KPiezoRx , KPiezoRy and

Rz Piezo

K are respectively the stiffness of three PZTs which create bending moments in X,Y, and Z axes.

From Eq.(13), it reveals S 1

K η Q K η Q

U=( P + R R PR) Trans (15) Accordingly, Eq.(6) is represented as

S 1

η F

θ= PR R Rot (16) From Eq.(14),

S 1

K η Q

θ= R R PR Rot (17)

數據

Fig. 4 Schematic diagram of X-Y-Z translation

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