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Gluing Let {Xi: i ∈ I} be a family of locally ringed spaces

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1. Gluing

Let {Xi: i ∈ I} be a family of locally ringed spaces. Assume that for each i, j ∈ I, there exist an open subset Uij of Xi and an open subset Uji of Xj so that for i, j, k ∈ I,

(1) ϕij : Uij → Uji is an isomorphism of locally ringed spaces, (2) ϕ−1ij (Uji∩ Ujk) = Uij ∩ Uik,

(3) ϕik= ϕjk◦ ϕij.

Here we set Uii= Xi and ϕii= idXi. A collection {(I, Xi, Uij, ϕij)} of such data is called a gluing data.

Proposition 1.1. Given a gluing data of locally ringed spaces, there is a locally ringed space X together with a family of open subspaces {Ui} and a family of isomorphisms of locally ringed spaces {ϕi : Xi → Ui} such that

(1) ϕ(Uij) = Ui∩ Uj and (2) ϕij = ϕ−1j |Ui∩Uj◦ ϕi|Uij.

Assume that we prove Proposition 1.1. We immediately obtain a scheme X when Xi are all schemes given in a gluing data:

Corollary 1.1. In Lemma 1.1 above, assume that Xi are all schemes. Then X is also a scheme.

Proof. Let x be a point in X. Then x is contained in some Ui. Since Ui is a scheme, there is an open neighborhood V of x in Ui so that V is an affine scheme. Since x is arbitrary, we prove that every point has an open neighborhood such that the open neighborhood is

also an affine scheme. By definition X is a scheme. 

Let`

iXi be the union of all {Xi : i ∈ I}. On `

iXi, we define an equivalent relation ∼ as follows. Let xi ∈ Xi and xj ∈ Xj. We say xi ∼ xj if and only if xi ∈ Uij and xj ∈ Uji and ϕij(xi) = xj.

Lemma 1.1. ∼ is an equivalence relation.

Proof. Let xi, xj and xk be elements of Xi, Xj and Xk respectively. It is obvious that xi ∼ xi since ϕii is the identity map on Xi and if xi ∼ xj, then xj ∼ xi by the fact that ϕij : Uij → Uji is an isomorphism. We only need to prove the relation is transitive.

Let xi ∼ xj and xj ∼ xk for some i, j, k. We want to show that xi ∼ xk. Since xi ∼ xj, xi ∈ Uij and xj ∈ Uji with ϕij(xi) = xj. Since xj ∼ xk, xj ∈ Ujk and xk ∈ Ukj with ϕjk(xj) = xk. We find xj ∈ Uji∩ Ujk. Hence

xi = ϕ−1ij (xj) ∈ ϕ−1ij (Uji∩Ujk) = Uij∩Uik and xk = ϕjk(xj) ∈ ϕjk(Uji∩Ujk) = Uki∩Ukj Hence xi ∈ Uik and xk∈ Uki. Moreover,

ϕik(xi) = ϕjkij(xi)) = ϕjk(xj) = xk.

We conclude xi∼ xk. 

The quotient space `

iXi/ ∼ is denoted by X. Let ϕi be the composition of the maps Xi → `

iXi → X, where the first map Xi → `

iXi is the inclusion map and the second map`

iXi → X is the quotient map. Denote Ui = ϕi(Xi). Then ϕi : Xi→ Ui is a bijection by the definition of ϕi. We can also verify that the conditions (1) and (2) in Proposition 1.1 hold.

Lemma 1.2. Let T be the family of subsets of X consisting of U so that ϕ−1i (V ) is open in Xi for all i ∈ I. The family forms a topology on X.

1

(2)

2

Proof. Since ϕ−1i (∅) = ∅ for all i, ∅ ∈ T . Since ϕ−1i (X) = Xi is open in Xi, X ∈ T . If {Vα} is a family of elements of T , then ϕ−1i (Vα) is open in Xifor all α. ByS

αϕ−1i (Vα) = ϕ−1i (S

αVα) and the union of open sets is open, ϕ−1i (S

αVα) is open in Xi for all i. Hence S

αVα ∈ T . If V1, V2 ∈ T , ϕ−1i (Vα) is open in Xi for α = 1, 2. Since ϕ−1i (V1 ∩ V2) = ϕ−1i (V1) ∩ ϕ−1i (V2), and the finite intersection of open sets is open, ϕ−1i (V1∩ V2) is open in

Xi for all i. This shows V1∩ V2 ∈ T . 

Since ϕ−1i (Uj) = Uij is open in Xi for all i, Uj is open in X. It also follows from the definition that ϕi : Xi → Ui is continuous for all i. We also have {Ui} forms an open covering of X.

To show ϕi is a homeomorphism, we show ϕi is an open mapping. Let W be an open subset of Xi. Then W ∩ Uij is open in Xi. Claim ϕi(W ) is open in X. Since ϕ−1ji(W )) = ϕij(W ∩ Uij) and ϕij is a homeomorphism for all i, j, ϕ−1ji(W )) is open in Xj for all j.

By definition, ϕi(W ) is open in X and hence is open in Ui.

Now, we only need to construct a sheaf of ring OX on X satisfying the requirement. Let OUi = ϕi,∗OXi. We obtain an isomorphism ϕi : Xi → Ui of locally ringed spaces. By the isomorphism of locally ringed spaces ϕij, we have an isomorphism of sheaf of rings

OUi|Ui∩Uj → OUj|Ui∩Uj

satisfying a cocycle condition from {ϕij}. We obtain a sheaf OX of rings so that OX|Ui ∼= OUi for each i compatible with the gluing maps above. Then (X, OX) is a ringed space. If x ∈ X, then x ∈ Ui for some i. Then OX,x ∼= OUi,x is a local ring.

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