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Contents lists available atScienceDirect

Applied Numerical Mathematics

www.elsevier.com/locate/apnum

A smoothing Newton method for absolute value equation associated with second-order cone

Xin-He Miao

a

,

1

, Jian-Tao Yang

a

, B. Saheya

b

,

2

, Jein-Shan Chen

c

,∗,

3

aDepartmentofMathematics,TianjinUniversity,China,Tianjin300072,China

bCollegeofMathematicalScience,InnerMongoliaNormalUniversity,Hohhot010022,InnerMongolia,PRChina cDepartmentofMathematics,NationalTaiwanNormalUniversity,Taipei11677,Taiwan

a r t i c l e i n f o a b s t r a c t

Articlehistory:

Received20May2016

Receivedinrevisedform26February2017 Accepted28April2017

Availableonline4May2017

Keywords:

Second-ordercone Absolutevalueequations SmoothingNewtonalgorithm

Inthispaper,weconsider thesmoothingNewtonmethodforsolving atypeofabsolute value equations associated with second order cone (SOCAVE for short), which is a generalizationofthestandardabsolutevalueequationfrequentlydiscussedintheliterature during the past decade. Based on a class of smoothing functions, we reformulate the SOCAVE as a family of parameterized smooth equations, and propose the smoothing Newton algorithm to solve the problem iteratively. Moreover, the algorithm is proved to be locally quadratically convergent under suitable conditions. Preliminary numerical resultsdemonstrate that thealgorithm is effective.Inaddition, two kinds ofnumerical comparisonsare presentedwhichprovidesnumericalevidenceaboutwhythesmoothing Newtonmethodisemployedand alsosuggestsasuitablesmoothingfunctionforfuture numericalimplementations.Finally,wepointoutthatalthoughthemainideaforproving theconvergenceissimilartotheone usedintheliterature,theanalysisisindeedmore subtleandinvolvesmoretechniquesduetothefeatureofsecond-ordercone.

©2017IMACS.PublishedbyElsevierB.V.Allrightsreserved.

1. Introduction

Thestandardabsolutevalueequation(AVE)isintheformof

Ax

+

B

|

x

| =

b

,

(1)

where A

∈ R

n×n, B

∈ R

n×n, B

=

0,andb

∈ R

n.Here

|

x

|

meansthecomponentwiseabsolutevalue ofvectorx

∈ R

n.When B

= −

I,whereI istheidentitymatrix,theAVE(1)reducestothespecialform:

Ax

− |

x

| =

b

.

ItisknownthattheAVE(1)wasfirstintroducedbyRohnin[38]andrecentlyhasbeeninvestigatedbymanyresearchers, forexample,Caccetta,QuandZhou[1],HuandHuang[14],JiangandZhang[22],KetabchiandMoosaei[23],Mangasarian [25–32],MangasarianandMeyer[34],Prokopyev[35],andRohn[40].

*

Correspondingauthor.

E-mailaddresses:[email protected](X.-H. Miao),[email protected](J.-T. Yang),[email protected](B. Saheya),[email protected] (J.-S. Chen).

1 Theauthor’sworkissupportedbyNationalNaturalScienceFoundationofChina(No. 11471241).

2 Theauthor’sworkissupportedbyNaturalScienceFoundationofInnerMongolia(AwardNumber:2014MS0119).

3 Theauthor’sworkissupportedbyMinistryofScienceandTechnology,Taiwan(No. 104-2115-M-003-011-MY2).

http://dx.doi.org/10.1016/j.apnum.2017.04.012

0168-9274/©2017IMACS.PublishedbyElsevierB.V.Allrightsreserved.

(2)

Inparticular,MangasarianandMeyer[34]showthat theAVE(1)isequivalent tothebilinearprogram,thegeneralized LCP(linear complementarityproblem),andthestandardLCP provided1 isnot an eigenvalueof A.Withtheseequivalent reformulations, they also show that the AVE(1) isNP-hard inits general formand provideexistence results.Prokopyev [35]furtherimprovestheaboveequivalencewhichindicatesthattheAVE(1)canbeequivalentlyrecastasLCPwithoutany assumptionon A and B,andalsoprovidesarelationshipwithmixedintegerprogramming.Ingeneral,ifsolvable, theAVE (1)canhaveeitherunique solutionormultiple(e.g.,exponentially many)solutions.Indeed,varioussufficiencyconditions on solvability and non-solvability of the AVE (1) with unique and multiple solutions are discussed in [34,35,39]. Some variantsoftheAVE,liketheabsolutevalue equationassociatedwithsecond-order coneandtheabsolutevalue programs, areinvestigatedin[16]and[41],respectively.

Inthispaper,we targetanother typeofabsolutevalue equationwhich isanaturalextension ofthestandard AVE(1).

More specifically the following absolute value equation associated with second-order cones, abbreviated as SOCAVE, as below:

Ax

+

B

|

x

| =

b

,

(2)

where A

,

B

∈ R

n×n andb

∈ R

n arethesame asthosein(1);

|

x

|

denotesthe absolutevalueof x coming fromthesquare root of the Jordan product “

of x and x. What is the difference betweenthe standard AVE (1) and the SOCAVE (2)?

Their mathematical formats look the same. In fact, the main difference is that

|

x

|

in the standard AVE (1) means the componentwise

|

xi

|

ofeach xi

∈ R

,i.e.,

|

x

| = (|

x1

|, |

x2

|, · · · , |

xn

|)

T

∈ R

n;however,

|

x

|

intheSOCAVE(2)denotesthevector satisfying

x2

:= √

x

x associatedwithsecond-orderconeunderJordanproduct.Tounderstanditsmeaning,we needto introducethedefinitionofsecond-ordercone(SOC).Thesecond-orderconein

R

n

(

n

1

)

,alsocalledtheLorentz cone,is definedas

K

n

:= 

(

x1

,

x2

) ∈ R × R

n1

| 

x2

 ≤

x1

 ,

where

 · 

denotestheEuclideannorm.Ifn

=

1,then

K

nisthesetofnonnegativereals

R

+.Ingeneral,ageneralsecond- ordercone

K

couldbetheCartesianproductofSOCs,i.e.,

K := K

n1

× · · · × K

nr

.

Forsimplicity,wefocusonthesingleSOC

K

nbecausealltheanalysiscanbecarriedovertothesettingofCartesianproduct.

TheSOCisaspecialcaseofsymmetricconesandcanbeanalyzedunderJordanproduct,see[11].Inparticular,foranytwo vectorsx

= (

x1

,

x2

) ∈ R × R

n1and y

= (

y1

,

y2

) ∈ R × R

n1,theJordanproduct ofx andy associatedwith

K

n isdefinedas

x

y

:=



xTy

y1x2

+

x1y2

 .

TheJordanproduct,unlikescalarormatrixmultiplication,isnotassociative,whichisamainsourceofcomplicationinthe analysisofoptimizationproblemsinvolvedSOC,see[3,10,12]andreferencesthereinformoredetails.Theidentityelement underthis Jordanproduct is e

= (

1

,

0

, ...,

0

)

T

∈ R

n. Withthesedefinitions, x2 means theJordan product ofx with itself, i.e.,x2

:=

x

x;and

x withx

K

n denotestheuniquevectorsuchthat

x

◦ √

x

=

x.Inotherwords,thevector

|

x

|

inthe SOCAVE(2)iscomputedby

|

x

| := √

x

x

.

As mentioned earlier,the significance ofthe AVE (1)arises fromthe fact that the AVEis capable to formulatemany optimizationproblems(alsosee[26,30,32,34,35]),suchas,linearprograms,quadraticprograms,bimatrixgames,andsoon.

Moreover,theabsolutevalue equationsisequivalent tothelinearcomplementarityproblem[34].Accordingly,weseethat theSOCAVE(2)plays similarrole invariousoptimizationproblemsinvolvedsecond-ordercones. Forsolvingthestandard AVE(1),therearemanyvariousnumericalmethodsproposedintheliterature(see[1,21,22,25–27,35,43]).AsfortheSOCAVE (2),Hu, Huangand Zhang[16] propose a generalizedNewton method forsolving theSOCAVE (2).It iswell known that smoothing-typealgorithmsisapowerfultoolforsolvingmanyoptimizationproblems,forexample,thelinearandnonlinear complementarityproblems[3,12,19,20,24],thesystemofequalitiesandinequalities[17,42].Inthispaper,weareinterested inasmoothing NewtonmethodforsolvingtheSOCAVE(2).OurnumericalresultsalsosupportthatthesmoothingNewton methodisabetterwaythanthegeneralizedNewtonmethodemployedin[16].Thatiswhyweadoptthisalgorithmasthe maintool todonumericalimplementations.Inaddition,we haveshownthat theproposed smoothingNewtonmethodis locallyquadraticallyconvergentundersuitable condition. Wereport somepreliminary numericalresultstoshowthat the methodisefficient.Moreover,numericalcomparisonsbasedonvariousvalueofp arepresentedaswell.

Toclosethissection,wesaya fewwordsaboutnotationsandtheorganizationofthispaper.Asusual,

R

n denotesthe space ofn-dimensional real columnvectors.

R

+ and

R

++ denotethe nonnegative andpositive reals. For anyx

,

y

∈ R

n, theEuclideaninner productisdenoted

x

,

y

=

xTy,andtheEuclideannorm



x



isdenotedas



x

 = √

x

,

x

.Thispaper isorganized asfollows.InSection2,webriefly describesome conceptsandpropertiesonsecond-ordercone.Besides,we reviewJordanproductandthespectraldecompositionforelementsx and y in

R

n.InSection3,weintroduceasmoothing function of the absolute value

|

x

|

, and study the Jacobian matrix of the smoothing function. In Section 4, we propose a smoothing Newton algorithm forsolving the SOCAVE (2), anddiscuss the convergenceof the proposed method under suitableconditions.InSection5,thepreliminarynumericalresultsandnumericalcomparisonsaregiven.

(3)

2. Preliminaries

Inthissection,werecallsomebasicconceptsandbackgroundmaterialsregardingthesecond-ordercone,whichwillbe extensivelyusedinthesubsequentanalysis.Moredetailscanbefoundin[3,10–12,16].First,werecalltheexpressionofthe spectraldecomposition ofx withrespecttoSOC.Forx

= (

x1

,

x2

) ∈ R × R

n1,thespectraldecompositionofx withrespectto SOCisgivenby

x

= λ

1

(

x

)

u(x1)

+ λ

2

(

x

)

u(x2)

,

(3)

where

λ

i

(

x

) =

x1

+ (−

1

)

i



x2



fori

=

1

,

2 and u(xi)

=

⎧ ⎪

⎪ ⎩

1 2

1

, (−

1

)

i x

T

x22

T

if



x2

 =

0

,

1 2

1

, (

1

)

i

ω

T

T if



x2

 =

0

,

(4)

with

ω ∈ R

n1 beinganyvector satisfying

 ω  =

1.Thetwo scalars

λ

1

(

x

)

and

λ

2

(

x

)

are calledspectral valuesof x;while thetwovectorsu(x1)andu(x2)arecalledthespectralvectorsofx.Moreover,itisobviousthatthespectraldecompositionof x

∈ R

nisuniqueifx2

=

0.

Lemma2.1.Foranyx

= (

x1

,

x2

) ∈ R × R

n1withthespectraldecompositiongivenasin(3)-(4),thefollowingresultshold.

(a) u(x1)

u(x2)

=

0 andu(xi)

u(xi)

=

u(xi)fori

=

1

,

2;

(b)



u(x1)



2

= 

u(x2)



2

=

12and



x



2

=

12

21

(

x

) + λ

22

(

x

))

.

Proof. Thepropertycanbeverifieddirectlyorcanbefoundin[3,11,12,16,10].

2

Inthenextcontent,wetalkabouttheprojectionontosecond-ordercone.Weletx+betheprojectionofx ontoSOC

K

n, and x betheprojection of

x ontothe dualcone

(K

n

)

of

K

n,wherethedual cone

(K

n

)

isdefinedby

(K

n

)

:= {

y

∈ R

n

|

x

,

y

0

,

x

K

n

}

.Infact,thedualconeof

K

n isitself,i.e.,

(K

n

)

= K

n.DuetothespecialstructureofSOC

K

n,the explicitformulaofprojectionofx

= (

x1

,

x2

) ∈ R × R

n1 onto

K

n isobtainedin[3,10–13]asbelow:

x+

=

⎧ ⎨

x if x

K

n

,

0 if x

∈ − K

n

,

u otherwise

,

where u

=



x1+x2



2 x1+x2

2



x2

x2

 .

Similarly,theexpressionofxisintheformof

x

=

⎧ ⎨

0 if x

K

n

,

x if x

∈ − K

n

,

w otherwise

,

where w

=

  −

x1−2x2

x1−x2 2



x2

x2

 .

Togetherwiththespectraldecompositionofx,itisshownthatx

=

x+

+

x−andtheexpressionofx+hastheform:

x+

= (λ

1

(

x

))

+u(x1)

+ (λ

2

(

x

))

+u(x2)

,

and

x

= (−λ

1

(

x

))

+u(x1)

+ (−λ

2

(

x

))

+u(x2)

,

where

( α )

+

=

max

{

0

, α }

for

α ∈ R

.

Next,wetalkabouttheexpressionof

|

x

|

associatedwithSOC.Thereisanalternativewayviatheso-calledSOC-function toobtaintheexpressionof

|

x

|

,whichcanbefoundin[2,4].Morespecifically,foranyx

∈ R

n,wedefinethe absolutevalue

|

x

|

ofx withrespecttoSOCas

|

x

| :=

x+

+

x−.Infact,inthesettingofSOC,theform

|

x

| =

x+

+

x−isequivalenttotheform

(4)

|

x

| = √

x

x.Combiningtheaboveexpressionofx+andx,itcabbeverifiedthattheexpressionoftheabsolutevalue

|

x

|

isintheformof

|

x

| = 

1

(

x

))

+

+ (−λ

1

(

x

))

+



u(x1)

+ 

2

(

x

))

+

+ (−λ

2

(

x

))

+



u(x2)

= λ

1

(

x

)

u(x1)

+ λ

2

(

x

)

u(x2)

.

Toendthissection,wepointouttherelationbetweenSOCAVEandSOCLCP(second-orderconelinearcomplementarity problem).In[16],itwasshownthatSOCAVE(2)isequivalenttothefollowingSOCLCP:findx

,

y

∈ R

n suchthat

Mx

+

P y

=

c

,

and x

K

n

,

y

K

n

,

x

,

y

=

0

,

whereM

,

P

∈ R

n×n arematricesandc

∈ R

n.However,theaboveisnotastandardSOCLCPbecausethereexiststheequations Mx

+

P y

=

c therein.Asbelow,weshowthattheSOCAVE(2)canbefurtherconvertedintoastandardSOCLCP.

Theorem2.1.TheSOCAVE(2)canbereducedtothesecond-orderconelinearcomplementarityproblem(SOCLCP):

v

K

n

× K

n

× K

n

,

w

=

Q v

+

q

K

n

× K

n

× K

n and

v

,

w

=

0

,

(5) where

Q

:=

⎣ −

I 2I 0

A B

A 0

A A

B 0

⎦ ,

v

:=

2x

|

x+

|

0

and q

:=

⎣ −

0b b

⎦ .

(6)

Proof. Bylookinginto(6),wehave

w

=

Q v

+

q

=

Ax

+

2xB

|

x

| −

b

Ax

B

|

x

| +

b

⎦ .

PluggingthisintoSOCLCP(5)impliesthat

Ax

+

B

|

x

| −

b

K

n and

Ax

B

|

x

| +

b

K

n

.

Since

K

n ispointed,itfollowsthat Ax

+

B

|

x

| −

b

=

0.Ontheother hand,theaboveargumentisreversible.Thus,weshow thatSOCAVE(2)isequivalenttosecond-orderconelinearcomplementarityproblem.

2

Remark2.1.From Theorem 2.1,itfollows thatwe can alsosolvethe SOCAVE(2)by employing manyefficientalgorithms forsolving SOCLCP(5).Nonetheless, whenwe apply theNewton methodto solveSOCLCP, itstill needs reformulateit as smoothequationsornonsmoothequations.Thismeansthatweneedtwicereformulationsifwefollowthisway.Inviewof this,inthispaper,wereformulatetheSOCAVE(2)directlyasthesmoothequations,andsolvetheequationsbysmoothing Newtonmethod.

3. SmoothingfunctionsassociatewithSOCAVE

Inthispaper,we employthe smoothingNewtonmethodforsolving theSOCAVE(2).Tothisend, weneed toadopta smoothingfunction. Dueto thenon-differentiability of

| α |

for

α ∈ R

,we consider aclass ofsmoothingfunctionsforthe absolutevaluefunction

| α |

.Morespecifically,wedefinethefunction

φ

p

( ·, ·) : R

2

→ R

as

φ

p

(

a

,

b

) := 

p

|

a

|

p

+ |

b

|

p

,

p

>

1

.

(7)

This class of functionsis extracted fromthe so-called generalized Fischer–Burmeister function

φ

p

(

a

,

b

) = 

p

|

a

|

p

+ |

b

|

p

(

a

+

b

)

,which isheavily studiedinmanyreferences[5–9,15].Forconvenience, westill usethenotation

φ

p even itisno longerexactlythesameasthegeneralizedFischer–Burmeisterfunction.

Lemma3.1.Let

φ

p

: R

2

→ R

bedefinedasin(7).Then,thefollowinghold.

(a)

φ

p

(

a

,

0

) = |

a

|

and

φ

p

(

0

,

b

) = |

b

|

; (b)

φ

p

(·, ·)

isLipschitzcontinuouson

R

2; (c)

φ

p

( ·, ·)

isstronglysemismoothon

R

2;

(5)

(d)

φ

p

(

a

,

b

)

iscontinuouslydifferentiableforany

(

a

,

b

) = (

0

,

0

) ∈ R

2with

∂φ

p

(

a

,

b

)

a

=

sgn

(

a

) |

a

|

p1

p

(

a

,

b

))

p1 and

∂φ

p

(

a

,

b

)

b

=

sgn

(

b

) |

b

|

p1

p

(

a

,

b

))

p1

,

wherethefunctionsgn

( ·)

isdefinedbysgn

( α ) :=

⎧ ⎨

1 if

α >

0

,

0 if

α =

0

,

1 if

α <

0

.

Proof. Pleasereferto[5–9,15]foraproof.

2

According to Lemma 3.1, it follows that for any a

∈ R

anda

0, we have

φ

p

(

a

,

b

) → |

b

|

. Therefore, combining the spectraldecompositionofx andthefunction

φ

p,wedefineavector-valuedsmoothingfunction



p

: R × R

n

→ R

n as



p

( μ ,

x

) = φ

p

( μ , λ

1

(

x

))

u(x1)

+ φ

p

( μ , λ

2

(

x

))

u(x2)

= 

p

| μ |

p

+ |λ

1

(

x

) |

pu(x1)

+ 

p

| μ |

p

+ |λ

2

(

x

) |

pu(x2)

,

where

μ ∈ R

isaparameter,and

λ

1

(

x

), λ

2

(

x

)

arethespectralvaluesofx.FromLemma 3.1,itiseasytoverifythat μlim→0



p

( μ ,

x

) = |λ

1

(

x

)|

u(x1)

+ |λ

2

(

x

)|

u(x2)

= |

x

|.

Inotherwords,thefunction



p

( μ ,

x

)

isauniformlysmoothingfunctionof

|

x

|

associatedwithSOC.Withthisfunction,for theSOCAVE(2),wefurtherdefineafunction H

( μ ,

x

) : R × R

n

→ R × R

n by

H

( μ ,

x

) =

 μ

Ax

+

B



p

( μ ,

x

)

b



,μ ∈ R,

x

∈ R

n

.

(8)

Then,weobservethat

H

( μ ,

x

) =

0

⇐⇒ μ =

0 and Ax

+

B



p

( μ ,

x

)

b

=

0

⇐⇒

Ax

+

B

|

x

| −

b

=

0 and

μ =

0

.

Thisindicatesthat x isasolutiontotheSOCAVE(2)ifandonlyif

( μ ,

x

)

isasolutiontotheequation H

( μ ,

x

) =

0.Infact, we oftenchoose

μ ∈ R

++.Applying Lemma 3.1again, itisnotdifficulttoshow thatthefunction H

( μ ,

x

)

iscontinuously differentiable on

R

++

× R

n.Fromdirectcalculation,wecanalsoobtaintheexplicitformulaoftheJacobianmatrixforthe function H asbelow:

H

( μ ,

x

) =



1 0

B∂p(μμ,x) A

+

B∂p(xμ,x)



(9)

forall

( μ ,

x

) ∈ R

++

× R

nwithx

= (

x1

,

x2

) ∈ R × R

n1,where

∂

p

( μ ,

x

)

μ =

∂φ

p

( μ , λ

1

(

x

))

μ

u

(1)

x

+ ∂φ

p

( μ , λ

2

(

x

))

μ

u

(2) x

= μ

p1

p

( μ , λ

1

(

x

))]

p1u

(1)

x

+ μ

p1

p

( μ , λ

2

(

x

))]

p1u

(2) x and

∂

p

( μ ,

x

)

x

=

⎧ ⎪

⎪ ⎪

⎪ ⎪

⎪ ⎩

sgn(x1)|x1|p1

√p

μp+|x1|pp1I if x2

=

0

,

b c x

T

x22 cxx2

2 aI

+ (

b

a

)

x2x

T

x222

if x2

=

0

,

with

a

= φ

p

( μ , λ

2

(

x

)) − φ

p

( μ , λ

1

(

x

)) λ

2

(

x

) − λ

1

(

x

) ,

b

=

1

2

sgn

2

(

x

))

2

(

x

) |

p1

p

( μ , λ

2

(

x

)) ]

p1

+

sgn

1

(

x

))

1

(

x

) |

p1

p

( μ , λ

1

(

x

)) ]

p1

,

(10)

c

=

1 2

sgn

2

(

x

))|λ

2

(

x

)|

p1

p

( μ , λ

2

(

x

))]

p1

sgn

1

(

x

))|λ

1

(

x

)|

p1

p

( μ , λ

1

(

x

))]

p1

.

(6)

4. SmoothingNewtonmethod

Inthissection,weinvestigatethesmoothingalgorithmbasedonthesmoothingfunction



p

( μ ,

x

)

forsolvingtheSOCAVE (2), and show the convergence properties of the considered algorithm. First, we present the generic framework of the smoothingalgorithm.

Algorithm4.1(AsmoothingNewtonalgorithm).

Step 0 Choose

δ ∈ (

0

,

1

)

,

σ ∈ (

0

,

1

)

, and

μ

0

∈ R

++, x0

∈ R

n. Set z0

:= ( μ

0

,

x0

)

, e

:= (

1

,

0

) ∈ R × R

n1. Choose

β >

1 satisfyingmin

{

1

, 

H

(

z0

) 

2

} ≤ β μ

0.Setk

:=

0.

Step 1 If



H

(

zk

)  =

0,stop.Otherwise,set

τ

k

:=

min

{

1

, 

H

(

zk

) }

. Step 2 Compute



zk

= ( μ

k

, 

xk

) ∈ R × R

n by

H

(

zk

) +

H

(

zk

) 

zk

=

1

β τ

k2e

,

(11)

whereH

(

zk

)

denotestheJacobianmatrixof H

(

zk

)

at

( μ

k

,

xk

)

givenby(9).

Step 3 Let

α

kbethemaximumofthevalues1

, δ, δ

2

, · · ·

suchthat



H

(

zk

+ α

k



zk

) ≤



1

σ (

1

1

β ) α

k





H

(

zk

).

(12)

Step 4 Setzk+1

:=

zk

+ α

k



zk andk

:=

k

+

1.Goto Step1.

In orderto explain that Algorithm 4.1 is well defined, we haveto prove that the systemof Newton equation (11)is solvable,andthelinesearch(12)iswell-defined.Tothisend,weneedthenexttwotechnicallemmas.

Lemma4.1.Forany M

,

N

∈ R

n×n,

σ

min

(

M

) > σ

max

(

N

)

ifandonlyif

σ

min

(

MTM

) > σ

max

(

NTN

)

.Inaddition,if

σ

min

(

MTM

) >

σ

max

(

NTN

)

,thenMTM

NTN ispositivedefinite.Here

σ

min

(

M

)

denotestheminimumsingularvalueofM,and

σ

max

(

N

)

denotes themaximumsingularvalueofN.

Proof. Theproofisstraightforwardorcanbefoundinusualtextbookofmatrixanalysis,soweomitithere.

2

Lemma4.2.LetA

,

S

∈ R

n×nandA besymmetric.SupposethattheeigenvaluesofA andS STarearrangedinnon-increasingorder.

Then,foreachk

=

1

,

2

, · · · ,

n,thereexistsanonnegativerealnumber

θ

ksuchthat

λ

min

(

S ST

) ≤ θ

k

≤ λ

max

(

S ST

)

and

λ

k

(

S A ST

) = θ

k

λ

k

(

A

).

Proof. Pleasesee[18,Corollary4.5.11]foraproof.

2

InordertoshowthattheJacobianmatrix H

( μ ,

x

)

inNewtonequation(11)isnonsingularforany

μ >

0.We needthe followingassumption:

Assumption4.1.FortheSOCAVE(2),itholds

σ

min

(

A

) > σ

max

(

B

)

.

Infact,undertheconditionofAssumption 4.1,the SOCAVE(2)hasauniquesolution,whichisverifiedin[33].

Theorem4.1.LetH bedefinedasin(8).SupposethatAssumption 4.1holds.Then,theJacobianmatrixH

( μ ,

x

)

inNewtonequa- tions(11)isnonsingularforany

μ >

0.

Proof. From the expression of H

( μ ,

x

)

given asin (9), we know that H

( μ ,

x

)

is nonsingular ifand only ifthe matrix A

+

B∂(μx,x) isnonsingular.Thus, itsufficestoshow thatthematrix A

+

B∂(μx,x) isnonsingular.Supposenot,i.e.,there existsavector0

=

v

∈ R

n suchthat



A

+

B

∂( μ ,

x

)

x



v

=

0

.

Thisimpliesthat vTATA v

=

vT

 ∂( μ ,

x

)

x



T

BTB

∂( μ ,

x

)

x v

.

(13)

(7)

Forconvenience,we denoteC

:=

∂(μx,x).Then, itfollowsthat vTATA v

=

vTCTBTBC v.ByLemma 4.2,thereexistsacon- stant

ˆθ

suchthat

λ

min

(

CTC

) ≤ ˆθ ≤ λ

max

(

CTC

)

and

λ

max

(

CTBTBC

) = ˆθλ

max

(

BTB

).

Notethatifwecanprovethat0

≤ λ

min

(

CTC

) ≤ λ

max

(

CTC

)

1,wehave

λ

max

(

CTBTBC

) ≤ λ

max

(

BTB

)

.Then,bytheassump- tion that the minimumsingular value of A strictlyexceeds the maximumsingular value of B,andapplying Lemma 4.1, weobtain vTATA v

>

vTCTBTBC v.Thiscontradictstheformula(13),whichshowstheJacobianmatrixH

( μ ,

x

)

inNewton equations(11)isnonsingularfor

μ >

0.

Thus, asdiscussed above, we only need to prove 0

≤ λ

min

(

CTC

) ≤ λ

max

(

CTC

)

1.For x2

=

0,we compute that C

=

sgn(x1)|x1|p−1

√p

μp+|x1|pp−1I.Then,itisclearthat 0

< λ(

CTC

) <

1 for

μ >

0.Forx2

=

0,usingthefactthat thematrixMTM isalways positive semidefiniteforanymatrix M

∈ R

m×n,weseethat theinequality

λ

min

(

CTC

)

0 alwaysholds.Inorderto prove that

λ

max

(

CTC

)

1,weneedtofurtherprovethatthematrixI

CTC ispositivesemidefinite.Toseethis,notethat

I

CTC

=

1

b2

c2

2bcxx2T2

2bcxx22

(

1

a2

)

I

+ (

a2

b2

c2

)

x2x2T

x22

⎦ .

Becauseb2

+

c2

=

1 2



2

(

x

) |

2(p1)

p

( μ , λ

2

(

x

)) ]

2(p1)

+

1

(

x

) |

2(p1)

p

( μ , λ

1

(

x

)) ]

2(p1)



<

1

2

·

2

=

1 for

μ >

0,wehave1

b2

c2

>

0.Moreover, theSchurcomplementof1

b2

c2hastheformof

(

1

a2

)

I

+ (

a2

b2

c2

)

x2x

T 2



x2



2

4b2c2 1

b2

c2

x2xT2



x2



2

= (

1

a2

)



I

x2x2T



x2



2

 +

1

b2

c2

4b2c2 1

b2

c2

x2x2T



x2



2

.

(14)

Ontheotherhand,

i

(

x

)| < φ

p

( μ , λ

i

(

x

)) (

i

=

1

,

2

)

for

μ >

0,wehave

φ

p

( μ , λ

2

(

x

)) − φ

p

( μ , λ

1

(

x

))

=

 

 

 

2

(

x

)|

p

− |λ

1

(

x

)|

p



p i=1

 φ

p

( μ , λ

2

(

x

)) 

pi



φ

p

( μ , λ

1

(

x

)) 

i1

 

 

 

=

 

 

 

(

2

(

x

) | − |λ

1

(

x

) |)



p i=1

2

(

x

) |

pi

1

(

x

) |

i1



p i=1

 φ

p

( μ , λ

2

(

x

)) 

pi



φ

p

( μ , λ

1

(

x

)) 

i1

 

 

 

< ||λ

2

(

x

)| − |λ

1

(

x

)||

≤ |λ

2

(

x

) − λ

1

(

x

)|.

Thistogetherwith(10)impliesthat1

a2

>

0 forany

μ >

0.Inaddition,forany

μ >

0,weobservethat

(

1

b2

c2

)

2

4b2c2

= (

1

− (

b

c

)

2

)(

1

− (

b

+

c

)

2

)

=



1

1

(

x

) |

2(p1)

 φ

p

( μ , λ

1

(

x

)) 

2(p1)



·



1

2

(

x

) |

2(p1)

 φ

p

( μ , λ

2

(

x

)) 

2(p1)



>

0

,

where theinequality holds dueto

i

(

x

) | < φ

p

( μ , λ

i

(

x

))

fori

=

1

,

2 and

μ >

0. Withall ofthese, we seethat the Schur complementof1

b2

c2 givenasin(14)isalinearpositive combinationofthematrices

I

xx22xT22

and x2x

T

x222,which yields that theSchur complement(14)of1

b2

c2 is positivesemidefinite. Hence, thematrix I

CTC isalso positive semidefinite,whichisequivalenttosaying0

≤ λ

min

(

CTC

) ≤ λ

max

(

CTC

)

1.Thus,theproofiscomplete.

2

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