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Integral as an iterated integral

Let U be an open subset of Rn and let f : U → Rm be a map defined on U with values in Rm. 1. Let K = I1× · · · × In, where Ij = [aj, bj] for each j = 1, . . . , n. Remember that

• the content (or volume) c(K) of K is defined to be

c(K) = (b1− a1) × · · · × (bn− an) =

n

Y

j=1

(bj− aj).

• a set Z ⊂ Rn has content (or volume) zero if ∀  > 0, ∃ a finite collectionC = {Kj}mj=1 of n-cells such that

Z ⊂

m

[

j=1

Kj, and

m

X

j=1

c(Kj) < ε.

2. Let A ⊂ Rn be a bounded set and let f : A → R be a bounded function. Suppose that K is a closed cell containing A and let fK : K → R be an extension of f defined by

fK(x) =

(f (x) if x ∈ A, 0 if x ∈ K \ A.

We say that f is integrable on A if fK is integrable on K, and define Z

A

f = Z

K

fK.

3. (The Jacobian Theorem) Let Ω ⊆ Rp be open. Suppose that

φ : Ω → Rp belongs to class C1(Ω) is injective on Ω, Jφ(x) 6= 0 for x ∈ Ω,

A has content and ¯A ⊂ Ω.

If ε > 0 is given, then there exists r > 0 such that if K is a closed cell with center x ∈ A and side length less than 2r, then

|Jφ(x)|(1 − ε)p ≤ c(φ(K))

c(K) ≤ |Jφ(x)|(1 + ε)p. 4. (Change of Variables Theorem) Let Ω ⊆ Rp be open. Suppose that

φ : Ω → Rp belongs to class C1(Ω) is injective on Ω, Jφ(x) = det dφ(x) 6= 0 for x ∈ Ω,

A has content and ¯A ⊂ Ω and

f : φ(A) → R is bounded and continuous.

Then Z

φ(A)

f = Z

A

(f ◦ φ)|Jφ|.

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Partition of unity

1. For each p ∈ Rn, and for any 0 < r1 < r2, there exists a continuous (or a smooth) function g : Rn → R such that

g(x) =

(1 if x ∈ Br1(p), 0 if x /∈ Br2(p).

2. Suppose K is a compact subset of Rn, and {Vα} is an open cover of K. Then there exist functions ψ1, . . . , ψs∈ C(Rn), the space of smooth functions on Rn, such that

(a) 0 ≤ ψi ≤ 1 for 1 ≤ i ≤ s;

(b) each ψi has its support in some Vα, i.e. {x ∈ Rn | ψi(x) 6= 0} ⊂ Vα, and (c)

s

X

i=1

ψi(x) = 1 for every x ∈ K.

Because of (c), {ψ} is called a partition of unity, and (b) is sometimes expressed by saying that {ψi} is subordinate to cover {Vα}.

3. If f ∈ C (Rn) is a continuous function in Rn and the support of f lies in K, then f (x) =

s

X

i=1

ψi(x)f (x) for x ∈ Rn. Note that each ψif has its support in some Vα.

4. Let A ⊂ Rn and let O be a collection of open subsets of Rn covering A. Then there is a collection Φ of continuous functions ϕ defined in an open set containing A, with the following properties:

(a) For each x ∈ A we have 0 ≤ ϕ(x) ≤ 1.

(b) For each x ∈ A there is an open set V containing x such that all but finitely many of ϕ ∈ Φ are 0 on V.

(c) For each x ∈ A we have X

ϕ∈Φ

ϕ(x) = 1 (by (b) for each x this sum is finite in some open set containing x).

(d) For each ϕ ∈ Φ there is an open set U ∈ O such that ϕ = 0 outside of some closed set contained in U.

A collection Φ satisfying (a) to (c) is called a continuous partition of unity for A. If Φ also satisfies (d), it is said to be subordinate to the cover O. In this chapter we will only use continuity of the functions ϕ.

5. Let A ⊆ Rn be an open subset and let O be an open cover of A. Then O is an admissible open cover if every U ∈O is contained in A.

LetO be an admissible open cover of the open set A ⊆ Rn, Φ be a partition of unity for A subordinate to O, and let f : A → R be bounded in some open set around each point of A.

Then we say f is integrable (in the extended sense) on A if X

ϕ∈Φ

Z

A

ϕ · |f | converges.

This implies convergence of X

ϕ∈Φ

| Z

A

ϕ · f |, and hence absolute convergence of X

ϕ∈Φ

Z

A

ϕ · f, which we define to be

Z

A

f, i.e. if X

ϕ∈Φ

Z

A

ϕ · |f | converges, then Z

A

f :=X

ϕ∈Φ

Z

A

ϕ · f.

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6. Recall that a subset A of Rn has content 0 if for every ε > 0 there is a finite cover {K1, . . . , Km} of A by closed n-cells such that

m

X

j=1

c(Ki) < ε. A subset A of Rn has mea- sure 0 if for every ε > 0 there is a cover {K1, K2, K3, . . .} of A by closed n-cells such that

X

j=1

c(Ki) < ε.

A bounded set C whose boundary has measure 0 is called Jordan-measurable.

• If A = A1∪ A2∪ A3∪ · · · and each Ai has measure 0, then A has measure 0.

• If A is compact and has measure 0, then A has content 0.

7. • If Ψ is another partition of unity, subordinate to an admissible cover F of A, then X

ψ∈Ψ

Z

A

ψ · |f | also converges, and

X

ϕ∈Φ

Z

A

ϕ · f =X

ψ∈Ψ

Z

A

ψ · f.

• If A and f are bounded, then f is integrable in the extended sense.

• If A is Jordan-measurable and f is bounded, then this definition of Z

A

f agrees with the old one.

8. (Sard’s Theorem) If U ⊂ Rn is open, g : U → Rn ∈ C1(U ), and if B = {x ∈ U | det Dg(x) = 0}, then g(B) has measure 0.

Tensors on vector space

1. Familiar with k-tensor on a vector space V, tensor product of two tensors, the dual space of vector space V, the inner product on a vector space V, the basis ofT k(V ), the alternating k-tensor on V and the space Λk(V ) of alternating k-tensors on V.

2. Know that

• if T ∈T k(V ), then Alt (T ) defined by Alt (T )(v1, . . . , vk) = 1

k!

X

σ∈Sk

sgn σ · T (vσ(1), . . . , vσ(k)) ∈ Λk(V ),

where Sk is the set of all permutations of numbers 1 to k.

• If w ∈ Λk(V ), then Alt (w) ∈ Λk(V ).

• If T ∈Tk(V ), then Alt (Alt (T )) = Alt (T ).

3. If w ∈ Λk(V ) and η ∈ Λ`(V ), we define the wedge product w ∧ η ∈ Λk+`(V ) by w ∧ η = (k + `)!

k! `! Alt (w ⊗ η).

Note that ∧ satisfies the following properties.

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• w ∧ η = (−1)k`η ∧ w,

• f(w ∧ η) = f(w) ∧ f(η).

• If w ∈ Λk(V ), η ∈ Λ`(V ), and θ ∈ Λm(V ), then (w ∧ η) ∧ θ = w ∧ (η ∧ θ) = (k + ` + m)!

k! `! m! Alt (w ⊗ η ⊗ θ) = w ∧ η ∧ θ.

4. If {vi}ni=1 is a basis for V and {ϕi}ni=1 is the dual basis such that

ϕi(vj) = δij =

(1 if i = j, 0 if i 6= j.

Then the set of all

i1 ∧ · · · ∧ ϕik | 1 ≤ i1 < i2 < . . . < ik ≤ n}

is a basis of Λk(V ), which therefore has dimension

n k



= n!

k! (n − k)!.

5. Let {vi}ni=1 be a basis for V, and let w ∈ Λn(V ). If {wi}ni=1 are n vectors in V with wi =

n

X

j=1

aijvj, then

w(w1, . . . , wn) = det(aij) · w(v1, . . . , vn).

Fields and forms

1. Familiar with definitions of a vector field on Rn, a k-form on Rn, the tangent space Rnp of Rn at p, the (push-forward) linear transformation f : [

p∈Rn

Rnp → [

p∈Rn

Rmf (p) defined by f(vp) = Df (p)(v)

f (p) for vp = (p, v) ∈ Rnp and p ∈ Rn, and the (pullback) linear transformation f : Λk(Rmf (p)) → Λk(Rnp) defined by fw(p)(v1, . . . , vk) = w(f (p))(f(v1), . . . , f(vk)) for v1, . . . , vk ∈ Rnp.

2. Let x = (x1, . . . , xn) ∈ Rn and y = (y1, . . . , ym) ∈ Rm. If f : Rn→ Rm is differentiable then

• f(dy`) =

n

X

i=1

Dif`dxi =

n

X

i=1

∂y`

∂xi dxi.

• f(dy`1 ∧ dy`2) =X

i<j

∂(y`1, y`2)

∂(xi, xj) dxi∧ dxj.

• f(dy`1 ∧ · · · ∧ dy`k) = X

i1<···<ik

∂(y`1, . . . , y`k)

∂(xi1, . . . , xik)dxi1 ∧ · · · ∧ dxik

• f(g · w) = (g ◦ f ) · f(w), where g : Rm → Rp is a function (i.e. 0-form) on Rm.

• f(w ∧ η) = fw ∧ fη.

3. If f : Rn→ Rn is differentiable, then

f(hdx1∧ · · · ∧ dxn) = (h ◦ f ) (det Df ) dx1∧ · · · ∧ dxn.

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4. For each k ≥ 0 and for each

w = X

1≤i1<i2<···<ik≤n

wi1,...,ikdxi1 ∧ · · · ∧ dxik ∈ Λk(Rn),

define the linear transformation d : Λk(Rn) → Λk+1(Rn) by

dw = X

1≤i1<i2<···<ik≤n n

X

α=1

Dα(wi1,...,ik) dxα∧ dxi1 ∧ · · · ∧ dxik.

Let w be a k-form and η be an `-form on Rm. Then

• d(w ∧ η) = dw ∧ η + (−1)kw ∧ dη.

• d(dw) = 0, i.e. d(Λk(Rm)) is a subset of the kernel of d : Λk+1(Rm) → Λk+2(Rm).

Briefly, d2 = 0.

• If f : Rn → Rm is differentiable, then f(dw) = d(fw).

• w is called closed if dw = 0 and is called exact if w = dτ, for some (k − 1) form τ.

5. (Poincar´e Lemma) Let A ⊂ Rn be an open set star-shaped with respect to 0, i.e. for each x ∈ A, the line segment from 0 to x is contained in A. Then every closed form on A is exact.

6. (Stokes’ Theorem) If w is a (k − 1)-form on an open set A ⊂ Rn and c is a k-chain in A, then

Z

c

dw = Z

∂c

w.

參考文獻

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