Integral as an iterated integral
Let U be an open subset of Rn and let f : U → Rm be a map defined on U with values in Rm. 1. Let K = I1× · · · × In, where Ij = [aj, bj] for each j = 1, . . . , n. Remember that
• the content (or volume) c(K) of K is defined to be
c(K) = (b1− a1) × · · · × (bn− an) =
n
Y
j=1
(bj− aj).
• a set Z ⊂ Rn has content (or volume) zero if ∀ > 0, ∃ a finite collectionC = {Kj}mj=1 of n-cells such that
Z ⊂
m
[
j=1
Kj, and
m
X
j=1
c(Kj) < ε.
2. Let A ⊂ Rn be a bounded set and let f : A → R be a bounded function. Suppose that K is a closed cell containing A and let fK : K → R be an extension of f defined by
fK(x) =
(f (x) if x ∈ A, 0 if x ∈ K \ A.
We say that f is integrable on A if fK is integrable on K, and define Z
A
f = Z
K
fK.
3. (The Jacobian Theorem) Let Ω ⊆ Rp be open. Suppose that
φ : Ω → Rp belongs to class C1(Ω) is injective on Ω, Jφ(x) 6= 0 for x ∈ Ω,
A has content and ¯A ⊂ Ω.
If ε > 0 is given, then there exists r > 0 such that if K is a closed cell with center x ∈ A and side length less than 2r, then
|Jφ(x)|(1 − ε)p ≤ c(φ(K))
c(K) ≤ |Jφ(x)|(1 + ε)p. 4. (Change of Variables Theorem) Let Ω ⊆ Rp be open. Suppose that
φ : Ω → Rp belongs to class C1(Ω) is injective on Ω, Jφ(x) = det dφ(x) 6= 0 for x ∈ Ω,
A has content and ¯A ⊂ Ω and
f : φ(A) → R is bounded and continuous.
Then Z
φ(A)
f = Z
A
(f ◦ φ)|Jφ|.
Partition of unity
1. For each p ∈ Rn, and for any 0 < r1 < r2, there exists a continuous (or a smooth) function g : Rn → R such that
g(x) =
(1 if x ∈ Br1(p), 0 if x /∈ Br2(p).
2. Suppose K is a compact subset of Rn, and {Vα} is an open cover of K. Then there exist functions ψ1, . . . , ψs∈ C∞(Rn), the space of smooth functions on Rn, such that
(a) 0 ≤ ψi ≤ 1 for 1 ≤ i ≤ s;
(b) each ψi has its support in some Vα, i.e. {x ∈ Rn | ψi(x) 6= 0} ⊂ Vα, and (c)
s
X
i=1
ψi(x) = 1 for every x ∈ K.
Because of (c), {ψ} is called a partition of unity, and (b) is sometimes expressed by saying that {ψi} is subordinate to cover {Vα}.
3. If f ∈ C (Rn) is a continuous function in Rn and the support of f lies in K, then f (x) =
s
X
i=1
ψi(x)f (x) for x ∈ Rn. Note that each ψif has its support in some Vα.
4. Let A ⊂ Rn and let O be a collection of open subsets of Rn covering A. Then there is a collection Φ of continuous functions ϕ defined in an open set containing A, with the following properties:
(a) For each x ∈ A we have 0 ≤ ϕ(x) ≤ 1.
(b) For each x ∈ A there is an open set V containing x such that all but finitely many of ϕ ∈ Φ are 0 on V.
(c) For each x ∈ A we have X
ϕ∈Φ
ϕ(x) = 1 (by (b) for each x this sum is finite in some open set containing x).
(d) For each ϕ ∈ Φ there is an open set U ∈ O such that ϕ = 0 outside of some closed set contained in U.
A collection Φ satisfying (a) to (c) is called a continuous partition of unity for A. If Φ also satisfies (d), it is said to be subordinate to the cover O. In this chapter we will only use continuity of the functions ϕ.
5. Let A ⊆ Rn be an open subset and let O be an open cover of A. Then O is an admissible open cover if every U ∈O is contained in A.
LetO be an admissible open cover of the open set A ⊆ Rn, Φ be a partition of unity for A subordinate to O, and let f : A → R be bounded in some open set around each point of A.
Then we say f is integrable (in the extended sense) on A if X
ϕ∈Φ
Z
A
ϕ · |f | converges.
This implies convergence of X
ϕ∈Φ
| Z
A
ϕ · f |, and hence absolute convergence of X
ϕ∈Φ
Z
A
ϕ · f, which we define to be
Z
A
f, i.e. if X
ϕ∈Φ
Z
A
ϕ · |f | converges, then Z
A
f :=X
ϕ∈Φ
Z
A
ϕ · f.
6. Recall that a subset A of Rn has content 0 if for every ε > 0 there is a finite cover {K1, . . . , Km} of A by closed n-cells such that
m
X
j=1
c(Ki) < ε. A subset A of Rn has mea- sure 0 if for every ε > 0 there is a cover {K1, K2, K3, . . .} of A by closed n-cells such that
∞
X
j=1
c(Ki) < ε.
A bounded set C whose boundary has measure 0 is called Jordan-measurable.
• If A = A1∪ A2∪ A3∪ · · · and each Ai has measure 0, then A has measure 0.
• If A is compact and has measure 0, then A has content 0.
7. • If Ψ is another partition of unity, subordinate to an admissible cover F of A, then X
ψ∈Ψ
Z
A
ψ · |f | also converges, and
X
ϕ∈Φ
Z
A
ϕ · f =X
ψ∈Ψ
Z
A
ψ · f.
• If A and f are bounded, then f is integrable in the extended sense.
• If A is Jordan-measurable and f is bounded, then this definition of Z
A
f agrees with the old one.
8. (Sard’s Theorem) If U ⊂ Rn is open, g : U → Rn ∈ C1(U ), and if B = {x ∈ U | det Dg(x) = 0}, then g(B) has measure 0.
Tensors on vector space
1. Familiar with k-tensor on a vector space V, tensor product of two tensors, the dual space of vector space V, the inner product on a vector space V, the basis ofT k(V ), the alternating k-tensor on V and the space Λk(V ) of alternating k-tensors on V.
2. Know that
• if T ∈T k(V ), then Alt (T ) defined by Alt (T )(v1, . . . , vk) = 1
k!
X
σ∈Sk
sgn σ · T (vσ(1), . . . , vσ(k)) ∈ Λk(V ),
where Sk is the set of all permutations of numbers 1 to k.
• If w ∈ Λk(V ), then Alt (w) ∈ Λk(V ).
• If T ∈Tk(V ), then Alt (Alt (T )) = Alt (T ).
3. If w ∈ Λk(V ) and η ∈ Λ`(V ), we define the wedge product w ∧ η ∈ Λk+`(V ) by w ∧ η = (k + `)!
k! `! Alt (w ⊗ η).
Note that ∧ satisfies the following properties.
• w ∧ η = (−1)k`η ∧ w,
• f∗(w ∧ η) = f∗(w) ∧ f∗(η).
• If w ∈ Λk(V ), η ∈ Λ`(V ), and θ ∈ Λm(V ), then (w ∧ η) ∧ θ = w ∧ (η ∧ θ) = (k + ` + m)!
k! `! m! Alt (w ⊗ η ⊗ θ) = w ∧ η ∧ θ.
4. If {vi}ni=1 is a basis for V and {ϕi}ni=1 is the dual basis such that
ϕi(vj) = δij =
(1 if i = j, 0 if i 6= j.
Then the set of all
{ϕi1 ∧ · · · ∧ ϕik | 1 ≤ i1 < i2 < . . . < ik ≤ n}
is a basis of Λk(V ), which therefore has dimension
n k
= n!
k! (n − k)!.
5. Let {vi}ni=1 be a basis for V, and let w ∈ Λn(V ). If {wi}ni=1 are n vectors in V with wi =
n
X
j=1
aijvj, then
w(w1, . . . , wn) = det(aij) · w(v1, . . . , vn).
Fields and forms
1. Familiar with definitions of a vector field on Rn, a k-form on Rn, the tangent space Rnp of Rn at p, the (push-forward) linear transformation f∗ : [
p∈Rn
Rnp → [
p∈Rn
Rmf (p) defined by f∗(vp) = Df (p)(v)
f (p) for vp = (p, v) ∈ Rnp and p ∈ Rn, and the (pullback) linear transformation f∗ : Λk(Rmf (p)) → Λk(Rnp) defined by f∗w(p)(v1, . . . , vk) = w(f (p))(f∗(v1), . . . , f∗(vk)) for v1, . . . , vk ∈ Rnp.
2. Let x = (x1, . . . , xn) ∈ Rn and y = (y1, . . . , ym) ∈ Rm. If f : Rn→ Rm is differentiable then
• f∗(dy`) =
n
X
i=1
Dif`dxi =
n
X
i=1
∂y`
∂xi dxi.
• f∗(dy`1 ∧ dy`2) =X
i<j
∂(y`1, y`2)
∂(xi, xj) dxi∧ dxj.
• f∗(dy`1 ∧ · · · ∧ dy`k) = X
i1<···<ik
∂(y`1, . . . , y`k)
∂(xi1, . . . , xik)dxi1 ∧ · · · ∧ dxik
• f∗(g · w) = (g ◦ f ) · f∗(w), where g : Rm → Rp is a function (i.e. 0-form) on Rm.
• f∗(w ∧ η) = f∗w ∧ f∗η.
3. If f : Rn→ Rn is differentiable, then
f∗(hdx1∧ · · · ∧ dxn) = (h ◦ f ) (det Df ) dx1∧ · · · ∧ dxn.
4. For each k ≥ 0 and for each
w = X
1≤i1<i2<···<ik≤n
wi1,...,ikdxi1 ∧ · · · ∧ dxik ∈ Λk(Rn),
define the linear transformation d : Λk(Rn) → Λk+1(Rn) by
dw = X
1≤i1<i2<···<ik≤n n
X
α=1
Dα(wi1,...,ik) dxα∧ dxi1 ∧ · · · ∧ dxik.
Let w be a k-form and η be an `-form on Rm. Then
• d(w ∧ η) = dw ∧ η + (−1)kw ∧ dη.
• d(dw) = 0, i.e. d(Λk(Rm)) is a subset of the kernel of d : Λk+1(Rm) → Λk+2(Rm).
Briefly, d2 = 0.
• If f : Rn → Rm is differentiable, then f∗(dw) = d(f∗w).
• w is called closed if dw = 0 and is called exact if w = dτ, for some (k − 1) form τ.
5. (Poincar´e Lemma) Let A ⊂ Rn be an open set star-shaped with respect to 0, i.e. for each x ∈ A, the line segment from 0 to x is contained in A. Then every closed form on A is exact.
6. (Stokes’ Theorem) If w is a (k − 1)-form on an open set A ⊂ Rn and c is a k-chain in A, then
Z
c
dw = Z
∂c
w.