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Introduction to Bayesian Statistics Lecture 3: Single Parameter (II)

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Introduction to Bayesian Statistics

Lecture 3: Single Parameter (II)

Rung-Ching Tsai

Department of Mathematics National Taiwan Normal University

March 11, 2015

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Conjugate Prior Distributions

Definition of Conjugacy: If F is a class of sampling distributions p(y |θ), and P is a class of prior distributions for θ, then the classP is conjugate for F if

p(θ|y ) ∈ P for all p(·|θ) ∈ F and p(θ) ∈ P.

Advantages of using conjugate priors:

computational convenience

being interpretable as additional data

Example: Beta is conjugate for binomial with θ ∼ Beta(α, β) and θ|y ∼ Beta(α + y , β + n − y ).

Exercise: What is the conjugate prior for Poisson(λ)?

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Conjugate Prior Distributions for exponential families

Definition: The class F is an exponential family if all its members have the form

p(yi|θ) = f (yi)g (θ)eφ(θ)Tu(yi), where φ(θ): the “natural parameter” of the family F .

Exercise: Show that the binomial(n, θ) is an exponential family with natural parameter logit(θ), and the conjugate prior on θ are Beta distributions.

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Conjugate Prior Distributions for exponential families

Likelihood of θ:

p(y|θ) =

" n Y

i =1

f (yi)

#

g (θ)nexp φ(θ)T

n

X

i =1

u(yi))

!

∝ g (θ)nexp



φ(θ)Tt(y)

 , where t(y) =Pn

i =1u(yi): sufficient statistic for θ

(Conjugate) Prior:

p(θ) ∝ g (θ)ηexp

φ(θ)Tν

Posterior:

p(θ|y) ∝ g (θ)η+nexp

φ(θ)T(ν + t(y) .

Known fact: Exponential families are, in general, the only classes of distributions that have natural conjugate priors.

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Single Parameter θ: Continuous y

y ∼ normal(θ, σ2), σ2 known, use Bayesian approach to estimate θ.

choose a conjugate prior for θ, p(θ) = e2+Bθ+C, such that p(θ) ∝ exp



1

02(θ − µ0)2



likelihood of θ: p(y |θ) = 1

2πσexp −12(y − θ)2

find the posterior distribution of θ:

p(θ|y ) ∝ p(θ)p(y |θ) exp



1 2

 (y − θ)2

σ2 +(θ − µ0)2 τ02



exp



1

12(θ − µ1)2

 , that is, θ|y ∼ normal(µ1, τ12), where

µ1=

1 τ 20

µ0+1

σ2y

1 τ 20

+1

σ2

and τ12 1

=τ12 0

+σ12.

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Single Parameter θ: Continuous y

θ ∼ normal(µ0, τ02), y ∼ normal(θ, σ2) ⇒ θ|y ∼ normal(µ1, τ12)

posterior precision τ12 1

Definition ofprecision: the inverse of variance

τ12 1

= τ12 0

+σ12, i.e., the posterior precision equals the prior precision plus the data precision.

posterior mean µ1

µ1=

1 τ 20

µ0+1

σ2y

1 τ 20

+1

σ2

, i.e., the posterior mean is a weighted average of the prior mean and the observed value y , with weights proportional to the precision.

the prior mean adjusted toward the observed y : µ1= µ0+ (y − µ0)σ2τ02 2

0

.

a compromise between the prior mean and the observed data y , with data shrunk toward the prior mean: µ1= y − (y − µ0)σ2σ2 2

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Single Parameter θ: Continuous y

Posterior predictive distribution p(˜y |y ) p(˜y |y ) =

Z

p(˜y |θ)p(θ|y )d θ

∝ Z

exp



− 1

2(˜y − θ)2

 exp



− 1

12(θ − µ1)2

 d θ

y |y ∼ normal(?, ?)˜

E(˜y |y ) = E(E(˜y |θ, y )|y ) = E(θ|y ) = µ1

var(˜y |y ) = E(var(˜y |θ, y )|y ) + var(E(˜y |θ, y )|y ) = E(σ2|y ) + var(θ|y ) = σ2+ τ12.

Note. E(˜y |θ) = θ, var(˜y |θ) = σ2

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Single Parameter θ: Continuous y = (y

1

, · · · , y

n

)

y1, · · · , yniid∼ normal(θ, σ2), σ2 known, use Bayesian approach to estimate θ.

choose a conjugate prior for θ, p(θ) ∝ exp

12 0

(θ − µ0)2

likelihood of θ: p(y|θ) =Qn i =1

1

2πσexp −12(yi− θ)2

find the posterior distribution of θ:

p(θ|y ) ∝ p(θ)p(y|θ) exp



1 2

 Pn

i =1(yi− θ)2

σ2 +(θ − µ0)2 τ02



exp



1

n2(θ − µn)2

 ,

that is, θ|y ∼ normal(µn, τn2), where µn=

1 τ 20

µ0+n

σ2¯y

1 τ 20

+n

σ2

and τ12 n =τ12

0

+σn2.

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Single Parameter θ: Continuous y = (y

1

, · · · , y

n

)

y1, · · · , yniid

∼ normal(θ, σ2), σ2 known, θ ∼ normal(µ0, τ02)

⇒ θ|y ∼ normal(µn, τn2)

posterior precision τ12 n = τ12

0

+σn2; posterior mean µn=

1 τ 20

µ0+n

σ2y¯

1 τ 20

+n

σ2

If n is large, the posterior distribution is largely determined by σ2and the sample value ¯y .

As τ0→ ∞ with n fixed, or as n → ∞ with τ02fixed, we have

p(θ|y) ≈ normal(θ|¯y ,σ2 n).

Compare the well-known result of classical statistics:

¯

y |θ, σ2∼ normal(θ,σn2) leads to the use ofy ± 1.96¯ σn as a 95%

confidence interval for θ.

Bayesian approach gives the same result for noninformative prior.

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Exercise

A random sample of n students is drawn from a large population, and their weights are measured. The average weight of the n sampled students is ¯y = 150 pounds. Assume the weights in the population are normally distributed with unknown mean θ and known standard deviation 20 pounds. Suppose your prior distribution for θ is normal with mean 180 and standard deviation 40.

(a) Give your posterior distribution for θ.

(b) A new student is sampled at random from the same population and has a weight of ˜y pounds. Give a posterior predictive distribution for ˜y .

(c) For n = 10, give a 95% posterior interval for θ and a 95% posterior predictive interval for ˜y .

(d) Do the same for n = 100.

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Single Parameter σ

2

: Continuous y = (y

1

, · · · , y

n

)

y1, · · · , yniid∼ normal(θ, σ2), θ known, use Bayesian approach to estimate σ2.

likelihood of σ2:

p(y|σ2) =

n

Y

i =1

1 2πσexp



1

2(yi− θ)2



σ−nexp



1

2(yi− θ)2



= 2)n2exp(− n 2v ) where v =n1Pn

i =1(yi− θ)2

choose a conjugate prior for σ2(inverse-gamma):

p(σ2) ∝ (σ2)−(α+1)eσ2β

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Single Parameter σ

2

: Continuous y = (y

1

, · · · , y

n

)

y1, · · · , yniid∼ normal(θ, σ2), θ known, estimate σ2.

likelihood of σ2: p(y|σ2) = (σ2)n2exp(−n2v )2

choose a conjugate prior for σ2(inverse-gamma):

p(σ2) ∝ (σ2)−(α+1)eσ2β, i.e.,σ2∼ Inv-χ20, σ02)

Note. A scaled inverse-χ2distribution with scale σ20 and ν0degrees of freedom: σ0X2ν0 ∼ χ2ν0, i.e., X ∼ Inv-χ20, σ02)

find the posterior distribution of σ2: p(σ2) p(σ2)p(y|σ2)

 σ20 σ2

ν0/2+1

exp



σ20ν0 2



· (σ2)n2exp(−n 2

v σ2)

2)−((n+ν0)/2+1)exp



1

20σ20+ nv )

 . that is,σ2|y ∼ Inv-χ2

ν0+ n,ν0νσ20+nv

0+n

 .

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Homework II

1. The following Table gives the number of fatal accidents and deaths on scheduled airline flights per year over a ten-year period.

Year Fatal Passenger Death Year Fatal Passenger Death

accidents death rate accidents death rate

1976 24 734 0.19 1981 21 362 0.06

1977 25 516 0.12 1982 26 764 0.13

1978 31 754 0.15 1983 20 809 0.13

1979 31 877 0.16 1984 16 223 0.03

1980 22 814 0.14 1985 22 1066 0.15

(a) Assume that the number of fatal accidents in each year are independent with a Poisson(θ) distribution. Set a prior distribution for θ and determine the posterior distribution based on the data from 1976 through 1985. Under this model, give a 95% predictive interval for the number of fatal accident in 1986. You can use normal approximation to the gamma and Poisson or compute using simulation.

(b) Repeat (a) above, replacing ‘fatal accidents’ with ‘passenger deaths’.

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Homework II

2. Censored and uncensored data in the exponential model:

(a) Suppose y |θ is exponentially distributed with rate θ, and the marginal (prior) distribution of θ is Gamma(α, β). Suppose we observe that y ≥ 100, but do not observe the exact value of y . What is the posterior distribution, p(θ|y ≥ 100), as a function of α and β? Write down the posterior mean and variance of θ.

(b) In the above problem, suppose that we are now told that y is exactly 100. Now what are the posterior mean and variance of θ?

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