COMPUTATION OF SOME EXAMPLES OF GROTHENDIECK GROUPS
1. Grothendieck Group of abelian Categories
Let A be an abelian category. The Grothendieck group of A is an abelian group generated by the isomorphism classes [A] of objects A of A, subject to the relations [A] = [A0] + [A00] whenever 0 → A0 → A → A00→ 0 is an exact sequence in A. This group can be constructed as follows.
Let F (A) be the free abelian group generated by isomorphism classes of objects [A]
of A and R(A) be the subgroup of F (A) generated by elements [A] − [A0] − [A00] when 0 → A0 → A → A00 → 0 is exact. The quotient group F (A)/R(A) is the Grothendieck group K(A). The image of [A] in K(A) is still denoted by [A]. Using the exact sequence 0 → A1 → A1⊕ A2 → A2 → 0, we obtain
[A1⊕ A2] = [A1] + [A2].
Given an abelian category A, we denote ob A the class of objects of A. Let G be an abelian group. A function
f : ob A → G is said to be additive if
f (A) = f (A0) + f (A00)
for any exact sequence 0 → A0 → A → A00 → 0. One can verify that an additive function f : ob A → G induces a group homomorphism f : K(A) → G.
Let us compute some examples.
Proposition 1.1. Let VectF be the category of finite dimensional vector spaces over a field F. Then K(VectF) ∼= Z.
Proof. Two finite dimensional F -vectors spaces are isomorphic if and only if they have the same dimension. In other words, let V and W be finite dimensional F -vector spaces. Then [V ] = [W ] if and only if dimF V = dimFW. We define an additive function
ψ : ob VectF → Z≥0, V 7→ dimFV.
For any exact sequences of K-vector spaces, 0 → V0→ V → V00→ 0, we have dimFV = dimFV0+ dimFV00.
Hence ψ induces a group homomorphism
ψ : K(VectF) → Z
defined by ψ([V ] − [W ]) = dimFV − dimFW. This is well-defined. In fact, this is a group isomorphism. To see this, ψ([V ] − [W ]) = 0, if and only if dimFV = dimF W for any representative V of [V ] and W of [W ]. We find [V ] = [W ]. Hence [V ]−[W ] = 0 in K(VectF).
We prove that ψ is a monomorphism. To show that it is surjective, we simply use the fact that ψ([Fn] − [Fm]) = n − m for any n, m ≥ 0. This completes the proof of our assertion.
Proposition 1.2. Let Ab be the category of finitely generated abelian groups. Then K(Ab) ∼= Z.
1
2 COMPUTATION OF SOME EXAMPLES OF GROTHENDIECK GROUPS
Proof. If G is a finitely generated abelian group, then there exists n ≥ 0 and d1, · · · , dr such that
G ∼= Zn⊕ Zd1 ⊕ · · · ⊕ Zdr. Here Zd= Z/dZ. Hence we obtain
[G] = n[Z] +
r
X
i=1
[Zdi].
Let f : Z → Z be the homomorphism defined by f (x) = dx. Then Im f = dZ and ker f = 0.
These give us a short exact sequence
0 → Z → Z → Zd→ 0,
This shows that [Z] = [Z] + [Zd], and thus [Zd] = 0. Notice that if we denote Gt the torsion part of G, then G/Gt is torsion free and thus free, and G/Gt∼= Zn. Let us consider a map
ψ : ob Ab → Z≥0, G → rank(G/Gt).
If 0 → G0 → G → G00 → 0 is an exact sequence of finitely generated abelian groups, we obtain an exact sequence of free modules
0 → G0/G0t→ G/Gt→ G00/G00t → 0 which implies that
rank(G/Gt) = rank(G0/G0t) + rank(G00/G00t).
In other words, ψ is an additive function. We obtain a group homomorphism ψ : K(Ab) → Z.
Notice that if ψ(G) = 0, then G is torsion and thus [G] = 0. Hence ψ is in fact a group isomorphism; surjectivity can be proved by taking ψ([Zn] − [Zm]) = n − m. This also shows that K(Ab) is the free abelian group generated by [Z]. Proposition 1.3. Let A be the category of finite abelian groups. Then K(A) is the free abelian group generated by {[Zp] : p is a prime}.
Proof. Any finite abelian group A has a composition series A = An⊃ · · · ⊃ A1⊃ A0 = 0
such that Ai/Ai−1∼= Zpi for some prime pi. By induction1, we can show that [A] =
n
X
i=1
[Ai/Ai−1].
Hence [A] =Pn
i=1[Zpi]. This shows that elements of K(A) is generated by {[Zp] : p is a prime}.
Let
rp : ob A → Z
to be rp(A) = the number of Ai/Ai−1 isomorphic to Zp. This is a well-defined function (independent of choice of composition series) by the Jordan Holder theorem. Then rp
induces a well-defined group homomorphism
rp : K(A) → Z
by rp([Zq]) = δpq for any primes p, q. Here we use rp for its induced map. Claim the set {[Zp] : p is a prime} is Z-linearly independent.
1We leave it to the readers as an exercise. You may consider the exact sequence 0 → Ai−1→ Ai→ Ai/Ai−1→ 0.
COMPUTATION OF SOME EXAMPLES OF GROTHENDIECK GROUPS 3
SupposePr
i=1ai[Zpi] = 0 for distinct prime numbers p1, · · · , pr. Then rpk
r
X
i=1
ai[Zpi]
!
=
n
X
i=1
aiδik = ak.
We obtain that ak = 0 since rp(0) = 0 for all prime p. This proves the linear independence of {[Zp] : p is a prime}. We complete the proof of our assertion. An object A in an abelian category A is simple if A has no proper subobject 2. We say that A has finite length if there exists a composition series
A = An⊃ An−1⊃ · · · ⊃ A0= 0 of sub objects of A with each Ai/Ai−1 simple.
Theorem 1.1. Let A be an abelian category such that every object of A has finite length.
Then the Grothendick group K(A) is a free abelian group with basis {[S] : S is simple}.
Proof. The proof is similar to the proof of Proposition 1.3.
2A subobject of an object A in an abelian category is a monomorphism j : A0→ A.