• 沒有找到結果。

Increasing stability of the inverse boundary value problem for the Schr¨ odinger equation

N/A
N/A
Protected

Academic year: 2022

Share "Increasing stability of the inverse boundary value problem for the Schr¨ odinger equation"

Copied!
10
0
0

加載中.... (立即查看全文)

全文

(1)

Increasing stability of the inverse boundary value problem for the Schr¨ odinger equation

V Isakov, S Nagayasu, G Uhlmann, and J-N Wang

Abstract. In this work we study the phenomenon of increasing stability in the inverse boundary value problem for the Schr¨odinger equation. This prob- lem was previously considered by Isakov in which he discussed the phenomenon in different ranges of the wave number (or energy). The main contribution of this work is to provide a unified and easier approach to the same problem based on the complex geometrical optics solutions.

1. Introduction

Most of inverse problems are known to be severely ill-posed. This weakness makes it extremely difficult to design reliable reconstruction algorithms in prac- tice. However, in some cases, it has been observed numerically that the stability increases with respect to some parameter such as the wave number (or energy) (see, for example, [4] for the inverse obstacle scattering problem). Several rigorous justifications of the increasing stability phenomena in different settings were ob- tained by Isakov et al [7, 9, 10, 1, 2]. In particular, in [10], Isakov considered the Helmholtz equation with a potential

(1.1) ∆ + k2+ q(x)u(x) = 0 in Ω ⊂ Rn

with n ≥ 3. He obtained stability estimates of determining q by the Dirichlet-to- Neumann map for different ranges of k, which demonstrate the increasing stability phenomena in k. The purpose of this work is to provide a more straightforward way to derive a similar estimate for the inverse boundary value for (1.1). In [10], Isakov used real geometrical optics solutions for the large wave number k. In this work,

2010 Mathematics Subject Classification. Primary 35R30; Secondary 65N21.

Key words and phrases. Stability estimate, Inverse boundary value problem, Schr¨odinger equation, Complex geometrical optics solutions.

Isakov was in part supported by the NSF grant DMS 10-08902 and by Emylou Keith and Betty Dutcher Distinguished Professorship at WSU.

Nagayasu was partly supported by Grant-in-Aid for Young Scientists (B).

Uhlmann was partly supported by NSF and The Fondation de Sciences Math´ematiques de Paris.

Wang was partly supported by the NSC grant 99-2115-M-002-006-MY3.

Isakov, Nagayasu, and Wang would like to dedicate this work to Gunther Uhlmann for his 60th birthday.

c

0000 (copyright holder) 1

(2)

by more careful choice of an additional large parameter and a priori constraints we are able to use complex geometrical optics (CGO) solutions introduced by Calder´on [3] and Sylvester-Uhlmann [12] for all k ≥ 1. This will simplify the proof in [10].

Recently similar results were obtained by Isaev and Novikov [8] by using less explicit and more complicated methods of scattering theory.

In this work, instead of considering the Dirichlet-to-Neumann map, we define the boundary measurements to be the Cauchy data corresponding to (1.1)

Cq =



u|∂Ω,∂u

∂ν ∂Ω



, where u is a solution to (1.1)

 .

Hereafter, ν is the unit outer normal vector of ∂Ω. Assume that Cq1 and Cq2 are two Cauchy data associated with refraction indices q1and q2, respectively. To measure the distance between two Cauchy data, we define

dist(Cq1, Cq2) = max (

max

(f,g)∈Cq1 min

( ef ,eg)∈Cq2

k(f, g) − ( ef ,eg)kH1/2⊕H−1/2

k(f, g)kH1/2⊕H−1/2

,

max

(f,g)∈Cq2

min

( ef ,eg)∈Cq1

k(f, g) − ( ef ,eg)kH1/2⊕H−1/2

k(f, g)kH1/2⊕H−1/2

) , where

k(f, g)kH1/2⊕H−1/2= kf k2H1/2(∂Ω)+ kgk2H−1/2(∂Ω)

1/2 . Our main theorem is stated as follows.

Theorem 1.1. Let n ≥ 3. Assume Cq1 and Cq2 are Cauchy data corresponding to q1(x) and q2(x), respectively. Let s > n/2 and M > 0. Assume kqlkHs(Ω)≤ M (l = 1, 2) and supp (q1− q2) ⊂ Ω. Denoteq the zero extension of qe 1− q2. Then for k ≥ 1 and dist(Cq1, Cq2) ≤ 1/e we have the following stability estimate:

(1.2) kqkeH−s(Rn)≤ Ck4dist(Cq1, Cq2) + C



k + log 1 dist(Cq1, Cq2)

−(2s−n)

, where C > 0 depends only on n, s, Ω, M and supp (q1− q2).

From estimate (1.2), it is obvious that the stability behaves more like Lipschitz type when k is large. We would like to point out that unlike in the acoustic case where the constant associated with the Lipschitz estimate grows exponentially in k [11], the constant here grows only polynomially in k. Similarly, the corresponding constant obtained in [10] (see estimate (8) there) also grows polynomially in k.

The paper is organized as follows. In Section 2, we will collect some known results about the CGO solutions and an estimate for the difference of potentials, which are essential tools in the proof. In Section 3, we present a detailed proof of Theorem 1.1.

2. Preliminaries

To begin, we state the existence of CGO solutions for (1.1). These special solutions are first constructed by Sylvester and Uhlmann [12]. Another construction based on the Fourier series is given by H¨ahner [6].

Lemma 2.1. Let s > n/2. Assume that ζ = η + iξ (η, ξ ∈ Rn) satisfies

|η|2= k2+ |ξ|2 and η · ξ = 0,

(3)

i.e., ζ · ζ = k2. Then there exist constants C and C > 0, which are independent of k, such that if |ξ| > CkqkHs(Ω) then there exists a solution u to the equation (1.1) of the form

(2.1) u(x) = eiζ·x 1 + ψ(x),

where ψ has the estimate

kψkHs(Ω)≤ C

|ξ|kqkHs(Ω).

Remark 2.2. Note that the correction term ψ decays in Im ζ. This property is crucial in obtaining that the constant associated with the Lipschiz estimate grows only polynomially in k.

Next inequality is an easy consequence of Alessandrini’s identity. We refer to [5] for the proof.

Proposition 2.3. Let ul and Cql be solution and Cauchy data to the equation (1.1) with q = ql, respectively (l = 1, 2). Then the following estimate holds:

Z

(q2− q1)u1u2dx

 u1,∂u1

∂ν



H1/2⊕H−1/2

 u2,∂u2

∂ν



H1/2⊕H−1/2

dist(Cq1, Cq1).

3. Proof of main theorem To prove Theorem 1.1, we first derive two lemmas.

Lemma 3.1. Under the assumptions in Theorem 1.1, (3.1) |Fq(rω)| ≤ Cke 4eCadist(Cq1, Cq2) +C

akqke H−s(Rn)

holds for k ≥ 1, r ≥ 0, ω ∈ Rn with |ω| = 1 and a > CM with k2+ a2 > r2/4, where C > 0 depends only on n, s, M, Ω and supp (q1− q2) and C is the constant given in Lemma 2.1.

Proof. We will use CGO solutions (2.1) with appropriately chosen parameter ζ. Let us denote ζl= ηl+ iξl, l = 1, 2. We can choose ω,ωe ∈ Rn satisfying

ω · ω= ω ·eω= ω·ωe= 0 and |ω| = |ωe| = 1.

Now we set

ξ1= aω, η1= −r 2ω +

r

k2+ a2−r2 4 ωe, ξ2= −ξ1 and η2= −rω − η1,

and thus

ξl· ηl= 0, |ηl|2= k2+ |ξl|2

and |ξl| = a ≥ CM ≥ Ckq`kHs(Ω). From Lemma 2.1, there exist CGO solutions ul(x) = elx 1 + ψl(x)

to equation (1.1) with q = ql, where ψlsatisfies kψlkHs(Ω)≤ C

l|kqlkHs(Ω).

(4)

Note that ψl also satisfies the estimate (3.2) kψlkHs(Ω)≤ C

l|kqlkHs(Ω)≤ CM

a < CM CM = C

C

.

Now, by Proposition 2.3 and using the relation −rω = ζ1+ ζ2, we have that

Z

eq(x)e−irω·x(1 + ψ1)(1 + ψ2) dx

= Z

(q2− q1)u1u2dx

 u1,∂u1

∂ν

 H1/2

⊕H−1/2

 u2,∂u2

∂ν

 H1/2

⊕H−1/2

dist(Cq1, Cq1).

Subsequently, we obtain

|Feq(rω)| = Z

eq(x)e−irω·xdx (3.3)

≤ Z

q(x)ee −irω·x(1 + ψ1)(1 + ψ2) dx +

Z

q(x)ee −irω·x1+ ψ2+ ψ1ψ2) dx

 u1,∂u1

∂ν



H1/2⊕H−1/2

 u2,∂u2

∂ν



H1/2⊕H−1/2

dist(Cq1, Cq1)

+ Z

q(x)ee −irω·x1+ ψ2+ ψ1ψ2) dx . In view of (3.3), we want to estimate

(ul, ∂ul/∂ν)

H1/2⊕H−1/2. Recall that ul solves (1.1) with q = ql. Using assumptions kqlkHs(Ω)≤ M , and s > n/2, and k ≥ 1, we have that

∂ul

∂ν

H−1/2(∂Ω)

≤ Ck2kulkL2(Ω)+ Ck∇ulkL2(Ω)

and thus

 ul,∂ul

∂ν

 H1/2

⊕H−1/2

≤ Ck2kulkL2(Ω)+ Ck∇ulkL2(Ω). We now choose R0> 0 large enough such that Ω ⊂ BR0(0). Then we have

|ul(x)| ≤ e−ξl·x 1 + |ψl(x)| ≤ Cel|R0 = CeaR0 since

l(x)| ≤ kψlkL(Ω)≤ CkψlkHs(Ω)≤ C by s > n/2 and (3.2). It follows that

kulkL2(Ω)≤ CeaR0.

On the other hand, in view of k∇ψlkL2(Ω)≤ kψlkHs(Ω) ≤ C (s > n/2 ≥ 3/2 > 1) and (3.2), we can estimate

k∇ulkL2(Ω)=

iulζl+ el·•∇ψl

L2(Ω)≤ |ζl|kulkL2(Ω)+ el|R0k∇ψlkL2(Ω)

≤ C k + |ξl|eaR0+ Cel|R0 = C(k + a)eaR0+ CeaR0 ≤ CkeCa.

(5)

Summing up, we obtain

 ul,∂ul

∂ν



H1/2⊕H−1/2

≤ Ck2kulkL2(Ω)+ Ck∇ulkL2(Ω)

(3.4)

≤ Ck2eCa+ CkeCa≤ Ck2eCa. Note that here C depends on n, s, M , and the diameter of Ω.

Let χ ∈ C0(Ω) be a cut-off function satisfying χ ≡ 1 near supp (q1− q2), then we have

Z

q(x)ee −irω·x1+ ψ2+ ψ1ψ2) dx (3.5)

= Z

eq(x)χ(x)e−irω·x1+ ψ2+ ψ1ψ2) dx

≤ Z

|q(x)||χ(ψe 1+ ψ2+ ψ1ψ2)| dx

≤ kqke H−s(Ω)kχ(ψ1+ ψ2+ ψ1ψ2)kHs(Ω). Since s > n/2 and (3.2), we can estimate

kχ(ψ1+ ψ2+ ψ1ψ2)kHs(Ω)

(3.6)

≤ kχkHs(Ω)1kHs(Ω)+ kψ2kHs(Ω)+ kψ1kHs(Ω)2kHs(Ω)



≤ kχkHs(Ω)

 CM a +CM

a + C C

·CM a



≤ C a.

Finally, (3.1) follows from (3.3), (3.4), (3.5), and (3.6). 

The following lemma is an easy corollary of Lemma 3.1.

Lemma 3.2. Suppose that the assumptions in Theorem 1.1 hold. Let R > CM with Cbeing the constant given in Lemma 2.1. Then for k ≥ 1, r ≥ 0 and ω ∈ Rn with |ω| = 1, the following estimates hold true: if 0 ≤ r ≤ k + R then

(3.7) |Fq(rω)| ≤ Cke 4eCRdist(Cq1, Cq2) +C

Rkqke H−s(Rn); if r ≥ k + R then

(3.8) |Fq(rω)| ≤ Cke 4eCrdist(Cq1, Cq2) +C

rkeqkH−s(Rn).

Proof. It is enough to take a = R when 0 ≤ r ≤ k + R, and take a = r when

r ≥ k + R in Lemma 3.1. 

Now we prove our main theorem.

(6)

Proof of Theorem 1.1. Written in polar coordinates, we have that kqke 2H−s(Rn)= C

Z 0

Z

|ω|=1

|Fq(rω)|e 2(1 + r2)−srn−1dωdr (3.9)

= C

Z k+R 0

Z

|ω|=1

|Fq(rω)|e 2(1 + r2)−srn−1dωdr

+ Z T

k+R

Z

|ω|=1

|Fq(rω)|e 2(1 + r2)−srn−1dωdr

+ Z

T

Z

|ω|=1

|Fq(rω)|e 2(1 + r2)−srn−1dωdr



=: C(I1+ I2+ I3),

where R > CM and T ≥ k + R are parameters which will be chosen later.

Our task now is to estimate each integral separately. We begin with I3. Since

|Fq(rω)| ≤ Ckqe 1− q2kL2(Ω), q1− q2∈ H0s(Ω) and s > n/2, we get

I3≤ C Z

T

kq1− q2k2L2(Ω)(1 + r2)−srn−1dr ≤ CT−mkq1− q2k2L2(Ω)

(3.10)

≤ CT−m



εkq1− q2k2H−s(Ω)+1

εkq1− q2k2Hs(Ω)



≤ CT−m



εkqke 2H−s(Rn)+1 ε



for ε > 0, where m := 2s − n.

On the other hand, by estimate (3.7), we can obtain

I1≤ Z k+R

0



Ck4eCRdist(Cq1, Cq2) +C

Rkqke H−s(Rn)

2

(1 + r2)−srn−1dr (3.11)

≤ C



k8eCRdist(Cq1, Cq2)2+ 1

R2kqke 2H−s(Rn)

 Z 0

(1 + r2)−srn−1dr

= C



k8eCRdist(Cq1, Cq2)2+ 1

R2kqke 2H−s(Rn)

 .

In the same way, using estimate (3.8), we have

I2≤ C Z T

k+R



Ck4eCrdist(Cq1, Cq2) +C

rkeqkH−s(Rn)

2

(1 + r2)−srn−1dr (3.12)

≤ Ck8dist(Cq1, Cq2)2 Z T

k+R

eCr(1 + r2)−srn−1dr

+ Ckeqk2H−s(Rn)

Z T k+R

(1 + r2)−srn−1dr

≤ C



k8eCTdist(Cq1, Cq2)2+ 1

R2kqke 2H−s(Rn)

 ,

(7)

where we have used Z T

k+R

eCr(1 + r2)−srn−1dr ≤ eCT Z T

k+R

(1 + r2)−srn−1dr

≤ eCt Z

0

(1 + r2)−srn−1dr = CeCT,

Z T k+R

(1 + r2)−srn−1dr ≤ Z T

k+R

r−2s+n−1dr

≤ 1

2s − n + 2

1

(k + R)2s−n+2 ≤ C

(k + R)2 ≤ C R2, and s > n/2, k ≥ 1. Combining (3.9)–(3.12) gives

kqke 2H−s(Rn)≤ C(I1+ I2+ I3) (3.13)

≤ C



k8eCRdist(Cq1, Cq2)2+ 1

R2kqke 2H−s(Rn)



+ C



k8eCT dist(Cq1, Cq2)2+ 1

R2kqke 2H−s(Rn)



+ CT−m



εkqke 2H−s(Rn)+1 ε



≤ C

 2

R2 + εT−m



kqke 2H−s(Rn)+ Ck8eCRdist(Cq1, Cq2)2

+ Ck8eCT dist(Cq1, Cq2)2+CT−m ε . To continue, we consider the following two cases:

(i) k + R ≤ p log 1

A and (ii) k + R ≥ p log 1 A,

where R > CM and p > 0 are constants which will be determined later. We begin with the first case (i). Taking

(3.14) R > 2

√ C and ε = cTm (c  1), we deduce that

(3.15) kqke 2H−s(Rn)≤ Ck8A + Ck8eCTA + CT−2m for any T ≥ k + R by (3.13), where A = dist(Cq1, Cq2)2.

Now we choose T = p log(1/A), which is greater than or equal to k + R by the condition (i). Our current aim is to show that there exists C1> 0 such that

(3.16) k8eCTA ≤ C1



k + log 1 A

−2m

and

(3.17) T−2m≤ C1



k + log 1 A

−2m

.

(8)

Substituting (3.16) and (3.17) into (3.15) clearly implies (1.2). We remark that (3.17) is equivalent to

(3.18) C1−1/2m



k + log 1 A



≤ p log 1 A. Since we have

k + log 1

A ≤ (k + R) + log 1

A ≤ (p + 1) log 1 A by (i), condition (3.18) (i.e. (3.17)) holds whenever

(3.19) C1−1/2m≤ p

p + 1. On the other hand, condition (3.16) is equivalent to (3.20) 8 log k + (Cp − 1) log 1

A + 2m log



k + log 1 A



≤ log C1. Using (i), we can bound the left-hand side of (3.20) by

(LHS of (3.20)) ≤ 8 log p + 2m log(p + 1) + (Cp − 1) log 1

A+ 2(m + 4) log log 1 A. Choosing

(3.21) p ≤ 1

2C, we can see that

(LHS of (3.20))

≤ 8 log 1

2C + 2m log

 1 2C + 1



−1 2log 1

A+ 2(m + 4) log log 1 A

≤ 8 log 1

2C + 2m log

 1 2C + 1

 + max

z≥2



−1

2z + 2(m + 4) log z



= 8 log 1

2C + 2m log

 1 2C + 1



+ 2(m + 4) log(4m + 16) − 1.

Therefore, condition (3.20) (i.e. (3.16)) is satisfied provided (3.22) 8 log 1

2C + 2m log

 1 2C + 1



+ 2(m + 4) log(4m + 16) − 1 ≤ log C1. Next we consider case (ii). We choose T = k + R and observe that the term I2

in (3.9) does not appear in this case. Hence, instead of (3.13), we have kqke 2H−s(Rn)

≤ C

 1

R2 + εT−m



kqke 2H−s(Rn)+ Ck8eCRdist(Cq1, Cq2)2+CT−m ε Setting ε = Tm/R2 implies that

kqke 2H−s(Rn)≤ 2C

R2kqke 2H−s(Rn)+ Ck8eCRA + CR2(k + R)−2m. Now we choose

(3.23) R > 2√

C and obtain that

keqk2H−s(Rn)≤ Ck8A + C(k + R)−2m,

(9)

which implies the desired estimate (1.2) since from condition (ii) we have k + R ≥ k

2 +k + R 2 ≥ k

2 +p 2log 1

A ≥ min{p, 1}

2



k + log 1 A

 .

As the last step, we choose appropriate R, p, and C1to complete the proof. We first pick R > CM sufficiently large satisfying (3.14) and (3.23) and then choose p small enough satisfying (3.21). Finally, we take C1large enough satisfying (3.19)

and (3.22). 

4. Conclusion

We think that increasing stability is an important feature of the inverse bound- ary problem for the Schr¨odinger potential which should lead to higher resolution of numerical algorithms. It is important to collect numerical evidence of this phe- nomenon. Our method is based on the CGO solutions constructed in [6] where the constants in Lemma 2.1 are explicit. So most likely one can give explicit constants in Theorem 1.1 at least for particular domains Ω like balls. Contrary to the acoustic case [11], the constants in the estimate (1.2) depend only polynomially on k. It is an important and challenging question to determine whether the exponential de- pendence on k of the estimates in [11] is indeed generic if there are no assumptions on rays.

References

[1] D. Aralumallige Subbarayappa and V. Isakov, On increased stability in the continuation of the Helmholtz equation, Inverse Problems, 23 (2007), no. 4, 1689-1697.

[2] D. Aralumallige Subbarayappa and V. Isakov, Increasing stability of the continuation for the Maxwell system, Inverse Problems, 26 (2010), no. 7, 074005, 14 pp.

[3] A.P. Calder´on, On inverse boundary value problem, Seminar on Numerical Analysis and its Applications to Continuum Physics, Rio de Janeiro, Editors W.H. Meyer and M.A. Raupp, Sociedade Brasileira de Matematica, (1980), 65-73.

[4] D. Colton, H. Haddar, and M. Piana, The linear sampling method in inverse electromagnetic scattering theory, Inverse Problems, 19 (2003), S105-S137.

[5] J. Feldman, M. Salo and G. Uhlmann, Calder´on’s problem: An inroduction to inverse problems. Preliminary notes on the book in preparation. http://www.math.ubc.ca/ feld- man/ibook/

[6] P. H¨ahner, A periodic Faddeev-type solution operator, J. Differential Equations, 128 (1996), 300-308.

[7] T. Hrycak and V. Isakov, Increased stability in the continuation of solutions to the Helmholtz equation, Inverse Problems, 20 (2004), 697-712.

[8] M. Isaev and R. Novikov, Energy and regularity dependent stability estimates for the Gelfand’s inverse problem in multi dimensions, J. Inverse Ill-Posed Problems, 20 (2012), 313-325.

[9] V. Isakov, Increased stability in the continuation for the Helmholtz equation with variable coefficient, Control methods in PDE-dynamical systems, 255V267, Contemp. Math., 426, AMS, Providence, RI, 2007.

[10] V. Isakov, Increasing stability for the Schr¨odinger potential from the Dirichlet-to-Neumann map, DCDS-S, 4 (2011), 631-640.

[11] S. Nagayasu, G. Uhlmann, and J.N. Wang, Increasing stability in an inverse problem for the acoustic equation, Inverse Problems, 29 (2013), 025012, 11 pp.

[12] J. Sylvester and G. Uhlmann, A global uniqueness theorem for an inverse boundary value problem, Ann. of Math., 185 (1987), 153-169.

(10)

Department of Mathematics and Statistics, Wichita State University, KS 67260- 0033, USA.

E-mail address: victor.isakov@wichita.edu

Department of Mathematical Sciences, University of Hyogo, Himeji 671-2201, Japan.

E-mail address: sei@sci.u-hyogo.ac.jp

Department of Mathematics, University of Washington, Box 354305, Seattle, WA 98195-4350, USA & Fondation de Sciences Math´ematiques de Paris

E-mail address: gunther@math.washington.edu

Department of Mathematics, NCTS (Taipei), National Taiwan University, Taipei 106, Taiwan.

E-mail address: jnwang@math.ntu.edu.tw

參考文獻

相關文件

Full credit if they got (a) wrong but found correct q and integrated correctly using their answer.. Algebra mistakes -1% each, integral mistakes

We would like to point out that unlike the pure potential case considered in [RW19], here, in order to guarantee the bulk decay of ˜u, we also need the boundary decay of ∇u due to

As a consequence, the Dirichlet (resp. Neumann) boundary value problem for 2D elasticity equation is equivalent to the Neumann (resp. Dirichlet) boundary value problem for the

The cross-section is a hexagon, and the shape of the solid looks like the union of two umbrellas..

Results for such increasing stability phenomena in the inverse source problems for the acoustic, electromagnetic, and elastic waves can be found in [ABF02, BLT10, BHKY18, BLZ20,

In this paper we study the stability question of the inverse bound- ary value problem for the Schr¨odinger equation with a potential and the conductivity equation by partial

In this paper we study the stability question of the inverse boundary value prob- lem for the Schr¨ odinger equation with a potential and the conductivity equa- tion by partial

In the inverse boundary value problems of isotropic elasticity and complex conductivity, we derive estimates for the volume fraction of an inclusion whose physical parameters