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# Differentiation Formulas

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### Differentiation Formulas

Let’s start with the simplest of all functions, the constant function f(x) = c.

The graph of this function is the horizontal line y = c, which has slope 0, so we must have f '(x) = 0. (See Figure 1.)

Figure 1

The graph of f(x) = c is the line y = c, so f′(x) = 0.

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### Differentiation Formulas

A formal proof, from the definition of a derivative, is also easy:

In Leibniz notation, we write this rule as follows.

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### Power Functions

We next look at the functions f(x) = xn, where n is a positive integer.

If n = 1, the graph of f(x) = x is the line y = x, which has slope 1. (See Figure 2.)

Figure 2

The graph of f(x) = x is the line y = x, so f '(x) = 1.

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### Power Functions

So

(You can also verify Equation 1 from the definition of a derivative.)

We have already investigated the cases n = 2 and n = 3.

We found that

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### Power Functions

For n = 4 we find the derivative of f(x) = x4 as follows:

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### Power Functions

Thus

Comparing the equations in (1), (2), and (3), we see a pattern emerging.

It seems to be a reasonable guess that, when n is a

positive integer, (d/dx)(xn) = nxn – 1. This turns out to be true.

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### Example 1

(a) If f(x) = x6, then f′(x) = 6x5. (b) If y = x1000, then y′= 1000x999. (c) If y = t4, then = 4t3.

(d) = 3r2

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### New Derivatives from Old

When new functions are formed from old functions by

addition, subtraction, or multiplication by a constant, their derivatives can be calculated in terms of derivatives of the old functions.

In particular, the following formula says that the derivative of a constant times a function is the constant times the derivative of the function.

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## Example 2

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### New Derivatives from Old

The next rule tells us that the derivative of a sum of functions is the sum of the derivatives.

The Sum Rule can be extended to the sum of any number of functions. For instance, using this theorem twice, we get

(f + g + h)′ = [(f + g) + h]′ = (f + g)′ + h′ = f′ + g′ + h′

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### New Derivatives from Old

By writing f – g as f + (–1)g and applying the Sum Rule and the Constant Multiple Rule, we get the following formula.

The Constant Multiple Rule, the Sum Rule, and the

Difference Rule can be combined with the Power Rule to differentiate any polynomial, as the following examples demonstrate.

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### Example 3

(x8 + 12x5 – 4x4 + 10x3 – 6x + 5)

= 8x7 + 12(5x4) – 4(4x3) + 10(3x2) – 6(1) + 0

= 8x7 + 60x4 – 16x3 + 30x2 – 6

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### New Derivatives from Old

Next we need a formula for the derivative of a product of two functions. By analogy with the Sum and Difference

Rules, one might be tempted to guess, as Leibniz did three centuries ago, that the derivative of a product is the product of the derivatives.

We can see, however, that this guess is wrong by looking at a particular example. Let f(x) = x and g(x) = x2. Then the Power Rule gives f′(x) = 1 and g′(x) = 2x. But (fg)(x) = x3,

so (fg)′(x) = 3x2. Thus (fg)′ ≠ f′g′.

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### New Derivatives from Old

The correct formula was discovered by Leibniz and is called the Product Rule.

In words, the Product Rule says that the derivative of a product of two functions is the first function times the

derivative of the second function plus the second function times the derivative of the first function.

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### Example 6

Find F′(x) if F(x) = (6x3)(7x4).

Solution:

By the Product Rule, we have F′(x) =

= (6x3)(28x3) + (7x4)(18x2)

= 168x6 + 126x6

= 294x6

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### New Derivatives from Old

In words, the Quotient Rule says that the derivative of a quotient is the denominator times the derivative of the

numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator.

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Let . Then

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### New Derivatives from Old

Note:

Don’t use the Quotient Rule every time you see a quotient.

Sometimes it’s easier to first rewrite a quotient to put it in a form that is simpler for the purpose of differentiation.

For instance, although it is possible to differentiate the function

F(x) = using the Quotient Rule.

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### New Derivatives from Old

It is much easier to perform the division first and write the function as

F(x) = 3x + 2x–1/2 before differentiating.

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### General Power Functions

The Quotient Rule can be used to extend the Power Rule to the case where the exponent is a negative integer.

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### Example 9

(a) If y = , then

= –x–2

= (b)

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### Example 11

Differentiate the function f(t) = (a + bt).

Solution 1:

Using the Product Rule, we have

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### Example 11 – Solution 2

If we first use the laws of exponents to rewrite f(t), then we can proceed directly without using the Product Rule.

which is equivalent to the answer given in Solution 1.

cont’d

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### General Power Functions

The differentiation rules enable us to find tangent lines without having to resort to the definition of a derivative.

It also enables us to find normal lines.

The normal line to a curve C at a point P is the line through P that is perpendicular to the tangent line at P.

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### Example 12

Find equations of the tangent line and normal line to the curve

y = /(1 + x2) at the point (1, ).

Solution:

According to the Quotient Rule, we have

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### Example 12 – Solution

So the slope of the tangent line at (1, ) is

We use the point-slope form to write an equation of the tangent line at (1, ):

y – = – (x – 1) or y =

cont’d

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### Example 12 – Solution

The slope of the normal line at (1, ) is the negative reciprocal of , namely 4, so an equation is

y – = 4(x – 1) or y = 4x –

The curve and its tangent and normal lines are graphed in Figure 5.

cont’d

Figure 5

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### General Power Functions

We summarize the differentiation formulas we have learned so far as follows.

Table of Differentiation Formulas

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