506002
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囡立臺 j彎科技大學 103 學年度碩士班招生試題 ih 所組另IJ 化學工程系碩士班
科 目 :化工熱力學與動力學 (總分為100分)
PART I. 化工熱力 學 (50%)
1. The heat of mixing for the n-octanol + n-decane liquid mixture at atmospheric
pressur巴 isapproximately fit by
ð.mixH = XIX2(A + B(Xl - X2)) Jjmo!
/ 頁共
3
頁where A = 2477.5 and B = -1455.9 at T = 300 K and x] being the n-octanol mole fraction. Compllte the difference between the partial molar and pure-component enthalpies ofn-octanol and n-decane atx] = 0.5 and T= 300 K. (15%)
2. A gas witb a heat capacity Cj> = 2il.il7 JK-1mo!-1 obeys the eqllation of sta峙，
P主 = RT+ β尸， wher巴 β is a function of tel1l.peratllre:
7~K)
I
200 250 300 400B( C1113
/11101) -35.2 -16.2 -4.2 +9.0
Detennine the JOllle-Thomson co巴fficientofthe gas at 20C. (15%)
3. A catalyst has be叫1日ollnd which gives adeqllate rate of reaction at 5000C in the reaction CO + 2l-h = CI-hOH. The feed contains CO a(ld j-h only with a 1110131
ratio CO/H2=1I2. Estimate the pressur官 reqllired to ob個in 10% CO c心nversIOn.
The free energy and heat of formation areas follows (cal/mol)
a'fd m ð.戶。298
CO -32810 -26420
CH30H 自 38690 -48080
Assuming the heat of reaction at 5個ndar廿日ta峙， MI\, is independent of temperature and the gases at th巴 reaction condition obey ideal gas law. (20%)
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506002
ih 所組別
科目
第 國立臺灣科技大學 103 學年度碩士班招生試題
化學工程系碩士班
化工熱力學與動力 學
三L 頁共
3
頁(總分為 100分)
PART II. 化工動力學 (50%)
1. (20%)
The adiabatic exothermic irreversible gas-phase reaction 2A+B • 2C
is to be carried out in a f10w reactor for an equimolar feed of A and B. The following data for this reaction are shown below, where F AO/( -rA) is the ratio of molar f10w rate of reactant A in the feed and the rate of consumption of reactant A per unit volume at conversion X.
Conversion 。 。 l 0.3 0.5 0.6 。 7 0.8
X
F AO/(-rA) 50 42 26 10 70/3 110/3 50
(m3)
(a) What PFR (Plug Flow Reactor) volume is necessary to achieve 50% conv巴rsion? (5%) (b) What CSTR (Continuous Stirred Tank Reactor) volume is necessary to achieve 50%
conversion? (5%)
(c) What conversion can be achieved ifan 8m3 CSTR is followed in a s巴ries by an 8 m3 PFR?
(10%)
Hint: Useful formula for this problem
(l)T1心
where fj is th巴 function value at 莉，如dh=(划划)/4
- b:t.Jb' - 4ac (2) For ax2 + bx + C = 0, the root5, p and q, are - v ~
v: .Uv
2。
Show All Your Work.
2. (15%)
Pharmacokinet叫(縈物動力學)concern5 the ingestion (攝取)， distribution, reaction, and elimination (移除) reaction of drug5 in the body. Consider the application of
pharmacokinetics to one of the 111吋 orproble111s in Taiwan, drinking and driving (酒E半開 車). Here, we shall 1110del how long one must wait to drive after having a tall ma圳1i (一 高杯的馬丁尼酒). In Taiwan, the legal intoxication limit (法定酒醉限值) is 0.3 g of ethanol (酒精) per liter ofbody f1uid. (In the United States, it is 0.8 g/L, in Sweden it is 0.2 g/L, and in Eastern Europe and Russia it is any value above 0.0 g/L.) Th巴Il1gestlOn of ethanol into the bloodstream(血液)and subsequent elimination can be modeled as a series reaction. The rate of absorption from the gastrointestinal tract (腹部的腸道) into
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國立臺灣科技大學 103 學年度碩士班招生試題 毒、所 f且另1)
料自
化學工程系碩士班 化工熱力學與動力學 (總分為100分)
10 If'. The rate at which ethanol is broken down in the bloodstream is limited by regeneration of a coenzyme. Consequently, the process may be modeled as a zero-order reaction with a specific reaction rate of 0.192 g/h' L of body fluid
(a) How 10ng wou1d a person have 切 waitto drive in Taiwan if they drank two tall martinis immediately after arriving at a party? (10%)
(b) Suppose that one went to a party, had one and a half tall martinis right away, and then
閃閃ived a phone call saying an emergency had come up and the person needed to drive home immediately. How many minutes would the individual h恥eto reach home before he/she became legally intoxicated (超出法定酒醉限值)，assuming that the person had nothing furth巴rto dri叫(?(5%)
(Hint: Base all ethanol conce祖trationson the volume of body fluid. Calculate and plot the concentration ofethanol in the blood as a function oftime.)
Additional infol'malion Etllanol in a tallma'iini: 40 g
Volum巴 ofbody flu泊: 40L Show All Your Work.
3 . (15%)
For the elementary reversible solid-catalyzed liquid-phase reaction
A 口 B
(a) Make a plot ofequilibrium conversion as a function oftemp巴rature. (5%)
Hint 1: Prepare a table of equilibrium constant Kc and equilibr心mconversion Xc as a function oftemperature at 298, 350, 400, 425, 450, 475, al1d 500 K first, and then make a plot ofXc vs. T in (a).
Hint 2: Kc(T) = Kc(T,) exp[é\HoRx/R (lIT, - 1汀))
(b) Determine the adiabatic equilibrium temperature and conversion when pure A is fed to the reactor at a temperature of300 K. (10%)
Addilional infol'mation:
HA 0 (298 K) = -40,000 cal/mol, HB 0 (298 K) = -60,000 cal/mol, CPA = 50 cal/mol.K, CPB = 50 cal/mol.K, Kc = 100,000 at 298 K, and R (gas constant) = 1.987 cal/mol.K.
Show All Your Work
“J.
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