# [PDF] Top 20 2018IMAS First Round Junior Division Problems

Has 2488 "2018IMAS First Round Junior Division Problems" found on our website. Below are the top 20 most common "2018IMAS First Round Junior Division Problems".

### 2018IMAS First Round Junior Division Problems

... When your teacher gives the signal, begin working on the **problems**. I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti ic cs s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s ... See full document

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### 2016IMAS First Round Junior Division Problems

... Record your answers on the reverse side of the Answer Sheet (not on the question paper) by FULLY filling in the circles which correspond to your choices.. Your Answer Sheet will be read[r] ... See full document

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### 2017IMAS First Round Junior Division Problems

... When your teacher gives the signal, begin working on the **problems**. I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti i cs c s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s ... See full document

9

### 2014IMAS First Round Junior Division Problems

... Record your answers on the reverse side of the Answer Sheet (not on the question paper) by FULLY filling in the circles which correspond to your choices.. Your Answer Sheet will be read[r] ... See full document

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### 2015IMAS First Round Junior Division Problems

... （A）20 （B）31 （C）42 （D）53 （E）64 19. In an election between four candidates, they are supported respectively by 11, 12, 13 and 14 of the **first** 50 voters. Six more votes are to be cast, each for one of the four ... See full document

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### 2018IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. **Round** 2 of **IMAS** is composed of three parts; the total score is 100 ... See full document

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### 2018IMAS First Round Junior Division Full Solutions

... If 2 and 8 are both to the right of 4, the sequence partially looks like 4ab2c8, where 1 must be a. If 4 is the **first** from the left, then the sequence looks like 41b2c8de, 3 and 6 must be at b, d, two choices for ... See full document

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### 2018IMAS First Round Middle Primary Division Problems

... 22. How many ways can we divide 6 students into 3 groups so that each group has exactly 2 students? 23. In the figure below, ABCD, EFGH and AJKL are squares. The area of AJKL is **2018** cm 2 . If rectangles EFCI and ... See full document

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### 2018IMAS First Round Upper Primary Division Problems

... Questions 21-25, 6 marks each 21. Mike constructs a sequence in the following way: the **first** two terms are 1 and 2. Starting from the third term, each term is the smallest possible integer that is not relatively ... See full document

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### 2017IMAS Second Round Junior Division Problems

... z Do not open the contest booklet until you are told to do so. z Be sure that your name and code are written on the space provided above. z **Round** 2 of **IMAS** is composed of three parts; the total score is 100 ... See full document

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### 2014IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. **Round** 2 of **IMAS** is composed of three parts; the total score is 100 ... See full document

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### 2015IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. **Round** 2 of **IMAS** is composed of three parts; the total score is 100 ... See full document

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### 2016IMAS Second Round Junior Division Problems

... z Do not open the contest booklet until you are told to do so. z Be sure that your name and code are written on the space provided above. z **Round** 2 of **IMAS** is composed of three parts; the total score is 100 ... See full document

9

### 2016IMAS First Round Junior Division Full Solutions

... 3 2 5 2 2016 − 2016 = 2016 (2016 × − = 1) 2015 2016 2017 × × = × × × × × × 2 3 5 7 13 31 2017 , so the prime factors of the positive integer which satisfy the conditions should be 11, 17, 19, …, 29, 37, …, 2011, 2027, …. ... See full document

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### 2017IMAS First Round Junior Division Full Solutions

... （A）12 （B）18 （C）24 （D）30 （E）36 【Solution 1】 From the given information, one student will participate in two events and each of other two students participate on exactly one event. Let the student (the one will participate ... See full document

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### 2014IMAS First Round Junior Division Full Solutions

... the **first** row, it follows that the difference of the sum of three numbers in the second row and the sum of three numbers in the **first** row equal the sum of three numbers in the **first** row, that is; the ... See full document

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### 2015IMAS First Round Junior Division Full Solutions

... Subtracting this from the total surface area of the individual cubes, we have 14 6 42 42 . Answer： （C） 19. In an election between four candidates, they are supported respectively by 11, 12, 13 and 14 of the ... See full document

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### 2016IMAS First Round Upper Primary Division Problems

... Record your answers on the reverse side of the Answer Sheet (not on the question paper) by FULLY filling in the circles which correspond to your choices.. Your Answer Sheet will be read[r] ... See full document

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### 2017IMAS First Round Middle Primary Division Problems

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### 2017IMAS First Round Upper Primary Division Problems

... 14. There are two routes starting in a bus stop. A bus departs for the **first** route every 8 minutes and departs the second route every 10 minutes. At 6:00 in the morning, two buses depart for the two routes at the ... See full document

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