• 沒有找到結果。

# [PDF] Top 20 2015IMAS First Round Junior Division Problems

Has 2035 "2015IMAS First Round Junior Division Problems" found on our website. Below are the top 20 most common "2015IMAS First Round Junior Division Problems".

### 2015IMAS First Round Junior Division Problems

... （A）20 （B）31 （C）42 （D）53 （E）64 19. In an election between four candidates, they are supported respectively by 11, 12, 13 and 14 of the first 50 voters. Six more votes are to be cast, each for one of the four ... See full document

9

### 2016IMAS First Round Junior Division Problems

... 8. The chart below shows the sale figures of a certain merchandise in 2014 and 2015 by the season. How many more items were sold in 2015 than in 2014? （A）23 （B）48 （C）85 （D）90 （E）110 9. ABC is an equilateral ... See full document

9

### 2018IMAS First Round Junior Division Problems

... When your teacher gives the signal, begin working on the problems. I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti ic cs s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s ... See full document

9

### 2017IMAS First Round Junior Division Problems

... When your teacher gives the signal, begin working on the problems. I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti i cs c s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s ... See full document

9

9

### 2015IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

7

### 2015IMAS First Round Junior Division Full Solutions

... Subtracting this from the total surface area of the individual cubes, we have 14 6 42    42 . Answer： （C） 19. In an election between four candidates, they are supported respectively by 11, 12, 13 and 14 of the ... See full document

8

### 2015IMAS First Round Middle Primary Division Problems

... 23. There are two classrooms on each of four floors in the school building, x01 and x02 where x is the floor number. Martial Arts and Drama are on the first floor. Calligraphy and Fine Arts are on the same floor. ... See full document

9

### 2015IMAS First Round Upper Primary Division Problems

... 6. From one-third of a positive integer, one-quarter of the next integer is subtracted. If the difference is 2, what is the sum of the two integers? （A）31 （B）45 （C）55 （D）79 （E）103 7. The diagram below is the seating plan ... See full document

9

### 2018IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

9

### 2017IMAS Second Round Junior Division Problems

... z Do not open the contest booklet until you are told to do so. z Be sure that your name and code are written on the space provided above. z Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

9

### 2014IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

9

### 2016IMAS Second Round Junior Division Problems

... z Do not open the contest booklet until you are told to do so. z Be sure that your name and code are written on the space provided above. z Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

9

### 2016IMAS First Round Junior Division Full Solutions

... 1) 2015 2016 2017 × × = × × × × × × 2 3 5 7 13 31 2017 , so the prime factors of the positive integer which satisfy the conditions should be 11, 17, 19, …, 29, 37, …, 2011, 2027, ...the first three forms ... See full document

11

### 2018IMAS First Round Junior Division Full Solutions

... If 2 and 8 are both to the right of 4, the sequence partially looks like 4ab2c8, where 1 must be a. If 4 is the first from the left, then the sequence looks like 41b2c8de, 3 and 6 must be at b, d, two choices for ... See full document

11

### 2017IMAS First Round Junior Division Full Solutions

... （A）12 （B）18 （C）24 （D）30 （E）36 【Solution 1】 From the given information, one student will participate in two events and each of other two students participate on exactly one event. Let the student (the one will participate ... See full document

10

### 2014IMAS First Round Junior Division Full Solutions

... the first row, it follows that the difference of the sum of three numbers in the second row and the sum of three numbers in the first row equal the sum of three numbers in the first row, that is; the ... See full document

11

### 2015IMAS Second Round Junior Division Full Solutions

... If the addition and the subtraction are performed consecutively, they will cancel out. The same applies to the multiplication and the division. To obtain a value other than 10, we must alternate the first ... See full document

7