Top PDF 2014IMAS Second Round Junior Division Problems
2014IMAS Second Round Junior Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
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2018IMAS Second Round Junior Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多
2017IMAS Second Round Junior Division Problems
z Do not open the contest booklet until you are told to do so.
z Be sure that your name and code are written on the space provided above.
z Round 2 of IMAS is composed of three parts; the total score is 100 marks.
z Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多
2015IMAS Second Round Junior Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
7 閱讀更多
2016IMAS Second Round Junior Division Problems
z Do not open the contest booklet until you are told to do so.
z Be sure that your name and code are written on the space provided above.
z Round 2 of IMAS is composed of three parts; the total score is 100 marks.
z Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多
2014IMAS First Round Junior Division Problems
Record your answers on the reverse side of the Answer Sheet (not on the question paper) by FULLY filling in the circles which correspond to your choices.. Your Answer Sheet will be read[r]
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2014IMAS Second Round Junior Division Full Solutions
We know the prime factor of each n 193 , 194, 197, 199, 201, 202 and 203 is greater than 20 and they are 193, 97, 197, 199, 67, 101 and 29; respectively, which cannot be the product of the second group.
When n 195 , one of the prime factors of n is 13, the second group must contain the number 13, so the sum of all numbers after removing from the second group will be
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2014IMAS Second Round Middle Primary Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多
2014IMAS Second Round Upper Primary Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多
2016IMAS First Round Junior Division Problems
8. The chart below shows the sale figures of a certain merchandise in 2014 and 2015 by the season. How many more items were sold in 2015 than in 2014?
（A）23 （B）48 （C）85 （D）90 （E）110
9. ABC is an equilateral triangle. D is a point inside such that BCD is a right isosceles triangle. The altitude BE of ABC intersects CD at F. What is the measure, in degrees, of ∠ CFE ?
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2018IMAS First Round Junior Division Problems
When your teacher gives the signal, begin working on the problems.
I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti ic cs s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s
2018 JUNIOR DIVISION FIRST ROUND PAPER Time allowed：75 minutes
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2017IMAS First Round Junior Division Problems
When your teacher gives the signal, begin working on the problems.
I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti i cs c s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s
2017 JUNIOR DIVISION FIRST ROUND PAPER Time allowed：75 minutes
9 閱讀更多
2015IMAS First Round Junior Division Problems
Record your answers on the reverse side of the Answer Sheet (not on the question paper) by FULLY filling in the circles which correspond to your choices.. Your Answer Sheet will be read[r]
9 閱讀更多
2018IMAS Second Round Junior Division Full Solutions
【Solution】
If all pieces were placed into black squares, there are two ways to put the pieces on the first and the third row, two ways to put the pieces on the second and the fourth row, totally there are 4 ways. Similarly, there are 4 ways to place all pieces into white squares. Hence there are 8 ways in total.
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2017IMAS Second Round Junior Division Full Solutions
To form a centrally symmetric picture by adding some white squares but no black squares, what is the least number of white squares needed.. 【Solution】.[r]
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2015IMAS Second Round Junior Division Full Solutions
If the addition and the subtraction are performed consecutively, they will cancel out. The same applies to the multiplication and the division. To obtain a value other than 10, we must alternate the first pair with the second. Thus we only have to examine eight cases:
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2016IMAS Second Round Junior Division Full Solutions
We first find all the possible number of ways of forming the 4-digits numbers that satisfies that condition of the problem , and then subtracting the cases where 0 is in the thousands [r]
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2014IMAS First Round Junior Division Full Solutions
From the given information, it shows the sum of the three numbers in the second row is equal to twice the sum of the three numbers in the first row, it follows that the difference of the sum of three numbers in the second row and the sum of three numbers in the first row equal the sum of three numbers in the first row, that is; the difference of these two rows is 19 + 20－5－6 = 28, then we have ☆ = 28－5－6 = 17. Thus, we select option (D).
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2018IMAS Second Round Middle Primary Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多
2018IMAS Second Round Upper Primary Division Problems
Do not open the contest booklet until you are told to do so.
Be sure that your name and code are written on the space provided above.
Round 2 of IMAS is composed of three parts; the total score is 100 marks.
Questions 1 to 5 are given as a multiple-choice test. Each question has five possible options marked as A, B, C, D and E. Only one of these options is correct.
9 閱讀更多