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# [PDF] Top 20 2014IMAS Second Round Junior Division Problems

Has 1776 "2014IMAS Second Round Junior Division Problems" found on our website. Below are the top 20 most common "2014IMAS Second Round Junior Division Problems".

### 2014IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2018IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2017IMAS Second Round Junior Division Problems

... z Do not open the contest booklet until you are told to do so. z Be sure that your name and code are written on the space provided above. z Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2015IMAS Second Round Junior Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2016IMAS Second Round Junior Division Problems

... z Do not open the contest booklet until you are told to do so. z Be sure that your name and code are written on the space provided above. z Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2014IMAS Second Round Junior Division Full Solutions

... We know the prime factor of each n  193 , 194, 197, 199, 201, 202 and 203 is greater than 20 and they are 193, 97, 197, 199, 67, 101 and 29; respectively, which cannot be the product of the second group. When n  ... See full document

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### 2014IMAS Second Round Middle Primary Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2014IMAS Second Round Upper Primary Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2016IMAS First Round Junior Division Problems

... 8. The chart below shows the sale figures of a certain merchandise in 2014 and 2015 by the season. How many more items were sold in 2015 than in 2014? （A）23 （B）48 （C）85 （D）90 （E）110 9. ABC is an equilateral ... See full document

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### 2018IMAS First Round Junior Division Problems

... When your teacher gives the signal, begin working on the problems. I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti ic cs s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s ... See full document

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### 2017IMAS First Round Junior Division Problems

... When your teacher gives the signal, begin working on the problems. I I nt n te er rn na at t io i on n al a l M Ma at t he h em ma at ti i cs c s A A ss s se es ss sm me en n ts t s f fo or r S Sc ch ho oo ol ls s ... See full document

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### 2018IMAS Second Round Junior Division Full Solutions

... 【Solution】 If all pieces were placed into black squares, there are two ways to put the pieces on the first and the third row, two ways to put the pieces on the second and the fourth row, totally there are 4 ways. ... See full document

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### 2017IMAS Second Round Junior Division Full Solutions

... To form a centrally symmetric picture by adding some white squares but no black squares, what is the least number of white squares needed.. 【Solution】.[r] ... See full document

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### 2015IMAS Second Round Junior Division Full Solutions

... If the addition and the subtraction are performed consecutively, they will cancel out. The same applies to the multiplication and the division. To obtain a value other than 10, we must alternate the first pair ... See full document

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### 2016IMAS Second Round Junior Division Full Solutions

... We first find all the possible number of ways of forming the 4-digits numbers that satisfies that condition of the problem , and then subtracting the cases where 0 is in the thousands [r] ... See full document

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### 2014IMAS First Round Junior Division Full Solutions

... the second row is equal to twice the sum of the three numbers in the first row, it follows that the difference of the sum of three numbers in the second row and the sum of three numbers in the first row ... See full document

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### 2018IMAS Second Round Middle Primary Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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### 2018IMAS Second Round Upper Primary Division Problems

... Do not open the contest booklet until you are told to do so. Be sure that your name and code are written on the space provided above. Round 2 of IMAS is composed of three parts; the total score is 100 ... See full document

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