請根據題目要求，答題時請詳細寫下解題過程。
(※答題請勿夾雜英文及中文，此部分題組試題請統一以同一語言作答，可選擇全部使用中 文或英文回答)
Follow the questions to construct your answers in reasoning mathematical expressions.
Read the Sources given below and answer all questions in the language of instruction in English/
Chinese.
(※Please only use one language to answer the questions, only in English/ Chinese. Do not mix up languages.)
例:
瑪莉決定在屋頂上鋪設太陽能板，並且使太陽能板能夠貼合兩邊的屋頂。每一塊太陽能板的 1. 根據資料 A，英國政府依據 1935 年 3 月在柏林的會議得出什麼樣的結論？
What was the conclusion the British government had drown regarding the March 1935 meeting in Berlin according to Source A ?
2. 根據資料 B，此諷刺性漫畫建議 1935 年英國和德國兩國維持什麼樣的關係最為適當？
What is the suggestion given by the sarcastic comic in Source B regarding the Anglo-German relations in 1935?
3. 假設你是一位研究國際關係的歷史學家，請依據資料 A 的來源及撰寫目的等內容，判斷 與分析其價值與限制性。(請引用資料 A 的內容做為論述證據，可列點說明)
Assume that you are a historian who studies international relations. Please evaluate the origin, purpose and content of Source A and determine its value and limitations in response to German aggression..
4. 請依據資料 A 和資料 B 的內容，對照與比較在希特勒統治期間，德國的對外政策及態度 為何？
Please determine the attitudes towards German foreign policy under Hitler in accordance with the comparison between Source A and B.
Mary decides to put solar panels on the roof. The solar panels are fitted to both sides of the roof.
Each panel is 1.9 m long and 0.8 m wide. All the panels must be arranged in uniform rows, with the shorter edge of each panel parallel to AB or AC. The length AB is approximately 2.8m. The length AC is approximately 2.6m. The length BD is approximately 12m. Each panel must be at least 0.4 m from the edge of the roof and the top of the roof, AF. (Diagram not to scale)
(1) 請問在全部的屋頂上最多能鋪設幾片完整的太陽能板? [3 分]
Find the maximum number of complete panels that can be fitted to the whole roof.
參考答案與給分標準：
12−2(0.4)
1.9
2.8−2(0.4)
0.8 OR 2.6−2(0.4)
0.8
20
Note: Award (M1) for correct calculation of the number of panels on the long side.正確計算長邊太陽能板數量時給予 M1 (M1: 方法/列式正確 1 分)
Note: Award point for correct calculation of the number of panels on either short side with no further incorrect working.
正確計算另一邊的太陽能板數量並且沒有其他錯誤時給予 M1 (M1: 方法/列式正確 1
分)
Note: Follow through from previous results in the question. (A1).
根據前面的計算得出答案，給予 A1 (A1:正確答案 1 分)。
B Solar panels
A
C F
B 太陽能板
A
C F
D D
(2) 瑪莉估計出太陽能板覆蓋的面積約為 20 平方公尺，請找出該估計值之誤差百分比為 何?(四捨五入取到小數點後一位) [3 分]
Mary estimates that the solar panels will cover an area of 20 𝑚2. Find the percentage error in her estimate. [Giving an answer to 1 decimal place.]
參考答案與給分標準：
20 ×1.9× 0.8(= 30.4)
20 30.4 100%
30.4
−
4.6(%) (4.60526 (%))
Note: Award (M1) for their 20 1.9 0.8 or 30.4 seen. Follow through from their 20 in part (1).
Award (M0) if their 20 is not an integer.
根據前一小題的答案寫出算式 20 1.9 0.8 或直接寫出 30.4 給予 M1 (M1: 方法正確 1 分)，但是若前一小題的答案不是寫整數時給予 M0(M0:方法正確但給 0 分)
Note: Award (M1) for correct substitution of their 30.4 into the percentage error formula.
Their 30.4 must be exact.
Accept a method in two steps where “ 100 ” is implicit from their answer. The second (M1) is contingent on the first (M1) being awarded, eg do not award (M0)(M1)(A0).
正確將第一部分得到的答案代入誤差公式時給予 M1
(
M1:
方法正確 1 分)
，他們的「30.4」必須是前一部分真正得出的值。可接受將百分比分兩階段寫出，其中(×100)隱 含在答案中。
第二部分的方法使用得分 M1
(
M1:
方法正確 1 分)
取決於第一部份的方法使用得分 M1(
M1:
方法正確 1 分)
，亦即第一部分方法使用不正確則後續不給分。Note: Follow through from their answer to part (1). Percentage sign is not required.
根據前述計算得出的答案而得給予A1(A1:正確答案 1 分)，%的符號不要求。
(3) 瑪莉在研究太陽能板排列方法時，將長邊與𝐴𝐵或𝐴𝐶平行。[2 分]
請說明新的太陽能板排列方式是否可在屋頂上鋪設更多的太陽能板呢?並驗證你的答案。
Mary investigates arranging the panels, such that the longer edge of each panel is parallel to AB or AC.
State whether this new arrangement will allow Mary to fit more solar panels to the roof.
Justify your answer.
參考答案與給分標準：
1×14(一側屋頂) OR 28 (全部)
No(不能)New arrangement will mean fewer solar panels.
(新的排列方式會得出較少的太陽能板)
Note: Follow through from their maximum number of panels in question 1. Do not award( R0)(A1) 經由與第一小題得出的最大數量比較而得給予 A1(A1:答案正確 1 分)。前一部分推理不正 確不給分 R0 (R0:錯誤推理 0 分)。
Note: Award (R1) for one correct array seen (114 ) or total number of panels (28 ). Working is not required, but award (R0) for incorrect working seen. Correct working is as follows.
(
12−0.80.8
,
2.6−0.81.9
,
2.8−0.81.9
)
Reasoning may compare both sides of the roof or just one side; accept correct comparisons with question1 values. Follow through from their treatment of tolerances in question1.
Award (R0) for any approach with no clearance or for any method which includes further incorrect working.
寫出一側屋頂的數量 14 或全部數量 28 給予(R1)(R1:正確推理 1 分)，不要求過程，
但是有錯誤的推理過程時給予 R0(R0:錯誤推理 0 分)。正確的計算過程為
(
12−0.80.8
,
2.6−0.81.9
,
2.8−0.81.9
)
推理時可以只比較一側屋頂或全部屋頂，以第一小題的答案進行比較也是可接受的。
不清楚的論述方式或任何包含錯誤過程的方法給予 R0(R0:錯誤推理 0 分)
(4) 為了產生足夠的電能，太陽能板上需有許多光電池。光電池能將太陽光轉換成直流電。太陽 光輻射到地球表面的平均強度為 245 (瓦特/公尺2)。在太陽能板上的光電池，以 25%轉換 效率，將太陽光的能量轉換成電能。
問：請預估每片太陽能板所提供的電功率[4 分]
Many photovoltaic cells are needed in solar panels to produce appreciable amounts of electrical power. A photovoltaic cell converts sunlight directly into direct current (DC). The average intensity of solar radiation incident on the Earth surface is 245 W/𝑚2. In an array of photovoltaic cells, solar energy is converted into electrical energy with an efficiency of 25%.
Estimate the electrical power provided of photovoltaic cells on each solar panel.
參考答案：
93.1 W
Note: Identify the power incident on a solar panel is 245×1.6×0.95 W (1)
The electrical power P=0.25×245×1.9×0.8=93.1 W (1)
說明太陽能板接收到的太陽光功率為 245×1.9×0.8 瓦特 (1)
計算電功率 P=0.25×245×1.9×0.8=93.1 瓦特 (1)
【附錄二】
基北區臺北市立西松高級中學 110 學年度高級中等學校特色招生考試分發入學