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4.2 Topologically crossing homoclinicity

4.2.2 Results

In this subsection, we state our results about the positive topological entropy derived from the topologically crossing homoclinicity. First, we see the result about perturbations of a map.

Theorem 4.14. Let Fλ be a one-parameter family of continuous maps on Rm such that Fλ(x) is continuous as a function jointly of λ ∈ R` and x ∈ Rm, where λ is a parameter. Assume that F0(x) = f (x) for all x ∈ Rm, where f : Rm → Rm is a C1 diffeomorphism with a hyperbolic periodic point which has a topologically crossing homoclinic point. Then there exist an integer

N > 0 and a number λ0 > 0 such that both f and Fλ with |λ| < λ0 have topological entropies at least log(2)/N .

Next, if the singular map F0 depends only on the phase variable of f, we have the following result.

Theorem 4.15. Let Fλ be a one-parameter family of continuous maps on Rm × Rk such that Fλ(x, y) is continuous as a function jointly of λ ∈ R`, x ∈ Rm and y ∈ Rk, where λ is a parameter. Assume that F0(x, y) = (f (x), g(x)) ∈ Rm× Rk for all x ∈ Rm and y ∈ Rk, where f : Rm → Rm is a C1 diffeomorphism with a hyperbolic periodic point which has a topologically crossing homoclinic point, and g : Rm → Rk is a continuous function. Then there exist an integer N > 0 and a number λ0 > 0 such that both f and Fλ with |λ| < λ0 have topological entropies at least log(2)/N .

For the case when the singular map is a skew product map locally trapping along the second variable, we have the following.

Theorem 4.16. Let Fλ be a one-parameter family of continuous maps on Rm × Rk such that Fλ(x, y) is continuous as a function jointly of λ ∈ R`, x ∈ Rm and y ∈ Rk, where λ is a parameter. Assume that F0(x, y) = (f (x), g(x, y)) ∈ Rm× Rk for all x ∈ Rm and y ∈ Rk, where f : Rm → Rm is a C1 diffeomorphism with a hyperbolic periodic point which has a topologically crossing homoclinic point, and g : Rm× Rk → Rk is continuous on Rm× S and g(Rm × S) ⊂ int(S) for some compact set S ⊂ Rk homeomorphic to the closed unit ball in Rk. Then there exist an integer N > 0 and a number λ0 > 0 such that both f and Fλ with |λ| < λ0 have topological entropies at least log(2)/N .

Denote by p the hyperbolic periodic point of f . Without loss of gen-erality, we may assume that p is a fixed point. Set u = dim Wu(p) and s = dim Ws(p). Since ˆWu(p) and ˆWs(p) have a topologically crossing inter-section, we have u + s = m. Let us fix a basis of Rm such that the Jacobian

matrix Dfp of f at p preserves the splitting Rm = Ru⊕ Rs. By the Hartman-Grobman Theorem, there exist a closed neighborhood U of p and a homeo-morphism ϕ of U into Rm such that ϕ(p) = (0, 0) and ϕ(f (z)) = Dfp(ϕ(z)) for z ∈ U . In order to simply our notation, we assume p = (0, 0) and ϕ = id, the identity map on Rm. Thus f is a linear map on U . Write f (x, y) = (Lux, Lsy) for (x, y) ∈ U, where Lu is a u × u matrix with all eigenvalues greater than one in absolute value and Ls is an s × s matrix with all eigenvalues less than one in absolute value. There exist norms | · |u and

| · |s on Ru and Rs, respectively, and constants ρ1 > 1 and 0 < ρ2 < 1 such that

|Lux|u > ρ1|x|u and |Lsy|s 6 ρ2|y|s for x ∈ Ru and y ∈ Rs. (4.17) Since all norms on Rm are equivalent, we may assume U = Bu × Bs and define the norm | · | on Rm to be the maximum norm of the norms | · |u and

| · |s on Ru and Rs. Notice that later we still need local coordinates while verifying h-sets in U as required in Definition 3.1. In order to prove the main results we need some lemmas. First, we recall the following lemma in [5]; for readers’ convenience, we repeat their proof below.

Lemma 4.17. [5, Lemma 1.4] Let V be a compact subset of Wu(p) ∩ int(U ).

Suppose we are given positive constants ρ and ε satisfying 0 < ρ < 1 and 0 < ε < d(V, ∂U ). Then for any large enough n ∈ N the following hold:

1. f−n(V ) ⊂ Bu(0, ρ) × {0}; and

2. if (x, 0) ∈ f−n(V ) then fn({x} × Bs) is in U and has diameter less than ε, where the diameter of a bounded set E ⊂ Rm is defined to be sup{|x − y| : x, y ∈ E}.

Proof. Since V ⊂ Wu(p), there exists a positive integer n1such that f−n1(V ) ⊂ Bu× {0}. Since f is a C1 diffeomorphism , we can take a constant K such

that K > sup{kDfzn1k : z ∈ U } and ε/(2K) < 1. Let n2 be an arbitrary positive integer such that

n2 > max{log(ρ−1)/ log(ρ1), log(ε/(2K))/ log(ρ2)}. (4.18) Since f is linear and preserves the splitting Ru× Rs on U , Equations (4.17) and (4.18) imply f−n1−n2(V ) ⊂ f−n2(Bu × {0}) ⊂ Bu(0, ρ) × {0}. This concludes item 1 of the desired result by considering n = n1+ n2. For item 2, let (x, 0) ∈ f−n1−n2(V ) and y ∈ Bs. Again Equations (4.17) and (4.18) imply fn2(x, y) = (Lnu2(x), Lns2(y)) ∈ {Lnu2(x)} × Bs(0, ε/(2K)) ⊂ U . Take any two points in {x} × Bs, say w = (x, y1) and v = (x, y2). Then fn2(w), fn2(v) ∈ U and |fn2(w) − fn2(v)| = |Lns2(y1) − Lns2(y2)| 6 ε/K. By the choice of K, we get that |fn1+n2(w) − fn1+n2(v)| < K|fn2(w) − fn2(v)| 6 ε. By considering n = n1+ n2, we have the desired result.

Since the submanifolds ˆWu(p) and ˆWs(p) have a topological crossing in-tersection, there exist a point q 6= p and two compact embedded submanifolds Vu of ˆWu(p) and Vs of ˆWs(p) such that Vu and Vs form a good pair, and q ∈ Vu∩ Vs. We may assume that both sets Vu and Vs are in int(U ), and Vu has no intersection with the subspace Ru× {0}, based on the following lemma.

Lemma 4.18. For any sufficiently integer n ∈ N, there exist submanifolds Vnu of ˆWu(p) and Vnu of ˆWs(p) such that Vnu and Vns form a good pair with the same oriented intersection number as good pair Vu and Vs, Vnu ⊂ fn(Vu), Vns ⊂ fn(Vs), and Vnu∪ Vns ⊂ int(U ).

Proof. First, we show that fn(Vu) and fn(Vs) form a good pair for n ∈ N.

Since f is a C1 diffeomorphism, fn(Vu) and fn(Vs) are compact embedded C1 submanifolds of ˆWu(p) and ˆWs(p), respectively. Since Vu ⊂ ˆWu(p), Vs ⊂ ˆWs(p), and ∂Vu∩Vs= Vu∩∂Vs = ∅, we also have ∂fn(Vu)∩fn(Vs) = fn(Vu) ∩ ∂fn(Vs) = ∅.

Let δ be a constant such that

0 < δ < min{d(∂fn(Vu), fn(Vs)), d(fn(Vu), ∂fn(Vs))}.

Since fnis continuous on the compact set Vu∪Vs, there exists a constant ε such that 0 < ε < min{d(∂Vu, Vs), d(Vu, ∂Vs)} and if x, y ∈ Vu ∪ Vs with |x − y| < ε then |fn(x) − fn(y)| < δ. Since Vu and Vs form a good pair, for such an ε, there exists a homotopy h0 satisfying item (2a)-(2d) of Definition 4.12. Define a homotopy hn = fn◦ h0 ◦ f−n. It is obviously true that hn(0, ·) = id and hn(1, ·) is an embedding. By item (2b) of Definition 4.12, for z ∈ fn(Vu) ∪ fn(Vs) and t ∈ [0, 1], we have

|hn(t, z) − z| = |fn(h0(t, f−n(z))) − fn(f−n(z))| < δ.

Moreover, hn(1, fn(Vu)) and fn(Vs) are transverse submanifolds and the oriented intersection number I(hn(1, fn(Vu)), fn(Vs)) = I(h0(1, Vu), Vs) is nonzero. Thus, fn(Vu) ⊂ ˆWu(p) and fn(Vs) ⊂ ˆWs(p) form a good pair.

If fn(Vu) ∪ fn(Vs) ⊂ int(U ), then we are done by taking Vnu = fn(Vu) and Vns = fn(Vs). Otherwise, since p is a hyperbolic fixed point with topologically crossing homoclinic point(s) in Vu ∩ Vs which has nonzero oriented intersection number, by letting n large enough, there exists q ∈ Vu ∩ Vs such that if we denote by Vnu and Vns the connected components of fn(Vu) ∩ (Bu(0, 4/5)) × (Bs(0, 4/5)) and fn(Vs) ∩ (Bu(0, 4/5)) × (Bs(0, 4/5)) containing the point fn(q), respectively, ∂Vnu ∩ Vns = Vnu ∩ ∂Vns = ∅ and I(hn(1, Vnu), Vns) = I(hn(1, fn(Vu)); fn(Vs)). Repeating the above argument, we have that Vnu ⊂ ˆWu(p) and Vns⊂ ˆWs(p) form a good pair with the same oriented intersection number as the good pair Vu and Vs. We have finished the proof of the desired result.

Set V2 = Vu. Since πu(q) = 0, there is a constant η such that 0 < η < 1 and Bu(0, η) ⊂ πu(V2)\πu(∂V2). Denote V1 = Bu(0, η) × {0}.

We shall construct two disjoint h-sets. Let ρ be a constant such that 0 < ρ < η. Denote R = Bu(0, ρ) × Bs. Let ε > 0 be so small that the closed neighborhoods of V1 and V2 are disjoint and contain in int(U ) and that the closed ε-neighborhoods of ∂Vu and ∂Bu(0, η) × {0} are contained in int(U ) \ R. Then

ε < min{d(V1, ∂U ), d(V2, ∂U )}.

By applying Lemma 4.17 to V1 and V2, we can pick a common integer N such that f−N(V1) ∪ f−N(V2) ⊂ Bu(0, ρ) × {0} and if (x, 0) ∈ f−N(V1) ∪ f−N(V2) then fN({x} × Bs) is in U and has diameter less than ε. Write f−N(q) = (q0, 0). Since f is a diffeomorphism, f−N(V1) and f−N(V2) are disjoint. More-over, since f is C1, V2 is a C1 submanifold of ˆWu(p) and hence there exists a C1 diffeomorphism ζ from Ru to Ru such that ζ(πu(f−N(ψ(x)))) = x for all x ∈ Bu, where ψ is a C1 parametrization of V2 on Bu such that V2 = ψ(Bu) and ψ(0) = q (mentioned in Lemma 4.13). Since f (x, y) = (Lux, Lsy) for (x, y) ∈ U under the Hartman-Grobman linearization setting at the begin-ning of this subsection, we have f−N(V1) = L−Nu (Bu(0, η)) × {0}. Define M1 = πu(f−N(V1)) × Bs and M2 = πu(f−N(V2)) × Bs; or equivalently define M1 = L−Nu (Bu(0, η)) × Bs and M2 = πu(f−N(ψ(Bu))) × Bs. Then M1 and M2 are disjoint h-sets with u(M1) = u(M2) = u, s(M1) = s(M2) = s, and cM1(x, y) = (LNux/η, y) and cM2(x, y) = (ζ(x), y) for all (x, y) ∈ Ru× Rs.

Next, we show that there are covering relations among M1 and M2. Lemma 4.19. The following covering relations hold:

Mi f

N

=⇒ Mj for i, j ∈ {1, 2}.

Proof. Define a homotopy H on Rm from fN(x, y) to πu◦ fN(x, 0) by H(t, x, y) = (1 − t)fN(x, y) + t(πu(fN(x, 0)), 0),

for (x, y) ∈ Ru× Rs and t ∈ [0, 1]. For i, j ∈ {1, 2}, we set a homotopy hji induced from H by hji(t, x, y) = cMj(H(t, c−1M

i(x, y))) for (x, y) ∈ Ru× Rs and

t ∈ [0, 1], and define Aji(x) = πu(hji(1, x, 0)) for x ∈ Ru. Since hji(1, x, y) is independent of y and lies on the subspace Ru× {0}, we get that hji(1, x, y) = (Aji(x), 0) for x ∈ Ru. Moreover, by the choice of N , we have

H(t, Mi) ∩ Mj = ∅ and H(t, Mi) ∩ Mj+= ∅ for t ∈ [0, 1].

It follows that Condition 1 and 2 of Definition 3.2 are satisfied with h = hji and ϕ = Aji .

For Condition 3 of Definition 3.2, we first show that deg(Aji, Bu, 0) 6= 0 for i = 1 and j ∈ {1, 2}. By the definition of homeomorphisms cMi, we get that fN ◦ c−1M

1(U ) ⊂ U and fN ◦ c−1M

2(U ) ⊂ U . Hence on Bu, the map A11 is linear and the map A21 is C1, in fact, they are of the following forms: for x ∈ Bu,

A11(x) = πu(h11(1, x, 0)) = LNux, A21(x) = πu(h21(1, x, 0)) = ζ(ηx).

Since Lu is a u × u matrix with all eigenvalues greater than one in absolute value, by item 8 of the properties of local Brouwer degree listed in subsection 3.2, we get

deg(A11, Bu, 0) = sgn(det(LNu)) 6= 0.

The choice of N implies πu(f−N(V2)) ⊂ Bu(0, ρ) ⊂ Bu(0, η) and hence the equation ζ(x) = 0 has a unique solution, namely q0, and q0 ∈ Bu(0, η). Since πu(f−N(V2)) is a u-dimensional C1 submanifold, 0 is a regular value for ζ and sgn(det Dζq0) 6= 0. It follows from items 8 again and Proposition 3.6 that

deg(A21, Bu, 0) = sgn(det Dζq0) · 1 6= 0.

Next, we shall show that deg(Aji, Bu, 0) 6= 0 for i = 2 and j ∈ {1, 2}

as applications of Lemma 4.13. By the definitions of the homeomorphisms

cMiand the linearization of f on U , we get that for x ∈ Bu, A12(x) = ϕ ◦ πu◦ ψ(x),

A22(x) = ζ ◦ πu◦ ψ(x),

where ϕ is a map on Ru defined by ϕ(x) = LNux/η. By the choice of η, there exists a bounded connected component, namely ∆, of Ru\ πu(ψ(∂Bu) such that 0 = ϕ−1(0) ∈ ∆. Since ϕ is linear, Proposition 3.6 implies that

deg(A12, Bu, 0) = deg(ϕ ◦ πu◦ ψ, Bu, 0) = sgn(det(LNu/η)) deg(πu ◦ ψ, Bu, 0) Note that ψ is a parametrization of V2. Since V2 and Vs form a good pair with the oriented orientation number not zero, by Lemma 4.13, we have deg(πu◦ ψ, Bu, 0) 6= 0. Therefore, deg(A12, Bu, 0) 6= 0.

Similarly, by the choices of η and N , we get ζ−1(0) = q0 ∈ ∆. Since ζ is C1, Proposition 3.6 gives us that

deg(A22, Bu, 0) = deg(ζ ◦ πu◦ ψ, Bu, 0) = sgn(det Dζq0) deg(πu◦ ψ, Bu, 0).

It follows that deg(A22, Bu, 0) 6= 0.

We have finished the proof of the desired result.

Finally, we are in position to prove our theorems.

Proof of Theorem 4.14. By applying Lemma 4.19 and Proposition 3.5, there exists λ0 > 0 such that if |λ| < λ0 then

Mi F

N

=⇒ Mλ j for for i, j ∈ {1, 2}.

Let θ be a positive integer and |λ| < λ0. Consider any closed loop Mi0 F

N

=⇒ Mλ i1 F N

=⇒ · · ·λ F N

=⇒ Mλ iθ,

with each iα ∈ {1, 2} and iθ = i0. By using Theorem 3.3, FλN has a periodic point x = x(λ) ∈ int(Mi0) such that FλN θ(x) = x. Since there are 2θ choices

of such closed loops, FλN has at least 2θ periodic points in M1 ∪ M2. These periodic points provide a (θ, δ)-separated set for FλN as long as δ is a positive number less than the distance of M1 and M2. Since θ is arbitrarily chosen, we have htop(FλN) > log(2) and so htop(Fλ) > log(2)/N > 0.

Lemma 4.20. The following covering relations hold:

Mi0 F

N

=⇒ M0 j0 for i, j ∈ {1, 2}.

Proof. Let i, j ∈ {1, 2} be arbitrary. We define a homotopy ˆhji(t, x, y, z) = (hji(t, x, y),1 − t

r g ◦ fN −1(c−1M

i(x, y))), where hji is the homotopy for the covering relation Mi f

N Bk, Condition 1 and 2 of Definition 3.2 are satisfied follows from the anal-ogous properties for hji stated in the proof of Theorem 4.14. Finally, notice that

ˆhji(1, x, y, z) = (hji(1, x, y), 0).

Therefore, Condition 3 of Definition 3.2 is satisfied.

By applying Lemma 4.20 and Proposition 3.5, there exists λ0 > 0 such that if |λ| < λ0 then the following covering relations hold for FλN:

Mi0 F

N

=⇒ Mλ j0 for i, j ∈ {1, 2}. (4.19) As in the proof of Theorem 4.14, the covering relations listed in Equation (4.19) implies the htop(Fλ) > log(2)/N > 0 with |λ| < λ0.

Proof of Theorem 4.16. Define Gλ = (id, c)◦Fλ◦(id, c)−1, where c is a home-omorphism from S to Bk. Then the topological entropies of Gλ and Fλ are equal. By applying the above argument as in the proof of Theorem 4.15 to the family Gλ while the corresponding cM of a covering relation N =⇒ M isGλ the identity map, we have the desired result.

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