We shall see shortly that the Lie derivative corresponds to an-other simple binary operation on vector fields, the Lie bracket.
1We remark that if M is compact, the interval (ap, bp) can be extended to (−∞, ∞)and φt will be a diffeomorphism from M to itself. In general, a vector field is called complete if it has this property.
7. VECTOR FIELDS AND FROBENIUS THEOREM 31
Definition 1.34. Let X, Y be C∞ vector fields on U. The Lie bracket is defined by[X, Y] :=XY−YX. That is,
[X, Y]pf =Xp(Y(f))−Yp(X(f)).
It seems that[X, Y]is a second order operator on C∞(U). In fact, it is still of the first order:
Proposition 1.35. [X, Y]is a C∞ vector field on U. The Lie bracket has the following basic (Lie algebra) properties:
Proposition 1.36. Let X, Y be C∞ vector fields. Then (1) (Anti-symmetry)[X, Y] = −[Y, X]
(2) (Jacobi identity)[[X, Y], Z] + [[Y, Z], X] + [[Z, X], Y] = 0 Now we can prove the important formula:
Theorem 1.37 (Lie, 1870). (LVW)p = [V, W]p
PROOF. Let V generate φtand W generate ψs. Choose a test func-tion h∈ C∞p. By definition,
(LVW)ph We may extend these concepts to some higher dimensional cases.
Definition 1.38. A k dimensional distribution D on a manifold M is a choice of a k dimensional subspace D(p)of TpM for each p∈ M.
We say D is C∞ if for every p ∈ M, there is a neighborhood U such that D is spanned by k C∞vector fields X1, X2, . . . , Xkon U.
The question in higher dimensions becomes: for a given distribu-tion D near p, does there exists a k dimensional submanifold S with p ∈S such that TqS=D(q)for all q∈ S?
If so, S is called an integral manifold of D passing through p.
Clearly a necessary condition for this integrability is the following:
Definition 1.39. D is called involutive if [X, Y] ∈ D for all X, Y ∈ D.
Here a vector field X ∈ D meansXp ∈ D(p)for all p.
This turns out to be sufficient at least locally:
Theorem 1.40 (Frobenius Integrability, 1877). If D is involutive, then for all p ∈ M there exists a maximal integral manifold Sp ⊂ M passing through p such that TqSp=D(q)for all q ∈ Sp.
7. VECTOR FIELDS AND FROBENIUS THEOREM 33
As in the case of integral curves, Sp ⊂ M needs not be closed.
That is Spmay not be with the induced topology.
The proof is based on two lemmas. To state the first one, we need Definition 1.41. For a smooth map f : S → M and a smooth vector field X∈ C∞(TS), the tangent map d f = f∗sends X to
The next lemma characterizes coordinate vector fields:
Lemma 1.42. If X1, . . . , Xk are k vector fields near a point p ∈ M that
7. VECTOR FIELDS AND FROBENIUS THEOREM 33
As in the case of integral curves, Sp ⇢ M needs not be closed.
That is Spmay not be with the induced topology.
The proof is based on two lemmas. To state the first one, we need Definition 1.41. For a smooth map f : S ! M and a smooth vector field X 2 C•(TS), the tangent map d f = f⇤ sends X to
The next lemma characterizes coordinate vector fields:
Lemma 1.42. If X1, . . . , Xk are k vector fields near a point p 2 M that
Let c(t, s) = ψ−s ◦φ−t ◦ψs ◦φt(p). Since LVW = 0 implies φ−t∗W =W, directly differentiation shows that
∂
∂sc(t, s) = −Wψ−s◦φ−t◦ψs◦φt(p) +ψ−s∗◦φ−t∗(Wψs◦φt(p))
=−Wc(t,s)+Wc(t,s) =0
Similarly, ∂c(t, s)/∂t =0. So c(t, s) = p for all well-defined t, s.
Now, suppose Xigenerates φifor i =1, 2, . . . , k near p. We define c(t1, t2, . . . , tk) :=φ1t1◦φ2t2◦ · · · ◦φktk.
We check that its coordinate tangent vectors are precisely X1, . . . , Xk: c∗(∂/∂t1) = ∂
∂t1φ1t1 ◦ · · · ◦φtkk =X1
c(t1,...,tk). And since every φiti commutes with each other,
c∗(∂/∂ti) = ∂
∂ti φiti ◦φt11◦ · · ·cφiti· · · ◦φktk =Xic
(t1,...,tk).
Let S := {c(t1, . . . , tk) | tj ∈ Ij, ∀ j } where Ij is chosen to be small enough such that every φtjj is well-defined for tj ∈ Ij. We see that c∗ is injective and then c is an immersion into M. By Lemma 1.16, there exists a chart (U, x) near p such that xi(c(t1, . . . , tk)) = ti for i = 1, . . . , k and xi(c(t1, . . . , tk)) = 0 for i = k+1, . . . , m. Hence S∩U is a coordinate slice{xj =0| j =k+1, . . . , m}on M. PROOF OF FROBENIUS THEOREM. We fix an arbitrary point p ∈ M. Since D(p) ⊂ TpM is a k dimensional subspace, we can select a chart(U, x) at p with D(p) = R∂1|p, . . . , ∂k|p
and construct the projection π : U ⊂ M → Rk onto the first k coordinates. Then there exists a smaller neighborhood U0 3 p such that
D ∼=π∗D =R
∂
∂x1, . . . , ∂
∂xk
, ∀q ∈U0.
For each i = 1, . . . , k, let Xi ∈ D be the vector field lifted from
∂/∂xi, i.e. π∗(Xi) =∂/∂xi. Then they are π-related and 0=
∂
∂xi, ∂
∂xj
= [π∗(Xi), π∗(Xj)] = π∗[Xi, Xj]⇐⇒ [Xi, Xj] = 0.
8. EXISTENCE, UNIQUENESS AND SMOOTH DEPENDENCE OF ODE 35 8. EXISTENCE, UNIQUENESS AND SMOOTH DEPENDENCE OF ODE 35
TpM
The above lemma then implies that there exists an integral manifold S passing through p such that TqS=D(q)for all q2 S.
Since p2 M is arbitrary, the union of all integral manifolds is the whole manifold M. Also for any two integral manifolds S and S0, if S\S0 6= ∆ then S[S0is also an integral manifold. We conclude that there is a maximal integral manifold Sppassing through p. ⇤
8. Existence, uniqueness and smooth dependence of ODE Now we go back to the ODE system:
8<
:
X0(t) = F(X(t)), F 2 C1(O, Rn)a vector field on O⇢Rn, X(0) = x0,
and assume the Picard–Lindel¨of theorem that there exists a unique continuous function f(t, x0)satisfying the equation for t2 J, a max-imal interval for the existence of solutions, and with f(0, x0) = x0.1
It is obviously that ∂t∂f(t, x0)exists. So, our goal is to discuss: the smooth dependence of the solution f(t, x0)on its initial value x0.
It turns out that f(t, x0) is C1 in x0. Moreover, an iterative argu-ment then implies the Ckcase as stated in Theorem1.32.
1In this section we work on Rn entirely and the symbols X, Y, Z etc. will be used to denote points in Rn. This should not be confused with the same symbols in the last section which denote vector fields on a manifold.
The above lemma then implies that there exists an integral manifold S passing through p such that TqS=D(q)for all q ∈S.
Since p∈ M is arbitrary, the union of all integral manifolds is the whole manifold M. Also for any two integral manifolds S and S0, if S∩S0 6= ∅ then S∪S0is also an integral manifold. We conclude that there is a maximal integral manifold Sppassing through p.
8. Existence, uniqueness and smooth dependence of ODE Now we go back to the ODE system:
X0(t) = F(X(t)), F∈ C1(O, Rn)a vector field on O⊂Rn, X(0) =x0,
and assume the Picard–Lindel¨of theorem that there exists a unique continuous function φ(t, x0)satisfying the equation for t ∈ J, a max-imal interval for the existence of solutions, and with φ(0, x0) =x0.2
It is obviously that ∂t∂φ(t, x0)exists. So, our goal is to discuss: the smooth dependence of the solution φ(t, x0)on its initial value x0.
It turns out that φ(t, x0)is C1in x0. Moreover, an iterative argu-ment then implies the Ckcase as stated in Theorem1.32.
2In this section we work on Rn entirely and the symbols X, Y, Z etc. will be used to denote points in Rn. This should not be confused with the same symbols in the last section which denote vector fields on a manifold.
Historically there exists two different proofs of this theorem, one goes through a classical method by estimates (c.f. [HSD13]) and the other makes use of the inverse function theorem on Banach spaces.
Below we follow the first method closely.
Suppose there are two solutions X(t) and ˜X(t) with the given initial data x0and x0+z0. The key point is to estimatekX(t)− ˜X(t)k in terms of x0and z0. We consider the variational equation:
(*)
U0(t) = A(t)U(t), U(0) = z0
where A(t) = F0(X(t)), which is C0dependent on t. The idea is that, when z0 is small, X(t) +U(t) should approximate ˜X(t) with initial data x0+z0. In fact, this comes from the intuition that if F is C2, then the solution to the variational problem is just the first order term of the Taylor expansion for ˜X(t)’s in z0.
Proposition 1.43. Let U(t, ξ)be the flow of (*), i.e. U(0, ξ) = ξ, x0+ξ ∈ O, and Y(t, ξ)be the flow of X0(t) = F(X(t))with Y(0, ξ) = ξ. Then
kξlimk→0
kY(t, ξ)−X(t)−U(t, ξ)k
kξk =0
uniformly on an interval of existence J.
Assuming the proposition, the theorem follows immediately.
Theorem 1.44. If F ∈ Ck, then the flow φ(t, x0) of the ODE system X0(t) = F(X(t)), X(0) = x0is Ckas well.
PROOF. By the proposition,
φ(t, x0+ξ)−φ(t, x0) =Y(t, ξ)−X(t) =U(t, ξ) +o(|ξ|). Note that from solving the linear system U0(t, ξ) = A(t)U(t, ξ)with U(0, ξ) = ξ, we see that
U(t, ξ) = eA(t)ξ
is linear in ξ. Hence D2φ(t, x0)ξ =U(t, ξ)and φ(t, x)is C1in x. This proves the theorem for the case k =1.
8. EXISTENCE, UNIQUENESS AND SMOOTH DEPENDENCE OF ODE 37
Back to the variational equation (*), we get d
dt(D2φ(t, x0)) = F0(φ(t, x0))D2φ(t, x0)
with D2φ(0, x0) = idRn. Then by induction, F ∈ Ck implies that
φ(t, x)is Ck in x.
PROOF OF PROPOSITION. We rewrite the differential equations into integral equations as:
X(t) =x0+ Z t
0 F(X(s))ds, Y(t, ξ) =x0+ξ+
Z t
0 F(Y(s, ξ))ds, U(t, ξ) =ξ+
Z t
0 F0(X(s))U(s, ξ)ds.
By the Taylor expansion, we have an estimate:
kY(t, ξ)−X(t)−U(t, ξ)k
≤ Z t
0 kF(Y(s, ξ))−F(X(s))−F0(X(s))U(s, ξ)kds
≤ Z t
0
|F0(X(s))kkY(s, ξ)−X(s)−U(s, ξ)k
+kR(X(s), Y(s, ξ)−X(s))kds where R is the first order remainder term.
We use the Gronwall’s inequality to deal with the iteration of dif-ference appearing in the integral.
Exercise 1.21 (Gronwall’s inequality, an easy version). If u ∈ C1[0, d], u > 0 and u satisfies u(t) ≤ c+Rt
0Ku(s)ds for some positive con-stants c, K. Then u≤ceKt on[0, d].
Therefore, the constant c=|ξ|can be taken to be small and kY(t, ξ)−X(t)k ≤ kξk +
Z t
0 kF(Y(s, ξ))−F(X(s))kds
≤ kξk + Z t
0 kF0kkY(s, ξ)−X(s)kds
Choose K large such that kF0k < K on a small neighborhood. By Gronwall’s inequality, kY(t, ξ)−X(t)k ≤ kξkeKt. So, for any e > 0, we can choose ξ small such that the remainder term
kR(X(s), Y(s, ξ)−X(s))k ≤ekY(s, ξ)−X(s)k. Denote g(t) =kY(t, ξ)−X(t)−U(t, ξ)kand rewrite
g(t)≤ Z t
0 Kg(s) +ekξkeKsds≤ekξkC+ Z t
0 Kg(s)ds
for some bounded constant C depending on F and the existece inter-val J. By Gronwall’s inequality again, g(t) ≤ekξkCeKt and hence
kY(t, ξ)−X(t)−U(t, ξ)k kξk ≤e ˜C
which is uniformly in t.
9. Problems
1. ([War83] Ch.1 #10) Let M be a compact manifold of dimension n, and let f : M→Rnbe C∞. Prove that f cannot everywhere be non-singular.
2. ([War83] Ch.1 #3) Let{Uα}be an open cover of a manifold M. Prove that there exists a refinement{Vα}such that Vα ⊂Uαfor each α.
3. ([War83] Ch.1 #9) Let f : R2→Rbe defined by f(x, y) =x3+xy+y3+1.
For which points p = (0, 0), p = (13,13), p = (−13,−13)is f−1 f(p)an imbedded submanifold in R?
4. ([War83] Ch.1 #16) Let N⊂M be a submanifold. Let γ : (a, b)→ M be a C∞ curve such that γ(a, b)⊂ N. Show that it is not necessarily true that
˙γ(t)∈ Nγ(t)for each t∈ (a, b).
5. ([War83] Ch.1 #17) Prove that any C∞vector field on a compact manifold is complete.
6. ([War83] Ch.1 #18) Prove that a C∞map f : R2 →R1cannot be one-to-one.
7. ([War83] Ch.1 #23) A Riemannian structure on a differentiable manifold M is a smooth choice of a positive definite inner producth, im on each tangent space Mm, smooth in the sense that whenever X and Y are C∞ vector fields on M, thenhX, Yiis a C∞function on M. Prove that there exists a Riemannian structure on every differentiable manifold. You will
9. PROBLEMS 39
need to use a partition of unity argument. A Riemannian manifold is a differentiable manifold together with a Riemannian structure.
8. ([War83] Ch.1 #6) Prove that if ψ : M→ N is C∞, one-to-one, onto, and everywhere non-singular, then ψ is a diffeomorphism.
9. ([War83] Ch.1 #19) Supply the details of the equivalence of the Frobenius theorem1.40and the classical version:
Remark 1.45 (classical Frobenius theorem). Let U and V be open sets in Rm and Rn respectively. We use coordinates r1, . . . , rm on Rm and s1, . . . , snon Rn. Let
b : U×V→ M(n, m)
be a C∞ map of U×V into the set of all n×m real matrices, and let (r0, s0)∈U×V. If
∂biβ
∂rγ −∂b∂riγ
β
+
∑
n j=1∂biβ
∂sj bjγ−∂b∂siγ
j bjβ
=0
(i=1, . . . , n; γ, β=1, . . . , m) on U×V, then there exist neighborhoods U0of r0in U and V0of s0in V and a unique C∞map
α: U0×V0→V such that if
αs(r) =α(r, s) (s ∈V0, r∈U0) then
αs(r0) =s, dαsr =b(r, α(r, s)) for all(r, s)∈U0×V0.
10. ([War83] Ch.1 #20) Let ϕ : N → M be C∞, and let X be a C∞vector field on N. Suppose that dϕ(X(p)) = dϕ(X(q))whenever ϕ(p) = ϕ(q). Is there a smooth vector field Y on M which is ϕ-related to X?