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We shall see shortly that the Lie derivative corresponds to an- an-other simple binary operation on vector fields, the Lie bracket

We shall see shortly that the Lie derivative corresponds to an-other simple binary operation on vector fields, the Lie bracket.

1We remark that if M is compact, the interval (ap, bp) can be extended to (∞, ∞)and φt will be a diffeomorphism from M to itself. In general, a vector field is called complete if it has this property.

7. VECTOR FIELDS AND FROBENIUS THEOREM 31

Definition 1.34. Let X, Y be C vector fields on U. The Lie bracket is defined by[X, Y] :=XY−YX. That is,

[X, Y]pf =Xp(Y(f))−Yp(X(f)).

It seems that[X, Y]is a second order operator on C(U). In fact, it is still of the first order:

Proposition 1.35. [X, Y]is a C vector field on U. The Lie bracket has the following basic (Lie algebra) properties:

Proposition 1.36. Let X, Y be C vector fields. Then (1) (Anti-symmetry)[X, Y] = −[Y, X]

(2) (Jacobi identity)[[X, Y], Z] + [[Y, Z], X] + [[Z, X], Y] = 0 Now we can prove the important formula:

Theorem 1.37 (Lie, 1870). (LVW)p = [V, W]p

PROOF. Let V generate φtand W generate ψs. Choose a test func-tion h∈ Cp. By definition,

(LVW)ph We may extend these concepts to some higher dimensional cases.

Definition 1.38. A k dimensional distribution D on a manifold M is a choice of a k dimensional subspace D(p)of TpM for each p∈ M.

We say D is C if for every p ∈ M, there is a neighborhood U such that D is spanned by k Cvector fields X1, X2, . . . , Xkon U.

The question in higher dimensions becomes: for a given distribu-tion D near p, does there exists a k dimensional submanifold S with p ∈S such that TqS=D(q)for all q∈ S?

If so, S is called an integral manifold of D passing through p.

Clearly a necessary condition for this integrability is the following:

Definition 1.39. D is called involutive if [X, Y] ∈ D for all X, YD.

Here a vector field X ∈ D meansXpD(p)for all p.

This turns out to be sufficient at least locally:

Theorem 1.40 (Frobenius Integrability, 1877). If D is involutive, then for all p ∈ M there exists a maximal integral manifold SpM passing through p such that TqSp=D(q)for all q ∈ Sp.

7. VECTOR FIELDS AND FROBENIUS THEOREM 33

As in the case of integral curves, Sp ⊂ M needs not be closed.

That is Spmay not be with the induced topology.

The proof is based on two lemmas. To state the first one, we need Definition 1.41. For a smooth map f : S → M and a smooth vector field X∈ C(TS), the tangent map d f = fsends X to

The next lemma characterizes coordinate vector fields:

Lemma 1.42. If X1, . . . , Xk are k vector fields near a point p ∈ M that

7. VECTOR FIELDS AND FROBENIUS THEOREM 33

As in the case of integral curves, Sp ⇢ M needs not be closed.

That is Spmay not be with the induced topology.

The proof is based on two lemmas. To state the first one, we need Definition 1.41. For a smooth map f : S ! M and a smooth vector field X 2 C(TS), the tangent map d f = f sends X to

The next lemma characterizes coordinate vector fields:

Lemma 1.42. If X1, . . . , Xk are k vector fields near a point p 2 M that

Let c(t, s) = ψsφtψsφt(p). Since LVW = 0 implies φtW =W, directly differentiation shows that

∂sc(t, s) = −Wψ−sφ−tψsφt(p) +ψsφt(Wψsφt(p))

=−Wc(t,s)+Wc(t,s) =0

Similarly, ∂c(t, s)/∂t =0. So c(t, s) = p for all well-defined t, s.

Now, suppose Xigenerates φifor i =1, 2, . . . , k near p. We define c(t1, t2, . . . , tk) :=φ1t1φ2t2◦ · · · ◦φktk.

We check that its coordinate tangent vectors are precisely X1, . . . , Xk: c(∂/∂t1) =

∂t1φ1t1 ◦ · · · ◦φtkk =X1

c(t1,...,tk). And since every φiti commutes with each other,

c(∂/∂ti) =

∂ti φitiφt11◦ · · ·cφiti· · · ◦φktk =Xi c

(t1,...,tk).

Let S := {c(t1, . . . , tk) | tjIj, ∀ j } where Ij is chosen to be small enough such that every φtjj is well-defined for tjIj. We see that c is injective and then c is an immersion into M. By Lemma 1.16, there exists a chart (U, x) near p such that xi(c(t1, . . . , tk)) = ti for i = 1, . . . , k and xi(c(t1, . . . , tk)) = 0 for i = k+1, . . . , m. Hence S∩U is a coordinate slice{xj =0| j =k+1, . . . , m}on M.  PROOF OF FROBENIUS THEOREM. We fix an arbitrary point p ∈ M. Since D(p) ⊂ TpM is a k dimensional subspace, we can select a chart(U, x) at p with D(p) = R1|p, . . . , ∂k|p

and construct the projection π : UMRk onto the first k coordinates. Then there exists a smaller neighborhood U0 3 p such that

D ∼=πD =R



∂x1, . . . ,

∂xk



, ∀qU0.

For each i = 1, . . . , k, let Xi ∈ D be the vector field lifted from

∂/∂xi, i.e. π(Xi) =∂/∂xi. Then they are π-related and 0=



∂xi,

∂xj



= [π(Xi), π(Xj)] = π[Xi, Xj]⇐⇒ [Xi, Xj] = 0.

8. EXISTENCE, UNIQUENESS AND SMOOTH DEPENDENCE OF ODE 35 8. EXISTENCE, UNIQUENESS AND SMOOTH DEPENDENCE OF ODE 35

TpM

The above lemma then implies that there exists an integral manifold S passing through p such that TqS=D(q)for all q2 S.

Since p2 M is arbitrary, the union of all integral manifolds is the whole manifold M. Also for any two integral manifolds S and S0, if S\S0 6= ∆ then S[S0is also an integral manifold. We conclude that there is a maximal integral manifold Sppassing through p. ⇤

8. Existence, uniqueness and smooth dependence of ODE Now we go back to the ODE system:

8<

:

X0(t) = F(X(t)), F 2 C1(O, Rn)a vector field on O⇢Rn, X(0) = x0,

and assume the Picard–Lindel¨of theorem that there exists a unique continuous function f(t, x0)satisfying the equation for t2 J, a max-imal interval for the existence of solutions, and with f(0, x0) = x0.1

It is obviously that ∂tf(t, x0)exists. So, our goal is to discuss: the smooth dependence of the solution f(t, x0)on its initial value x0.

It turns out that f(t, x0) is C1 in x0. Moreover, an iterative argu-ment then implies the Ckcase as stated in Theorem1.32.

1In this section we work on Rn entirely and the symbols X, Y, Z etc. will be used to denote points in Rn. This should not be confused with the same symbols in the last section which denote vector fields on a manifold.

The above lemma then implies that there exists an integral manifold S passing through p such that TqS=D(q)for all q ∈S.

Since p∈ M is arbitrary, the union of all integral manifolds is the whole manifold M. Also for any two integral manifolds S and S0, if S∩S0 6= ∅ then SS0is also an integral manifold. We conclude that there is a maximal integral manifold Sppassing through p. 

8. Existence, uniqueness and smooth dependence of ODE Now we go back to the ODE system:



X0(t) = F(X(t)), F∈ C1(O, Rn)a vector field on O⊂Rn, X(0) =x0,

and assume the Picard–Lindel¨of theorem that there exists a unique continuous function φ(t, x0)satisfying the equation for t ∈ J, a max-imal interval for the existence of solutions, and with φ(0, x0) =x0.2

It is obviously that ∂tφ(t, x0)exists. So, our goal is to discuss: the smooth dependence of the solution φ(t, x0)on its initial value x0.

It turns out that φ(t, x0)is C1in x0. Moreover, an iterative argu-ment then implies the Ckcase as stated in Theorem1.32.

2In this section we work on Rn entirely and the symbols X, Y, Z etc. will be used to denote points in Rn. This should not be confused with the same symbols in the last section which denote vector fields on a manifold.

Historically there exists two different proofs of this theorem, one goes through a classical method by estimates (c.f. [HSD13]) and the other makes use of the inverse function theorem on Banach spaces.

Below we follow the first method closely.

Suppose there are two solutions X(t) and ˜X(t) with the given initial data x0and x0+z0. The key point is to estimatekX(t)− ˜X(t)k in terms of x0and z0. We consider the variational equation:

(*)



U0(t) = A(t)U(t), U(0) = z0

where A(t) = F0(X(t)), which is C0dependent on t. The idea is that, when z0 is small, X(t) +U(t) should approximate ˜X(t) with initial data x0+z0. In fact, this comes from the intuition that if F is C2, then the solution to the variational problem is just the first order term of the Taylor expansion for ˜X(t)’s in z0.

Proposition 1.43. Let U(t, ξ)be the flow of (*), i.e. U(0, ξ) = ξ, x0+ξ ∈ O, and Y(t, ξ)be the flow of X0(t) = F(X(t))with Y(0, ξ) = ξ. Then

kξlimk→0

kY(t, ξ)−X(t)−U(t, ξ)k

kξk =0

uniformly on an interval of existence J.

Assuming the proposition, the theorem follows immediately.

Theorem 1.44. If F ∈ Ck, then the flow φ(t, x0) of the ODE system X0(t) = F(X(t)), X(0) = x0is Ckas well.

PROOF. By the proposition,

φ(t, x0+ξ)−φ(t, x0) =Y(t, ξ)−X(t) =U(t, ξ) +o(|ξ|). Note that from solving the linear system U0(t, ξ) = A(t)U(t, ξ)with U(0, ξ) = ξ, we see that

U(t, ξ) = eA(t)ξ

is linear in ξ. Hence D2φ(t, x0)ξ =U(t, ξ)and φ(t, x)is C1in x. This proves the theorem for the case k =1.

8. EXISTENCE, UNIQUENESS AND SMOOTH DEPENDENCE OF ODE 37

Back to the variational equation (*), we get d

dt(D2φ(t, x0)) = F0(φ(t, x0))D2φ(t, x0)

with D2φ(0, x0) = idRn. Then by induction, F ∈ Ck implies that

φ(t, x)is Ck in x. 

PROOF OF PROPOSITION. We rewrite the differential equations into integral equations as:

X(t) =x0+ Z t

0 F(X(s))ds, Y(t, ξ) =x0+ξ+

Z t

0 F(Y(s, ξ))ds, U(t, ξ) =ξ+

Z t

0 F0(X(s))U(s, ξ)ds.

By the Taylor expansion, we have an estimate:

kY(t, ξ)−X(t)−U(t, ξ)k

≤ Z t

0 kF(Y(s, ξ))−F(X(s))−F0(X(s))U(s, ξ)kds

≤ Z t

0

|F0(X(s))kkY(s, ξ)−X(s)−U(s, ξ)k

+kR(X(s), Y(s, ξ)−X(s))kds where R is the first order remainder term.

We use the Gronwall’s inequality to deal with the iteration of dif-ference appearing in the integral.

Exercise 1.21 (Gronwall’s inequality, an easy version). If u ∈ C1[0, d], u > 0 and u satisfies u(t) ≤ c+Rt

0Ku(s)ds for some positive con-stants c, K. Then u≤ceKt on[0, d].

Therefore, the constant c=|ξ|can be taken to be small and kY(t, ξ)−X(t)k ≤ kξk +

Z t

0 kF(Y(s, ξ))−F(X(s))kds

≤ kξk + Z t

0 kF0kkY(s, ξ)−X(s)kds

Choose K large such that kF0k < K on a small neighborhood. By Gronwall’s inequality, kY(t, ξ)−X(t)k ≤ kξkeKt. So, for any e > 0, we can choose ξ small such that the remainder term

kR(X(s), Y(s, ξ)−X(s))k ≤ekY(s, ξ)−X(s)k. Denote g(t) =kY(t, ξ)−X(t)−U(t, ξ)kand rewrite

g(t)≤ Z t

0 Kg(s) +ekξkeKsdsekξkC+ Z t

0 Kg(s)ds

for some bounded constant C depending on F and the existece inter-val J. By Gronwall’s inequality again, g(t) ≤ekξkCeKt and hence

kY(t, ξ)−X(t)−U(t, ξ)k kξk ≤e ˜C

which is uniformly in t. 

9. Problems

1. ([War83] Ch.1 #10) Let M be a compact manifold of dimension n, and let f : M→Rnbe C. Prove that f cannot everywhere be non-singular.

2. ([War83] Ch.1 #3) Let{Uα}be an open cover of a manifold M. Prove that there exists a refinement{Vα}such that VαUαfor each α.

3. ([War83] Ch.1 #9) Let f : R2Rbe defined by f(x, y) =x3+xy+y3+1.

For which points p = (0, 0), p = (13,13), p = (−13,13)is f1 f(p)an imbedded submanifold in R?

4. ([War83] Ch.1 #16) Let N⊂M be a submanifold. Let γ : (a, b)→ M be a C curve such that γ(a, b)⊂ N. Show that it is not necessarily true that

˙γ(t)∈ Nγ(t)for each t∈ (a, b).

5. ([War83] Ch.1 #17) Prove that any Cvector field on a compact manifold is complete.

6. ([War83] Ch.1 #18) Prove that a Cmap f : R2R1cannot be one-to-one.

7. ([War83] Ch.1 #23) A Riemannian structure on a differentiable manifold M is a smooth choice of a positive definite inner producth, im on each tangent space Mm, smooth in the sense that whenever X and Y are C vector fields on M, thenhX, Yiis a Cfunction on M. Prove that there exists a Riemannian structure on every differentiable manifold. You will

9. PROBLEMS 39

need to use a partition of unity argument. A Riemannian manifold is a differentiable manifold together with a Riemannian structure.

8. ([War83] Ch.1 #6) Prove that if ψ : M→ N is C, one-to-one, onto, and everywhere non-singular, then ψ is a diffeomorphism.

9. ([War83] Ch.1 #19) Supply the details of the equivalence of the Frobenius theorem1.40and the classical version:

Remark 1.45 (classical Frobenius theorem). Let U and V be open sets in Rm and Rn respectively. We use coordinates r1, . . . , rm on Rm and s1, . . . , snon Rn. Let

b : U×VM(n, m)

be a C map of U×V into the set of all n×m real matrices, and let (r0, s0)∈U×V. If

∂b

∂rγ∂b∂r

β

+

n j=1

∂b

∂sj b∂b∂s

j b



=0

(i=1, . . . , n; γ, β=1, . . . , m) on U×V, then there exist neighborhoods U0of r0in U and V0of s0in V and a unique Cmap

α: U0×V0V such that if

αs(r) =α(r, s) (s ∈V0, r∈U0) then

αs(r0) =s, dαs r =b(r, α(r, s)) for all(r, s)∈U0×V0.

10. ([War83] Ch.1 #20) Let ϕ : N → M be C, and let X be a Cvector field on N. Suppose that dϕ(X(p)) = (X(q))whenever ϕ(p) = ϕ(q). Is there a smooth vector field Y on M which is ϕ-related to X?

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