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X n=1 sin π n2

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HW 2

JIA-MING (FRANK) LIOU

1. Part I

(1) Determine whether the series converges or diverges. Write c if it is convergent and d if it is divergent. Explain your answer.

(a)

X

n=1

sin π n2. (b)

X

n=1

n!

nn. (c)

X

n=1

(−1)n−1 1 2n + 1. (d)

X

n=1

cos nπ 2n . (e)

X

n=1

n + 2 (n + 1)3. (f)

X

n=1

(2n − 1)(n2− 1) (n + 1)(n2+ 4)2.

(2) Determine whether the series is absolutely convergent, conditionally convergent or divergent. Explain your answer.

(a)

X

n=1

(−1)n−1

4

n . (b)

X

n=1

n 2 3

n

.

(c)

X

n=1

 1 + 1

n

n2

.

(d)

X

n=1

(−3)n (2n + 1)!. (e) X

n=1

(2n)!

n!n!. (f)

X

n=1

 n2+ 1 2n2+ 1

n

1

(2)

2 JIA-MING (FRANK) LIOU

(3) Let hn = √n

n − 1 for n ≥ 1. In this exercise, we are going to study whether the alternating series

X

n=1

(−1)n−1hnis absolutely convergent or conditionally convergent.

(a) Show that

0 < hn<

r2

n, n ≥ 2

(Hint: consider (1 + hn)n.) By the Sandwich principle, we find lim

n→∞

n

n = 1.

(b) Show that for n ≥ 3,

nn+1> (n + 1)n. Using this, show that (hn) is decreasing.

(c) From (a) and (b), we know that the series

X

n=1

(−1)n−1hn is convergent by the Leibnitz test. Is the series absolutely convergent?

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