1. hw 5
(1) Let (an) and (bn) be sequence of real numbers. Assume that there exists N ∈ N so that for any n ≥ N, an≤ bn. Assume further that lim
n→∞an= ∞. Show that lim
n→∞bn= ∞.
(2) Let (an) and (bn) be sequence of real numbers. Assume that 0 < an ≤ bn for all n ≥ 1.
(a) Suppose that both
∞
X
n=1
an and
∞
X
n=1
bn are convergent. Show that
∞
X
n=1
an≤
∞
X
n=1
bn.
(b) Suppose that
∞
X
n=1
an= ∞. Show that
∞
X
n=1
bn= ∞.
(3) Evaluate (a)
∞
X
n=1
1
n(n + 1)(n + 2). (b)
∞
X
n=1
1
n(n + 1)(n + 3).
(4) Let a1, · · · , ambe positive integers with a1< a2< · · · < am. Define a polynomial Q(x) by Q(x) = (x + a1) · · · (x + am).
Evaluate
∞
X
n=1
1 Q(n).
(5) A sequence (an) of real numbers is a positive sequence if an> 0 for all n ≥ 1. Assume that (an) is a positive sequence so that lim
n→∞nan = c with c > 0. Show that the infinite series
∞
X
n=1
an is divergent.
(6) Let (an) be a sequence of real numbers.
(a) Suppose
∞
X
n=1
|an| is convergent. Show that
∞
X
n=1
a2n is convergent.
(b) Is the converse of the above statement true? It yes, prove it. If not, provide a coun- terexample.
(7) An infinite series
∞
X
n=1
an is called absolutely convergent if
∞
X
n=1
|an| is convergent.
(a) Suppose
∞
X
n=1
a2n is convergent. Show that
∞
X
n=1
an
n is absolutely convergent.
(b) Suppose
∞
X
n=1
a2n and
∞
X
n=1
b2n are both convergent. Show that
∞
X
n=1
anbn is absolutely convergent.
(8) Prove that
∞
X
n=3
1
n(ln n)p converges when p > 1 and diverges when p < 1.
(9) Determine whether the series converges or diverges. Explain your answer.
(a)
∞
X
n=1
(−1)n n n + 1.
1
2
(b)
∞
X
n=1
sin π n2. (c)
∞
X
n=1
n!
nn. (d)
∞
X
n=1
(−1)n−1 1 2n + 1. (e)
∞
X
n=1
cos nπ 2n . (f)
∞
X
n=1
n + 2 (n + 1)3. (g)
∞
X
n=1
(2n − 1)(n2− 1) (n + 1)(n2+ 4)2. (h)
∞
X
n=1
cosnπ3
√n .
(i)
∞
X
n=1
cosnπ3 sin2nπ
√n .
(10) Determine whether the series is absolutely convergent, conditionally convergent or diver- gent. Explain your answer.
(a)
∞
X
n=1
(−1)n−1
√4
n . (b)
∞
X
n=1
n 2 3
n
.
(c)
∞
X
n=1
1 + 1
n
n2 .
(d)
∞
X
n=1
(−3)n (2n + 1)!. (e) X
n=1∞
(2n)!
n!n!. (f)
∞
X
n=1
(−1)n n2+ 1 2n2+ 1
n