1. Homework 6 (1) In this exercise, we are going to prove lim
x→2x2= 4.
(a) Show that for 0 < |x − 2| < 1,
|x2− 4| < 5|x − 2|.
(b) Use (a) to prove the result.
(2) In this exercise, we are going to prove lim
x→3
1 x= 1
3. (a) Show that for 0 < |x − 3| < 1,
1 x−1
3
< 1 6|x − 3|.
(b) Use (a) to prove the result.
(3) Use definition to prove that lim
x→2
√ x
x2+ 5 = 2 3. (4) Suppose lim
x→af (x) = A and lim
x→ag(x) = B.
(a) Show that there exists d > 0 such that |g(x)| ≤ (|B| + 1) for 0 < |x − a| < d.
(b) Use (a) to show that
|f (x)g(x) − AB| ≤ (|B| + 1)|f (x) − A| + |A||g(x) − B|
for 0 < |x − a| < d.
(c) Use (b) to show that lim
x→af (x)g(x) = AB.
(d) Suppose B 6= 0. Show that there exists d0> 0 such that
|g(x)| > |B|/2, 0 < |x − a| < d0. (e) Use (d) to show that
1 g(x)− 1
B
< 2
B2|g(x) − B|
for 0 < |x − a| < d0. (f) Use (e) to show that lim
x→a
1 g(x)= 1
B. (g) Use (c) and (f) to show that lim
x→a
f (x) g(x) = A
B provided that B 6= 0.
(h) Use induction and (c) to prove that lim
x→af (x)n= An for any n ∈ N.
(5) Let n ≥ 2 be a natural number and a > 0. Denote M = an−1n
2(1 − qn
1 2)
.
(a) Show that if |x − a| < a/2, we have
xn−1n + an1xn−2n + · · · + an−2n xn1 + an−1n > M.
(b) Show that if |x − a| < a/2, we have
|√n x −√
a| < M−1|x − a|.
(c) Show that lim
x→a
√n
x = √n a.
(6) (Sandwich Principle) Suppose that f, g, h are functions defined on 0 < |x − a| < d for some d > 0 and
h(x) ≤ f (x) ≤ g(x), 0 < |x − a| < d.
If lim
x→ah(x) = lim
x→ag(x) = L, show that lim
x→af (x) = L. Use this to evaluate lim
x→0
p3
x + x2sin1 x.
1
2
(7) Let f (x) be a real-valued function on R defined by f (x) =
(sin x2
x2 if x 6= 0, 1 otherwise.
Is f (x) continuous at 0?
(8) Let f (x) and g(x) be real valued functions on R defined below.
f (x) =
(0 if x is rational,
1 if x is irrational., g(x) =
(0 if x is rational, x if x is irrational.
Evaluate lim
x→0f (x) and lim
x→0g(x) if they exist.
(9) Find the value a such that lim
x→0
√3
ax + 8 − 2
x = 5
12. (10) Let p(x) = x6+ 2x5− x + 1. Evaluate lim
x→∞(p6
p(x) − x).
(11) Evaluate the following limits.
(a) lim
x→3
√x + 6 − x x3− 3x2 . (b) lim
x→0
(1 + x)(1 + 2x)(1 + 3x) − 1
x .
(c) lim
x→1
x10− 1 x99− 1. (d) lim
x→2
(x10− 210) − 10 · 29(x − 2)
(x − 2)2 .
(e) lim
x→1
m
1 − xm− n 1 − xn
where m, n are distinct natural numbers.
(f) lim
x→−2
√3
x − 6 + 2 x3+ 8 . (g) lim
x→1
m√ x − 1
√n
x − 1, where m, n are natural numbers.
(h) lim
x→0
sin 20x
x .
(i) lim
x→0
sin 5x sin 7x. (j) lim
x→0
1 − cos x x2 . (k) lim
x→0
sin 6x − sin 5x sin x .