全文
【解】
(a)平行四邊形定律 合力大小 R
2 2
15 10 2 15 10 cos 75 20.07 kN
25°
15kN
R 50°
105°
θ α
合力方向角 使用正弦定律
sin105 sin
= θ
15
sin sin105
⇒ θ=
1 15
sin sin105 46.23 20.07
θ= − =
，方向角α=50− =θ 3.77
故合力
合力大小 R
2 2
15 10 2 15 10 cos105 20.07 kN
合力方向角 使用正弦定律
sin105 sin
= θ
15
sin sin105
⇒ θ=
1 15
sin sin105 46.23 20.07
θ= − =
，方向角α=50− =θ 3.77
故合力
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