2008 W -C L Calculus(I)

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Calculus (I)

WEN-CHING LIEN

Department of Mathematics National Cheng Kung University

2008

WEN-CHINGLIEN Calculus (I)

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5.3 The Fundamental Theorem of Calculus.

Theorem (I)

If f is continuous on[a,b],then the function F defined by

F(x) = Z x

a

f(u)du, axb

is continuous on [a,b]and differentiable on(a,b),and d

dxF(x) =f(x)

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h0

x+h

x

x+h

x

f (u)du ≤ M

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h0

x+h

x

x+h

x

f (u)du ≤ M

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h0

x+h

x

x+h

x

f (u)du ≤ M

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⇒ I.V.T. ∃Ch∈ [x,x+h]

such that f(Ch) = Ih, lim

h0Ch=x

∵f is continuous, lim

h0f(Ch) =f(x)

d

dxF(x) =f(x). 2

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⇒ I.V.T. ∃Ch∈ [x,x+h]

such that f(Ch) = Ih, lim

h0Ch=x

∵f is continuous, lim

h0f(Ch) =f(x)

d

dxF(x) =f(x). 2

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⇒ I.V.T. ∃Ch∈ [x,x+h]

such that f(Ch) = Ih, lim

h0Ch=x

∵f is continuous, lim

h0f(Ch) =f(x)

d

dxF(x) =f(x). 2

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Remark:

(1)F(x) =Rx

a f(u)du

F(x) =f(x)

F(x)is an anti-derivative of f(x)

We call R

f(x)dx an indefinite integral.

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Remark:

(1)F(x) =Rx

a f(u)du

F(x) =f(x)

F(x)is an anti-derivative of f(x)

We call R

f(x)dx an indefinite integral.

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Remark:

(1)F(x) =Rx

a f(u)du

F(x) =f(x)

F(x)is an anti-derivative of f(x)

We call R

f(x)dx an indefinite integral.

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Remark:

(1)F(x) =Rx

a f(u)du

F(x) =f(x)

F(x)is an anti-derivative of f(x)

We call R

f(x)dx an indefinite integral.

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1

3

2

xdx

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1

3

2

xdx

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Theorem (Leibnizs Rule) d

dx Z h(x)

g(x)

f(u)du =f(h(x))h(x) −f(g(x))g(x) Here f is continuous ,g and h are differentiable

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Exercises:

1 d

dx Rx

0(eu2u)du

2 d

dx Rsinx

0 (x22x)dx

3 d

dx Rx3

x2 udu

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Exercises:

1 d

dx Rx

0(eu2u)du

2 d

dx Rsinx

0 (x22x)dx

3 d

dx Rx3

x2 udu

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Exercises:

1 d

dx Rx

0(eu2u)du

2 d

dx Rsinx

0 (x22x)dx

3 d

dx Rx3

x2 udu

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Theorem (II)

Assume that f is continuous on [a,b],them Z b

a

f(x)dx =F(b) −F(a), where F(x)is an anti-derivative of f(x)

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x

a

⇒ G(a) = 0, G(a) =F (a) + C

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x

a

⇒ G(a) = 0, G(a) =F (a) + C

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x

a

⇒ G(a) = 0, G(a) =F (a) + C

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C= −F(a)

G(x) = F(x) −F(a)

⇒ Rx

a f(u)du =F(x) −F(a) 2

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C= −F(a)

G(x) = F(x) −F(a)

⇒ Rx

a f(u)du =F(x) −F(a) 2

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C= −F(a)

G(x) = F(x) −F(a)

⇒ Rx

a f(u)du =F(x) −F(a) 2

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Exercises:

1 R2

1 x2− 2 xdx

2 Rπ

0 cosx dx

3 R1

0 xe2x 2dx

4 Re

1

1 xdx

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Exercises:

1 R2

1 x2− 2 xdx

2 Rπ

0 cosx dx

3 R1

0 xe2x 2dx

4 Re

1

1 xdx

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Exercises:

1 R2

1 x2− 2 xdx

2 Rπ

0 cosx dx

3 R1

0 xe2x 2dx

4 Re

1

1 xdx

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Exercises:

1 R2

1 x2− 2 xdx

2 Rπ

0 cosx dx

3 R1

0 xe2x 2dx

4 Re

1

1 xdx

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Compute the following integrals

R (x −1)2 R cos3x dx R1

0(x2−√ x)dx

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Compute the following integrals

R (x −1)2 R cos3x dx R1

0(x2−√ x)dx

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Compute the following integrals

R (x −1)2 R cos3x dx R1

0(x2−√ x)dx

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2

0

t2

h

0

h 0

x

x

0

2

, find f ( x )

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2

0

t2

h

0

h 0

x

x

0

2

, find f ( x )

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2

0

t2

h

0

h 0

x

x

0

2

, find f ( x )

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Example:

f(x) =

 0 , if x is irrational,

1 , if x is rational, for 0≤ x ≤1.

DoesR1

0 f(x)dx exist ?

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Thank you.

WEN-CHINGLIEN Calculus (I)

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