Advanced Calculus (I)
WEN-CHINGLIEN
Department of Mathematics National Cheng Kung University
WEN-CHINGLIEN Advanced Calculus (I)
7.2 Uniform convergence of series
Definition
Let fk be a sequence of real functions defined on some set E and set
sn(x ) :=
n
X
k =1
fk(x ), x ∈ E , n ∈N.
(i)
The series
∞
P
k =1
fk is said to converges pointwise on E if and only if the sequence sn(x ) converges pointwise on E as n → ∞.
WEN-CHINGLIEN Advanced Calculus (I)
7.2 Uniform convergence of series
Definition
Let fk be a sequence of real functions defined on some set E and set
sn(x ) :=
n
X
k =1
fk(x ), x ∈ E , n ∈N.
(i)
The series
∞
P
k =1
fk is said to converges pointwise on E if and only if the sequence sn(x ) converges pointwise on E as n → ∞.
WEN-CHINGLIEN Advanced Calculus (I)
7.2 Uniform convergence of series
Definition
Let fk be a sequence of real functions defined on some set E and set
sn(x ) :=
n
X
k =1
fk(x ), x ∈ E , n ∈N.
(i)
The series
∞
P
k =1
fk is said to converges pointwise on E if and only if the sequence sn(x ) converges pointwise on E as n → ∞.
WEN-CHINGLIEN Advanced Calculus (I)
7.2 Uniform convergence of series
Definition
Let fk be a sequence of real functions defined on some set E and set
sn(x ) :=
n
X
k =1
fk(x ), x ∈ E , n ∈N.
(i)
The series
∞
P
k =1
fk is said to converges pointwise on E if and only if the sequence sn(x ) converges pointwise on E as n → ∞.
WEN-CHINGLIEN Advanced Calculus (I)
(ii)
The series
∞
P
k =1
fk is said to converge uniformly on E if and only if the sequence sn(x ) converges uniformly on E as n → ∞.
(iii)
The series
∞
P
k =1
fk is said to converge absolutely (pointwise) on E if and only if
∞
P
k =1
|fk(x )| converges for each x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
(ii)
The series
∞
P
k =1
fk is said to converge uniformly on E if and only if the sequence sn(x ) converges uniformly on E as n → ∞.
(iii)
The series
∞
P
k =1
fk is said to converge absolutely (pointwise) on E if and only if
∞
P
k =1
|fk(x )| converges for each x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
(ii)
The series
∞
P
k =1
fk is said to converge uniformly on E if and only if the sequence sn(x ) converges uniformly on E as n → ∞.
(iii)
The series
∞
P
k =1
fk is said to converge absolutely (pointwise) on E if and only if
∞
P
k =1
|fk(x )| converges for each x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
(ii)
The series
∞
P
k =1
fk is said to converge uniformly on E if and only if the sequence sn(x ) converges uniformly on E as n → ∞.
(iii)
The series
∞
P
k =1
fk is said to converge absolutely (pointwise) on E if and only if
∞
P
k =1
|fk(x )| converges for each x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
(ii)
The series
∞
P
k =1
fk is said to converge uniformly on E if and only if the sequence sn(x ) converges uniformly on E as n → ∞.
(iii)
The series
∞
P
k =1
fk is said to converge absolutely (pointwise) on E if and only if
∞
P
k =1
|fk(x )| converges for each x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR and let {fk} be a sequence of real functions defined on E.
(i)
Suppose that x0 ∈ E and that each fk is continuous at x0 ∈ E. If f =
∞
P
k =1
fk converges uniformly on E, then f is continuous at x0∈ E.
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR and let {fk} be a sequence of real functions defined on E.
(i)
Suppose that x0 ∈ E and that each fk is continuous at x0 ∈ E. If f =
∞
P
k =1
fk converges uniformly on E, then f is continuous at x0∈ E.
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR and let {fk} be a sequence of real functions defined on E.
(i)
Suppose that x0 ∈ E and that each fk is continuous at x0 ∈ E. If f =
∞
P
k =1
fk converges uniformly on E, then f is continuous at x0∈ E.
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR and let {fk} be a sequence of real functions defined on E.
(i)
Suppose that x0 ∈ E and that each fk is continuous at x0 ∈ E. If f =
∞
P
k =1
fk converges uniformly on E, then f is continuous at x0∈ E.
WEN-CHINGLIEN Advanced Calculus (I)
(ii)[Term-by-term integration]
Suppose that E = [a, b] and that each fk is integrable on [a,b]. If f =
∞
P
k =1
fk converges uniformly on [a,b], then f is integrable on [a,b] and
Z b a
∞
X
k =1
fk(x )dx =
∞
X
k =1
Z b a
fk(x )dx .
WEN-CHINGLIEN Advanced Calculus (I)
(ii)[Term-by-term integration]
Suppose that E = [a, b] and that each fk is integrable on [a,b]. If f =
∞
P
k =1
fk converges uniformly on [a,b], then f is integrable on [a,b] and
Z b a
∞
X
k =1
fk(x )dx =
∞
X
k =1
Z b a
fk(x )dx .
WEN-CHINGLIEN Advanced Calculus (I)
(ii)[Term-by-term integration]
Suppose that E = [a, b] and that each fk is integrable on [a,b]. If f =
∞
P
k =1
fk converges uniformly on [a,b], then f is integrable on [a,b] and
Z b a
∞
X
k =1
fk(x )dx =
∞
X
k =1
Z b a
fk(x )dx .
WEN-CHINGLIEN Advanced Calculus (I)
(iii)[Term-by-term differentation]
Suppose that E is bounded, open interval and that each fk
is differentiable on E. If
∞
P
k =1
fk converges at some x0 ∈ E, and
∞
P
k =1
fk0 converges uniformly on E, then f :=
∞
P
k =1
fk
converges uniformly on E, f is differentiable on E, and
∞
X
k =1
fk(x )
!0
=
∞
X
k =1
fk0(x )
for x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
(iii)[Term-by-term differentation]
Suppose that E is bounded, open interval and that each fk
is differentiable on E. If
∞
P
k =1
fk converges at some x0 ∈ E, and
∞
P
k =1
fk0 converges uniformly on E, then f :=
∞
P
k =1
fk
converges uniformly on E, f is differentiable on E, and
∞
X
k =1
fk(x )
!0
=
∞
X
k =1
fk0(x )
for x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
(iii)[Term-by-term differentation]
Suppose that E is bounded, open interval and that each fk
is differentiable on E. If
∞
P
k =1
fk converges at some x0 ∈ E, and
∞
P
k =1
fk0 converges uniformly on E, then f :=
∞
P
k =1
fk
converges uniformly on E, f is differentiable on E, and
∞
X
k =1
fk(x )
!0
=
∞
X
k =1
fk0(x )
for x ∈ E .
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR, let fk :E → R, k ∈N, and let Mk ≥ 0 satisfy
∞
P
k =1
Mk < ∞. If |fk(x )| ≤ Mk for k ∈N and x ∈ E , then
∞
P
k =1
fk converges absolutely and uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR, let fk :E → R, k ∈N, and let Mk ≥ 0 satisfy
∞
P
k =1
Mk < ∞. If |fk(x )| ≤ Mk for k ∈N and x ∈ E , then
∞
P
k =1
fk converges absolutely and uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR and suppose that fk,gk :E → R, k ∈N. If
n
X
k =1
fk(x )
≤ M < ∞
for n ∈N and x ∈ E , and if gk ↓ 0 uniformly on E as k → ∞, then
∞
P
k =1
fkgk converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
Let E be a nonempty subset ofR and suppose that fk,gk :E → R, k ∈N. If
n
X
k =1
fk(x )
≤ M < ∞
for n ∈N and x ∈ E , and if gk ↓ 0 uniformly on E as k → ∞, then
∞
P
k =1
fkgk converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
A double series is convergent if and only if
∞
X
j=1
akj converges for each k ∈N
and
∞
X
k =1
∞
X
j=1
akj := lim
N→∞
N
X
k =1
∞
X
j=1
akj
exists and is finite.
WEN-CHINGLIEN Advanced Calculus (I)
A double series is convergent if and only if
∞
X
j=1
akj converges for each k ∈N
and
∞
X
k =1
∞
X
j=1
akj := lim
N→∞
N
X
k =1
∞
X
j=1
akj
exists and is finite.
WEN-CHINGLIEN Advanced Calculus (I)
A double series is convergent if and only if
∞
X
j=1
akj converges for each k ∈N
and
∞
X
k =1
∞
X
j=1
akj := lim
N→∞
N
X
k =1
∞
X
j=1
akj
exists and is finite.
WEN-CHINGLIEN Advanced Calculus (I)
Let akj ∈ R for k , j ∈ N and suppose that
Aj =
∞
X
k =1
|akj| < ∞
for each j ∈N. If
∞
P
j=1
converges (i.e., the double sum converges absolutely), then
∞
X
k =1
∞
X
j=1
akj =
∞
X
j=1
∞
X
k =1
akj.
WEN-CHINGLIEN Advanced Calculus (I)
Let akj ∈ R for k , j ∈ N and suppose that
Aj =
∞
X
k =1
|akj| < ∞
for each j ∈N. If
∞
P
j=1
converges (i.e., the double sum converges absolutely), then
∞
X
k =1
∞
X
j=1
akj =
∞
X
j=1
∞
X
k =1
akj.
WEN-CHINGLIEN Advanced Calculus (I)
Proof:
Let E = {0, 1,12,13, · · · }. For each j ∈N,define a function fj on E by
fj(0) =
∞
X
k =1
akj, fj
1 n
=
∞
X
k =1
akj, n ∈ N.
By hypothesis, fj(0) exists and by the definition of series convergence,
n→∞lim fj
1 n
=fj(0);
WEN-CHINGLIEN Advanced Calculus (I)
Proof:
Let E = {0, 1,12,13, · · · }. For each j ∈N, define a function fj on E by
fj(0) =
∞
X
k =1
akj, fj
1 n
=
∞
X
k =1
akj, n ∈ N.
By hypothesis, fj(0) exists and by the definition of series convergence,
n→∞lim fj
1 n
=fj(0);
WEN-CHINGLIEN Advanced Calculus (I)
Proof:
Let E = {0, 1,12,13, · · · }. For each j ∈N,define a function fj on E by
fj(0) =
∞
X
k =1
akj, fj
1 n
=
∞
X
k =1
akj, n ∈ N.
By hypothesis,fj(0) exists and by the definition of series convergence,
n→∞lim fj
1 n
=fj(0);
WEN-CHINGLIEN Advanced Calculus (I)
Proof:
Let E = {0, 1,12,13, · · · }. For each j ∈N, define a function fj on E by
fj(0) =
∞
X
k =1
akj, fj
1 n
=
∞
X
k =1
akj, n ∈ N.
By hypothesis, fj(0) exists and by the definition of series convergence,
n→∞lim fj
1 n
=fj(0);
WEN-CHINGLIEN Advanced Calculus (I)
Proof:
Let E = {0, 1,12,13, · · · }. For each j ∈N, define a function fj on E by
fj(0) =
∞
X
k =1
akj, fj
1 n
=
∞
X
k =1
akj, n ∈ N.
By hypothesis,fj(0) exists and by the definition of series convergence,
n→∞lim fj
1 n
=fj(0);
WEN-CHINGLIEN Advanced Calculus (I)
Proof:
Let E = {0, 1,12,13, · · · }. For each j ∈N, define a function fj on E by
fj(0) =
∞
X
k =1
akj, fj
1 n
=
∞
X
k =1
akj, n ∈ N.
By hypothesis, fj(0) exists and by the definition of series convergence,
n→∞lim fj
1 n
=fj(0);
WEN-CHINGLIEN Advanced Calculus (I)
i.e., fj is continuous at 0 ∈ E for each j ∈
since |fj(x )| ≤ Aj for all x ∈ E and j ∈N, The Weierstrass M-Test implies that
f (x ) :=
∞
X
j=1
fj(x )
converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
i.e., fj is continuous at 0 ∈ E for each j ∈ Moreover, since |fj(x )| ≤ Aj for all x ∈ E and j ∈N,The Weierstrass M-Test implies that
f (x ) :=
∞
X
j=1
fj(x )
converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
i.e., fj is continuous at 0 ∈ E for each j ∈
since |fj(x )| ≤ Aj for all x ∈ E and j ∈N, The Weierstrass M-Test implies that
f (x ) :=
∞
X
j=1
fj(x )
converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
i.e., fj is continuous at 0 ∈ E for each j ∈
since |fj(x )| ≤ Aj for all x ∈ E and j ∈N,The Weierstrass M-Test implies that
f (x ) :=
∞
X
j=1
fj(x )
converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
i.e., fj is continuous at 0 ∈ E for each j ∈
since |fj(x )| ≤ Aj for all x ∈ E and j ∈N, The Weierstrass M-Test implies that
f (x ) :=
∞
X
j=1
fj(x )
converges uniformly on E.
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
from the sequential characteristization of continuity (Theorem 3.21) that f (1
n) →f (0) as n → ∞. Therefore,
∞
P
k =1
∞
P
j=1
akj = lim
n→∞
n
P
k =1
∞
P
j=1
akj
= lim
n→∞
∞
P
j=1 n
P
k =1
akj
= lim
n→∞
∞
P
j=1
fj
1 n
=f (0) =
∞
P
j=1
∞
P
k =1
akj.2
WEN-CHINGLIEN Advanced Calculus (I)
Thank you.
WEN-CHINGLIEN Advanced Calculus (I)