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Definition 1. An m × 1 random vector X is said to have an elliptical distribution with parameter µ (m × 1) and V (m × m) if its density function has the form:

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2. Preliminary Results

First we introduce the definition of elliptical distribution, which we will use to develop our methods in the sequent.

Definition 1. An m × 1 random vector X is said to have an elliptical distribution with parameter µ (m × 1) and V (m × m) if its density function has the form:

c m (det V ) 1/2 h ¡

(x − µ) ´ V −1 (x − µ) ¢

for some function h, where c m is a normalizing constant, and V is positive definite.

To achieve our goal, first we need to study the asymptotic distribution of r. The following Theorems 2 and 3 are the well-known results for this, which can be found, for example, in Muirhead (1982), section 5.1.

Theorem 2. Let r be the correlation coefficient formed from a sample of size n from a bivariate elliptical distribution with correlation coefficient ρ and kurtosis parameter κ. Then the asymptotic distribution, as n → ∞, of √

n − 1 1−ρ r−ρ

2

is N(0, 1 + κ) .

Theorem 2 states that r is asymptotically normal as n → ∞. A more accurate result can be obtained by considering z = tanh −1 r = 1 2 log 1+r 1−r . Fisher (1921) showed that the distribution of z converges to the normal distribution much faster than r itself.

Theorem 3. Let r be the correlation coefficient formed from a sample of size n, n > 1, from a bivariate elliptical distribution with correlation coefficient ρ and kurtosis parameter κ. Define z=tanh −1 r= 1 2 log 1+r 1−r and ξ=tanh −1 ρ= 1 2 log 1+ρ 1−ρ . Then, as n → ∞, the asymptotic distribution of √

n − 1 (z − ξ) is N (0, 1 + κ) .

Proof. We use the fact that if {X n } is a sequence of random variables such that √

n − 1 (X n − µ) → N (0, σ 2 ) in distribution as n → ∞, and if f (x) is a function which is differentiable at x = µ, then √

n − 1 {f (X n ) − f (µ)} → N ¡

0, f ´ (µ) 2 σ 2 ¢

in distribution as n → ∞ ; see, e.g., Bichel

and Doksum (1977), p.461. Let f (x) = 1 2 log 1+x 1−x . Note that f ´ (x) 2 (1 − x 2 ) 2 = 1. According

to Theorem 2,

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√ n − 1 (r − ρ) → N ³

0, (1 + κ) ¡

1 − ρ 2 ¢ 2 ´

as n → ∞, and hence

√ n − 1 {f (r) − f (ρ)} → N ³

0, f ´ (ρ) 2 (1 + κ) ¡

1 − ρ 2 ¢ 2 ´

as n → ∞,

namely

√ n − 1 (z − ξ) → N (0, (1 + κ)) as n → ∞

¤

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