Link Budget
PROF. MICHAEL TSAI
2011/9/22
What is link budget?
•
Accounting all losses and gains from the transmitter, the medium, to the receiver.
• Therefore the word “budget”.
•
Generally,
− =
.
•
There is a minimum required
,
associated with the minimum required “service quality”.
•
How much you can spend on the channel loss?
• Range
•
How much transmission power do you need?
• Energy
•
How much sensitivity do you need?
• Cost
GainLoss
Transmitter
N
SINGLE LINK
The link budget – a central concept
PTX
”POWER” [dB]
L f ,TX Ga ,TX
Noise reference level
Antenna Propagation gain loss Transmit Feeder
Lp
Antenna Noise
Receiver
Ga , RX L f , RX C
gain
Feeder Received
Required C/N at receiver
input This is a simple
version of the link budget.
CRITERION TO MEET:
dB in general
When we convert a measure X into decibel scale, we always divide by a reference value Xref:
Independent of the dimension of X (and
), this value is always dimension-
less.
The corresponding dB value is calculated as:
= 10 log |
|
Power
We usually measure power in Watt (W) and milliWatt [mW]
The corresponding dB notations are dB and dBm
Non-dB dB
Watt:
milliWatt:
RELATION:
= 10 log |
1| = 10 log
= 10 log |
1| = 10 log
= 10 log |
0.001| = 10 log
+ 30
=
+ 30
GSM base station TX: 40 W = 16 dBW or 46 dBm Vacuum cleaner: 1600 W = 32 dBW or 62 dBm
Example: Power
Sensitivity level of GSM RX: 6.3x10-14 W = -132 dBW or -102 dBm Bluetooth TX: 10 mW = -20 dBW or 10 dBm
GSM mobile TX: 1 W = 0 dBW or 30 dBm
Car engine: 100 kW = 50 dBW or 80 dBm
TV transmitter (Hörby, SVT2): 1000 kW ERP = 60 dBW or 90 dBm ERP Nuclear powerplant (Barsebäck): 1200 MW = 91 dBW or 121 dBm
ERP – Effective Radiated Power
Amplification and attenuation
(Power) Amplification:
The amplification is already
dimension-less and can be converted directly to dB:
(Power) Attenuation:
The attenuation is already
dimension-less and can be converted directly to dB:
Note: It doesn’t matter if the power
is in mW or W.
Same result!
! 1/#
= ! ⇒ ! =
=
# ⇒ # =
! = 10 log%&! #
= 10 log%&#
Example: Amplification and attenuation
30 dB
4 dB
10 dB 10 dB
Detector Ampl. Cable Ampl. Ampl.
A B
The total amplification of the (simplified) receiver chain (between A and B) is
G
A, B|
dB= 30 − 4 + 10 + 10 = 46
Noise sources
The noise situation in a receiver depends on several noise sources
Detector Noise picked up by the antenna
Analog circuits Thermal
noise
Output signal with requirement on quality
Wanted signal
Man-made noise
Copyright: IEEE
Receiver noise: Equivalent noise source
To simplify the situation, we replace all noise sources with a single equivalent noise source.
Detector
Output signal with requirement on quality
Wanted signal
C
Noise free N
Analog circuits Noise free
Same “input quality”, signal-to-noise ratio, C/N in the whole chain.
How do we determine N from the other
sources?
Receiver noise: Noise sources (1)
The power spectral density of a noise source is usually given in one of the following three ways:
1) Directly [W/Hz]:
2) Noise temperature [Kelvin]:
3) Noise factor [1]:
N
sT
sF
sThe relation between the tree is
N
s= kT
s= kF
sT
0where k is Boltzmann’s constant (1.38 ( 10)*+ W/Hz) and T0 is the, so called, room temperature of 290 K (17-).
This one is sometimes given i dB and
called noise figure.
Receiver noise: Noise sources (2)
Antenna example
Noise temperature of antenna 1600 K
Power spectral density of antenna noise is and its noise factor/noise figure is
.
/= 1600 / 290 = 5.52 = 7.42 dB
Noise free antenna
Na Model
0/ = 1.38 ( 10)*+ ( 1600 = 2.21 ( 10)*&3/45 = −196.6 783/45
System component Noise factor F
Model System
component Noise free
Receiver noise: System noise
Nsys
Due to a definition of noise factor (in this case) as the ratio of noise powers on the output versus on the input, when a resistor in room temperature (T0=290 K) generates the input noise, the PSD of the equivalent noise source (placed at the input) becomes
N
sys= k ( F − 1 ) T
0W/Hz
Equivalent noise temperature Don’t use dB value!
System 1 System 2
F1 F2
Receiver noise: Sev. noise sources (1)
A simple example Ta
1
N
a= kT
aN
1= k ( F − 1 ) T
0N
2= k ( F
2− 1 ) T
0Noise free
System 1
Noise
System 2
Noise
N2 Na N1
Receiver noise: Sev. noise sources (2)
After extraction of the noise sources from each component, we need to move them to one point.
When doing this, we must compensate for amplification and attenuation!
G Amplifier:
Attenuator:
1/L N
N
G
1/L
NG
N/L
The isotropic antenna
The isotropic antenna radiates equally in all directions
Radiation pattern is spherical
Elevation pattern
Azimuth pattern
This is a theoretical antenna that cannot
be built.
Azimuth pattern
λ
/ 2Feed
A dipole can be of any length, but the antenna patterns shown
are only for the λ/2-dipole. Antenna pattern of isotropic
antenna.
The dipole antenna
Elevation pattern
λ
/ 2 -dipoleThis antenna does not radiate straight up or down. Therefore, more energy is available in other directions.
THIS IS THE PRINCIPLE BEHIND WHAT IS CALLED ANTENNA GAIN.
Antenna gain (principle)
Antenna gain is a relative measure.
We will use the isotropic antenna as the reference.
Radiation pattern
Isotropic and dipole, with equal input power!
Isotropic, with increased input power.
The amount of increase in input power to the isotropic antenna, to
obtain the same maximum radiation is called the antenna gain!
Antenna gain of the λ/2 dipole is 2.15 dB.
A note on antenna gain
Sometimes the notation dBi is used for antenna gain (instead of dB).
The ”i” indicates that it is the gain relative to the isotropic antenna (which we will use in this course).
Another measure of antenna gain frequently encountered is dBd, which is relative to the λ/2 dipole.
G |
dBi= G |
dBd+ 2.15
Be careful! Sometimes it is not clear if the
antenna gain is given in dBi or dBd.
EIRP: Effective Isotropic Radiated Power
EIRP = Transmit power (fed to the antenna) + antenna gain
Answers the questions:
How much transmit power would we need to feed an isotropic antenna to obtain the same maximum on the radiated power?
How ”strong” is our radiation in the maximal direction of the antenna?
This is the more important one, since a limit on EIRP is a limit on the radiation in
the maximal direction.
9:;
= <=
!<=
GainLoss
GTX |dB PTX |dB
EIRP and the link budget
”POWER” [dB]
EIRP
9:;
= <=
!<=
Path loss
Distance, d
TX RX
Received power [log scale]
∝ 1/7*
∝ 1/7>
?= = <=!?=!<= @ 4B7
*
?= = <=!?=!<= @ 4B7C /D
* 7C /D 7
>
Fading margin
1. Fading channel loss is time-variant (stochastic process) 2. Sometimes received power could be smaller than desired
3. Add some extra transmission power to decrease that probability 4. The extra transmission power Fading margin
DETECTOR CHARACTERISTIC Quality OUT
Quality IN (C/N)
Required C/N – another central concept
DETECTOR Quality IN
(C/N) Quality OUT
The detector characteristic is different for different system design choices.
REQUIRED QUALITY OUT:
Audio SNR
Perceptive audio quality Bit-error rate
Packet-error rate etc.
Example:
Mobile radio system
•
Consider a mobile radio system at 900-MHz carrier frequency, and with 25-kHz bandwidth.
• It is affected only by thermal noise (temperature of the environment E = 300F).
• Antenna gains at the TX and RX sides are 8 dB and -2 dB, respectively.
• Losses in cables, combiners, etc. at the TX are 2 dB.
• The noise figure of the RX is 7 dB.
• The 3-dB bandwidth of the signal is 25 kHz.
• The required operating SNR is 18 dB and the desired range of coverage is 2 km.
• The breakpoint is at 10-m distance; beyond that point, the path loss exponent is 3.8.
• The fading margin is 10 dB.
•
What is the minimum TX Power?
•
Textbook p42 (example 3.2)
Noise and interference limited links
C
N
Distance Min C/N
Power
Max distance
C
N
Distance Power
Min C/I
I
Max distance
TX RX TX RX TX
NOISE LIMITED INTERFERENCE LIMITED
What is required distance between BSs?
Copyright: Ericsson