• 沒有找到結果。

H T Chapter4

N/A
N/A
Protected

Academic year: 2021

Share "H T Chapter4"

Copied!
36
0
0

加載中.... (立即查看全文)

全文

(1)

H

ODGE

T

HEOREM

We have seen in variations of geodesics and submanifolds that a geo- metric object with the minimizing property leads to strong constraint on the global geometry. However, it is in general difficult to find a minimiz- ing object due to the hard non-linear analysis involved. For geodesics we bypass the difficulty using the completeness assumption. For minimal sur- faces this is already subtle and will only be discussed in later chapters.

There is nevertheless a situation where the analysis involved is entirely within linear elliptic PDE and a satisfactory solution is achieved. This is Hodge’s theory of harmonic forms on a compact oriented Riemannian manifold (Mm, g): every cohomology class [w] 2 HdRp (M, R) admits a unique har- monic representative which is also the absolute minimizer of the energy func- tional E(w) = R

Mw^ ⇤wwithin the class. Indeed what Hodge proved is the famous decomposition theorem named after him

Ap(M) =Ker4?Im4 = Hp ?dAp 1?dAp+1

for the Laplace operator4 = dd+dd, where d = ( 1)mp+1dis the formal adjoint of d. The essential part is to show that the harmonic space Hp=Ker4is finite dimensional and consists of C p-forms.

Hodge developed his theory around 1930s. One has to go to Hilbert space completions (generalized functions) to start the discussion. Nowa- days a nice approach is to use Fourier transforms on L2spaces and Sobolev spaces Hs to encode the degree of differentiability. The key result is the regularity theorem called Garding’s inequality. Historically it was Hodge’s theorem which laid the foundation of general linear elliptic PDEs.

We present the details in this chapter. We also give applications of har- monic forms under the Bochner principle which describes the difference between 4 and the connection Laplacian trr2 in terms of the curvature tensor. This leads to strong topological constraint when Ric 0.

127

(2)

1. Hodge⇤operator

We need some preparation on inner product spaces in linear al- gebra. On an inner product space (V, h , i) with dimRV = m, we define the Hodge⇤operator on Lp(V)(the space of p-vectors)

: Lp(V) !Ln p(V)

as follows: for an O.N.B. e1, . . . , em 2V, we consider the “orthogonal complement”

e1^. . .^ep

7 !ep+1^. . .^em.

By taking into account the sign, for a =ei1^. . .^eip 2 Lp(V),⇤a 2 Ln p(V)is the wedge of complemented ej’s with

a^ ⇤a =e1^. . .^em.

For general a 2 Lp(V),⇤is then defined by linear extensions.

For general p-vectors a, b 2 Lp(V), a = Â|I|=paIei1 ^. . .^eip, b|J|=pbJej1^. . .^ejp,

a^ (⇤b) =

Â

|I|,|J|=p

aIbJ(ei1^. . .^eip)^ ⇤(ej1^. . .^ejp)

=ha, bie1^. . .^en

whereha, biis the induced inner product on Lp(V): in the notations in Exercise3.1, for Pv = P(v1. . . vp), Pw =P(w1. . . wp),

hv1^. . .^vm, w1^. . .^wmi:=hPv, Pwi =det(vtw).

Exercise 4.1. Show that⇤ is independent of the choices of orthonor- mal basis with the same orientation and⇤2 = ( 1)p(n p).

For a general oriented Riemannian manifold (Mm, g), we define Hodge ⇤ operator: Ap(M) ! Am p(M) by applying the above definition on each TpM.

Exercise 4.2. Let w = f dx1^. . .^dxp in a chart (U, x). Give the explicit formula of⇤wusing the metric tensor gij.

(3)

In order to make use of the exterior algebra and ⇤ operator in its full strength, we recall that vector fields are associated with their corresponding 1-forms by the “Riesz representations”:

TpM // TpM v // ˜v : w 7! hv, wi,

˜f oo f2 TpM.

It is also customary to write ˜v as v[ since it is a one form vi = gijvj and ˜f as f#since it is a vector field fi =gijfj.

The advantage to consider forms rather than vector fields is that we may add or wedge forms in a transparent manner.

For example, in the Euclidean space M = R3, gij = dij, a vector field F =P∂x +Q∂y +R∂z has ˜F= P dx+Q dy+R dz and

rfgrad f =d f ,f div F= ⇤d˜F, curl F=⇤gd ˜F.

Thus we can put everything we need in vector calculus in the frame- work of differential forms. Moreover, the above intrinsic (coordinate- free) expressions extend the definitions of rf , div F and curl F to arbitrary Riemannian manifolds(M, g).

Exercise 4.3. Let(M, g)be a Riemannian manifold, w be its volume form.

(1) For f 2 C(M), find the expression for rf in local coordi- nates(U, x).

(2) For X 2 C(TM), show that (divX)w = LX(w). Deduce the expression for divX in local coordinate(U, x)from it.

Exercise 4.4. Let(M, g)be a Riemannian manifold, f 2 C(M), we define the Laplace–Beltrami operator DLB acting on C(M)by

4LBf =divrf

(4)

Show that in local coordinate(U, x), 4LBf = p1g∂xj

✓pggijf

∂xi

◆ ,

where g = det(gij). Deduce that the highest order term of 4LB is just the usual Laplacian and the lower order term vanishes at x =0 if we take normal coordinate.

Particularly, this shows that 4LB is the usual Laplacian when (M, g) is the standard Euclidean space. In the next section, we will generalize Laplacian to differential forms by Hodge Laplacian.

Example 4.1. The Maxwell equations describing the electric field E = (E1, E2, E3)and the magnetic field B= (B1, B2, B3)read as

curl E = 1 c

∂B

∂t, (4.1)

div B =0, (4.2)

div E =4pr, (4.3)

curl B = 1 c

∂E

∂t +4p c ~j, (4.4)

where r is the charge density and~j is the current density.

Consider the Minkowski space(-time) R3,1 with x0 = ct and de- fine the energy–momentum tensor by the two form

F=

Â

Fijdxi^dxj

:=

Â

3 i=1

Eidxi^dx0+B1dx2^dx3+B2dx3^dx1+B3dx1^dx2. Or in matrix form:

(Fij) = 0 BB B@

0 E1 E2 E3

E1 0 B3 B2

E2 B3 0 B1 E3 B2 B1 0

1 CC CA.

Then we check easily that (4.1) and (4.2) are equivalent to dF=0,

(5)

while (4.3) and (4.4) are equivalent to

dF= 4p c ˜j.

Here j = (cr,~j)is the density vector. The two equations can be fur- ther simplified to one equation using concepts in the next section.

Exercise 4.5. Carry out the details in Example4.1.

2. Harmonic forms

Given a closed (i.e. compact without boundary) oriented mani- fold Mm with a Riemannian metric g, we define an inner product on the space Ap(M)of smooth p-form on M by

(a, b) := Z

Mha, bidV = Z

Ma^ ⇤b,

where⇤ : Lp !Lm pis the Hodge⇤operator with⇤2 = ( 1)(m p)p. Given a cohomology class[a] 2 HdRp (M), a closed p-form a0 rep- resents [a] if and only if a0 = a+db for some b 2 Ap 1(M). An important observation made by Hodge is that we can obtain a canon- ical representation of the class[a]by requiring the normka+dbkto be minimal.

Let d be the formal adjoint1of d : Ap(M) ! Ap+1(M). Namely (a, db) := (da, b) =

Z

Mda^ ⇤b

= Z

Md(a^ ⇤b) ( 1)pa^d(⇤b)

= ( 1)mp+1 Z

Ma^ ⇤(⇤db). Since this holds for all a, we get

d = ( 1)mp+1d: Ap+1(M)! Ap(M).

1So far(Ap(M),(,))is only a pre-Hilbert space. We call dthe formal adjoint of d to distinguish with the adjoint of a linear operator on Hilbert spaces

(6)

Definition 4.2. Let (Mm, g) be a Riemannian manifold, compact or not, the formal adjoint of d is defined by d := ( 1)mp+m+1don Ap(M).

Exercise 4.6. Give the formula of din local coordinates.

We will consider only compact manifolds in this chapter unless specified otherwise. Let a be a closed p-form which has ”minimal norm” in[a]2 HdRp (M). Then for any t 2 R, b 2 Ap 1(M),

(a+tdb, a+tdb)

= (a, a) +2(a, db)t+ (db, db)t2

 (a, a) This happens if and only if that

0 = (a, db) = (da, b), 8b2 Ap 1(M) which is equivalent to da =0. The discussion implies that

Lemma 4.3. A closed C p-form a has minimal normkakin its de Rham cohomology class if and only if that da =0. It is unique if it exists.

Definition 4.4. The Laplace operator on Ap(M) (or called the Hodge Laplacian) is defined by

4 = (d+d)2 =dd+dd : Ap(M) ! Ap(M). We call a2 Ap(M)is a harmonic form if4a=0.

Lemma 4.5. For a compact Riemannian manifold(M, g), 4a = 0 if and only if da=0 and da =0.

This follows easily from

(4a, a) = (dda+dda, a) = (da, da) + (da, da).

(7)

Thus, instead of looking for closed forms with minimal norm2, Hodge’s observation is to look for the harmonic representative of the cohomology class[a]2 HdRp (M).

First of all, the operator4is self-adjoint, i.e.(4a, b) = (a,4b) or 4 = 4. Furthermore, the truly crucial property is that 4 is elliptic—a notion to be explained soon. It turns out that we may and should pose more general questions:

(1) When is the equation4a = bsolvable?

(2) How to solve it if it is solvable?

The answer is provided by Hodge decomposition theorem whose pre- cise form is given in the next section. Let H = {a | 4a = 0} be the space of harmonic forms. Then Hodge decomposition theorem asserts that Da= bis solvable if and only if b2 H?, the orthogonal complement of harmonic forms.

The “only if part” is easy. For any g2 H,

(b, g) = (4a, g) = (a,4g) =0=) b2 H?.

For example, since M is compact, the only harmonic functions are constants. Let b 2 A0(M) (a function). If Da = b is solvable, then b2H? =R?, i.e. R

MbdV =0.

The “if part” is non-trivial even for p = 0. The proof requires a, by now standard, formalism in functional analysis. Here we give a sketch of it and leave the details to the next section.

Let L : H ! H be a continuous (i.e. with bounded norm kLk) linear operator on a pre-Hilbert space H with adjoint operator L. Consider the equation Lw=b. For any f 2 H,

(w, Lf) = (Lw, f) = (b, f).

Thus any solution w defines a linear functional`such that (4.5) `(Lf) = (b, f) 8f2 H.

2This amounts to prove that a minimizing sequence aihas a smooth limit after passing to a subsequence, known as the direct method of calculus of variations.

However in practice it relies on technical estimates on various norms which are eventually equivalent to proving the regularity theorem in the related PDE.

(8)

If we know that ` is bounded, which is the hard part and requires that b 2 H? in the case we want to apply to, then the domain of definition of` can be extended from Im L toH, while keeping the same normk`k, by the Hahn–Banach theorem.

Definition 4.6. A bounded linear functional`onHsatisfying (4.5) is called a weak solution to Lw= b.

IfHis furthermore a Hilbert space (i.e. complete), then by Riesz representation theorem, such an`comes from some a 2 Hwith

`(Lf) = (a, Lf) = (La, f).

Hence(La b, f) = 0 for all f 2 Hand then La= b. However, the space of C forms Ap(M) is never complete and one must pass to certain completion to apply the above formalism. As a result, the so- lution a is a priorily only a certain L2form and we need a “regularity theorem” to conclude that a is indeed a C form.

3. Elliptic operators and Hodge decomposition Consider the following typical situation:

E

✏✏

a C vector bundle of rank r,

Mm

f : a section

[[

a C manifold,

and H = C(M, E)be the vector space of all C sections. E.g. E = Lp(TM), r=Cmp, andH = Ap(M).

Definition 4.7. A R-linear map L : C(M, E) ! C(M, E)is a linear differential operator of order d 2 N if under any local trivialization U ⇢ Rm, E|U ⇠=U⇥Rr, C(U, E U) ⇠=C(U)r, L is represented by a differnetial operator of order d:

L : C(U)r !C(U)r. That is, under the multi-index notations,

L f =

Â

|a|d

Aa(x)Daf , x2 U,

(9)

where f = (f1, . . . , fr)t and Aa 2 Mrr(C(U)). Write

L=

Â

|a|=d

Aa(x)Da+

Â

|a|<d

Aa(x)Da with non-trivial top order term Ld :=Â|a|=dAaDa 6⌘0.

For x = (x1, . . . , xm)t 2 Rm, we define the polynomial in xi’s by pL(x, x) :=

Â

a

Aa(x)xa

called the symbol of L over E|U. In general it depends on the trivial- ization and is not globally defined. Nevertheless we have

Exercise 4.7. Show that the top order term sL(x, x) := pLd(x, x)

forms a tensor sL 2 C(Symd(TM)⌦End E), called the principal symbol of L.

Definition 4.8. Let L be a differential operator of order d on E !M.

(1) L is elliptic over an open subset U⇢ M if sL(x, x)2 End E

is invertible for all x 2U and x 2 TxM\ {0}.

(2) Suppose that E ! M is equipped with a C bundle metric.

Then L is uniform elliptic over a subset S ⇢ M if

|sL(x, x)v| C|x|d|v|, 8 x2 S, x 6=0, for some C independent of x 2S.

In particular, ellipticity on U implies uniform ellipticity over any compact subsets S ⇢U.

Remark 4.9. In a similar manner we define differential operators L : C(E) ! C(F) of order d between vector bundles over M. The principal symbol is a section sL 2 C(Symd(TM)⌦Hom(E, F)) and L is elliptic if sL(x, x)is invertible for all x 2 M, x 2 TM\ {0}. In particular rk E = rk F. But E and F need not be isomorphic. For our current purpose it is enough to consider the case E =F.

(10)

Exercise 4.8. Show that s4(x, x) = |x|2Id for the Hodge Laplacian 4on Ap(M), hence it is uniformly elliptic on M.

Now we state two fundamental results in elliptic PDE.

Let Lw = bbe a linear elliptic PDE on E ! M over a compact manifold M. In order to apply the Hilbert space formalism we as- sume that(M, g)is Riemannian and E has a bundle metric h. If E is a complex vector bundle we require that the metric h is hermitian.

Denote by L : H ! H with H = C(E). His a pre-Hilbert space under(f , g):=R

Mh(f , g)dV. Denotekfk = (f , f)1/2. Then

Theorem 4.10 (Regularity theorem). Any weak solution of Lw = bis automatically smooth.

Theorem 4.11 (Compactness theorem). For a sequence an 2 H, if kank  C and kLank  C are both bounded, then {an} has a Cauchy subsequence.

Remark 4.12. We will show later that both theorems are consequences of the G˚arding inequality: for f 2 H,

kfks+dC(kL fks+kfks),

where d is the order of L, and the norms are Sobolev norms to be defined and studied in section 5.

Now we return to the case L=D,H = Ap = Ap(M). By assum- ing the above two PDE theorems, we prove

Theorem 4.13 (Hodge decomposition theorem). Let H = Hp := {a 2 Ap(M)| 4a =0}be the space of harmonic p-forms.

(1) dim H <•, and

(2) Ap =H ?4Ap. That is, Im4 =H?. PROOF. (1) If dim H =•, we select

u1, u2, . . .2 H, kuik =1, ui ?uj 8i6= j

satisfying Dui = 0. It is clear that{ui} has no Cauchy subsequence hence contradicts to the compactness theorem (Theorem4.11). Thus

(11)

l :=dim H <• and H ⇢ His a closed subspace. In particular H? is also a closed subspace and Ap =H H?. Indeed, pick an O.N.B.

{w1, w2, . . . , wl}of H. For any a2 Ap, a =b+

Â

l i=1

(a, wi)wi =: b+H(a) where b 2H?and H(a)is the harmonic projection of a.

(2) We need to show H? =4Ap. The direction “ ” is clear:

(4a, g) = (a,4g) =0 8g 2H. For the other direction we need the following

Claim 4.14. There exists c >0 such thatkbk  ck4bkfor all b2 H?. Let a2 H?and we define a linear functional`on Im4by

`(4f) := (a, f).

It is well defined: if4f1 =4fthen f1 f 2 Hand then (a, f1) = (a, f). Also ` is a bounded linear functional on Im4: let b = f H(f)2 H?, then

k`(4f)k = k`(4b)k = k(a, b)k  kak · kbk

ckak · k4bk = (ckak) · k4fk.

By Hahn–Banach theorem, ` can be extended to a bounded linear function onH = Ap. That is,`is a weak solution to4w =a.

By the regularity theorem (Theorem4.10), there exists a smooth w 2 Ap such that4w=a. So H? ⇢ 4Apfollows. ⇤ PROOF OF CLAIM 4.14. Suppose the contrary, then there exists a sequence bj 2H?withkbjk = 1 andk4bjk !0.

By the compactness theorem (Theorem 4.11), we may assume that{bj}is itself a Cauchy sequence. For y2 Ap, define

`(y) := lim

j!(bj, y).

The linear functional`is clearly bounded: k`k 1, and

`(4y) = lim

j!(bj,4y) = lim

j!(4bj, y) =0

(12)

by Cauchy’s inequality, i.e.`is a weak solution of4b =0.

By the regularity theorem (Theorem4.10), there exists a b 2 Ap such that`(y) = (b, y)and4b=0, i.e. b2 H.

Then (bj, y) ! (b, y) and in particular 0 = (bj, b) ! kbk2 and thus b =0. On the other hand, the Cauchy sequence{bj} has limit bimplies thatkbk = limj!kbjk =1, which is a contradiction. ⇤

The proof actually applies to more general cases:

Exercise 4.9. Extend the Hodge decomposition for any elliptic op- erator L : C(E) ! C(F) between two vector bundles E, F over a compact M. (Assuming regalarity and compactness theorems.)

For the Hodge Laplacian4, a lot more can be said.

Definition 4.15. Since Ap =H (4Ap), we define the Green operator

G := 8<

:

0 on H,

D 1 on H?. i.e. I =H+DG,

where H : Ap !His the harmonic projection. Hence Ga is the unique solution in H?for Dw =a H(a).

Recall that a bounded linear operator is compact if the image of any bounded subset has compact closure.

Exercise 4.10. Show that

(1) G commutes with any operator T with T4 = 4T.

(2) G is a bounded, self-adjoint, compact operator.

Notice that from4 = dd+dd we see immediately that d4 = ddd =4d and d4 =ddd =4d. Hence

[d, G] = [d, G] = [D, G] =0.

The Hodge decomposition can be refined to Ap =H Im4 =H Im d Im d,

which is still an orthogonal decomposition. A precise formula could be given in terms of the Green operator G. Indeed we can rewrite

(13)

the identity I = H+DG as

a = H(a) + (dd+dd)Ga

= H(a) +d(dGa) +d(dGa). In particular we have:

Proposition 4.16. If da=0 then a= H(a) +d(dGa).

Therefore, the harmonic representation of a cohomology class is unique: if a1 a2 =db then H(a1) H(a2) = H(db) =0.

Here is another simple yet important application of the Hodge decomposition theorem:

Theorem 4.17 (Poincar´e duality). Let M be a Ccompact oriented man- ifold of dimension m. Then the natural pairing

HdRp (M)⌦HdRm p(M) ! HmdR(M) ⇠=R : (w, h)7!

Z

Mw^h, is a perfect pairing. In particular,

HdRp (M) ⇠= HdRm p(M).

PROOF. Let g be a metric on M. It suffices to prove the theorem using harmonic representatives of de Rham cohomology.

Since⇤4 = 4⇤, we see that⇤ : Hp ! Hm p which maps har- monic forms to harmonic forms. From⇤2= ( 1)p(n p) we conclude that⇤ : Hp ⇠=Hn p. This isomorphism depends on g and is not the natural one stated in the theorem.

Nevertheless it shows that Hn is spanned by⇤1=dVgand hence HdRm (M) ⇠= R under[W] 7! R

MW (the trace map). Moreover, it also implies that the natural pairing is perfect by noticing that

(w,w)7!

Z

Mw^ ⇤w =kwk2 6=0

if[w]6=0. This completes the proof. ⇤

Exercise 4.11. (1) Let M = Rm/L where L ⇢ Rm is a lattice gen- erated by m linearly independent vectors. Let g be the flat metric induced from Rm. Determine Hp(M) and show that the wedge of harmonic forms is still harmonic.

(14)

(2) Give an example(M, g)and two harmonic forms w, h so that w^h is not harmonic.

4. Bochner Principle

Given any C manifold M, letrbe an affine connection on TM.

We denote the induced connection on TM andVpTM again byr. For w 2 Ap(M),rw(X0, X1, . . . , Xp) 2 Ap(M)⌦A1(M)is given by

(rw)(X0, . . . , Xp) = (rX0w)(X1, . . . , Xp). We define the anti-symmetrization(rw)alt 2 Ap+1(M)by

(rw)alt(X0, . . . , Xp) =

Â

p j=0

( 1)j(rXjw)(X0, . . . , cXj, . . . , Xp).

Exercise 4.12. Show that ris torsion-free if and only if (rw)alt = dw.

Now, we assumeris the Levi-Civita connection on(M, g). Definition 4.18. For X, Y 2 C(TM), we define r2X,Y acting on any tensor fields T by

r2X,YT =rXrYT rrXYT.

The connection Laplace acting on any tensor fields T is defined by the trace tr(r2T)with respect to g.

Exercise 4.13. For f 2 C(M), show that 4LBf = tr(r2f), where 4LBis the Laplace–Beltrami operator. Also, we have4 = 4LB.

In general,4and trr2are related by

Proposition 4.19 (Bochner formula). Let M be compact.

4 = trr2

Â

i,j

hi^iejR(ei, ej),

where{ej}is an orthonormal local frame of TM,{hi}is its dual frame.

(15)

In the literature this is also known as the Bochner–Lichnerwicz–

Witezenb¨ock formula.3.

Exercise 4.14. With the notations in proposition4.19, for w 2 Ap(M), prove that

(4.6) dw =

Â

n i=1

hi^ reiw; dw =

Â

n i=1

ieireiw.

Exercise 4.15. (1) Prove the Bochner formula4.19using (4.6).

(2) Denote byr the formal adjoint ofr, show that

rr = trr2.

Hence, another common form of Bochner formula is given by 4 = rr

Â

i,j

hi^iejR(ei, ej).

Now, following Bochner, we use Proposition 4.19 to derive the topological constraints given by the Ricci curvature conditions.

Corollary 4.20 (Bochner). Let(M, g)be a closed Riemannian manifold.

(1) If Ric>0 then b1 =h1(M) =0. More precisely,

(2) If Ric 0 then h1(M)  m=dim(M). If furthermore Ric>0 at some point, then h1(M) = 0. The equality holds if and only if M is a flat torus, i.e. M ⇠=Rn/G where G⇠=Zn is a lattice.

PROOF. Before proving the statements, we first prove an identity also due to Bochner.

3In general, an identity expressing difference between two second–order el- liptic operator with the same principle symbols in terms of curvatures is known as Weitzenb¨ock formula or Bochner formula. Such formula was first indicated by Witzenb¨ock in 1925, yet it was Bochner who first used the formula to relate topol- ogy and curvature estimates on compact manifolds (cf. Corollary 4.20) in 1948.

There are many variants for formula of such type in different contexts. For in- stance, in 1963, Lichnerwicz developed an analogous formula for Dirac operators on spin bundles, which we will discuss in later chapter.

(16)

Claim 4.21. For any q 2 A1(M),

h4q, qi = 124|q|2+|rq|2+Ric(˜q, ˜q), where ˜q2 C(TM)is the metric dual of q (cf. section 1).

Given p 2 M, assume that {hi}mi=1 is the dual frame of a local orthonormal frame{ei}mi=1of TM around p. We write qmi=1aihi.

Since{ei}is an orthonormal frame, g(ei, ej) = dijand hencereiei = 0. The connection Laplace of q is then given by

trr2q =

Â

m

i=1r2ei,eiq =

Â

m

i=1reireiq.

Therefore, from Proposition4.19we deduce h4q, qi =

Â

i hreireiq, qi

| {z }

(I)

h

Â

i,j

hi^iejR(ei, ej)q, qi

| {z }

(II)

.

By direct calculation, (I) =

Â

i

eihreiq, qi |reiq|2 = 1

24|q|2 |rq|2, and

(II) =

Â

i,j

(R(ei, ej)q)(ej)hhi, qi

Notice that for X, Y, Z 2 C(M), w 2 A1(M), a direct computa- tion shows(R(X, Y)w)(Z) = w(R(X, Y)Z). Therefore,

(II) =

Â

i,j

q(R(ei, ej)ej)hhi, qi

=

Â

i,j,k,l

akaihRljijel, eki =

Â

i,j,k

akaiRkjij

= Ric(

Â

k

akek,

Â

i

aiei) = Ric(˜q, ˜q). As a result, we have proved:

h4q, qi = 124|q|2+|rq|2+Ric(˜q, ˜q).

We now prove (1) and (2) by contradiction. If h1(M) 6= 0, we take a non-zero cohomology class[q] 2 HdR1 (M). By Hodge decomposition

(17)

(cf. 4.13), we choose q 6= 0 to be the harmonic 1-form representing [q]6= 0.

For (1), if Ric > 0, choose p 2 M such that |q(p)| > 0 achieves maximal. Then(4|q|2)(p) 0 by second derivative test. However, this contradicts to Ric(˜q, ˜q) > 0.

For (2), if Ric 0 , by taking integration on both sides of4.21, 0= 1

2 Z

M4|q|2+ Z

M|rq|2+ Z

MRic(˜q, ˜q). By Stokes’ theorem, since ∂M =∆, we have

0= Z

M|rq|2+ Z

MRic(˜q, ˜q).

Since Ric 0, we must conclude that rq0, i.e. q is parallel and is determined by qq 2 TqM,8q 2 M. Hence h1dim Tq(M) = m.

Also,rq0 and Ric 0 in turn implies Ric(˜q, ˜q) ⌘0. Now, if Ric>

0 at one point p and q6= 0, we have Ric(˜q, ˜q) >0, a contradiction.

On the other hand, if the equality holds, h1 = dim M = m, then the universal cover ˜M ! M has m parallel 1-forms. Therefore it has m parallel vector fields. We conclude that ˜M ⇠=Rm. ⇤

5. Fourier Transform and Sobolev Spaces

Let us first introduce some standard notations.

(1) x= (x1, . . . , xm) 2Rm.

(2) x·y= x1y1+x2y2+· · · +xmym,|x| = (x·x)1/2.

(3) a= (a1, . . . , am)multi-index, ai 2N[ {0}, |a| = Âmi=1ai. (4) xa =xa11x2a2· · ·xamm.

(5) ∂a = ∂xa1|a|

1 ···∂xamm , Da = ( i)|a|a.

To prove the regularity theorem and compactness theorem (cf.

theorem4.10,4.11), we need to define the concept of Sobolev space. To achieve this, we first need the some rudiments in Fourier analysis.

Definition 4.22 (Fourier transdorm). For x 2 Rm, x 2 Rm, let f 2 C0(Rm, C)be a smooth function with compact support. The Fourier

(18)

transform of f is defined as ˆf(x) = (2p) m/2

Z

Rme ix·xf(x)dx.

Also, recall the convolution of two functions f ⇤g :=

Z

Rm f(x y)g(y) dy= Z

Rm f(z)g(x z)dz.

It is a standard trick to use convolution to construct smooth ap- proximation of functions with inferior smothness. Let f 2 C0(Rm) withR

Rm f =1, f 0, f(0) 6=0. Such a function is sometimes called a molifier. The existence of molifiers is evident from our construc- tion on bump functions in chapter 1. For u 2 R+, define fu(x) :=

u1mf⇣

xu

⌘.We can see that R

Rm fu = 1. Such a sequence fu is called a

“d-function”, and we can write it as d0= lim

u!0fu.

Proposition 4.23. For g2 C0, fug(x)! g(x)as u!0+is a smooth approximation of identity4.

Exercise 4.16.

(1) Prove the above proposition.

(2) Show that C0 (Rm) is dense in L2(Rm) (with respect to L2- norm).

Thus, we may extend the definition Fourier transform ˆf to f 2 L2(Rm) by continuity. That is, we define ˆf = limk! bfk, where fk 2 C0(Rm) and fk ! f in L2(Rm). Recall that we also have inverse Fourier transform.

Definition 4.24 (Inverse Fourier Transform). For g(x) 2 C0(Rm), the inverse Fourier transform ˇg(x)is defined as5

ˇg(x):= (2p) m/2 Z

Rmeix·xg(x)dx.

4That is, d0=limu!0fuis the identity element for

5There are several conventions for Fourier transform and its inversion. An- other common convention is that ˆf(x) = R

Rm f(x)e ix·xdx while the inversion is given by ˇg(x):= (2p) mR

Rmg(x)eix·xdx.

(19)

Similarly, we can define ˇg for g 2 L2(Rm) by continuity argu- ments. We list the basic properties and correspondence with con- volutions in the following theorem and refer the proof to [Gil95], Chapter 1.1.

Theorem 4.25 (Basic Properties of Fourier Transform). For f 2 C0(Rm), we have

(1) ˇˆf= f .

(2) Dxa ˆf(x) = \xaf(x),D\axf(x) =xa ˆf(x). (3) [fg= ˆfˆg, ˆf⇤ ˆg = fd·g.

Moreover, Fourier Transform on L2(Rm)is an isometry onto itself6, i.e.

L2(Rm) ˆ· // L2(Rm)

ˇ·

oo .

From the formula dDxaf =xa ˆf, we notice that derivatives of f will corresponds multiplications of ˆf in the frequency (phase) space. This formula enlightens the idea of weak derivatives. First, for k 2 N, f 2 C0 (Rm, C), any multi-index a with |a| = k, we consider the norm to evaluate the L2-norms of its derivatives:

Z

Rm

Â

|a|k

|Daf(x)|2dx.

Thus, from dDaxf =xa ˆf, we have

|f|2k :=

Â

|a|k

Z

Rm|Daf(x)|2dx

=

Â

|a|k

Z

Rm|Ddaf(x)|2dx =

Â

|a|k

Z

Rm|xa|2|bf(x)|2dx.

Observe that there exists constant C1, C2 >0 such that C1(1+|x|2)k

Â

|a|=k|xa|2C2(1+|x|2)k.

6This is called Plancherel theorem

(20)

Hence, the norm is equivalent to the norm7 Z

Rm(1+|x|2)k|bf(x)|2dx,

which is free of any differentiation. More generally, we have the following definition.

Definition 4.26.

(1) For s 2 R, which is regarded as order of L2-derivatives , we define

Sobolev s-norm of a L2-function f by

|f|2s := Z

Rm(1+|x|2)s| ˆf(x)|2dx, and the inner product(·,·)s by

(f , g)s := Z

Rm(1+|x|2)s ˆf(x)ˆg(x) dx.

2) The Sobolev s-space Hs(Rm)is defined to8be the completion of C0(Rm)in L2(Rm)(w.r.t the s-norm).

7Another common choice of weight is(1+|x|)2k.

8Here is an alternative way to define Sobolev space. The notion of weak derivative can be defined more directly by ”integration by part”. That is, we say v 2 L2(Rm, C) is a a-th L2-weak derivative for a locally integrable function

f 2L1loc(Rm)if it satisfies Z

Rmvjdx= ( 1)|a|

Z

Rm f(aj)dx, 8j2C0(Rm, C).

For k2N, if we assume that f 2L2(Rm)having L2-derivative daf for any|a| k, we then define Sobolev k-norm by

(4.7) |f|2k :=

Z Rm

Â

|a|k

|daf(x)|2dx,

and define the Sobolev space Hk(Rm)by

(4.8) Hk(Rm):={u2 L1loc(Rm):9af 2L2(Rm), 8|a| k}.

The definition is in fact equivalent to our definition. More generally, for 1 p <

•, we can consider Wk,p consisting of locally integrable function f having Lp- weak derivative up to order k. We can also define the Sobolev norm on Wk,pby

|f|k,p=Â|a|k|daf|pLp1/p.

(21)

Then again by the formula dDaxf =xa ˆf, Da : Hs\C0 ! Hs |a|,

|Daxf|2s |a| = Z

Rm(1+|x|2)s |a||xa ˆf(x)|2dx.

The key question here is that: although we define the weak de- rivative by multiplication in frequency space, when is f is actually Ck-differentiable if ˆf lies in some Sobolev space Hs, i.e. xa ˆf(x)lies in L2-space? This is answered by the following

Theorem 4.27 (key lemmas in Euclidean spaces).

(1) (Sobolev lemma) If s> k+m/2 and f 2 Hs, then f 2 Ck and there exists a universal constant C >0 depending only on s such that

|f|CkC|f|s.

where |f|Ck = Â|a|ksupx2Rm|af(x)| is the supremum norm of Ck-functions.

(2) (Rellich lemma) If s>t, Hs ,! Ht is a compact imbedding.

(3 (interpolation inequality) Let s>t >u.8 e>0,9 C(e)such that

|f|te|f|s+C(e)|f|u

for all f 2 C0. PROOF.

(1) Let k =0. First, we consider f 2 C00(Rm):

|f(x)| = Z

Rmeixx ˆf(x) dx

= Z

Rm

heixx ˆf(x)(1+|x|2)s/2i(1+|x|2) s/2dx

 |f|s

Z

Rm

1

(1+|x|2)s dx

1/2

(Cauchy–Schwarz inequality)

C|f|s,

for some C depending on s >m/2. In other words, |f|C0  C|f|s, for some constant C>0 depending only on s.

(22)

Now, for any f 2 Hs(Rm), we can choose a sequence fj H!s f with fj 2 C00(Rm). By the above result,

|fi fj|C0C|fi fj|s

infers that fi forms a Cauchy sequence in C0. Thus, fi ! f uniformly implies that f 2 C0. So

|f|C0  |f fi|C0+|fi|C0C(|f fi|s+|fi|s) and then|f|C0C|f|sby taking i !•.

For k >0 and s > k+m/2, apply the same argument to Daf , for any multi-index a with|a| =k:

|Daf|C0C|Daf|s kC|f|s.

Hence, for any a with |a| = k, Daf 2 C0(Rm), and thus HsCk. Also, we obtain|f|CkC|f|s.

(2) Consider K ⇢cpt Rm, fn 2 C\Hs with supp(fn) ⇢ K and

|fn|sC.

Let g 2 C0(Rm) with g ⌘ 1 on K. Then g· fn = fn and thus ˆfn = ˆg⇤ ˆfn. We then have

jˆfn =j(ˆg⇤ ˆfn) = (jˆg)⇤ ˆfn.

|jˆfn(x)|  Z

Rm

∂ ˆg

∂xj(x h)ˆfn(h) dh

 |fn|s

Z

Rm

|(xjˆg)(x h)|2 (1+|h|2)s dh

!12

(Cauchy–Schwarz).

We denote hj(x) := R

Rm(1+|h|2) s|(xjˆg)(x h)|2dh

12

. From theorem4.25, for any multi-indices a, b,

xbDaxˆg = \Dbx(xbg),

and Dxb(xbg) 2 C0 (Rm) since g 2 C0 (Rm). We conclude from Plancherel’s theorem that |xbDxaˆg|0 = |Dxb(xbg)|0 <

參考文獻

相關文件

In this process, we use the following facts: Law of Large Numbers, Central Limit Theorem, and the Approximation of Binomial Distribution by Normal Distribution or Poisson

We conclude this section with the following theorem concerning the relation between Galois extension, normal extension and splitting fields..

Al atoms are larger than N atoms because as you trace the path between N and Al on the periodic table, you move down a column (atomic size increases) and then to the left across

substance) is matter that has distinct properties and a composition that does not vary from sample

Students are asked to collect information (including materials from books, pamphlet from Environmental Protection Department...etc.) of the possible effects of pollution on our

Then, we tested the influence of θ for the rate of convergence of Algorithm 4.1, by using this algorithm with α = 15 and four different θ to solve a test ex- ample generated as

Particularly, combining the numerical results of the two papers, we may obtain such a conclusion that the merit function method based on ϕ p has a better a global convergence and

Wiedijk (2008), “the Law of Quadratic Reciprocity is the first nontrivial theorem that a student encounters in the mathematics curriculum.”.. Properties of the Jacobi Symbol.. The