本文以共旋轉有限元素推導法,殼元素來分析膜結構的皺折,由本 文分析之數值例題的結果,可得以下的結論:
(1)膜結構邊界受剪力側向挫屈後有很多不同平衡路徑,且膜結構受 力後的變形很敏感,差異很小的負荷條件,有可能會造成差異很大的 變形結果。
(2)由本文例題結果發現膜結構受剪位移時,若元素網格不夠密,則 膜結構皺折的數目太少。若欲得到精確的結果,應使用較密元素網格。
(3)本文對於平面膜結構產生側方向位移的機制為在分歧點加上挫 屈模態擾動,使膜結構有側方向的位移,本研究發現挫屈模態與膜結 構挫屈後皺折的的形狀差異很大。
(4)由本研究分析的結果與文獻上的實驗結果比較,可以發現兩者的 皺折型態有相同的特徵,但細部仍有差異,其原因可能是本研究分析 時,元素的數目不夠,文獻上的結構有初始不完美,且實驗操作上真 實的邊界條件可能與分析的邊界條件不同。
本文例題發現使用太密的元素網格,會出現不易收斂的情形,這可 能是因為本研究以平板三角殼元素來模擬薄膜結構的行為,可能因平 板殼元素沒有考慮撓曲變形與膜變形間的耦合及採用近似的幾何剛 度,造成收斂的困難。也可能是個數值方法上的問題,未來可考慮採 用其他元素或數值方法,若能解決這些困難,使用較密的元素網格,
有可能可以得到更精確的結果。
參考文獻
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圖 Mesh λ (mm) +wmax(mm) +wmax所在位置的初始座標 −wmax(mm) −wmax所在位置的初始座標 4.18 40×40 0.0507 0.421 (114.5, 114.5, 0) -0.608 (177.48, 0, 0)
4.18 60×60 0.0493 0.676 (91.6, 0, 0) -0.368 (122.13, 125.95, 0) 4.18 80×80 0.0507 0.507 (91.6, 0, 0) -0.448 (40.075, 229, 0) 4.19 40×40 0.401 1.062 (114.5, 114.5, 0) -1.770 (177.48, 0, 0) 4.19 60×60 0.404 1.578 (57.25, 229, 0) -0.933 (118.32, 118.32, 0) 4.19 80×80 0.406 0.791 (157.44, 229, 0) -1.124 (174.61, 0, 0) 4.20 40×40 0.601 1.296 (114.5, 114.5, 0) -2.170 (171.75, 0, 0) 4.20 60×60 0.604 1.529 (45.8, 229, 0) -1.480 (129.77, 0, 0) 4.20 80×80 0.606 0.797 (88.74, 74.43, 0) -1.564 (71.56, 0, 0) 4.21 40×40 0.801 1.493 (114.5, 114.5, 0) -2.510 (171.75, 0, 0) 4.21 60×60 0.804 1.078 (34.35, 229, 0) -2.036 (129.77, 0, 0) 4.21 80×80 0.806 0.868 (85.88, 74.43, 0) -1.919 (131.68, 229, 0) 4.22 40×40 1.000 1.666 (114.5, 114.5, 0) -2.805 (51.53, 229, 0) 4.22 60×60 1.000 1.024 (145.03, 156.48, 0) -2.376 (129.77, 0, 0) 4.22 80×80 1.000 0.930 (85.88, 74.43, 0) -2.153 (131.68, 229, 0)
表4.1膜結構側方向最大正負位移點所在位置的初始座標
圖1.1皺折的示意圖
圖1.2 波長的示意圖,圖上符號λ為半波長,取自文獻[9]
圖1.3文獻[11]例題之結構示意圖 I
A
B C
D )
( 1mm
=
∆
L
L
U X , V
Y ,
38 . 0
) /
( 3790
) ( 0762 . 0 ,
) ( 229
2
= ν
=
=
=
mm N E
mm h
Thickness mm L
圖 2.1 三角殼元素的示意圖及節點自由度 x1
x2
x3
u3
v3
w3
3
θ
x3
θ
y 3θ
zh 1
2
3
圖2.2 總體座標與元素座標 X1
X2
0 3
x
0 1
x
0
x
23
1
2
ion configurat Initial 3
1 2
x
3 Ix
1 I Ix
2ion configurat
m equilibriu th
I − 1
2
3
3
x x
2x
1ion configurat Current
X3
圖 2.3 旋轉向量 R R′
n
φ
圖 2.4 DKT元素的節點及其三邊上的局部座標示意圖
s
s s
n
23n
13n
12α
13α
23α
12 1x
5 4
3
1 6 2
x
2圖2.5 CST元素在元素座標上的變形位移
x
12 u
2x
23 v
3u
3ion configurat Current
ion configurat Initial
1
nt displaceme
nodal
Membrane : u
m= { 0 0 u
20 u
3v
3}
圖 2.6 變形前板元素中心面之單位法向量n受旋轉向量θ作用的 示意圖
θ
θ nd
n
x2
x1
圖 2.7 元素座標的剛體旋轉 (a)面外旋轉(out-of plane rotation),(b) 面內旋轉(in-plane roration)
O
I
Ix1
x1
x2
x
3α
α
I
x
3x2
) ( a
O
x′
1x1
x′
2β β
3 3
, x x ′
x2
)
( b
圖2.8 決定板元素節點變形轉角的第3個步驟的示意圖
j
x′
1x′
2Φ
tj∆
Φ
tj∆ x′
3I n′dj
ndj
n′u
圖 4.1圓柱殼結構示意圖及其受之位移負荷圖,(例題一)
M L λ
M
Pinned
Free
L B
θ R
0.3
a) 3102.75(Mp E
0.1(rad) 6.35(mm) h
254(mm) L
2540(mm) R
= ν
=
= θ
=
=
= A
D
E
F
G C
H Y
X
圖4.2 M 點之反力-負荷參數曲線圖(例題一)
-5 0 5 10 15 20 25 30 35
-0.4 -0.2 0.0 0.2 0.4 0.6
R
M(kN)
Loading parameter λ (mm)
whole structure
1/2 structure
1/4 structure
圖4.3 M 點之反力-負荷參數曲線圖(例題一)
-5 0 5 10 15 20 25 30 35 -0.4
-0.2 0.0 0.2 0.4 0.6
R
M(kN )
Loading parameter λ (mm)
[18]
Present
圖4.4 正方形膜結構示意圖及其受之位移負荷圖(例題二)
I A
B C
H D
F
G E
N J K
M
L
L
U X , V
Y ,
λ
0.5L HD
EH
0.25L MB
EM KE
AK 0.38 ν
) 3790(N/mm E
0.0762(mm) h
Thickness, 229(mm) L
2
=
=
=
=
=
=
=
=
=
=
圖4.5挫屈模態,例題二,Mesh 4040×
Z
X Y
圖 4.6挫屈模態,例題二,Mesh 6060×
Z
X Y
圖 4.7挫屈模態,例題二,Mesh 8080×
Z
X Y
圖4.8 挫屈模態的剖面圖 (a)FH斷面,(b)EG 斷面,例題二 0.0 0.2 0.4 0.6 0.8 1.0
0.010 0.015 0.020 0.025 0.030
deflection
X/L
Mesh 40x40 60x60 80x80
0.0 0.2 0.4 0.6 0.8 1.0 0.000
0.005 0.010 0.015 0.020 0.025 0.030
deflection
Y/L
Mesh 40x40 60x60 80x80 A
B C
D λ
V Y,
U X,
E G
F H
) (a
) (b
圖 4.9 I點之位移wI與E點之位移w -E 負荷參數λ曲線圖,
例題二,Mesh 4040×
A
B C
D λ
V Y,
U X, E I
0.0 0.2 0.4 0.6 0.8 1.0
0.0 0.5 1.0 1.5
w(mm)
Loading parameter
λ(mm)
w
I0.0 0.2 0.4 0.6 0.8 1.0
-3.0 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5
w(mm)
Loading parameter
λ(mm)
w
E圖 4.10 I 點之位移wI與E點之位移w -E 負荷參數λ曲線圖,
例題二,Mesh 6060×
A
B C
D λ
V Y,
U X, E I
0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0
w(mm)
Loading parameter λ (mm) wI
0.0 0.2 0.4 0.6 0.8 1.0
-2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
Loading parameter
λ(mm)
w
E圖 4.11 I點之位移wI與E點之位移w -E 負荷參數λ曲線圖,
例題二,Mesh 8080×
0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0
w(mm)
Loading parameter λ (mm) wI
0.0 0.2 0.4 0.6 0.8 1.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
Loading parameter
λ(mm)
w
EA
B C
D λ
V Y,
U X, E I
圖 4.12 不同增量位移下,I 點之位移wI與E點之位移w -E 負荷參 數λ曲線圖,例題二,Mesh 6060×
0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0
wI(mm)
Loading parameter λ (mm)
∆λ (mm) 0.005 0.005, 0.02 0.02
0.0 0.2 0.4 0.6 0.8 1.0 -2.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
wE(mm)
Loading parameter λ (mm)
∆λ (mm) 0.005 0.005, 0.02 0.02
A
B C
D λ
V Y,
U X, E I
圖 4.13 不同元素網格之I點之位移wI與E點之位移w -E 負荷參數 λ曲線比較圖,例題二
0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0
w(mm)
Loading parameter λ (mm)
wI
Mesh 60x60 Mesh 80x80
0.0 0.2 0.4 0.6 0.8 1.0 -2.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w( m m )
Loading parameter
λ(mm)
wE
Mesh 60x60 Mesh 80x80
A
B C
D λ
V Y,
U X, E I
圖4.14 例題二,位移邊界 AD上
(a)X方向節點力合力
∑
RXi–位移負荷參數λ 曲線圖(b) Y 方向節點力合力
∑
RYi–位移負荷參數λ 曲線圖0.0 0.2 0.4 0.6 0.8 1.0
0 10 20 30 40
Σ
R
Xi(N )
Loading parameter
λ(mm)
Mesh 40x40 60x60 80x80
) (a
) (b
0.0 0.2 0.4 0.6 0.8 1.0
-60 -50 -40 -30 -20 -10 0
Σ
R
Yi(N )
Loading parameter λ (mm)
Mesh
40x40
60x60
80x80
圖4.15 (a)位移邊界AD 上X 方向的節點反力圖(b)位移邊界AD 上Y 方向的節點反力圖,例題二,Mesh 4040×
0.0 0.2 0.4 0.6 0.8 1.0 0
1 2 3
R
Xi(N )
X/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0 )
(a
) (b
0.0 0.2 0.4 0.6 0.8 1.0
-10 -8 -6 -4 -2 0
R
Yi(N )
X/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0
圖4.16 (a)位移邊界AD 上X 方向的節點反力圖(b)位移邊界AD 上Y 方向的節點反力圖,例題二,Mesh 6060×
) (a
0.0 0.2 0.4 0.6 0.8 1.0
0.0 0.5 1.0 1.5 2.0 2.5
R
Xi(N )
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
) (b
0.0 0.2 0.4 0.6 0.8 1.0
-8 -6 -4 -2 0
R
Yi(N )
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
圖4.17 (a)位移邊界AD 上X 方向的節點反力圖(b)位移邊界AD 上Y 方向的節點反力圖,例題二,Mesh 8080×
0.0 0.2 0.4 0.6 0.8 1.0
0.0 0.5 1.0 1.5 2.0
R
Xi(N )
X/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0
0.0 0.2 0.4 0.6 0.8 1.0
-7 -6 -5 -4 -3 -2 -1 0
R
Yi(N )
X/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0 )
(a
) (b
圖 4.18 膜結構變形圖,例題二(a) Mesh 40×40, )λ=0.0507(mm , (b)Mesh 60×60, )λ=0.0493(mm ,
圖 4.19 膜結構變形圖,例題二(a)Mesh 4040× , )λ=0.401(mm , (b)Mesh 60×60, )λ=0.404(mm , (c)Mesh 8080× , )λ=0.406(mm
78 . 1.4 1.00 100000000........0080604020204080 1.07 1 w(mm)
−−
−−
−−
−+ ++ ++ +
00 . 100000000........0060402020406080 1.20 1.40 1.58 w(mm)1
−−
−− ++ ++ ++ ++ +
13 . 1.00 100000000000..........90705040201010507080 w(mm)
−−
−−
−−
−− ++ ++ +
)
(a (b) (c)
圖 4.20 膜結構變形圖,例題二(a)Mesh 4040× , )λ=0.601(mm , (b)Mesh 60×60, )λ=0.604(mm , (c)Mesh 8080× , )λ=0.606(mm
17 . 2.00 2.60 1.40 1.00 1000000......208020206080 1.30 1 w(mm)
−−
−−
−−
−+ ++ ++ +
60 . 1.20 1.00 10000000.......00804020204080 1.40 1.53 w(mm)1
−−
−−
−− ++ ++ ++ +
60 . 1.40 1.20 1.00 1000000000........8060402020406080 w(mm)
−−
−−
−−
−− ++ ++ +
)
(a (b) (c)
圖 4.21 膜結構變形圖,例題二(a)Mesh 4040× , )λ=0.801(mm , (b)Mesh 60×60, )λ=0.804(mm , (c)Mesh 8080× , )λ=0.806(mm
51 . 2.20 2.80 1.40 1.10 100000.....0060202040 1.40 1.50 1 w(mm)
−−
−−
−−
−+ ++ ++ +
04 . 2.00 2.60 1.40 1110000000........0008806020204080 w(mm)
−−
−−
−−
−+ ++ ++ +
92 . 1.80 1.40 1.20 1000000000........8040202040608087 w(mm)
−−
−−
−−
−+ ++ ++ +
)
(a (b) (c)
圖 4.22 膜結構變形圖,例題二(a)Mesh 4040× , )λ=1 mm( , (b)Mesh 60×60, )λ=1 mm( ,
圖 4.23軸線 AB之Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60
A
B C
D λ
V Y,
U X,
) (a
0.0 0.2 0.4 0.6 0.8 1.0 -3
-2 -1 0 1
w(mm)
Y/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0
) (b
0.0 0.2 0.4 0.6 0.8 1.0
-3 -2 -1 0 1
w(mm)
Y/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0 -3
-2 -1 0 1
w( m m )
Y/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
) (a
圖 4.24軸線 AB之Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80
0.0 0.2 0.4 0.6 0.8 1.0
-2.0 -1.5 -1.0 -0.5 0.0 0.5
w(mm)
Y/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0
) (b
A
B C
D λ
V Y,
U X,
圖 4.25軸線 FH之Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60
A
B C
D λ
V Y,
U F X,
H
0.0 0.2 0.4 0.6 0.8 1.0
-1.0 -0.5 0.0 0.5 1.0 1.5
w(mm)
Y/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0
) (b
) (a
0.0 0.2 0.4 0.6 0.8 1.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
Y/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
圖 4.26軸線 FH之Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80 0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0 0.5 1.0
w(mm)
Y/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0 -1.0
-0.5 0.0 0.5 1.0
w(mm)
Y/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0 A
B C
D λ
V Y,
U F X,
H
) (b
) (a
圖 4.27軸線 CD之Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60
A
B C
D λ
V Y,
U X,
0.0 0.2 0.4 0.6 0.8 1.0
-3 -2 -1 0 1
w(mm)
Y/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0
0.0 0.2 0.4 0.6 0.8 1.0 -2
-1 0 1 2
w(mm)
Y/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
) (b
) (a
圖 4.28軸線 CD之Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80 0.0 0.2 0.4 0.6 0.8 1.0 -2
-1 0 1 2
w(mm)
Y/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0 -2.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
Y/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0 A
B C
D λ
V Y,
U X,
) (b
) (a
圖 4.29軸線 JK之Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60
0.0 0.2 0.4 0.6 0.8 1.0
-1.0 -0.5 0.0 0.5 1.0 1.5
w(mm)
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0 A
B C
D λ
V Y,
U X, K J
0.0 0.2 0.4 0.6 0.8 1.0
-3.0 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0
) (b
) (a
圖 4.30軸線 JK之Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80
0.0 0.2 0.4 0.6 0.8 1.0
-1.0 -0.5 0.0 0.5 1.0 1.5
w(mm)
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0
-2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0 A
B C
D λ
V Y,
U X, K J
) (b
) (a
圖 4.31 軸線EG之 Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60
0.0 0.2 0.4 0.6 0.8 1.0
-2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0 -3
-2 -1 0 1 2
w (mm)
X/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0 A
B C
D λ
V Y,
U X, G E
) (a
) (b
圖 4.32 軸線EG之 Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80
0.0 0.2 0.4 0.6 0.8 1.0
-2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0 -2.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w( m m )
X/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0 A
B C
D λ
V Y,
U X, G E
) (a
) (b
圖 4.33 軸線MN之 Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60
A
B C
D λ
V Y,
U X,
M N
0.0 0.2 0.4 0.6 0.8 1.0
-3 -2 -1 0 1
w(mm)
X/L
λ (mm) 0.0507 0.401 0.601 0.801 1.0
0.0 0.2 0.4 0.6 0.8 1.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
) (a
) (b
圖 4.34 軸線MN之 Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80
0.0 0.2 0.4 0.6 0.8 1.0
-1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0493 0.404 0.604 0.804 1.0
0.0 0.2 0.4 0.6 0.8 1.0
-2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0
w(mm)
X/L
λ (mm) 0.0507 0.406 0.606 0.806 1.0 A
B C
D λ
V Y,
U X,
M N
) (a
) (b
圖 4.35對角軸線 BD之Z方向位移分佈圖,例題二,
(a)Mesh 4040× ,(b) Mesh 60×60 L
2 S/
) (b
0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0 0.5 1.0
w (mm)
λ (mm)0.0493 0.404 0.604 0.804 1.0 A
B C
D λ
V Y,
U X, L S
L
0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0 0.5 1.0 1.5
w( m m )
λ (mm) 0.0507 0.401 0.601 0.801 1.0 )
(a
L 2 S/
圖 4.36對角軸線 BD之Z方向位移分佈圖,例題二,
(a)Mesh 6060× ,(b) Mesh 80×80 0.0 0.2 0.4 0.6 0.8 1.0 -1.5
-1.0 -0.5 0.0 0.5 1.0
w(mm)
λ (mm) 0.0493 0.404 0.604 0.804 1.0
L 2 S/
) (a
A
B C
D λ
V Y,
U X, L S
L
0.0 0.2 0.4 0.6 0.8 1.0 -1.0
-0.5 0.0 0.5 1.0
w(m m )
λ (mm) 0.0507 0.406 0.606 0.806 1.0
) (b
L 2 S/
圖 4.37 膜結構變形圖,例題二,λ=1 mm( )
(a) Present, Mesh 40×40, (b)文獻[12]Experiment(Photogrammetry), (c)文獻[11] (ABAQUS S4R5)
3.11 -2.79 -2.48 -2.16 -1.85 -1.53 -1.22 -0.90 -0.59 -0.27 -w(mm)0.040.360.67 ++ +
3.15 -2.79 -2.43 -2.07 -1.71 -1.35 -0.99 -0.63 -0.27 -0.01 -w(mm)10.450.82.18 ++ +
) (c )
(b )
(a
81 . 2.75 2.50 2.00 2.50 1.00 11110000......00506750575 w(mm)
−−
−−
−−
−+ ++ ++ +
圖 4.38 膜結構變形圖,例題二,λ=1 mm( )
(a)Present, Mesh 60×60, (b)文獻[12]Experiment(Photogrammetry), (c)文獻[11] (ABAQUS S4R5)
3.11 -2.79 -2.48 -2.16 -1.85 -1.53 -1.22 -0.90 -0.59 -0.27 -w(mm)0.040.360.67 ++ +
3.15 -2.79 -2.43 -2.07 -1.71 -1.35 -0.99 -0.63 -0.27 -0.01 -w(mm)10.450.82.18 ++ +
) (c )
(b )
(a
38 . 2.00 2.60 1.20 1.00 1000000......006020204080 1.03 w(mm)1
−−
−−
−−
−+ ++ ++ +
圖 4.39 膜結構變形圖,例題二,λ=1 mm( )
(a)Present, Mesh 80×80, (b)文獻[12]Experiment(Photogrammetry), (c)文獻[11] (ABAQUS S4R5)
3.11 -2.79 -2.48 -2.16 -1.85 -1.53 -1.22 -0.90 -0.59 -0.27 -w(mm)0.040.360.67 ++ +
3.15 -2.79 -2.43 -2.07 -1.71 -1.35 -0.99 -0.63 -0.27 -0.01 - 10.450.82.18 w(mm) ++ +
) (c )
(b )
(a
16 . 2.00 2.80 1.60 1.20 1.00 10000000......602020608093 w(mm)
−−
−−
−−
−− ++ ++ +
附錄 A DKT 元素的形狀函數
在(2.29)式裡面的H 與x H 分別有y 9個分量,其表示式為[21]
Hx1=1.5(a6N6 −a5N5) Hx2 =b5N5+b6N6 Hx3 = N1 −c5N5 −c6N6 Hx4 =1.5(a4N4 −a6N6) Hx5 =b6N6 +b4N4 Hx6 = N2 −c6N6 −c4N4 Hx7 =1.5(a5N5 −a4N4) Hx8 =b4N4 +b5N5 Hx9 = N3 −c4N4 −c5N5
Hy1 =1.5(d6N6 −d5N5) Hy2 =−N1 +e5N5 +e6N6 Hy3 =−Hx2
Hy4 =1.5(d4N4 −d6N6) Hy5 =−N2 +e6N6 +e4N4 Hy6 =−Hx5
Hy7 =1.5(d5N5 −d4N4) Hy8 =−N3 +e4N4 +e5N5 Hy9 =−Hx8
其中
2
ij ij
k l
a −x
=
4 2
)
1
k
附錄 B CST 元素的剛度矩陣
附錄 C
逆冪法解廣義特徵值問題之數值方法
廣義特徵值問題(generalized eigenvalue problem)可表示成 AX =λBX (C.1) 若(C.1)式的最小特徵值沒有重根,則可利用逆冪法(inverse power method)求其最小的特徵值及特徵向量。
以逆冪法求解廣義特徵值問題的數值方法可說明如下:
將(C.1)式之兩邊各減掉λSBX,其中λS為一接近欲求之特徵值的 給定值,則(C.1)式可被改寫成
AX= λBX, (C.2) A =A−λSB, (C.3) λ =λ−λS。 (C.4) 令λ0 =0與X0 =
{
1,1,L,1}
,並計算Y =BX0。將Y 正規化,亦即
Y
Y0 = Y 。 (C.5)
求解
AX1=Y0, (C.6) 求得X1。再計算
Y1 =BX1, (C.7)
1 1 1 0
1 X Y
Y X
t t
=
λ 。 (C.8)
檢查以下兩個挫屈收斂準則
X t
X e X
X
X ≤
−
1 0
0 1
1 , (C.9)
≤ λ λ
λ
−
λ e
1 0
1 , (C.10)
其中e 與X e 為給定之容許誤差。λ
若(C.9)與(C.10)式同時滿足,則取λ= λ1+λS 為所求之挫屈負 荷參數,而X 代表對應1 λ 之挫屈模態(buckling mode),並停止迭代;
否則令X0 =X1、Y=Y1、與λ0 =λ1,並回到步驟(3)繼續迭代。