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Friday July 8 2005

1.1 Multiplier space sufficiency

j=1

bjkzα,pj

Bp

≤ C

j=1

ajkzα,pj

Bp

, whenever |bj| ≤ |aj| . (5)

3. {zj}j=1 = cαj

j=1 where {αj}j=1 is a sequence in a Bergman tree Tn sat-isfying

β (zi, 0)≤ Cβ (zi, zj) , i = j and (6)

j=1

(1 + d (αj, o))1−pδαj satisfies the tree condition (??).

1.1 Multiplier space sufficiency

Here we prove that (6) implies (4) for 1 < p < ∞, and also that (3) implies (4) for p > 2n, beginning with the proof that the multiplier interpolation property (4) follows from (6). We generalize the main ideas in Böe’s one-dimensional proof to the unit ball Bn. First we give the following characterization of multipliers in terms of Carleson measures.

Theorem 3 Let ϕ ∈ H(Bn)∩ Bpσ(Bn) and m + σ > np. Then ϕ is a pointwise multiplier on Bpσ(Bn), i.e. ϕf Bσ

p ≤ C f Bσp for all f ∈ Bpσ(Bn), if and only if 1− |z|2 m+σϕ(m)(z)

p

n(z) is a Bpσ(Bn)-Carleson measure on Bn.

Proof. Using

ϕf pBσ p =

Bn

1− |z|2 m+σ(ϕf )(m)(z) pn(z) , together with

(ϕf )(m)(z) = ϕ(m)(z) f (z) + ... + ϕ (z) f(m)(z) ,

we see that the last term ϕ (z) f(m)(z)can be handled using the boundedness of ϕ, while the first term is handled by the Carleson embedding. The intermediate terms are handled by an interpolation argument - see [8].

For z ∈ Bn and β < 1, define the region Vzβ by

Vzβ = w∈ Bn:|1 − w · P z| ≤ (1 − |z|)β ,

where P z denotes the radial projection of z onto the sphere ∂Bn. The intersection of Vzβ with the complex line Cz through z and the origin is

w∈ Bn∩ Cz : |w − P z| ≤ (1 − |z|)β ,

and the intersection of Vzβ with the sphere ∂Bn is an “ellipse” with radius (1− |z|)β in the radial tangential direction, and radius (1 − |z|)β2 in the com-plex tangential directions. Using arguments in Marshall and Sundberg [24], the separation condition in (3) implies the following geometric separation conditions.

Lemma 4 Suppose the separation condition in (3) holds. Then there are con-stants 0 < β < 1 < βη < η such that if Vzβi ∩ Vzβj = φ and |zj| ≥ |zi|, then zi ∈ V/ zβj

and

(1− |zj|) ≤ (1 − |zi|)η. (7) We now fix constants β and η as in Lemma 4, and write Vz = Vzβ.

Lemma 7 below is the key construction in the sufficiency proof and is moti-vated by the formula ((1.35) in [39])

Rs−n,n 1

(1− w · z)1+s = 1

(1− w · z)n+1+s, valid for s not a negative integer. The point is that if we define

Γsg (z)≡

Bn

g (w) 1− |w|2 s

(1− w · z)1+s dw (8)

for a given (not necessarily holomorphic) function g, then with ϕ (z) = Γsg (z), so that ϕ is essentially an n-fold antiderivative of g, we have

Rs−n,nϕ (z) = Rs−n,nΓsg (z) =

Bn

g (w) 1− |w|2 s

(1− w · z)n+1+sdw, (9) and by the reproducing formula valid for Re s > −1, we also have that

Rs−n,nϕ (z) = cn,s Bn

Rs−n,nϕ (w) 1− |w|2 s (1− w · z)n+1+s dw.

Thus Rs−n,nϕ (w)behaves morally like g (w), and this provides flexibility in choos-ing g so that ϕ has desirable algebraic multiplier properties on the one hand, while

controlling the multiplier norm of ϕ on the other hand. Indeed, by Theorem 3, the multiplier norm is equivalent to the Carleson norm of 1− |z|2 nnϕ (z)

p

n(z), which can in turn be dominated by the “tree condition” norm of 1− |z|2 ng (z)

p

n(z) by the lemma in the next subsubsection.

Finally, we note that the construction of an approximate zero-one Dirichlet multiplier in Lemma 7 below (which results in a holomorphic function that is close to one on a Carleson tent and close to zero away from it) is a substitute for Jones’ clever construction of an exact zero-one Hardy multiplier in the disk using Blaschke products. In the analogous result on the Bergman tree, the Dirichlet multiplier construction is given simply by defining a sequence hj ={hj(α)}α∈Tn

to satisfy hjj) = 1and to decrease linearly to 0 on a sufficiently small stretch of the geodesic preceding α, and then “linearly” to 0 off the geodesic as well. See [7] for such constructions.

Terminology We say that a measure µ on Bn satisfies the tree condition if its discretization µ does.

It is here that we first use the tree condition in a significant way.

1.1.1 Transformation of Carleson measures

Lemma 5 (analogue of Lemma 2.4 in [12]) Suppose that g satisfies the following reverse Hölder condition on Bergman kubes,

Kα

|g (z)|pn(z)

1 p

≤ C0

Kα

|g (z)| dλn(z) , α ∈ Tn, (10) and that the measure

dµ (z) = 1− |z|2 ng (z)

p

n(z)

satisfies the tree condition with norm C1. Then for s sufficiently large, both 1− |z|2 nRs−n,nΓsg (z)

p

n(z) and

1− |z|2 nnΓsg (z)

p

n(z) satisfy the tree condition with norms at most C (C0+ C1).

Note that it then follows that both measures in the conclusion of the lemma are Bp-Carleson measures. The proof of the lemma uses only Schur’s test and lengthy calculations involving discretization of functions and measures, and uni-tary rotations of the Bergman tree. We emphasize again that this is where the

tree condition is used in a significant way. The multiplier norm of ϕ (z) = Γsg (z) is the same as the Carleson measure norm of

1− |z|2 m+σmΓsg (z) pn(z) ,

and the tree condition norm of this latter expression is estimated by the tree condition norm of

1− |z|2 ng (z)

p

n(z) .

Following Böe [12] one can prove the following alternate version of Lemma 5, where the tree condition is replaced by the Bp-Carleson measure condition, for the range p > 2n with s > n − p1. This version will be instrumental in proving the implication (3) implies (4) for p > 2n below.

Lemma 6 (another analogue of Lemma 2.4 in [B]) Suppose that sup

ζ∈Bn

1− |ζ|2 ng (ζ) ≤ C0, (11) and that the measure

dµ (z) = 1− |z|2 ng (z)

p

n(z)

is a Carleson measure for Bp with norm C1. Then for p > 2n and s > n − p1, both

1− |z|2 nRs−n,nΓsg (z)

p

n(z) and

1− |z|2 nnΓsg (z)

p

n(z)

are also Carleson measures for Bp, and with norms at most C (C0+ C1).

The simpler Lemma 6 uses the characterization of Bp given by Theorem 6.28 of [39], which states that

f pBp

Bn Bn

|f (z) − f (w)|p

|1 − w · z|2(n+1+t)t(z) dνt(w) , (12) provided t > −1 and p > 1, n = 1

2n n > 1. In order to obtain the full range 1 < p < ∞ when n > 1, we instead need to use the the tree condition to obtain Lemma 5.

1.1.2 Multiplier approximations

The next lemma constructs a holomorphic function that is close to 1 on the Carleson region associated to a point w ∈ Bn, and decays appropriately away from the Carleson region. We follow Böe’s proof in [12], which adapts a real-variable argument of Marshall and Sundberg in [24] to produce a holomorphic multiplier approximation. Given β < ρ < α < 1, we will use the cutoff function cρ,α defined by

cρ,α(γ) =



0 for γ < ρ

γ−ρ

α−ρfor ρ ≤ γ ≤ α 1 for α < γ

. (13)

Lemma 7 (analogue of Lemma 4.1 in [12]) Suppose s > −1. There are ρ and α satisfying β < ρ < α < 1 such that for every w ∈ Bn, we can find a function gw

so that

ϕw(z) = Γsgw(z) =

Bn

gw(ζ) 1− |ζ|2 s 1− ζ · z 1+s dζ satisfies









ϕw(w) = 1

ϕw(z) = cρ,αw(z)) + O log 1

1−|w|2

−1 , z ∈ Vw

w(z)| ≤ C log1−|w|1 2 1−p, z /∈ Vw

, (14)

where γw(z) is defined by

|1 − z · P w| = 1 − |w|2 γw(z) and cρ,α is as in (13). Furthermore we have the estimate

Bn

1− |ζ|2 ngw(ζ) pn(ζ) dζ ≤ C log 1 1− |w|2

1−p

. (15)

The final estimate (15) will lead to the Carleson measure estimate for 1− |z|2 ng (z)

p

n(z) .

Remark 1 The proof of Lemma 7 shows that the third estimate in (14) can be vastly improved, and also holds for a larger range of z; namely there is β < β1 < ρ such that

w(z)| ≤ C log 1 1− |w|2

−1

1− |w|2 (ρ−β1)(1+s), z /∈ Vwβ1. This fact will be used in the proof of Lemma 8 below.

Proof. Define gw(ζ)by gw(ζ) 1− |ζ|2 s

1− ζ · w 1+s = K log 1 1− |w|2

−1

1− ζ · P w −n−1, (16) when ζ lives in the annular sector S centred at P w given as the intersection of the annulus

A = Aw = ζ ∈ Bn: 1− |w|2 α≤ 1 − ζ · P w ≤ 1 − |w|2 ρ (17) and the cone

C = Cw = ζ ∈ Bn: Im ζ· P w + ζ − ζ · P w P w 2 ≤ c 1 − ζ · P w , where c is a suitably small constant. Define gw(ζ) = 0 otherwise. The following observation will be used repeatedly.

Remark 2 The cone Cw corresponds to the geodesic in the Bergman tree Tn joining the root to the “boundary point” P w. To see this, consider the case w = (t, 0, ..., 0) and ζ = re, ζ with re = x + iy, so that Im ζ · P w = y, ζ− ζ · P w P w = (0, ζ ) and 1 − ζ · P w = 1 − r.

Now choose K so that ϕw(w) = 1, i.e.

K = log 1

1− |w|2 S

1− ζ · P w −n−1

−1

, which satisfies

K ≈ Kα,ρ,n = cn

α− ρ (18)

since the annular sector

Ea = ζ ∈ Bn: a≤ 1 − ζ · P w ≤ 2a ∩ C

is comparable to a Bergman ball of radius one, 1 − ζ · P w −n−1dζ is comparable to invariant measure dλn(ζ)on Ea, and S ≈ ∪Jj=0E2j(1−|w|2)α where

J = log 1− |w|2 ρ

1− |w|2 α = (ρ− α) log 1 − |w|2 . Note also that

1− ζ · P w ≈ 1 − ζ · w ≈ 1 − |ζ|2, ζ ∈ S, (19)

and so gw satisfies the estimate

|gw(ζ)| ≤ C log 1 1− |w|2

−1

1− ζ · P w −n, ζ ∈ Bn. (20) Now fix z ∈ Vw and set

E1= ζ ∈ Bn: 1− ζ · P w ≤ 1 − |w|2 γw(z) ,

E2= Bn\ E1 = ζ ∈ Bn: 1− ζ · P w > 1 − |w|2 γw(z) .

Thus the common boundary of E1 and E2 passes through z. The main contribu-tion to ϕw(z) will come from integration over E2. Thus we write

ϕw(z) =

E1

gw(ζ) 1− |ζ|2 s 1− ζ · z 1+s dζ +

E2

gw(ζ) 1− |ζ|2 s

1− ζ · z 1+s dζ = I + II.

By (19), (20) and the definition of γw(z), term I is dominated by C log 1

1−|w|2

−1

times

{(1−|w|2)α|1−ζ·P w|≤|1−z·P w|}∩C

1− |ζ|2 1− ζ · z

1+s

n(ζ) , which is at most a constant C since

1− ζ · z ≈ |1 − z · P w| , ζ ∈ C ∩ E1. Thus we have

|I| ≤ C log 1 1− |w|2

−1

. We now write

II =

E2∩S

gw(ζ) 1− |ζ|2 s 1− ζ · z 1+s

=

E2∩S

gw(ζ) 1− |ζ|2 s

1− ζ · z 1+s −gw(ζ) 1− |ζ|2 s 1− ζ · w 1+s dζ +

E2∩S

gw(ζ) 1− |ζ|2 s 1− ζ · w 1+s

= III + IV.

The point of isolating term IV is that the variable z occurs there only in the exponent γw(z), and this leads to the following exact calculation. Using (18),

and that gw is supported in S, we calculate that term IV is log1−|w|1 2 −1 times K

(1−|w|2)γw(z)|1−ζ·P w|(1−|w|2)ρ ∩C

1− ζ · P w −n−1dζ = γw(z)− ρ

α− ρ log 1 1− |w|2 in the case ρ < γw(z) < α. We also have IV = 0 in the case γw(z) < ρ, and IV = log 1

1−|w|2 in the case α < γw(z). This gives the estimate IV = cρ,αw(z)) + O log 1

1− |w|2

−1

, z ∈ Vw. Using

1

1− ζ · z 1+s − 1

1− ζ · w 1+s ≤ C |z − w|

1− |ζ|2 2+s together with (19) and (20), we obtain that

|III| ≤ C

E2∩S|gw(ζ)| 1 − |ζ|2 −2|z − w| dζ

≤ C |z − w| log 1 1− |w|2

−1

E2∩S

1− |ζ|2 −1n(ζ)

≤ C log 1 1− |w|2

−1

,

as required. This completes the proof of the second estimate in (14).

We now turn to the third estimate in (14). For z /∈ Vw, we have 1 − ζ · z ≥ c 1− |w|2 β for ζ ∈ S, and thus

w(z)| ≤ log 1 1− |w|2

−1

S

1− |ζ|2 1− ζ · z

1+s

n(ζ)

≤ C log 1 1− |w|2

−1

1− |w|2 (ρ−β)(1+s)

≤ Cp log 1 1− |w|2

1−p

.

Finally, the estimate (15) is a calculation using (19), (20) the definition of the support of gw. Indeed, the left side of (15) is at most

C

S

log 1 1− |w|2

−p

n(ζ)≤ C log 1 1− |w|2

1−p

.

The next lemma uses Lemma 5 to construct inductively a holomorphic func-tion whose restricfunc-tion to the sequence {zj}j=1 approximates an arbitrarily pre-scribed bounded sequence ξj j=1.

Lemma 8 (analogue of Lemma 4.2 in [12]) Suppose s > −1, that ξj

j=1 and let 0 < δ < 1. Let ϕj, gj and γj correspond to zj as in Lemma 7 and with the same s. Then there is {ai}i=1 such that ϕ = i=1aiϕi satisfies

ξj− ϕ (zj) j=1

< δ ξj j=1

(21)

and

{ai}i=1 , ϕ H(Bn) ≤ C ξj j=1

. (22)

Remark 3 The series i=1aiϕi in Lemma 8 converges absolutely for each z ∈ Bn. In fact, the proof below will show that (using #G ≤ Cβ (0, z ))

i=1

i(z)| ≤ C 1 + log 1

1− |z|2 , z ∈ Bn.

Remark 4 The construction in the proof below shows that both the sequence {ai}i=1 and the function ϕ depend linearly on the data ξj j=1.

Proof. We follow the proof of Lemma 4.2 in [12]. Let ξj j=1

= 1. We first choose J so large that

sup

j≥J

log 1 1− |zj|

−1

+

j=J

log 1 1− |zj|

1−p

< ε, (23) where ε > 0 will be determined later. Note that the series above converges by the Carleson embedding. By standard arguments in [24], we may discard the finitely many points {zj}J−1j=1. Thus we may assume that J = 1 in (23).

Order the points {zj}j=1 so that 1 − |zj+1| ≤ 1 − |zj| for j ≥ 1. We now define a “forest structure” on the index set N by declaring that j is a child of i (or that i is a parent of j) provided that

i < j, (24)

Vzj⊂ Vzi,

Vzj# Vzk for i < k < j.

Note that a child j chooses the “nearest” parent i if we have competing indices i and i with Vzj ⊂ Vzi∩ Vzi . We define a partial order associated with this parent-child relationship by declaring that j is a successor of i (or that i is a predecessor

of j) if there is a “chain” of indices {i = k1, k2, ..., km = j} ⊂ N such that k+1 is a child of k for 1 ≤ < m. Under this partial ordering, N decomposes into a disjoint union of trees. Thus associated to each index ∈ N, there is a unique tree containing and, unless is the root of the tree, a unique parent P ( ) of in that tree. Denote by G the unique geodesic joining the root of the tree to . We will now define the coefficients {ai}i=1 of ϕ = i=1aiϕi, where ϕi is the function ϕzi in Lemma 7 with w there replaced by zi, by considering separately the indices in each tree of the forest N.

Let Y be a tree in the forest N with root k0. For each k ∈ Y \ {k0}, define βk ∈ [0, 1] by

βk= c γP (k)(zk) ,

where the functions c = cρ,α and γj = γzj are defined as in the statement of Lemma 7 with w there replaced by zj. Note that by Lemma 7 with w = zP (k), we have the estimate

ϕP (k)(zk) = c γP (k)(zk) + O

 log 1

1− zP (k) 2

−1

= βk+ O

 log 1

1− zP (k) 2

−1

 ,

which can serve as motivation for the definition of the coefficients given below in (26). Indeed, with gross oversimplification, what we want is

ξk= ϕ (zk)≈ akϕk(zk) + aP (k)ϕP (k)(zk) + ...

≈ ak+ aP (k)βk+ ..., which leads to (26).

We will now define numbers {ak}k∈Y by induction on the linear ordering in Y induced from the natural ordering of N, so that

|ak| ≤ 2

i∈Gk\{k0}βiaP (i) ≤ 1 (25) holds for all k ∈ Y. First define ak0 = ξk0. Now fix ∈ Y \ {k0} and assume that ak has been defined for all k ∈ Y for which k < so that (25) holds for all k ∈ Y for which k < . We now define a by

a = ξ −

i∈G \{k0}

βiaP (i). (26)

Of crucial importance is the observation that the geodesics G and GP ( )are related by

GP ( ) =G \ { } ,

i.e. if G = [k0, k1, ..., km−1, km] with km = , then km−1 = P ( ) and GP ( ) = [k0, k1, ..., km−1]. At this point the reader should draw a picture. The region Vzkj = Vzβ

kj is essentially a Carleson tent with vertex not at zkj, but rather at the point zkβj lying on the ray through zkj and having distance 1 − zkj

β to the boundary, much larger than the distance 1 − zkj from zkj to the boundary. Note that zkj can have infinitely many children in the tree Y, one of which is the point zkj+1 having Vzkj+1 ⊂ Vzkj with 1 − zkj+1 1− zkj . Finally, note that βj+1 equals 1 if zkj+1 lies within the smaller Carleson tent Vzα

kj, βj+1 equals 0 if zkj+1

lies outside the Carleson tent Vzρ

kj, and βj+1 is defined linearly in (0, 1) for zkj+1

within the annulus of Carleson tents Vzρ

kj \ Vzαkj. By the induction assumption and the fact that P ( ) ∈ Y and P ( ) < , we have

i∈GP ( )\{k0}

βiaP (i) ≤ 1.

We have from (26) and the above that

i∈G \{k0}

βiaP (i) =

i∈GP ( )\{k0}

βiaP (i)

 + β

ξP ( )

i∈GP ( )\{k0}

βiaP (i)

= β ξP ( )+ (1− β )

i∈GP ( )\{k0}

βiaP (i)

≤ β ξP ( ) + (1− β )

i∈GP ( )\{k0}

βiaP (i) ≤ 1.

From this and (26) once more it immediately follows that |a | ≤ 2, which shows that (25) holds for k = as well. This completes the inductive definition of the sequence {ak}k∈Y satisfying (25) on the tree Y, and hence defines the entire sequence {ai}i=1.

We omit the proof that both (21) and (22) hold for the function ϕ = i=1aiϕi. 1.1.3 The proof of multiplier interpolation

Using Lemma 8, we first complete the proof that (6) implies (4) for 1 < p < ∞.

Fix s > −1, 0 < δ < 1 and ξj

j=1 with ξj j=1

= 1. Then by Lemma 8 there is f1 = i=1a1iϕi ∈ H(Bn) such that ξj − f1(zj) j=1

< δ and {a1i}i=1 , f1 H(Bn) ≤ C where C is as in (22). Now apply Lemma 8 to the sequence ξj − f1(zj) j=1 to obtain the existence of f2 = i=1a2iϕi ∈ H(Bn)

such that ξj − f1(zj)− f2(zj) j=1

< δ2and {a2i}i=1 , f2 H(Bn) ≤ Cδ where C is as in (22). Continuing inductively, we obtain fm = i=1ami ϕi ∈ H(Bn) such that

ξj

m

i=1

fi(zj)

j=1

< δm, {ami }i=1 , fm H(Bn)≤ Cδm−1. If we now take ϕ = m=1fm, we have

ξj= ϕ (zj) , 1≤ j < ∞, (27) ϕ H(Bn)≤ Cδ,

as well as ϕ = i=1aiϕi with {ai}i=1 ≤ Cδ. Recall that the series ϕ =

i=1aiϕi converges absolutely by Remark 3, and depends linearly on the data ξj j=1 by Remark 4 and the linear construction in this paragraph. Thus ϕ ∈ H(Bn) linearly interpolates the values ξj j=1 on the sequence {zj}j=1, and it remains to prove that ϕ ∈ MBp. Recall that our function ϕ depends on our choice of s > −1.

By Theorem 3, ϕ ∈ MBp will follow if we show that 1− |z|2 nnϕ (z)

p

n(z)

Carleson ≤ C. (28)

Since

ϕ =

i=1

aiϕi =

i=1

aiΓsgi = Γsg

where g = i=1aigi with supi≥1|ai| ≤ Cδ, (28) will follow from Theorem ?? and Lemma 5 for s sufficiently large provided we show that (10) holds and that

1− |z|2 ng (z)

p

n(z)

satisfies the tree condition. From the definition of gi in (16), and the fact that the supports of the gi are pairwise disjoint by the separation condition, we may assume that the reverse Hölder condition on Bergman balls in (10) holds. The tree condition estimate will follow from the next lemma.

Lemma 9 With s > n − p1 and g = i=1aigi as above, we have 1− |z|2 ng (z)

p

n(z)

tree condition≤ C. (29)

Proof. Inequality (29) follows from the estimate (15) as follows. If we discretize (15), we obtain with w = zi and S (α) ≈ Vzi,

β∈Tn:β≥α

1− |cβ|2 npgzi(β)p ≤ C log 1 1− |zi|2

1−p

. (30)

Denote the Carleson tent at cβ by S (β) = Tβ =∪γ≥βKγ. We are assuming that the tree condition holds for the measure ν = j=1 log 1

1−|zj|2

1−pδzj, i.e.

β∈Tn:β≥α

zj∈Tβ

log 1 1− |zj|2

1−p

p

(31)

=

β∈Tn:β≥α

Iν (β)p

≤ CpIν (α) = Cp

zj∈Tα

log 1 1− |zj|2

1−p

<∞, α ∈ Tn.

If we now also discretize (29), we see that we must prove

β∈Tn:β≥α

Iµ (β)p ≤ CpIµ (α) <∞, α ∈ Tn,

where

µ (β) = 1− |cβ|2 ng (β)

p

, g (β) =

Kα

|g| dλn, Iµ (α) =

β∈Tn:β≥α

µ (β) ,

for all g = i=1aigi as above. Since ν = j=1 log 1

1−|zj|2

1−pδzj satisfies the tree condition, it suffices to prove

β∈Tn:β≥α

Iµ (β)p ≤ CpIν (α) , α∈ Tn. (32)

Indeed, (32) shows that µ+ν satisfies the tree condition , and now the equivalence with the Carleson embedding on the tree shows that µ satisfies the tree condition as well (since the Carleson embedding is preserved for smaller measures).

Now g = i=1aigi where the supports of the gi = gzi are pairwise disjoint by

Now we use (30) to dominate the last sum above by

C

where the final inequality follows from (31). This establishes (32), and completes the proof of Lemma 9.

With this done, we have completed the proof that (6) implies (4) for 1 < p <

∞.

We now prove that (3) implies (4) for p > 2n. For this we will argue as above but with Lemma 5 replaced by Lemma 6, and with Lemma 9 replaced by the following analogue.

Proof. Inequality (33) follows from estimate (15),

Bn

as follows. Fix an index i. From Remark 2 we see that the support of gzi is essentially the union of a geodesic segment of Bergman kubes K1i, K2i, ..., KMi i where

Mi ≈ (α − ρ) log 1 1− |zi|2.

Indeed, recall that the support gzi is contained in the intersection of the cone Czi

and the annulus Azi. Now for ζ in the cone Czi, we have 1 − ζ · P zi ≈ 1 − |ζ|2, and thus for ζ in the annulus Azi as well, we have approximately

log 1

1− |ζ|2 ∈ ρ log 1

1− |zi|2, α log 1 1− |zi|2 .

Thus ζ ∈ supp gzi lies in the union of those kubes in Tnalong the geodesic joining the root to the “boundary point” P zi, and having tree distance from the root lying roughly between ρβ (0, zi) and αβ (0, zi). Moreover, this segment can be contin-ued to a longer sequence of adjacent Bergman kubes K1i, K2i, ..., KMi i, ...KJii = Kzi

connecting the support of gzi to the kube Kzi containing zi, and where Ji ≈ log 1

1− |zi|2. (35)

Choose wj ∈ Kji for 1 ≤ j < Ji. Then we have for z ∈ Kmi , 1 ≤ m ≤ Mi, and f ∈ Bp(Bn),

|f (z)|p= [f (z)− f (wm)] +

Ji−1

j=m

[f (wj)− f (wj+1)] + [f (wJi)− f (zi)] + f (zi)

p

 |f (z) − f (wm)|p+ (Ji)p−1

Ji−1

j=1

|f (wj)− f (wj+1)|p +|f (wJi)− f (zi)|p+|f (zi)|p

≤ C (Ji)p−1

Ji

j=1

max

z1,z2(Kji)|f (z1)− f (z2)|

p

+ C|f (zi)|p.

Using this together with (34), (35) and the fact that the supports of the gzi are pairwise disjoint, we obtain

Bn

|f (z)|p 1− |z|2 ng (z) pn(z)

≤ C

i Ji

j=1

max

z1,z2(Kji)|f (z1)− f (z2)|

p

+C

i

|f (zi)|p log 1 1− |zi|2

1−p

.

Since the kubes Kji are pairwise disjoint by Lemma 4, the first term on the right is dominated by

α∈Tn

z1max,z2∈Kα|f (z1)− f (z2)|

p

≤ C f pBp(Bn)

by Theorem 6.30 of [Zhu]. The second term is dominated by C f pB

p(Bn) since we are assuming in (3) that i log 1

1−|zi|2

1−pδzi is a Bp(Bn)-Carleson measure.

This completes the proof of Lemma 10.

Arguing as above, the proof that (3) implies (4) will follow from the char-acterization of Carleson measures on trees, together with Lemma 6 provided we show that (11) holds and that

1− |z|2 ng (z)

p

n(z)

is a Bp(Bn)-Carleson measure. From the definition of gi in (16), and the fact that the supports of the gi are pairwise disjoint by the separation condition, we have that (11) holds. Lemma 10 above shows that 1− |z|2 ng (z) pn(z) is a Bp(Bn)-Carleson measure for p > 2n, and this completes the proof that (3) implies (4) for p > 2n.

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