行政院國家科學委員會專題研究計畫 成果報告
T-S 模糊系統估測器輸出回授 H∞ 控制之研究(I)
研究成果報告(精簡版)
計 畫 類 別 : 個別型
計 畫 編 號 : NSC 96-2221-E-151-056-
執 行 期 間 : 96 年 08 月 01 日至 97 年 10 月 31 日
執 行 單 位 : 國立高雄應用科技大學電機工程系
計 畫 主 持 人 : 方俊雄
計畫參與人員: 碩士班研究生-兼任助理人員:邱德議
碩士班研究生-兼任助理人員:爐啟銓
碩士班研究生-兼任助理人員:黃信源
碩士班研究生-兼任助理人員:許聖雨
博士班研究生-兼任助理人員:曾冠瑄
報 告 附 件 : 出席國際會議研究心得報告及發表論文
處 理 方 式 : 本計畫涉及專利或其他智慧財產權,2 年後可公開查詢
中 華 民 國 97 年 11 月 02 日
行政院國家科學委員會專題研究計畫成果報告
T-S模糊系統估測器輸出回授H
∞控制之研究
Observer-based output feedback H
∞control for T-S Control
計畫編號:
NSC-96-2221-E-151-056
執行期限:96年8月1日至97年7月31日
主持人:方俊雄教授 國立高雄應用科技大學 電機系
參與計畫人員:曾冠瑄、邱德議、爐啟銓、黃信源、許聖雨
一、 中文摘要 本計畫針對T-S模糊系統,探討以觀測器為基礎 的H∞控制問題,根據Lyapunov function的精神,配合 LMI觀念,結合本研究室所研發的三指標,改善文獻 中關於觀測器輸出回授H∞控制器設計條件之寬鬆 度,當考慮觀測器含有雜訊項時,本論文的結果不但 比文獻中的條件更寬鬆,也證明現有文獻的結果是本 論文的特例情形。當考慮觀測器不含系統雜訊項時, 條件的型式更加複雜,必須透過兩階段才能使用LMI 求解,如果要簡化成一階段求解,本文引入等式限 制,成功避開兩階段求解的麻煩。 關鍵字:T-S模糊系統,線性矩陣不等式,H∞控制。 AbstractThe observer-based H∞ control problem for T-S fuzzy
systems is solved in the project. By Lyapunov stability and the three index combination technique, a new nonlinear matrix inequality condition for the existence of an
observer-based H∞ controller is derived. To solve
controllers with LMI algorithms, a set of LMI conditions which are necessary and sufficient to the derived nonlinear condition are developed as well. It can be shown that the present result is more relaxed than the existing ones and includes them as special cases.
Keywords—T-S fuzzy systems, linear matrix inequality
(LMI), H∞ control.
二、緣由與目的
Fuzzy sets and systems have gone through substantial development since the introduction of fuzzy set theory by Zadeh in 1965 [18]. There have been a great variety of successful applications in the area of image processing, industrial applications, medicine, finance, control engineering and so on in the literature [1,2,6,10,17,19]. In particular, the T-S fuzzy model, also called the Type-III fuzzy model by Sugeno [11,12], is recognized as a powerful tool. For example, it offers an alternative approach to describing nonlinear systems [20]. By using the fuzzy model, lots of nonlinear control problems can be solved easily [13,15,16]. Therefore, considerable attention has been paid to the analysis and synthesis of T-S fuzzy systems, and various techniques have been developed during the decade [4,14].
The H∞ control problem of T-S fuzzy systems has been
investigated by many authors recently. For example, the
papers [3,7,8,9] and the references therein solved the H∞
control problem via fuzzy observer-based feedback control. Among which, the result of [8] is quite interesting. It introduced a new type of observer and developed a nonlinear condition for the existence of controllers. For obtaining controllers, a sufficient LMI condition was proposed and solved by a two-step procedure. Later on, the reference [7] proposed an improved result, in which an LMI condition equivalent to the nonlinear condition was developed. By the LMI conditions, the controller and observer can be obtained simultaneously. Thus remove the drawback of two-step procedure in [8].In our paper, a new nonlinear condition which is more relaxed than that of [8] is proposed. An LMI condition which is equivalent to our nonlinear condition is also given. The present LMI condition is more relaxed than those of [7] and [8]. Such improvement on relaxization makes possible for finding
a controller achieving a better H∞ performance and
allowing a larger size of uncertainties for robust control. 三、結果與討論
1. Preliminaries
Consider a nonlinear system that is represented by the following T-S fuzzy model:
Plant Rule i : If θ1(t) is Mi1 and … and θs(t) is Mis
Then
( )
( )
( )
( )
( )
( )
( )
( )
( )
( )
i wi ui zi ui yi yix t
A x t
B w t
B u t
z t
C x t
D u t
y t
C x t
D w t
⎧
=
+
+
⎪
=
+
⎨
⎪
=
+
⎩
(1)In (1), Mij (i = 1,2,…,r, j = 1,2,…,s) is the fuzzy set and
r is the number of If-Then rules. θi(t), i=1,2,…,s are the
premise variables which are measurable. is
the state vector, the exogenous disturbance,
n
x
∈
w mw
∈
pz
∈
the controlled output, the outputvector, and the control input vector. Assume
q
y
∈
u mu
∈
,
n n iA
∈
× and,
u n m uiB
∈
× n mw,
wiB
∈
×,
p n ziC
∈
× p mu,
uiD
∈
× q n,
yiC
∈
×w q m yi
D
∈
× . Given a pair of (x(t), u(t)), the finaloutput of the fuzzy system is inferred as follows:
(
)(
1( )
r i( )
i( )
wi( )
ui( )
i)
x t
=
∑
h
θ
t
A x t
+
B w t
+
B u t
(
)(
)
( )
r i( )
zi( )
ui( )
z t
=
∑
h
θ
t
C x t
+
D u t
(
)
(
)
1( )
( )
( )
r i( )
yi yi iC x t
D w t
y t
h
θ
t
=+
=
∑
or simplicity is replaced by in the
equel.
efinitions: If w(t) = 0, the system (2) is termed to be
e”. A distu s
e quadratically stable if there exists a
m (2) is = 1 i= (2) where F ,
h
i(
θ
( )
t
)
h
i s D“disturbance-fre rbance-free fuzzy ystem is
said to b
P
>
0
such that
V
(
x t <
( )
)
0
, where(
( )
)
T( )
( )
V
x t =
x t Px t
. If u(t) = 0, the systetermed to be “unforc scribed scalar
0
ed”. Given a pre
γ
>
, if for anyw t
(
)
square integrable signals), the response z(t) of the unforced fuzzy system
2
( )
∈
L
0, ,
∞
mw (the set ofi satisfie
then the unforced fuzzy system (2) is said to with
(2), under zero init al condition, s 2 0
( ) ( )
0( ) ( )
T Tz t z t dt
γ
w t w t dt
∞ ∞<
∫
∫
(3) be stableγ
-disturbance attenuation.Consider the observer model same as in [7,8]
(4)
i
u t
=
∑
h K x t
(5)where and are the controller gains a
observer gains to be determined. Den
errors as and construct an
ted
is
i) The unforced fuzzy system (6) is stable with
Assume the fuzzy controller is
1 i i=
ˆ
( )
r( )
iK
L
i ndote the estimation
ˆ
( )
( )
( )
e t
≡
x t
−
x t
augmen system (6)γ
-disturbance attenuation. The ffor the ease o son with our result
from a theo
L real number
ollowing is the main result of [8]. It is stated here f relaxization compari
retic viewpoint in next section.
emma 1 [8] : For a given
γ
>
0
, thecontrol objectives can be achieved if there exist matrices
0
X
>
,G
>
0
,K
i ,L
i,Z
ii,i
=
1,2,...,
r
,Z
ij, T ji ijZ
=
Z
,i
=
1, 2,...,
r
−
1
,j i
= +
1,...,
ch that ther
su T T ii ii wi wi ui i T T T i ui ii ii V X XV X B X XB Kfollowing matrix inequalities hold
, 1, 2,..., , ii B 2 Z K B X G G − ⎡ + + ⎤ ⎢ − Γ + Γ ⎥ ⎣ ⎦ i r γ − < = (7) ( )
(
)
(
( ))
( )(
)
(
( ))
1(
( ))
1 , s i i r i j i i t h t t M t t β θ θ β θ β θ = = =∏
∑
(
)
(
)
(
)
2 , , T T T ij ij wi wj wj wi ui j uj i T ij ij T T T T T i uj j ui ij ij V X XV X B B B B X X B K B KThe objectives of the observer-based
H
∞ control are(i) The disturbance-free fuzzy system (6) quadratically stable. Z Z K B K B X G G j i γ− ⎡ + + + − + ⎤ ⎢ ⎥ ≤ + ⎢ − + Γ + Γ ⎥ ⎣ ⎦ > (8) (9) WhereVii =Ai+B K Vui i, ij =Ai+Aj+B Kui j+B Kuj i, L C , A A L C L C U, ii Ai i yi ij i j i yj j yi ik Γ = + Γ = + + + =
[
C
zi+
D K
ui k−
D K
ui k]
.Note that the inequalities (7)-(9) are actually nonlinear
with respect to and . In order to solve and
with LMI algorithms, following the idea of [3,9], it
o-s ce la
by
sufficient to our developed
i
K
L
iK
ii
L
the paper [8] presented another sufficient condition and then proposed a two-step procedure to solve . The
drawback of tw tep pro dure was overcome tterly
[7], in which a set of LMI conditions were developed and was proved to be equivalent to the nonlinear matrix conditions of [7]. In next section, a new nonlinear condition that is more relaxed than Lemma 1 is proposed. A new LMI condition necessary and
nonlinear condition is also derived for obtaining the gains in one step. Actually, we will show the present result is more relaxed than those of [8] and [7] and includes them as special cases.
2. Main results
Lemma 2 : For a given positive number
γ
>
0
, thecontrol objectives can be achieved if there e
ij θj 1 i= xist matrices
X
>
0
,G
>
0
,K
i ,L
i ,Y
iii ,1, 2, ,
i
=
…
r
;Y
jii=
Y
iijT ,Y
iji ,i
=
1
, 2,
,
r
,( )
(
)
1 ˆ ( ) ˆ( ) ( ) ( ) ( ) ( ) ˆ r i i wi ui i i t h A tx B w t B u t L y t y t x = = + + −(
)
ˆ( ) r i yiˆ( ) yi ( .) y t =∑
h C x t +D w t − 1 1 0 ( ) . ( ) i ui j ui j j i i yj zi ui j ui j i j i j B A L C x t K D K e t = = ⎜∑
…
j i
≠
,j
=
1, 2, ,
…
r
,Y
ji=
Y
ijT ,Y
j i=
Y
i jT , T2
2
ij jiY
=
Y
,i
=
1, , ,
r
−
1 1 ( ) ( ) ( ) ( ) ( ) 0 ( ) r r wi i i j r r A B K K x t x t B h h w t e t e t C D z t h h = = ⎛⎡ + − ⎤ ⎞ ⎡ ⎤= ⎡ ⎤ ⎡+ ⎤ ⎟ ⎢ ⎜ + ⎥ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎟ ⎣ ⎦ ⎝⎣ ⎦⎣ ⎦ ⎣ ⎦ ⎠ ⎡ ⎤…
,j i
= +
1, ,
…
r
−
1
,1, ,
j
r
=
+ − ⎢ ⎥ ⎣ ⎦ ⎣ ⎦ 11 1 1 1 0, 1, 2, , , T r ik T T r rr rk T k rk Z Z U k r Z Z U U U I ⎡ ⎤ ⎢ ⎥ ⎢ ⎥ < = ⎢ ⎥ ⎢ ⎥ − ⎢ ⎥ ⎣ ⎦ … = ⎡ ⎤∑∑
∑∑
+ …
such that the llowing matriinequa old
fo x
,
1, 2, ,
iiY i
iiir
Λ <
=
…
) ii ijΛ + Λ + Λ
(10,
ji≤
Y
iij+
Y
iji+
Y
iiji
=
…
r
,
1, 2, ,
T,
1, 2, ,
j i j
≠
=
…
r
…
…
,r
(11),
1, 2, ,
2,
1, 2, . ,
ij i ji j i j ij i j ji T T T ij i j jiY
Y
Y
Y
Y
Y
i
r
j i
Λ + Λ + Λ + Λ + Λ + Λ ≤
+
+
+
+
+
=
−
= +
1,
1, 2, ,
r
−
= +
j
…
(12) 1 1 1 1 1 10
1, 2, ,
T j jr j T rj rjr rj j rjY
Y
U
j
r
Y
Y
U
U
U
I
⎡
⎤
⎢
⎥
⎥
⎢
<
=
⎢
⎥
⎢
⎥
−
⎢
⎥
⎣
⎦
…
(13) where T T T i i j ui T T yj i i yj A X XA K B X XB K XB K XB B X A G GA K B X C L G GL Cγ
− ⎡ + + − ⎤ ⎢+ + ⎥ ⎢ ⎥ Λ = + + − + ⎢ ⎥ ⎣ ⎦ 2 T T T i i j ui ui j T ui j wi wj ij ⎢ ⎥ ⎢ ⎥[
]
ik zi ui k ui k U = C +D K −D K .In what follows, we are going to show that Lemma 2 is more relaxed than Lemma 1 and includes it as a special case.
ossible for finding a controller achieving a b
Theorem 1: The set of solutions to (7)-(9) in Lem
ma 1 is a subset of solutions to (10)-(13) in Lemm a 2.
Remark 1: Since Lemma 2 is more relaxed than L
emma 1, the controller set obtained by Lemma 2 is lager than that of Lemma 1. This improvement m akes p
etter H∞ control performance and allowing a bigger size of uncertainties for robust control. This will b e demonstrated in the numerical example section.
Theorem 2 : For a given positive number
γ
>
0
,there exist matrices
X
>
0
,G
>
0
,K
i,L
i,iii
Y
,i
=
1, 2, ,
…
r
,Y
jii=
Y
iijT,Y
iji,i
=
1, 2
, , r
…
,j i
≠
,j
=
1, 2, ,
…
r
,Y
ij ,Y
ji=
Y
ijT ,Y
ji=
Y
i jT , , T ij jiY
=
Y
i
=
1, 2, ,
…
r
−
2
,j i
= +
1, ,
…
r
−
1
,1, ,
j
r
= + …
, such that the matrix inequalities (10)-(13) hold if and only if there exist matrices
X
>
0
,0
Y
>
,M
i , , , , ,i iii
Q
iii ,T
jii
=
Q
iij ,P
iji ,Q
iji ,i
=
1, 2, ,
…
r
,J
P
i
=
1, 2, ,
…
r
T jii iijP
=
P
Q
j i
≠
,j
=
1, 2, ,
…
r
,=
, T T , T j i i j , T ji ijP
P
ji ijQ
=
Q
, , , ji ijP
=
P
Q
=
Q
T ij jiP
=
P
T ij jiQ
=
Q
i
=
1, 2, ,
…
r
−
2
,j i
= +
1, ,
…
r
−
1
,1, ,
j
r
= + …
such that the following matri inequalities hold x 2 , 1,2 , T T T T i i i ui ui i wi wi iii XA A X M B B B B P i r γ− + + + + < = … (14) M , T i iJ +J Ci yi<Qiii (15) 1, 2 , T T i i y A Y YA C i r + + = …(
)
(
)
(
)
(
)
(
)
2 2 2 1, 2 , , 1, 2 T T T T T i j i j i ui uj T T j ui ui uj i ui j T T T wi wi wi wj wj wi iij X A A A A X M B B M B B B M B M , T iji iij B B B B B B P i r i j j rγ
− + + + + + + + + + + + + ≤ = … ≠ = … (16) P P + +(
)
(
)
(
)
(
)
2 2 , 1, 2 , , 1, 2 T T T T T i j i j yi i j T T yj i i j yi i yj Tiij iji iij
A A Y Y A A C J J C J J J C J C Q Q Q i r i j j + + + + + + + + + ≤ + + = … ≠ = …r (17)
(
)
(
)
(
)
2 2 2 1, 2 T T T T T i j i j j ui T T T T T T T T T T uj i uj uj i u j u ui j ui uj i uj u i u j T T T T wi wj wi w wj wi wj w T T w wi w wj T T T ij i j ji ij i j ji X A A A A A A X M B M B M B M B M B M B B M B M B M B M B M B M B B B B B B B B B B B B P P P P P P i r γ− + + + + + + + + + + + + + + + + + + + + + + + ≤ + + + + + = … −2, j i= +1…r−1, = +j 1…r (18)(
)
(
)
2 2 1, 2 2, 1 1, 1 T T T T T i j i j yj i T T T T T T T T T T y i yi j y j yi yj i i y j yi yi yj T T T ij i j ji ij i j ji yj A A A Y Y A A A C J C J C J C J C J C J J C J C J C J C J C Q Q Q Q Q Q i r j i r j + + + + + + + + + + + + + + + + ≤ + + + + + = … − = + … − = + …r (19) 1 1 1 1 1 1 1 1 0, 1, 2, T T T k kr z k T T T rk rkr zr k ur z u k zr ur k P P XC M P P XC M C X D M C X D M I k r ⎡ + ⎤ ⎢ ⎥ ⎢ ⎥ < ⎢ + ⎥ ⎢ ⎥ + + − ⎢ ⎥ ⎣ ⎦ = … u D D (21)In this case, the controller gains and the observer gains can be chosen as (20) 1 1 1 1 0, 1,2, k kr rk rkr Q Q k r Q Q ⎡ ⎤ ⎢ ⎥ < = ⎢ ⎥ ⎢ ⎥ ⎣ ⎦ … . 1
and
1,
1, 2, ,
i i i iK
=
M X
−L
=
Y J i
−=
…
r
(22)Consider a nonlinear system [13]
(
2)
1 1 3 2 3( )
( ) sin ( ) 0.1 ( )
( ) 1 ( )
( )
( ) 2 ( ) 3 ( )
( )
3. A numerical examplex
2 3 1 2 1 2( ) sin ( )
( )
( )
t
x t
x t
x t
x t
u t
w t
x t
x t
x t
w t
=
+
−
+
+
+
=
−
+
x t
=
x t
−
x t
+
w t
(
1 2)
1 1 2 2 1 ( ) ( ) 2.3 ( ) ( ) ( ) 1 ( ) 0.5 ( ) ( ) ( ) 0.5 ( ). z t x t u t y t x t x t w t y t x t w t = + = + + = + Assumex t
1( )
∈ −
[
a a
]
,
x t
2( )
∈ −
[
b
b
]
,where a and b are positive numb e two parameters
will be also used later to test the conservativeness of conditions. The premise membership functions and the
nt matrices are ers. Th conseque 2 1 11 2 21
,
x
M
M
a
=
=
M
31= −
1
M
11=
M
41,
2 2sin
sin
0
(
b
x
x
b
x
x b
M
M
−
⎧
≠
⎪
=
= ⎨
2 2 12 32 2sin )
,
0
b
x
−
⎪
=
⎩
+
⎢
⎥
= ⎢
⎥
⎢
⎥
⎣
⎦
1
0
0
ya
C
= ⎢
⎡
+
⎤
⎥
⎣
⎦
b b
A
b b
⎡
⎤
⎢
⎥
= ⎢
⎥
⎢
⎥
⎣
⎦
⎥
⎦
⎥
⎦
1
221
12 42,
M
= −
M
=
M
11
1
-0.1
,
2
3
0
0
1
-1
A
⎡
⎤
⎢
⎥
=
⎢
−
⎥
⎢
⎥
⎣
⎦
2 11
,
0
0
ua
B
⎡
⎤
2 10 1
0
,
-1
21 sin( ) /
-0.1
,
2
-3
0
0 sin( ) /
2 21
,
0
0
ua
B
⎡
+
⎤
⎢
⎥
= ⎢
⎥
⎢
⎥
⎣
⎦
2 20 1
0
,
1
0
0
ya
C
= ⎢
⎡
+
⎤
⎥
⎣
⎦
31 1 -0.1
,
2 -3
0
0 1
-1
A
⎡
⎤
⎢
⎥
= ⎢
⎥
⎢
⎥
⎣
⎦
31
,
0
0
uB
⎡ ⎤
⎢ ⎥
= ⎢ ⎥
⎢ ⎥
⎣ ⎦
30 1 0
,
1 0 0
yC
= ⎢
⎡
⎤
⎣
41 sin( ) /
-0.1
,
2
-3
0
0 sin( ) /
-1
b b
A
b b
⎡
⎤
⎢
⎥
= ⎢
⎥
⎢
⎥
⎣
⎦
41
,
0
0
uB
⎡ ⎤
⎢ ⎥
= ⎢ ⎥
⎢ ⎥
⎣ ⎦
40 1 0
,
1 0 0
yC
= ⎢
⎡
⎤
⎣
[
]
1 2 3 41 1 1
,
T w w w wB
=
B
=
B
=
B
=
[
]
1 2 3 42.5 3 0
,
z z z zC
=
C
=
C
=
C
=
Du1 = Du2 = u3 = Du4 = 0.001, Dy1 = D = D = D = 0.005. In thissimulation, assume
a
=
1.4 and
b
=
0.7
. ByTheorem 2, choosing D y2 y3 y4
0.2
γ
=
[
]
[
]
[
]
[
3 4 7732 -0.3923 , , -10.8100 -1.1630 0 1041 -10.1789 -1.077 K = K = -3.8066 -0.60 -3.9595 L]
1 -6.6894 -0.4333 0.0397 , 2 -6. 0.0390 , . 4 0.0990 K = K = 41 -0.5219 -0.3339 0.6601 -0.2907 0.6559 -1.4381 -16.5338 -1.4346 -16.2066 , -4.4155 -2.6641 -3.9927 -2.5747 -0.8670 0.6159 L L L 1 2 3 4 -1.5494 -16.7745 -1.5705 -16.6232 , , ⎡ ⎤ ⎡ ⎤ ⎢ ⎥ ⎢ ⎥ =⎢ ⎥ =⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎣ ⎦ ⎣ ⎦ ⎡ ⎤ ⎢ ⎥ =⎢ ⎥ = ⎢ ⎥ ⎣ ⎦ . -0.7884 0.6053 ⎡ ⎤ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎣ ⎦Finally, we compare the conservativeness of Theorem with [7] and [8]. For the above numerical example, the maximal interval of the positive parameter a such that the conditions are feasible is given Table 1. Our result allows the largest interval for three different cases.
2
Table 1 the maximal allowable interval of a by using
different conditions cases Theorem 2 [7] [8]
0 a
, we obtain0.2
γ
=
b
=
0.01
7132042
≤
0 a
< ≤ 0 a
< ≤
1931000
1421000
<
0 a
0.2
γ
=
b
=
π
/ 2
1527433
≤
0 a
< ≤
1126768
0
935466
a
< ≤
<
0.1
γ
=
b
=
2
0
2200000
a
< ≤
0
430414
a
< ≤
0
226590
a
< ≤
Since our condition is the mo relaxed, e designed controller may achieve a better control H∞ performance which is demonstrated as follows.
ble 2 the comparison of H∞ control performance by
st th
Ta
using different design approaches
Theorem 2 [7] [8] a=4358774, b=0.01
γ
=0.198γ
=0.4γ
=1.5 a=1527433,/ 2
b
=
π
γ
=0.2γ
=1.87γ
=3.2 a=610558, b=2γ
=0.06γ
=0.2γ
=1.2 Fig. 1 show t system whenhe state response of the closed-loop fuzzy the initial condition is [0.7 0.5 0.1]T an
− d
bance gi w t tsin
w(t) is a distur ven by ( ) 0.5e−0.5 (5 tπ ).
olid line denotes th ariab e dotted line
enotes the observer state.
= le, th
The s e state v
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 0 Time (Sec) -0.1 0.1 0.4 0.3 0.2 0.5 0.6 0.7 (a)
ˆx
1andx
1 0 0.5 1 1.5 2 2.5 3 0 Time (Sec) 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0.5 (b)ˆx
2andx
2 0 1 2 3 4 5 6 7 -0.1 -0.05 0 0.05 0.1 0.15 0.2 Time (Sec) 0.25 (c)ˆx
3andx
3Fig. 1 Responses of the state and its estimation 四、計畫成果自評
In this project, a new nonlinear matrix inequality
condition for the existence observer-base control
of T-S fuzzy systems is developed. The condition is shown to be more relaxed than [
H
∞8] and include it as a
special case. For solving the observer and the controller via LMI algorithms by one step, a set of LMI conditions necessary and sufficient to the new developed nonlinear condition is also derived. Our LMI condition is more relaxed than that of [7] since the result of [7] is only equivalent to the nonlinear condition of [8].
計畫的成果已經發表在2007年中華民國第十五屆 模糊理論及應用研討會:H.-W. Chen, S.-W. Kau, C.-C
Lu, T.-Y. Chiu, C.-H. Fang, “Observer-based H∞ fuzzy control design,” 中華民國第十五屆模糊理論及應用 研討會, Dec.14-15, pp. 376-381, 2007. 目前正在整理 投稿的國際期刊上
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