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Chapter 4
Subspaces in R m
Rm , 線性 Rm ( 性),
Proposition 1.2.3 8 , vector space. Rm
vector space, Rm subspace. Rm subspaces
性 .
4.1. Subspace and basis
, subspace basis .
Rm V , Rm , Proposition 1.2.3 8
(3), (4) ( O∈ V v∈ V, −v ∈ V) 性 ,
線性 性 ( V 線性 V ), v∈ V,
O =0v∈ V −v = (−1)v ∈ V. V 線性 性
Proposition 1.2.3 8 , Rm vector space
. .
Definition 4.1.1. V Rm . V 線性
V ( v1, . . . , vn∈ V c1, . . . , cn∈ R c1v1+··· + cnvn∈ V), V
Rm subspace ( ).
/0 subspace. Rm {O} Rm
subspace, Rm Rm subspace.
, Span(v1, . . . , vn) Rm v1, . . . , vn 線性 ( Definition 1.3.1),
Span(v1, . . . , vn) ={v ∈ Rm| r1v1+··· + rnvn, for some r1, . . . , rn∈ R}.
V Rm subspace v1, . . . , vn∈ V
Span(v1, . . . , vn)⊆ V. (4.1) 69
V subspace, V 線性
V , . , , 線性
.
Proposition 4.1.2. V Rm , V Rm subspace O∈ V
u, v∈ V, r ∈ R u + rv∈ V.
Proof. (⇒) : V , v∈ V. 0v = O, subspace
0v∈ V, O∈ V. subspace , u, v∈ V, r ∈ R
u + rv∈ V.
(⇐) : O∈ V u, v∈ V, r ∈ R u + rv∈ V. O∈ V, V Rm
. (4.1), v1, . . . , vn∈ V, Span(v1, . . . , vn)⊆ V.
數 n 數學 . ( n = 1),
v1∈ V, Span(v1) ⊆ V. Span(v1) rv1 ,
r ∈ R rv1∈ V. u = O, v = v1, rv1 = O + rv1=
u + rv. u + rv∈ V, n = 1 . n = k ,
v1, . . . , vk ∈ V Span(v1, . . . , vk)⊆ V. v1, . . . , vk, vk+1∈ V Span(v1, . . . , vk, vk+1)⊆ V. w∈ Span(v1, . . . , vk+1), c1, . . . , ck, ck+1∈ R
w = c1v1+··· + ckvk+ ck+1vk+1. u = c1v1+··· + ckvk, u∈ V.
r = ck+1∈ R v = vk+1∈ V, w = u + rv∈ V, Span(v1, . . . , vk+1)⊆ V.
數 學 , v1, . . . , vn ∈ V Span(v1, . . . , vn)⊆ V, V Rm
subspace.
Proposition 4.1.2, V subspace,
(1) O∈ V
(2) u, v∈ V, r ∈ R ⇒ u + rv ∈ V.
.
Example 4.1.3. a, b, c, d∈ R, S ={(x,y,z) ∈ R3 | ax + by + cz = d}.
a, b, c, d S R3 subspace. S subspace, (x, y, z) = (0, 0, 0) = O∈ S,
d = 0. , d = 0 u = (x, y, z)∈ S, v = (x′, y′, z′)∈ S r∈ R, ax + by + cz = 0, ax′+ by′+ cz′= 0
a(x + rx′) + b(y + ry′) + c(z + rz′) = (ax + by + cz) + r(ax′+ by′+ cz′) = 0,
u + rv = (x + rx′, y + ry′, z + rz′)∈ S. d = 0 d = 0 , S R3 subspace.
Example 4.1.3 , a, b, c, d 0 S =R3, R3 subspace.
Rm subspaces, Proposition 1.3.2 v1, . . . , vn∈ Rm, Span(v1, . . . , vn) Rm subspace ( Rm subspace ).
4.1. Subspace and basis 71
m×n matrix A. A column vectors , A column
space. a1, . . . , an∈ Rm A column vectors, Span(a1, . . . , an) A column space.
A row vectors , A row space. A m× n matrix,
column space Rm subspace, row space Rn subspace.
A subspace, homogeneous linear system Ax = O
, {x ∈ Rn| Ax = O}. x = O∈ Rn Ax = O . x = u∈ Rn,
x = v∈ Rn Ax = O , r∈ R,
A(u + rv) = Au + rAv = O,
x = u + rv Ax = O . proposition 4.1.2 {x ∈ Rn| Ax = O} Rn
subspace, A nullspace.
Rm standard basis e1, . . . , em, Rm
e1, . . . , em 線性 , . standard basis ,
Rm , Rm 性 . Rm
subspace 性 , .
Definition 4.1.4. V Rm subspace. v1, . . . , vn∈ V, v∈ V, c1, . . . , cn∈ R c1v1+··· + cnvn= v, v1, . . . , vn V basis ( ).
Definition 4.1.4 basis ,
basis , .
v1, . . . , vn∈ Rm column vectors m× n matrix A, A =
v 1 v2 ··· vn
.
v = c1v1+··· + cnvn x1= c1, . . . , xn= cn Ax = v , v∈ V, c1, . . . , cn∈ R c1v1+··· + cnvn= v, v∈ V
Ax = v . 性 .
Proposition 4.1.5. V Rm subspace v1, . . . , vn∈ V. A v1, . . . , vn
column vectors m× n matrix. v1, . . . , vn V basis v∈ V,
Ax = v .
, m× n matrix A v∈ V, Ax = v
, A column vectors V basis. A column vectors
V . V basis vectors V .
, V Rm standard basis , standard basis
Rm subspace basis, basis !
v1, . . . , vn, Proposition 4.1.5 前學
v1, . . . , vn V basis.
, basis.
v1, . . . , vn ∈ V, V Rm subspace, Span(v1, . . . , vn)⊆ V.
v1, . . . , vn V basis , v∈ V c1, . . . , cn∈ R v =
c1v1+··· + cnvn, v∈ V v∈ Span(v1, . . . , vn). V ⊆ Span(v1, . . . , vn),
V = Span(v1, . . . , vn). 性 v1, . . . , vn, .
Definition 4.1.6. V Rm subspace. v1, . . . , vn∈ Rm Span(v1, . . . , vn) = V , v1, . . . , vn V spanning vectors.
v1, . . . , vn V spanning vectors, v1, . . . , vn∈ V. v1, . . . , vn∈ Span(v1, . . . , vn), V = Span(v1, . . . , vn) v1, . . . , vn∈ V.
v1, . . . , vn V basis , v∈ V c1, . . . , cn∈ R
c1v1+··· + cnvn= v, V subspace, O∈ V, v = O ,
c1, . . . , cn∈ R c1v1+···+cnvn= O. c1=··· = cn= 0 c1v1+···+cnvn= O,
性 , c1, . . . , cn∈ R c1v1+··· + cnvn= O. 言 ,
c1=··· = cn= 0 c1v1+··· + cnvn= O. 性 v1, . . . , vn, .
Definition 4.1.7. v1, . . . , vn∈ Rm. v1, . . . , vn c1=··· = cn= 0 c1v1+··· + cnvn= O, v1, . . . , vn linearly independent.
A v1, . . . , vn column vectors m× n matrix, v1, . . . , vn linearly independent homogeneous linear system Ax = O nontrivial solution.
x1= c1, . . . , xn= cn Ax = O nontrivial solution, c1, . . . , cn 0 c1v1+··· + cnvn= O, v1, . . . , vn linearly independent .
spanning vectors linear independence 性 , .
, v1, . . . , vn∈ V V basis, v1, . . . , vn V
spanning vectors linearly independent. basis ,
.
Proposition 4.1.8. V Rm subspace v1, . . . , vn∈ V. v1, . . . , vn V basis v1, . . . , vn V spanning vectors linearly independent.
Proof. v1, . . . , vn V spanning vectors linearly independent
v1, . . . , vn V basis. Proposition 4.1.5, A v1, . . . , vn
column vectors m× n matrix, v∈ V, Ax = v
. v1, . . . , vn V spanning vectors, v1, . . . , vn∈ V, A column vectors V , Lemma 3.4.1 V = Span(v1, . . . , vn) v∈ V,
Ax = v . v1, . . . , vn linearly independent, homogeneous
4.2. Spanning Vectors and Linear Dependence 73
linear system Ax = O nontrivial solution. Theorem 3.4.6
Ax = v . Proposition 4.1.5 v1, . . . , vn V basis.
Question 4.1. V Rm subspace v1, . . . , vn∈ V. A v1, . . . , vn column
vectors m× n matrix. v1, . . . , vn V basis, A column space ? A
nullspace ?
4.2. Spanning Vectors and Linear Dependence
spanning vectors linear independence . ,
步 性 .
4.2.1. Spanning Vectors. Rm subspace V , v1, . . . , vn∈ Rm, V spanning vectors v1, . . . , vn∈ V. V spanning vectors,
V .
, 數 , spanning vectors . Corollary
3.4.4 , n < m ,Rm n Rm spanning vectors.
v1, . . . , vn 數 , vn+1 subspace Span(v1, . . . , vn, vn+1) subspace Span(v1, . . . , vn), 大,
subspace 大.
Lemma 4.2.1. v1, . . . , vn, vn+1∈ Rm. Span(v1, . . . , vn)⊆ Span(v1, . . . , vn, vn+1), Span(v1, . . . , vn)̸= Span(v1, . . . , vn, vn+1) vn+1̸∈ Span(v1, . . . , vn).
Proof. Span(v1, . . . , vn, vn+1) Rm subspace, v1, . . . , vn∈ Span(v1, . . . , vn, vn+1), (4.1)
Span(v1, . . . , vn)⊆ Span(v1, . . . , vn, vn+1). (4.2) vn+1∈ Span(v1, . . . , vn), Span(v1, . . . , vn) Rm subspace, v1, . . . , vn, vn+1∈ Span(v1, . . . , vn)
Span(v1, . . . , vn, vn+1)⊆ Span(v1, . . . , vn). (4.3) (4.2), (4.3)
Span(v1, . . . , vn) = Span(v1, . . . , vn, vn+1).
Span(v1, . . . , vn)̸= Span(v1, . . . , vn, vn+1) vn+1̸∈ Span(v1, . . . , vn).
, vn+1̸∈ Span(v1, . . . , vn), vn+1∈ Span(v1, . . . , vn, vn+1), Span(v1, . . . , vn)̸=
Span(v1, . . . , vn, vn+1).
V Rn subspace. v1, . . . , vn ∈ V V spanning vectors , Span(v1, . . . , vn)̸= V, V vn+1 vn+1̸∈ Span(v1, . . . , vn). Lemma 4.2.1 , Span(v1, . . . , vn, vn+1) Span(v1, . . . , vn) 大,
, V spanning vectors.
4.2.2. Linear Dependence. linearly independent ,
linearly dependent linear independent , “線
性 ”.
linearly dependent, ,
線性 . v1, . . . , vn linearly dependent, vi
v1, . . . , vi−1, vi+1, . . . , vn 線性 . vi 線性
. 步 , vi= r1v1+··· + rn−1vn−1+ rn+1vn+1+··· + rnvn,
rj 數.
r1v1+··· + rn−1vn−1− vi+ rn+1vn+1+··· + rnvn= O.
0 數 c1, . . . , cn c1v1+···+cnvn= O. , 0 數 c1, . . . , cn c1v1+··· + cnvn= O. ci̸= 0,
vi=−c1
ci
v1+··· +−ci−1
ci
vi−1+−ci+1
ci
vi+1+··· +−cn
ci
vn,
vi v1, . . . , vi−1, vi+1, . . . , vn 線性 . , 0
數 c1, . . . , cn c1v1+···+cnvn= O v1, . . . , vn .
線性 線性 , .
線性 .
Definition 4.2.2. v1, . . . , vn∈ Rm, 0 數 c1, . . . , cn c1v1+··· + cnvn= O,
v1, . . . , vn linearly dependent.
v1, . . . , vn∈ Rm Definition 4.2.2, 0 數 c1, . . . , cn
c1v1+··· + cnvn= O, v1, . . . , vn 線性 .
Definition 4.1.7 linearly independent . linearly
independent linear dependent . A v1, . . . , vn column vectors m×n matrix. v1, . . . , vn linearly independent homogeneous linear system Ax = O nontrivial solution, v1, . . . , vn linearly dependent
homogeneous linear system Ax = O nontrivial solution.
v1, . . . , vn linearly independent, :
c1v1+··· + cnvn= O, c1, . . . , cn 0. ,
, v1, . . . , vn linearly dependent ( 0
數 c1, . . . , cn c1v1+··· + cnvn= O), .
, 大 , .
Example 4.2.3. v1, . . . , vn∈ Rm linearly independent. v1, . . . , vn
線性 . v1, . . . , vn vn, v1, . . . , vn−1
linearly independent. , , c1v1+··· +
cn−1vn−1= O c1, . . . , cn−1 0. , 0
4.2. Spanning Vectors and Linear Dependence 75
數 c1, . . . , cn−1 c1v1+··· + cn−1vn−1= O. cn= 0, 0 數
c1, . . . , cn
c1v1+··· + cn−1vn−1+ cnvn= c1v1+··· + cn−1vn−1= O.
v1, . . . , vn∈ Rm linearly independent , v1, . . . , vn−1 linearly independent. 大 , v1, . . . , vn−1∈ Rm linearly dependent
, vn∈ Rn , v1, . . . , vn−1, vn linearly dependent.
Example 4.2.3 , v1, . . . , vn∈ Rm linearly independent
, , linearly independent 性 .
. linearly
independent.
Lemma 4.2.4. v1, . . . , vn, vn+1∈ Rm. v1, . . . , vn linearly independent, v1, . . . , vn, vn+1 linearly independent vn+1̸∈ Span(v1, . . . , vn).
Proof. vn+1∈ Span(v1, . . . , vn), v1, . . . , vn, vn+1 線性 , linearly de- pendent. v1, . . . , vn, vn+1 linearly independent, vn+1∈ Span(v1, . . . , vn)
. vn+1̸∈ Span(v1, . . . , vn).
, vn+1̸∈ Span(v1, . . . , vn) v1, . . . , vn, vn+1 linearly independent.
, v1, . . . , vn, vn+1 linearly dependent, 0 數
c1, . . . , cn, cn+1 c1v1+··· + cnvn+ cn+1vn+1= O. cn+1 0, vn+1= −c1
cn+1
v1+··· + −cn
cn+1
vn,
vn+1∈ Span(v1, . . . , vn) . cn+1= 0, c1, . . . , cn 0 數
c1v1+··· + cnvn= c1v1+··· + cnvn+ cn+1vn+1= O,
v1, . . . , vn linearly dependent. v1, . . . , vn linearly independent
, v1, . . . , vn, vn+1 linearly independent.
V Rn subspace, v1, . . . , vn∈ V linearly independent. v1, . . . , vn
V spanning vectors, V vn+1 vn+1̸∈ Span(v1, . . . , vn).
Lemma 4.2.1 v1, . . . , vn, vn+1 linearly independent.
, 數 , linearly independent . Corollary
3.4.8 , n > m ,Rm n linearly dependent.
.
Lemma 4.2.5. w1, . . . , wk∈ Rm. v1, . . . , vn∈ Span(w1, . . . , wk) n > k, v1, . . . , vn
linearly dependent.
Proof. v1, . . . , vn∈ Span(w1, . . . , wk) ai j 1≤ i ≤ n, 1 ≤ j ≤ k v1 = a1 1w1 + a1 2w2 + ··· + a1 kwk
...
vn = an 1w1 + an 2w2 + ··· + an kwk. c1, . . . , cn∈ R
c1v1 = c1a1 1w1 + c1a1 2w2 + ··· + c1a1 kwk ...
cnvn = cnan 1w1 + cnan 2w2 + ··· + cnan kwk. , n× k matrix A = [ai j] c1v1+··· + cnvn= b1w1+··· + bkwk
[ c1 ··· cn
]A =[
b1 ··· bk
], AT
c1
... cn
=
b1
... bk
.
AT k×n matrix n > k, Corollary 3.4.7 homogeneous linear system ATx = O nontrivial solution. c1, . . . , cn∈ R 0, AT
c1
... cn
=
0
... 0
, [ c1 ··· cn
]A =[
0 ··· 0 ]
. 0 c1, . . . , ck
c1v1+··· + cnvn= 0w1+··· + 0wk= O.
v1, . . . , vn linearly dependent.
Question 4.2. v1, . . . , vn linearly independent. w1, . . . , wk∈ Span(v1, . . . , vn) k < n, Span(w1, . . . , wk)̸= Span(v1, . . . , vn).
4.3. Dimension of subspace
Rm subspace basis, .
Rm nonzero subspace basis. subspace
basis 數 , 數 subspace dimension.
dimension 性 .
V Rm subspace. V ={O}, O V , O V
spanning vector. O linearly independent, c̸= 0
cO = O. V basis . V ̸= {O} , v1∈ V v1̸= O.
V1= Span(v1). V1= V , v1 V spanning vector, v1 linearly independent, v1 V basis. V1̸= V, v2∈ V v2̸∈ V1= Span(v1).
V2= Span(v1, v2). Lemma 4.2.1, V1⊆ V2 V1̸= V2, V2 V1 大. Lemma 4.2.4 v1, v2 linearly independent. V2= V ,
v1, v2 V spanning vectors, linearly independent, v1, v2
V basis. V2̸= V, 步 , .
4.3. Dimension of subspace 77
Theorem 4.3.1. V Rm subspace V̸= {O}, v1, . . . , vn∈ V, n≤ m,
V basis.
Proof. 前 , V2̸= V , . , m 大,
前 步 步 , 數學 . 前
, i vectors v1, . . . , vi linearly independent, 步
, n n≤ m Span(v1, . . . , vn) = V .
數學 , k v1, . . . , vk linearly independent (
k = 1 ). Vk= Span(v1, . . . , vk). Vk= V , v1, . . . , vk V spanning vectors, linearly independent, v1, . . . , vk V basis. Vk ̸= V, Vk ⊆ V vk+1∈ V vk+1̸∈ Vk. v1, . . . , vk, vk+1, v1, . . . , vk linearly independent vK+1̸∈ Vk Lemma 4.2.4 v1, . . . , vk, vk+1 linearly independent.
數學 步 vectors linearly independent.
, 步 n≤ m, Span(v1, . . . , vn) = V .
m , Span(v1, . . . , vm) = V , 前 數學 v1, . . . , vm linearly independent. vm+1 ∈ V vm+1̸∈ Span(v1, . . . , vm), Lemma 4.2.4 v1, . . . , vm, vm+1 linearly independent. v1, . . . , vm+1∈ V v1, . . . , vm+1∈ Rm,
Corollary 3.4.8 v1, . . . , vm+1 m + 1 linearly dependent.
v1, . . . , vm, vm+1 linearly independent . m
Span(v1, . . . , vm) = V , n≤ m v1, . . . , vn V spanning vectors. v1, . . . , vn linearly independent, v1, . . . , vn V
basis.
Theorem 4.3.1 , v1. . . vk∈ V linearly independent,
v1, . . . , vk 大 V basis. v1, . . . , vk V spanning vectors, 前 , vk+1, . . . , vn ∈ V v1, . . . , vk, vk+1, . . . , vn V
basis.
Theorem 4.3.1 basis 性, basis
性. Rm subspace basis .
[ 1 0
] ,
[ 0 1
] [
1 1
] ,
[ −1 1
]
R2 basis.
v1, . . . , vn Rm basis, Corollary 3.4.4 n < m, v1, . . . , vn
Rm spanning vectors, n≥ m. n > m, Corollary 3.4.8 v1, . . . , vn
linearly independent, n = m. Rm basis m
. .
Theorem 4.3.2. V Rm subspace. v1, . . . , vn w1, . . . , wk V basis, n = k.
Proof. , n̸= k. 性, n > k. w1, . . . , wk V spanning vectors, v1, . . . , vn∈ V = Span(w1, . . . , wk). n > k Lemma 4.2.5
v1, . . . , vn linearly dependent. v1, . . . , vn V basis .
n̸= k, n = k.
Theorem 4.3.2 V basis 數 . n
V basis, V basis n .
.
Definition 4.3.3. V Rm subspace. V basis 數 V
dimension ( ), dim(V ) .
Rm basis m , dim(Rm) = m.
Theorem 4.3.1 , V linearly independent
linearly independent spanning vectors
. , V spanning vectors, spanning vectors
linearly independent . ,
.
Proposition 4.3.4. V Rm subspace v1, . . . , vn∈ V.
(1) v1, . . . , vn V spanning vectors, dim(V )≤ n. , v1, . . . , vn linearly dependent, dim(V ) < n.
(2) v1, . . . , vn linearly independent, dim(V )≥ n. , v1, . . . , vn V spanning vectors, dim(V ) > n.
Proof. dim(V ) = k, w1, . . . , wk V basis.
(1) v1, . . . , vn V spanning vectors, Span(v1, . . . , vn) = V . w1, . . . , wk V basis, w1, . . . , wk∈ Span(v1, . . . , vn) w1, . . . , wk linearly independent.
k > n, Lemma 4.2.5 w1, . . . , wk linearly dependent. ,
dim(V ) = k≤ n. v1, . . . , vn linearly dependent, v1, . . . , vn
線性 . 性 vn, vn∈ Span(v1, . . . , vn−1).
Lemma 4.2.1 Span(v1, . . . , vn−1) = Span(v1, . . . , vn−1, vn) = V , v1, . . . , vn−1 V spanning vectors. dim(V )≤ n − 1, dim(V ) < n.
(2) v1, . . . , vn∈ V linearly independent. w1, . . . , wk V basis, Span(w1, . . . , wk) = V , v1, . . . , vn∈ Span(w1, . . . , wk). n > k, Lemma 4.2.5
v1, . . . , vn∈ V linearly dependent . n≤ k = dim(V). v1, . . . , vn V spanning vectors, vn+1∈ V vn+1̸∈ Span(v1, . . . , vn) Lemma 4.2.4
v1, . . . , vn, vn+1 linearly independent. dim(V )≥ n + 1,
dim(V ) > n.
4.3. Dimension of subspace 79
v1, . . . , vn V basis, v1, . . . , vn V
spanning vectors linearly independent . dim(V )
n, spanning vectors linearly independent
.
Corollary 4.3.5. V Rm subspace v1, . . . , vn∈ V. . (1) v1, . . . , vn V basis.
(2) dim(V ) = n v1, . . . , vn V spanning vectors.
(3) dim(V ) = n v1, . . . , vn linearly independent.
Proof. (1)⇒ (2): v1, . . . , vn V basis, V basis n , dim(V ) = n. basis spanning vectors, v1, . . . , vn V spanning vectors. (1)⇒ (2).
(2)⇒ (3): v1, . . . , vn V spanning vectors, Proposition 4.3.4 (1) dim(V )≤ n. v1, . . . , vn linearly independent, Proposition 4.3.4 (1)
dim(V ) < n. dim(V ) = n , v1, . . . , vn linearly independent.
(2)⇒ (3).
(3)⇒ (1): v1, . . . , vn linearly independent, Proposition 4.3.4 (2) dim(V )≥ n. v1, . . . , vn V spanning vectors, Proposition 4.3.4 (2) dim(V ) >
n. dim(V ) = n , v1, . . . , vn V spanning vectors. v1, . . . , vn V
basis, (3)⇒ (1).
Theorem 4.3.1 V Rm subspace, V basis 數
m, dim(V )≤ m, dim(V )≤ dim(Rm).
.
Corollary 4.3.6. V,W Rm subspaces V ⊆ W, dim(V )≤ dim(W).
dim(V ) = dim(W ) V = W .
Proof. dim(V ) = n v1, . . . , vn V basis. v1, . . . , vn∈ V V ⊆ W, v1, . . . , vn∈ W. v1, . . . , vn∈ W linearly independent Proposition 4.3.4 (2) dim(V ) = n≤ dim(W).
V = W , dimension 性 dim(V ) = dim(W ). , dim(V ) = dim(W )
V ̸= W. v1, . . . , vn∈ W linearly independent W spanning vectors, Proposition 4.3.4 (2) dim(V ) = n < dim(W ). dim(V ) = dim(W ) ,
V = W .
dim(V ) = dim(W ) 代 V = W . R2 v̸= O, Span(v)
dimension 1 subspace. w̸= O v , Span(v)̸= Span(w),
dimension 1 subspace. Corollary 4.3.6 V ⊆ W 前 dim(V ) = dim(W ) V = W .
4.4. Column Space and Nullspace
column space, row space nullspace basis.
column space row space dimension rank.
subspace basis.
, column space nullspace 數
. column space nullspace 性, :
Definition 4.4.1. A =
a 1 a2 ··· an
Rm a1, . . . , an column
vectors m× n matrix.
(1) Span(a1, . . . , an) A column space, C(A) A column space.
(2) homogeneous linear system Ax = O A nullspace
N(A) A nullspace. N(A) ={x ∈ Rn| Ax = O}.
Lemma 3.4.1 Theorem 3.4.6 .
Proposition 4.4.2. A m× n matrix b∈ Rm, Ax = b.
(1) Ax = b b∈ C(A).
(2) Ax = b N(A) ={O}.
column space nullspace sub-
spaces basis. Rm subspace V basis, V
spanning vectors. spanning vectors linearly independent
. , lin-
early independent. , linearly
independent, .
Example 4.4.3.
v1=
0 3 0 1
,v2=
2
−5 0 0
,v3=
0 7
−1 0
.
4.4. Column Space and Nullspace 81
v1, v2, v3 linearly independent, c1= c2= c3= 0 , c1v1+ c2v2+ c3v3= O.
c1v1+ c2v2+ c3v3= c1
0 3 0 1
+ c2
2
−5 0 0
+ c3
0 7
−1 0
=
2c2
3c1− 5c2+ 7c3
−c3
c1
.
c1v1+ c2v2+ c3v3= O, c1v1+ c2v2+ c3v3 1-st entry 2c2, 3-rd entry
−c3 4-th entry c1 0, c1= c2= c3= 0. c1= c2= c3= 0 , c1v1+ c2v2+ c3v3= O, v1, v2, v3 linearly independent.
Example 4.4.3 , v1, . . . , vn vi entry
0, entry 0, v1, . . . , vn linearly independent. ( Example 4.4.3 v1 4-th entry 1, v2, v3 4-th entry 0; v2 1-st entry 2, v1, v3
1-st entry 0; v3 3-rd entry −1, v1, v2 3-th entry 0, ).
vi 0 entry ai, c1v1+··· + cnvn entry ciai, c1v1+··· + cnvn= O, ciai = 0, ci 0. v1, . . . , vn linearly independent.
A m×n matrix, A nullspace N(A) homogeneous linear system Ax = O
. Ax = O , nullspace
basis .
Ax = O , elementary row operations A
echelon form ( reduced echelon form) A′. A′x = O Ax = O ,
A A′ nullspace. free variable, free variable
代 數, . , pivot variable free
variables , free variable , . free
variables xi1, . . . , xik. j = 1, . . . , k, xij= 1, free variable 0 , vj. vj ij-th entry 1, vij′ ij-th entry 0, 前 v1, . . . , vk linearly independent. r1, . . . , rk∈ R, r1v1+··· + rkvk
free variables xi1, . . . , xik 代 xi1 = r1, . . . , xik= rk . 言
r1v1+··· + rkvk , v1, . . . , vk A nullspace spanning vectors. v1, . . . , vk A nullspace basis, A nullspace
dimension free variables 數, A column 數 pivot 數,
.
Proposition 4.4.4. A m× n matrix. row operations A echelon
form A′ , A′ pivot 數 r, A nullspace dimension n− r. A′x = O
free variables xi1, . . . , xik. j = 1, . . . , k, xij= 1, free variable 0, vj. v1, . . . , vk A nullspace basis.
nullspace echelon form , nullspace
dimension , Proposition 4.4.4 “
elementary row operations echelon form , pivot 數
”. Definition 2.3.1 rank well-defined.
Example 4.4.5. A nullspace,
A =
2 1 1 0 0 0
1 0 0 1 0 0
1 1 1 0 1 2
1 2 2 −2 1 2
.
A 2-nd row −2, −1, −1 1-st, 3-rd 4-th row, 1-st, 2-nd
rows
1 0 0 1 0 0
0 1 1 −2 0 0
0 1 1 −1 1 2
0 2 2 −3 1 2
.
2-nd row −1,−2 3-rd 4-th row
1 0 0 1 0 0
0 1 1 −2 0 0
0 0 0 1 1 2
0 0 0 1 1 2
.
3-rd row −1 4-th row, echelon form
1 0 0 1 0 0
0 1 1 −2 0 0
0 0 0 1 1 2
0 0 0 0 0 0
.
homogeneous linear system
x1 +x4 = 0
x2 +x3 −2x4 = 0
+x4 +x5 +2x6 = 0
. echelon form x1, x2, x4 pivot variable, x3, x5, x6 free variable.
x6= 1, x5= 0, x3= 0, x4=−2, x2=−4, x1= 2, x6= 0, x5= 1, x3= 0 x4=−1, x2=−2, x1= 1, x6= 0, x5= 0, x3= 1 x4= 0, x2=−1, x1= 0.
v1=
2
−4 0
−2 0 1
, v2=
1
−2 0
−1 1 0
, v3=
0
−1 1 0 0 0
4.4. Column Space and Nullspace 83
A nullspace basis. , x6, x5, x3 數 r, s,t,
x4=−2r − s, x2=−4r − 2s −t, x1= 2r + s. A nullspace
2r + s
−4r − 2s −t t
−2r − s s r
= r
2
−4 0
−2 0 1
+ s
1
−2 0
−1 1 0
+ t
0
−1 1 0 0 0
= rv1+ sv2+ tv3.
v1, v2, v3 A nullspace spanning vectors, v1, v2, v3 linearly independent, v1, v2, v3 N(A) basis.
Question 4.3. Example 4.4.5 A reduced echelon form.
N(A) basis ?
matrix A column space C(A) basis.
A column space, Ax = v v .
v, A column space. A 數
constrain equations v. ,
, .
Example 4.4.6. Example 4.4.5 4×6 matrix A. A column vectors
basis. b A column space , Ax = b ,
b =
b1 b2
b3
b4
,
b1, b2, b3, b4 .
2x1 +x2 +x3 = b1
x1 +x4 = b2
x1 +x2 +x3 +x5 +2x6 = b3
x1 +2x2 +2x3 −2x4 +x5 +2x6 = b4
augmented matrix [A| b], Example 4.4.5 elementary row operations
2 1 1 0 0 0 b1
1 0 0 1 0 0 b2
1 1 1 0 1 2 b3
1 2 2 −2 1 2 b4
∼
1 0 0 1 0 0 b2
0 1 1 −2 0 0 b1− 2b2
0 1 1 −1 1 2 b3− b2
0 2 2 −3 1 2 b4− b2
∼
1 0 0 1 0 0 b2
0 1 1 −2 0 0 b1− 2b2
0 0 0 1 1 2 b3+ b2− b1
0 0 0 1 1 2 b4+ 3b2− 2b1
∼
1 0 0 1 0 0 b2
0 1 1 −2 0 0 b1− 2b2
0 0 0 1 1 2 b3+ b2− b1
0 0 0 0 0 0 b4− b3+ 2b2− b1
.
( 2.1 (2)(a)(b) ) , Ax = b
b4− b3+ 2b2− b1= 0. 言 , b1− 2b2+ b3− b4= 0 , b