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提要 6:如何建立數學模式?(五)

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提要 6:如何建立數學模式?(五)

茲以自由落體運動說明之,請參考紅色框線內之說明。

Notice:

1. 在地球表面上,物體自由落下之運動加速度約為 9.81m sec2 。 2. 2 9.81

2 =

dt y

d 為自由落體運動定律的化身。

3. 本問題之數學模式為二階(2 次微分)之常微分方程式,故其解會出現兩個積分常數。

4. 因有兩個積分常數會出現在通解中,故需安排兩個初始條件解之。

Physical System (實際系統)

試推算自由落體運動中,物體之移 動距離與移動時間的關係。

Modeling (模式化)

由自由落體試驗得知,在地球表面 附 近 , 物 體 之 運 動 加 速 度 為

sec2

81 .

9 m 。若考慮任意時刻t(秒)

時,物體之位移量為y(公尺),則物

體之運動加速度可以位移量y

( )

t 對 時間t 的兩次微分表示之,即

81 .

2 9

2 =

dt y d

在初始條件的考慮上,可定位移起 始點為y ,即0 y

( )

0 = y0;另外可考 慮物體之初始速度為v ,因物體之0 運動速度可表為

dt

dy,故另一初始條

件可表為

( )

0

0 v dt

dy = 。以上兩個初始

條件即可用以解出將來通解中所出 現的兩個積分常數C1C2Mathematical Model

(數學模式) 1. 控制方程式: 2 9.81

2 =

dt y d

2. 初始條件:y

( )

0 = y0

( )

0

0 v dt dy =

Solution(解)

0 0 2

2

1gt v t y

y= + +

(請參考提要 8 例題 3 之說明) Solution

Methods (解題方法) 可 採 用 直 接 積 分 法求解。

10

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習題

1. Air containing 0.06% CO2 is pumped into a room whose volume is 8,000 m3. The rate at which the air is pumped in is 2,000 m3/min, and the circulated air is then pumped out at the same rate. If there is an initial CO2 concentration of 0.2%, find the differential equation for A t

( )

, the amount (in m3) of CO2 in the room at time t.【90 交大物理所 15%】

2. Find a curve in xy plane that passes through

( )

0,3 and whose tangent line at a point

( )

x y, has slope 2x y2 .【88 成大製造所 10%】

3. Suppose that a mothball loses volume by evaporation at a rate proportional to its instantaneous area. If the diameter of the ball decreases from 2 cm to 1 cm in 3 months, how long will it take until the ball has practically gone, say, until its diameter is 1 mm.

【87 中原化工所 20%】

4. An oil tanker of mass M is sailing in a straight line. At time zero it shut off its engines and coasts. Assume that the water tends to slow the tanker with a force proportional to

( )

m

v t

  , in which v t

( )

is the velocity at time t and m is constant.

(a) Derive a differential equation for v t

( )

and solve it. (Let v v= at time zero.) 0 (b) Does the tanker eventually come to a full stop? If so, find the time required for the

tanker to stop. If not, why?

Hint: Solve and discuss the problem by considering cases on m. (i) 0< <m 1 (ii) 1

m= (iii) m>1.【89 台大化工所 15%】

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