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Calculus II Quiz 2 May 19, 2010 Name: TA/研討課教室

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Calculus II Quiz 2 May 19, 2010

Name: TA/研討課教室:

1. (10 pts) Given sin (xyz) =x+ 2y+ 3z, use implicit differentiation to find ∂z∂x.

2. (5 pts) Suppose thatg(t) =f(x(t), y(t)), wheref is a differentiable function ofx and y, and x=x(t) and y=y(t) both have first-order derivatives. Given that

x(1) = 1, y(1) = 2, x(2) = 3, y(2) = 4,

x(1) = 5, y(1) = 6, x(2) = 7, y(2) = 8, fx(1,2) = 7, fy(1,2) = 8, fx(3,4) = 1, fy(3,4) = 2, f(1,2) = 5, f(2,3) = 6, f(3,4) = 7, f(4,5) = 8, computeg(2).

3. (10 pts) Given Y = uev, u = r+s, v = rs, use the Chain Rule to find the partial derivatives, ∂Y∂r, ∂Y∂s, when (r, s) = (1,0).

4. (15 pts) Givenf(x, y, z) =xe2yz,P(3,0,2) and⃗u=< 23,−23,13 >, (a) find the gradient of f,

(b) evaluate the gradient at the pointP,

(c) find the rate of change off atP in the direction of the vector⃗u.

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Name: Student ID number:

5. (a) (10 pts) Find the local maximum and minimum values and saddle points of the function,

f(x, y) = 2x2+ 3y28x−5.

(b) (10 pts) Use the Method of Lagrange Multiplier to find the absolute maxi- mum and minimum values of the function f(x, y) = 2x2+ 3y28x−5 subject to the constraintx2+y2 = 1.

(c) (10 pts) Find the absolute maximum and minimum values of the functionf(x, y) = 2x2+ 3y28x−5 subject to the constraint x2+y21.

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Name: Student ID number:

6. (10 pts) Evaluate the iterated integral,

1

0

x

0

1 + 2y dydx.

7. (10 pts) Evaluate the iterated integral by first changing the order of integration,∫ 1

0

1

y

ex2dxdy.

8. (10 pts) 求由兩曲面z=x2+y2z= 4−x2−y2 所圍之體積

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