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Abstract
Up to the present, it is an important study for calculating Bernoulli
number.
There are many different methods to claculate Bernoulli
number. But for these methods, we must take lots of steps to calaulate
Bernoulli number. Based on this, our research applies Riemann–zeta
function and the extended function of the sums of powers of
consecu-tive integers to get an easier method. Then, we will calculate Bernoulli
number by using Matlab 7.1, and investigate the relationship between
Bernoulli nmuber and Stirling number of second kind.
Our results are as follows.
1. The formula of Bernoulli number is
B
2k=
1
2k + 1
(
C
2k2k+1S
10(−1) +
kX
i=1C
2i+12k+1S
2k−2i0(−1)
)
, k ∈ N.
2. When k is bigger, Bernoulli number will become bigger and be
alternated between plus and minus.
3. The relationship between Bernoulli number and Stirling number
of second kind is
B
m+1=
m+1X
k=1(−1)
kk + 1
· k! · S
2(m + 1, k).
Keywords: the extended function of the sums of powers of
consecutive integers, Riemann–zeta function,
Bernoulli number, Stirling number of second kind.
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: Sk(n) = 1 k + 1n k+1 + 1 2n k + k 2B2n k−1 + k(k − 1)(k − 2) 2 × 3 × 4 B4n k−3 + · · · ,w2
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Bi˚Ñ+›‰b
(Bernoulli number);W
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Sˆ0(x) = x ,FJ
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:â4”
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∞ X k=0 ˆ Sk0(−1)T k k! = T eT − 1, (2.6)FJ
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∞ X k=0 ˆ Sk(−1) Tk k! = 1 − eT eT − 1 = −1,FJ
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(2.7)),/
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Sˆp+10 (x) = Sp+10 (x), ∀x ∈ R.yŸ })
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k ,I
+›‰b
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-Þ4”
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J
kÑ×kk
25£cbv
,†
Bk(0) = Bk(1)„p
:ÄÑ
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∞ X k=0 Sk0(x)T k k! = T eT (x+1) eT − 1 ,]
∞ X k=0 Bk(x) Tk k! = T eT x eT − 1,Ĥ
∞ X k=0 Bk(1) Tk k! = T eT et− 1, (2.8) ∞ X k=0 Bk(0) Tk k! = T eT − 1, (2.9)â
(2.8) (2.9)sª)
T = ∞ X k=0 {Bk(1) − Bk(0)} Tk k!,ª7#|
B0(1) = B0(0), B1(1) − B1(0) = 1, Bk(1) = Bk(0), ∀K ≥ 2,)„
;W4”
2.1.3,ì
2ƶ,5U‚ƒb
Ck(x) ,∀k ≥ 2à-
: Ck(x) = Bk x 2π , ∀x ∈ [0, 2π]/
Ck(x) = Ck(x + 2π).LÔ U‚
ƒb
Ck(x)5
Z s‰²
â†/ð
(1991)5
Z s}&»ød
,ªøU‚
ƒb[ýÑ
Ck(x) = X m∈z an,keinx, n ∈ Z, k ≥ 2,w2
einx = cos (nx) + i sin (nx),
an,k = 1 2π Z 2π 0 e−inxCk(x)dx,
;W
Ck(x)5ì2D }d‰b‰²
,ª)
an,k = Z 1 0 e−2πinxBk(x)dx, n ∈ Z, k ≥ 2,Q
6;Wcb
n5¦
Mª}Ñ
n 6= 0D
n = 0s8$Vl
an,k.ç
n = 0v
, Z 1 0 e−2nπxiBk(x)dx = Z 1 0 Bk(x)dx = Sk(0) − Sk(−1) = 0, k ≥ 2,]
a0,k = 0, ∀k ≥ 2.ç
n 6= 0v
,ÄÑ
Z 1 0 e−2πinxB0(x)dx = Z 1 0 e−2πinxdx = 0, Z 1 0 e−2nπxiB1(x)dx = Z 1 0 e−2nπxi x − 1 2 dx = Z 1 0 xe−2nπxidx − 1 2 Z 1 0 e−2nπxidx(= 0) = −xe −2nπxi 2nπi 1 0 + 1 2nπi Z 1 0 e−2nπxidx(= 0) = − 1 2nπi,l
R1 0 e −2πinxB k(x)dx5NbÞA
ƒb
,ª)
∞ X k=0 Z 1 0 e−2nπxiBk(x)dx Tk k! = Z 1 0 e−2nπxi ( ∞ X k=0 Bk(x) Tk k! ) dx = Z 1 0 e−2nπxi T e T x eT − 1 dx = T eT − 1 Z 1 0 e(T −2nπi)xdx = T eT − 1 · 1 T − 2nπi h e(T −2nπi)x 1 0 i = T T − 2nπi,FJ
Z 1 0 e−2nπxi T e T x eT − 1 dx = − T 2nπi + ∞ X k=2 an,k Tk k!,]
an,k = − k! (2nπi)k, n ∈ Z, n 6= 0, k ≥ 2,;W
Z s‰²
Ck(x) = Pn∈Zan,ke−2nπxi ,FJ
Bk x 2π = X n∈Z,n6=0 − k! (2nπi)ke −inx , k ≥ 2,¹
,úL<
k ≥ 2, x ∈ [0, 1], Bk(x) = X n∈Z,n6=0 − k! (2nπi)ke 2nπxi = − k! (2πi)k X n∈Z,n6=0 1 nke 2nπxi = − k! (2πi)k X n∈Z,n6=0 1 nk[cos (2nπx) + i sin (2nπx)] = − k! 2k(πi)k ( ∞ X n=1 1 nk [cos (2nπx) + i sin (2nπx)] + ∞ X n=1 1 (−n)k[cos (2nπx) − i sin (2nπx)] ) . (2.10)â
(2.10),ªJ)ƒ
kѣ
Xbv
, Sk0(x − 1) = − k! 2k−1(−πi)k ∞ X n=1 1 nk cos (2nπx), ∀x ∈ [0, 1],7ç
kÑ×k
15Jbv
, Sk0(x − 1) = − k! 2k−1(−πi)k ∞ X n=1 1 nk sin (2nπx), ∀x ∈ [0, 1].L
S0 k(x)D-^*ƒb5É:
ç
kѣ
Xbv
, Sk0(0) = − k! 2k−1(πi)k ∞ X n=1 1 nk = − k! 2k−1(πi)kζ(k), (2.11)7ç
kÑ×kø5Jbv
, Sk0(0) = 0, (2.12);W
Sk(x) = 1 k + 1{(x + 1) k+1− Ck+1 2 Sk−1(x) − · · · − Ckk+1S1(x) − x − 1},ªJ)ƒ
:ç
kѣ
Xbv
, ζ(k) = −2 k−1(πi)k (k + 1)! k − Ck+1 2 S 0 k−1(0) − C k+1 3 S 0 k−2(0) − · · · − C k+1 k S 0 1(0) , (2.13)‚à
(2.4)J£
(2.11) ,ª)
ζ(2) = ∞ X n=1 1 n2 = S 0 2(0)π2 = π2 6 ,QOy‚à
(2.3) (2.4) (2.5) (2.12)(2.13)ª)
ζ(4) = ∞ X n=1 1 n4 = − π4 154 − C 5 2S 0 3(0) − C 5 3S 0 2(0) − C 5 4S 0 4(0) = π4 90,./‚à
(2.11),)ƒ
S40(0) = − 1 30,°Ü
,;W
(2.13)ª)
ζ(6) = ∞ X n=1 1 n6 = 2π6 3156 − C 7 3S 0 4(0) − C57S 0 2(0) − C67S 0 1(0) = π6 945,Y¤éR
,ç
k×k
65
Xbv
,ªJ
"Τj¶
,lMøl|
S10(0), S20(0), · · · , Sk−20 (0),Í(yªø¥‚à
S10(0), S20(0), · · · , Sk−20 (0),¹ª
)ƒ
ζ(k)5
M
ù
+›‰b5óÉû˝
Ô úk
n = 1, 2, 3, · · · ;
Bn = 2(2n)! (2π)2nS2n,w2
BnÑ
+›‰b
, S2n =P∞ m=1 1 m2n„p
:lVû˝ø_x½b@àíζ âk
ex = 1 + x +x 2 2! + · · · + xn n! + · · · ,FJ
x ex− 1 = x x + x2 2! + · · · + xn n! + · · · = 1 1 + 2!x + x3!2 + · · · + xn−1n! + · · ·,cq¥_¼Býúk—Düí
xMª[Ab
x ex− 1 = 1 + ∞ X n=1 βn n!x n ,í$
,w[b¦A
βn n!í$
,¥ccuÑ7üì[bvœÑjZ
;WÉ[
1 + x 2!+ x2 3! + · · · + xn−1 n! + · · · × 1 + β1 1! + β2 2!x 2 + · · · + βn n!x n + · · · = 1,Ç˝V®_j4
xn(n = 1, 2, · · · )í[bkÉ ªJ)|j˙
1 n!βn+ 1 (n − 1)!2!βn−1+ · · · + 1 (n − k + 1)!k!βn−k+1+ · · · + β1 1!n!+ 1 (n + 1)! = 0,si
J
(n + 1)!)
C1n+1βn+ C2n+1βn−1+ · · · + Ckn+1βn+1−k+ · · · + Cnn+1β1+ 1 = 0,‚àwDâùáóNíÉ[
,¥<j˙¯Uí$,ªJŸA
: (β + 1)n+1− βn+1 = 0 (n = 1, 2, · · · ),Í(zùáÇ
,¾ |òá
βn+1(
,4j
βkTà
β kH
,)ƒüì
βn(n = 1, 2, · · · )í̤j˙
2β1+ 1 = 0, 3β2 + 3β1+ 1 = 0, 4β3+ 6β2+ 4β1+ 1 = 0, 5β4+ 10β3+ 10β2+ 5β1+ 1 = 0, (2.14)â
(2.14)ª)
β1 = − 1 2, β2 = 1 6, β3 = 0, β4 = − 1 30, β5 = 0, β6 = 1 42, β7 = 0, β8 = − 1 30, β9 = 0, β10= 5 66, β11 = 0, β12= − 691 2730, β13 = 0, β14= 7 6, (2.15);W
úk
|x| < 1, x coth x = 1 + ∞ X n=1 (−1)n−12 2nB n (2n)!x 2n,¥ê
BnÑ
+›‰b
,B1 = 1 6, B2 = 1 30, · · · , (2.16)ªø
x ex− 1+ x 2 = x 2 ex+ 1 ex− 1 = x 2 ex2 + e− x 2 ex2 − e− x 2 = x 2coth x 2 = 1 + ∞ X m=1 (−1)m−1· Bm (2m)!x 2m,âk
(2.15)2
βn(n > 1)íJbáÌÑÉ
,â
exx−1 + x 2íÇø
x ex− 1 + x 2 = 1 + ∞ X n=2 βm m!x m ,úk
Xb—™í
β ,
β2n= (−1)n−1Bn,ku
B1 = 1 6, B2 = 1 30, B3 = 1 42, B4 = 1 30, B5 = 5 66, B6 = 691 2730, B7 = 7 6, · · · .â
úk
|x| < 1, πx coth πx = 1 + 2 ∞ X m=1 (−1)m−1S2mx2m,¥ê
S2m= ∞ X n=1 1 n2m,£
(2.16) ,
πx coth πx = 1 + 2 ∞ X n=1 (−1)n−1S2nx2n, πx coth πx = 1 + ∞ X n=1 (−1)n−1(2π) 2nB n (2n)! x 2n,*,Þsªø
S2n = (2π)2n 2(2n)!Bn.¡
¸Ä
(2006)ê[5dı
A Note on the Sums of Powers of ConsecutiveIntegers
d2Tƒ
: Sn(k) = 1n+ 2n+ · · · + (k − 1)n, k ∈ N, k > 1 = Z k 0 Bn(x)dx,¢
Z k+1 k Bn(x)dx = Z k+1 0 Bn(x)dx − Z k 0 Bn(x)dx = Sn(k + 1) − Sn(k) = kn,ø
kà
x¦H
Z x+1 x Bn(t)dt = xn,øsi}
Bn(x + 1) − Bn(x) = nxn−1,é
x = 0ƒ
x = k + 1Ú‹
Bn(k) − Bn(0) = nSn−1(k) = n Z k 0 Bn−1(x)dx, Sn(k) = 1 n + 1[Bn+1(k) − Bn+1(0)], Bn(k) = n Z k 0 Bn−1(x)dx + Bn(0),/
Bn = Bn(0) = Sn0(0),é
Bx(0) = 1, Bn(x) = n Z x 0 Bn−1(t)dt + Bn, n = 1, 2, 3, · · · ,I
n = 1, 2, 3, · · · , B1(x) = x + B1, B2(x) = x2+ 2B1x + B2, B3(x) = x3+ 3B1x2 + 3B2x + B3, .. .ª)
Bn(x) = n X i=0 CinBixn−i, Sn(k) = 1 n + 1 n X i=0 Cin+1Bikn+1−i,ÇøjÞ
,é
x = 0, Bn(1) − Bn(0) = 0,FJ
Bn = Bn(0) = Bn(1) = n X i=0 CinBi,]
Bn+1 = n+1 X i=0 Cin+1Bi = n X i=0 Cin+1Bi+ Bn+1,Ĥ
n X i=0 Cin+1Bi = 0,FJ
Bn= − 1 n + 1 n−1 X i=0 Cin+1Bi.Ù;Æ
(2000)4¸D+›‰bí¡j¶
4¸
M − N[ýí¡j¶+›‰b
Bk¸
+›‰Öá
Bk(y)Êb
û˝2”ѽb
,…bâà-
ƒbì2
x ex− 1 = ∞ X k=0 Bk k!x k , (|x| < 2π), xexy ex− 1 = ∞ X k=0 Bk(y) k! x k, y ∈ R, B0 = 1, B1 = − 1 2, B2k+1 = 0 (k ≥ 1). ùÜ 2.2.1. k ≥ 2 ,†
Sk(n) = k Z n 0 Sk−1(x)dx + Bk· n. (2.17) ùÜ 2.2.2. (M − N )[ýp
M = 2n + 1, N = n(n + 1) ,†
S2k(n) = M N 2(2k + 1) k−1 X r=0 (−1)rA(k, r)Nk−r−1, (2.18) S2k+1(n) = N2 2 k−1 X r=0 (−1)r A(k, r) k + 1 − rN k−r−1, (2.19)w2
A(k, 0) = 1, A(k, 1) = 1 3C 2 k, A(k, 2) = 7k−1 60 C 3 k, A(k, r) = r X j=1 (−1)j−1 1 2j + 1C 2j k+j−rA(k, r − j), (2.20) A(k, r) = 1 k + 1 r X j=1 (−1)j−1Ck+12j+1A(k − j, r − j), (2.21) A(k, r) = (k − r + 1)! (k + 1)! Ck+2−r3 Ck+2−r1 Ck+3−r5 Ck+3−r3 Ck+3−r1 · · · · Ck2r−1 · · · C1 k Ck+12r+1 · · · C3 k+1 , (2.22) ùÜ 2.2.3. k ≥ 0 ,†
Bk( 1 2) = 1 2k(2 − 2 k)B k. (2.23) ùÜ 2.2.4.qÅ—‘K
p − 1|2kíF[bÑ
p1, p2, · · · , ps ,†
1. B2kí}‚u
p1p2· · · ps(s ≥ 2),1/
,B2k = p1pa22k···ps,a2kÑJb
; 2.J/ÑJ
p ∈ {p1, p2, · · · , ps}v
, p|(pB2k+ 1)í}ä
, p||B2kí}‚
ìÜ 2.2.1. k ≥ 2, 1 ≤ r ≤ k − 2v
A(k, k − 2) = 3A(k, k − 1) = (−1)k−16(2k + 1)B 2k, C22k−2r+1A(k, r) = Ck−r+12 A(k, r − 1) + C2k+12 A(k − 1, r).
(2.24)
„p
:âùÜ
2.2.1)
2kS2k−1(n) + B2k = d dnS2k(n), (2.25)âùÜ
2.2.2,1·<
M2 = 4N + 1, dM = 2dn, dN = M dn)
2k(2k + 1) k−2 X r=0 (−1)rA(k − 1, r) k − r N k−r + 2(2k + 1)B2k = k−1 X r=0 (−1)rA(k, r) d dn(N M k−r ) = k−1 X r=0 (−1)rA(k, r)[2Nk−r+ (k − r)M2Nk−r−1] = k−1 X r=0 (−1)rA(k, r)[(4k − 4r + 2)Nk−r+ (k − r)Nk−r−1] = k−1 X r=1 (−1)r[(4k − 4r + 2)A(k, r) − (k + 1 − r)A(k, r − 1)]Nk−r +(4k + 2)A(k, 0)Nk+ (−1)k−1A(k, k − 1).ªœsi
Ní°Ÿ
á[b¹)„
ìÜ 2.2.2. k ≥ 1, 0 ≤ r ≤ k − 1 ,†
A(k, r) = (−1 4) r r X j=0 (2 − 4j)B2jC2k+12j C k−r k−j. (2.26)„p
:âùÜ
2.2.3£
M = 2n + 1)
M 2 + m X k=1 S2k(n) x2k (2k)! = 1 2 + ∞ X k=0 S2k(n) x2k (2k)! = 1 2 + n X r=1 ( ∞ X k=0 (rx)2k (2k)! ) = 1 2 + n X r=1 chrx = sh M 2 x 2shx2 = shM x 2 ex2 ex− 1 = 1 xsh M x 2 · xex2 ex− 1 = 1 x " ∞ X k=0 1 (2k + 1)! M x 2 2k+1# · " ∞ X k=0 Bk(12) k! x k # = M 2 " ∞ X k=0 M2k 4k(2k + 1)!x 2k # " ∞ X k=0 2 − 2k 2k· k!x k # ,ªœJ,si
x2kí[b)
S2k(n) = M 2 · 4k(2k + 1) k X r=0 (2 − 4r)C2k+12r B2rM2k−2r, (2.27)â
M2 = 4N + 1)
S2k(n) = M (4k + 2)4k k X r=0 (2 − 4r)C2k+12r B2r(4N + 1)k−r, S2k(n) = M 4k + 2 k−1 X r=0 " 1 4 r X j=0 (2 − 4j)B2jC2k+12j Ck−jk−r # Nk−r, (2.28)ªœ
(2.18)D
(2.28) Ní[b†)ƒ
(2.26)Q-Vu
+›‰bí0§¶
,íl
: ìÜ 2.2.3. k ≥ 2 ,†
k X r=0 (2 − 4r)B2rC2k+12r = 0, (2.29) B2k = −8 3(2k + 1)4k k−2 X r=0 (2 − 4r)B2rC2k+12r Ck−r2 , (2.30) B2k = 2 (2k + 1)4k k−1 X r=0 (2 − 4r)B2rC2k+12r Ck−r1 , (2.31) B2k = (−1)k−1 (2k + 1)(k + 1)! C3 3 C31 C5 4 C43 C41 · · · · Ck2k−3 · · · C1 k Ck+12k−1 · · · Ck+13 . (2.32)„p
:I
n = 0 ,†
M = 1, N = 0, S2k(n) = 0 ,â
(2.27)¹)ƒ
(2.29) ,C6â
(2.26)£
A(k, k) = 06)ƒ
(2.29)â
(2.22)¸
(2.26)£
A(k, k − 2) = 3A(k, k − 1) = (−1)k−16(2k + 1)B 2k†
¹)ƒ
(2.30) (2.31) (2.32)Ù;Æ
(1997)4¸íˆD+›‰bílídı2J°)7+›‰b
B0 ∼ B106 ,Oç
kœ×vÿÌ?щ7 *ìÜ
2.2.1ªJõ|
,úœ×í
kM
6ªJ0§Ë|
A(k, r)í
M
,1/
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A(k, r)í
M
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B2kí
M 7/
,|(|í
B2k ,ªàùÜ
2.2.4'
ñqð„w£ü4
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A(k, r)í£ü4 ;W¥øj¶
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106_
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B102 ∼ B106¸
S101(N )í
M 7;W
S2k(N ) = 2k+1M S2k+10 (N )¹ª|
S100(N )í
M
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(1998)Ék
Pn i=1i kí°¸£w
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,1„p7
Pn i=1i k°¸Ö
á[bDO±í+›‰5Èí
É[ *7ßZû|7+›‰bí]Rt
ìÜ 2.2.4.úL<£cb
k, n-É[A
: n X i=1 ik = ak0nk+1+ ak1nk+ · · · + akkn,w2
ak0 = 1 k + 1, akj = 1 k − j + 1[C j k− ak0Ck+1j+1− ak1Ckj− · · · − akjCk−j+22 ], (2.33) j = 1, 2, 3, · · · , k.„p
:I
fk(Z) − fk(Z − 1) = Zk ,üìw[b
,¹
ak0(x − 1 + 1)k+1+ ak1(x − 1 + 1)k+ · · · + akk(x − 1 + 1) −[ak0(x − 1)k+1+ ak1(x − 1)k+ · · · + akk(x − 1)] = (x − 1 + 1)k,FJ
ak0[Ck+11 (x − 1)k+ Ck+12 (x − 1)k−1+ · · · + Ck+1k+1] +ak1[Ck1(x − 1) k−1+ C2 k(x − 1) k−1+ · · · + Ck k] +ak2[Ck−11 (x − 1) k−2+ C2 k−1(x − 1) k−3+ · · · + Ck−1 k−1] + · · · + akk = (x − 1)k+ Ck1(x − 1)k−1+ Ck2(x − 1)k−2+ · · · + 1,ªœsi[b)
: ak0 = 1 k + 1, akj = 1 k − j + 1 C j k− ak0Ck+1j+1− ak1Ckj − ak2Ck−1j−1− · · · − akj+1Ck−j+22 , j = 1, 2, 3, · · · , k.üì[b(í
fk(x)Å—
fk(x) − fk(x − 1) ≡ xk , −∞ < x < +∞ ,éÍ
fk(0) = 0, fk(1) = fk(1) − fk(0) = 1 ,FJ
fk(n) = [fk(n) − fk(n − 1)] + [fk(n − 1) − fk(n − 2)] + · · · + [fk(2 − fk(1)] = n X i=1 ik,FJ
n X i=1 ik = m X i=0 akjnk+1−j. ìÜ 2.2.5. ak1 = 12„p
:â]Rt
(2.33))
ak1 = 1 k − 1 + 1 C 1 k− ak0Ck+11+1 = 1 2. ìÜ 2.2.6. ak0+ ak+ · · · + ak(1 k)×2 = 1 2„p
:ÄÑ
f (0) − f (−1) = 0,FJ
f (−1) = 0,â
fk(1) + fk(−1) 2 = fk(1) − fk(−1) 2 = 1 2,¹)…A
ìÜ 2.2.7. ak 2i+1 = 0, i = 1, 2, · · · ,k−12„p
:ç
kÑ
Xbv
, fk(−n) = [−fk(1 − n) − fk(−n)] − [fk(2 − n) − fk(1 − n)] − · · · − [fk(−1) − fk(−2)] + fk(−1) = − n X i=1 ik,FJ
fk(n) + fk(−n) = nk, ⇒ 2ak1nk+ 2ak3nk−2+ · · · + 2ak k−1n2 = nk, ⇒ 2ak3nk−2+ 2ak5nk−4+ · · · + 2ak k−1n2 = 0, ⇒ ak3 = ak5 = · · · = ak k−1 = 0,ç
kÑJbv
,ÄÑ
f (−n) = n−1 X i=1 ik,FJ
fk(n) − fk(−n) = nk = 2ak1nk+ 2ak3nk−2+ · · · + 2akkn.°šË
ak3 = ak5 = · · · = akk = 0 ,‚àìÜ
2.2.5ìÜ
2.2.7ø
(2.33)“Ñ
akj = 1 k − j + 1 j − 1 2(j + 1)C j k− ak2Ck−1j−1− ak4Ck−3j−3− · · · − ak j−2Ck−j+33 , (2.34)˚
(2.34)Ñd²]Rt
,-Þy„ø_Z]Rt
ìÜ 2.2.8. fk(x)D
fk−1(x)Öá[bÅ-É[
: akj = kak−j k − j + 1, j = 0, 1, · · · , k − 1.„p
: [fk(x) − fk(x − 1)]0 = kxk−1 = k[fk−1(x) − fk−1(x − 1)],¹
[(k + 1)ak0xk+ kak1(x − 1)k−1+ · · · + akk] −[(k + 1)ak0(x − 1)k+ kak1(x − 1)k−1+ · · · + akk] = k[ak−1,0(x − 1)k−1+ · · · + ak−1,k−1(x)] −k[ak−1,0(x − 1)k+ ak−1,1(x − 1)k−1+ · · · + ak−1,k−1(x − 1)],ªœsi[b)
akj = kak−1 j k + 1 − j, j = 0, 1, 2, · · · , k − 1. (2.35)˚
(2.35)Ñó²]Rt
½µ‚à
(2.35)ª)
ùÜ 2.2.5. akj = 1 k + 1C j k+1ajj, (k > j). (2.36)yø
(2.36)Hp
(2.33) ,1‚àìÜ
2.2.7)
ùÜ 2.2.6. aii = 0,ç
iÑ×k
1íJbv
1 2,ç
i = 1v
1 i+1 i−1 2 C 4i+1a22− Ci+14 aii− Ci+1i+2ai−2,i−2 ,
ç
iÑ×k
1íJbv
p
f0(n) = 10+ 20+ · · · + n0 = n ,‚à
(2.35))
fk(x)í[búi[
:1 1 1 2 1 2 1 3 1 2 1 6 1 4 1 2 1 4 0 1 5 1 2 1 3 0 −1 30 1 6 1 2 5 12 0 −1 12 0 1 7 1 2 1 2 0 −1 6 0 1 42 1 8 1 2 7 12 0 −7 24 0 1 2 0 1 9 1 2 2 3 0 −7 15 0 2 9 0 −1 30 ... ... ... ... ... ... ... ... ... zpW 2.2.1.
;Wúi$[ªø
n X i=1 i8 = 1 9n 8+1 2n 8+ 2 3n 7− 7 15n 5+ 2 9n 3− 1 30n,9õ,
a00 = 1, a11= 1 2, a22 = 1 6, a44 = −1 30, · · · ,Zu
O±í+›‰b
ìÜ 2.2.9.I
Bi = aii, i 6= 1. −aii, i = 1.†-É[A
z ez− 1 = ∞ X n=0 BnZn n! , |z| < 2π. (2.37)„p
:5?
∞ X n=0 BnZn n ! ez − 1 z = 1,¹
∞ X n=0 BnZn n ! ∞ X n=0 1 (n + 1)!z n= 1 ! ,ø,˝iO
zí4bÇ
,)
B0 = 1, zní[bÑ
4n= 1 (n + 1)!B0+ 1 n! B1 1! + 1 (n − 1)! B2 2! + · · · + 1 1! Bn n! ,ø
(2.36) (yâìÜ
2.2.5,ìÜ
2.2.6,ìÜ
2.2.7)
4n = 0)Hp
4ní[®
,)
4n = 1 n!(an0− an1+ an2+ ann),ÄÑ
z ez − 1Ê
|z| < 2πj&
,FJìÜ
2.2.9A Ĥ
,˚Å—É[
(2.37)í[b
BnÑ
+›‰b
Q6‚àùÜ
2.2.6)
+›‰bílt
, à-B2i = 1 2i + 1 2i − 1 2 − C 22i+1B2− C2i+14 B4− · · · − C2i+12i−2B2i−2
, i = 1, 2, · · · . zpW 2.2.2. B2 = 1 2 + 1 × 2 − 1 2 = 1 6, B4 = 1 2 × 2 + 1 2 × 2 − 1 2 − C 2 5B2 = − 1 30, B6 = 1 7 5 2 − C 2 7B4 = 1 42, · · · .
ú
ùéÍ,Šb5óÉû˝
Ô
ÛÅ
(2005)Õ¯í•}DùéÍ,Šb
íl
,lV
ÜÍ,Šbí ¯<2£4” ùéÍ,ŠbªJ*s.
°íiVj„ øÑ}º½æ
,ø
n_–í7[p
m_ó°í]ä
,b°
®].˛
,†.°í[7j¶bÑ
S2(n, m)Çø†ÑÕ¯í•}
,ø
Ö
n_
jÖíÕ¯/ß}A
m_Ìå
ݲäÕíF.°•}íbñ
,¹
S2(n, m)ùéÍ,Šb
S2(n, m)-Þí4”
: 4” 2.3.1. S2(n, 0) = 0, S2(n, 1) = 1, S2(n, 2) = 2n−1 − 1, S 2(n, n − 1) = Cn 2, S2(n, n) = 1 4” 2.3.2.Å—à-í]Rt
: S2(n, m) = mS2(n − 1, m) + S2(n − 1, m − 1).ÛÊVõÕ¯
A = {1, 2, 3, 4, 5},Öý_.°í
gÉ[ .°í•}
bÑ
S2(5, 1) + S2(5, 2) + S2(5, 3) + S2(5, 4) + S2(5, 5) = 1 + 15 + 25 + 10 + 1 = 52,Ä7
A,
52_.°ígÉ[
Q-V„pJ-ís_ä
: S2(n, 2) = 2n−1− 1, S2(n, n − 1) = C2n.„p
: S2(n, 2) = S2(n − 1, 1) + 2S2(n − 1, 2) = 1 + [S2(n − 2, 1) + 2S2(n − 3, 2)] = 1 + 2 + 4S2(n − 3, 2) = · · · = 1 + 2 + 22+ · · · + 2n−2S2(2, 2) = 2n−1− 1. S2(n, n − 1) = S2(n − 1, n − 2) + (n − 1)S2(n − 1, n − 1) = S2(n − 2, n − 3) + (n − 2)S2(n − 2, n − 2) + (n − 1) = C2n.7jêw ¯<2£4”5(
,yV
w…àùéÍ,ŠbíNbÞAƒb
Vl
S2(n, m).âk
(ex− 1)m = x +x 2 2! + · · · m = ∞ X n=0 an xn n!, (2.38)w2
an= X n! n1!n2! · · · nm! ,uú
n1+ n2+ · · · + nm = níø~£cbjV°
â
n_.°í7/ß[ƒ
m_.°í]ä³
,[7j¶u
m!S2(n, m),
an= 0, n < m, P n! n1!n2!···nm! =P C n n1n2···nm = m!S2(n, m), n ≥ m.ø¥!‹Hp
(2.38))
(ex− 1)m = Xm!S 2(n, m) xn n!, (ex− 1)m = Cm me mx− Cm m−1e (m−1)x+ Cm m−2e (m−2)x− · · · + (−1)mCm 0 · 1 = Cnm 1 + m 1!x + m2 2! x 2+ · · · −Cm m−1 1 + m − 1 1! x + (m − 1)2 2! x 2+ · · · + (−1)mC0m· 1,ªœ,si
xn n!í[b)
m!S2(n, m) = Cmmm n− Cm m−1(m − 1) n + Cm−2m (m − 2)n− · · · + (−1)m−1C1m· 1,*7)ƒ
S2(n, m) = 1 m! m−1 X k=0 (−1)kCkm(m − k)n.ø,5!‹TÑ@à
,1/V„p-Þs
: S2(n, n − 1) = C2n, S2(n, n − 2) = C3n+ 3C n 4.„p
:ÄÑ
S2(n, n) = 1, X (−1)kCkn−1 = (n − 1)!C2n,FJ
S2(n, n − 1) = C2n ⇒ X(−1)kC2n−2(n − 2 − k)n ⇒ (n − 2)! {Cn 3 + 3C n 4} ⇒ S2(n, n − 2) = C3n+ 3C4n.
Ü
(2005)ùéÍ,ŠbíÀ4”
ìÜ 2.3.1. S(n, n − 2) = Cn 3 + 3C4n„p
:â
S(n, k) = S(n − 1, k − 1) + kS(n − 1, k),w2
1 ≤ k ≤ 1í]RÉ[
,)
S(n, n − 2) = S(n − 1, n − 3) + (n − 2)S(n − 1, n − 2) = S(n − 1, n − 3) + (n − 2)C2n = S(n − 2, n − 4) + (n − 3)S(n − 2, n − 3) + (n − 2)C2n−1 = · · · = S(3, 1) + 2C23+ 3C24+ · · · + (n − 3)C2n−2+ (n − 2)C2n−1 = 1 2[1 2+ 22+ · · · + (n − 2)2+ 13 + 23+ · · · + (n − 2)3] = 1 2 (n − 2)(n − 1)(2n − 3) 6 + 3(n − 2)2(n − 1)2 12 = n(n − 1)(n − 2) 6 + 3(n − 1)(n − 2)(n − 3) 24 = C3n+ 3C4n. ìÜ 2.3.2. S(n, n − 3) = Cn 4 + 10 + C5n+ 15C6n„p
:àbç¦Ñ¶
:ç
n = 4v
,éÍA
cqç
n = k − 1vA
,¹
S(k − 1, k − 4) = C4k−1+ 10C5k−1+ 15C6k−1,†
S(k, k − 3) = S(k − 1, k − 4) + (k − 3)S(k − 1, k − 3) = C4k−1+ C3k−1+ 10C5k−1+ 10C4k−1+ 15C5k−1+ 15C5k−1 +(k − 4)C3k−1+ (3k − 19)C4k−1− 15Ck−1 6 = C4k+ 10C5k+ 15C6k. ìÜ 2.3.3. mn= Cm k · S(n, k) · k!,w2
m, nu£cb
„p
:íl
,¯,ø_}º½æq)ƒìÜí„p
,¹z
n_.°í7[p
m_
.°í]ä³
,or˛]
,†[7íj¶buÖý
j¶ø
:ø
n_.°í7}pÑ
x1, x2, · · · xn, m_.°í]ä}pd
b1, b2, · · · , bm,©_7
xi(1 ≤ i ≤ n)·ªJ[p
m_.°í]ä
bj(1 ≤ j ≤ m)2íLSø_
,¹©_7·
m.°í[¶
,Ä7
n_.°í7u
mn[¶
j¶ù
:lVõ
n_.°í7[p
m_.°í]ä³
,.
or˛]íj
bÑ
S(n, m)m!9õ,
,lwÑ]äuêró°í
,z
n_7ZAí ¯
A{x1, x2, · · · , xn}•}A
m_ݲäÕ
A1, A2, · · · , Am ,Í(ø©_
Ai(1 ≤ i ≤ m)[p©ø_]ä³
,ZAø_³˛]í}ºj ¥³
A1, A2, · · · , Amu
Aíø_
m}
’
,wjbÑ
S(n, m)7¥³í
m_]äuêr.°í
FJ
, Aí
m_ä
Õí.°§ZAí}ºju.°í
,¹Ñ
S(n, m)m!*
m_.°í]äL²ø_íj¶bÑ
Cm 1 ,z7r¶[p
,”ìÑ˛]
,†j¶bÑ
C1 mS(n, 1)1!â¤ø
m2²
k_.°í]äz
n_7r¶[p
,b
°²|í
k_.°í
]ä.or˛í
,„
²í·Ñ˛] ;W ¶ŸÜø
,j
¶bÑ
Cm k S(n, k)k!;W‹¶ŸÜø
,z
n_.°í7[p
m_.°í]ä
³
,or˛]
,†[7íj¶bu
Pm k=1Ckm· S(n, k) · k!âj¶ø£j¶ùªøìÜA
¡ †±3
(2001)ùéÍ,Šbí4”£w@à
cq
Auø_Ý˛Õ¯
, A1, A2, · · · , AkuÕ¯
AíݲäÕ¯
,à‹
Ai∩ Aj = φ(i 6= j), A1 ∪ A2 ∪ · · · ∪ Ak = A,†˚
A1, A2, · · · , AkÑÕ¯
Aíø
_
kéí}• ø
n_jÖíÕ¯}Ñ
kéí.°}•í_bpÑ
S(n, k),†
˚
S(n, k)Ñ
ùéÍ,Šb .°}•í,b
(}ÑL<b
)pÑ
Tn ,ku
Tn =Pnk=1S(n, k)cq
A1, A2, · · · , AkuÕ¯
Aíø_
ké}•
,à‹
|Ai| ≥ r(i = 1, 2, · · · , k),w2
1 ≤ r ≥ n,¥ší}•_bpÑ
Sr(n, k),†˚
Sr(n, k)Ñ
2ùéÍ,
Šb w,bpÑ
: Tr(n) = n X k=1 Sr(n, k).Ê7
jêùéÍ,ŠbJ£2ùéÍ,Šbí–1¸pU(
,Q-V
²w…w4” à-
: 4” 2.3.3. S(n, 1) = S(n, n) = 1, S(n + 1, k) = S(n, k − 1) + kS(n, k)„p
:5?
n + 1_jÖíÕ¯
A ,Ê}¥_Õ¯Ñ
k_äÕí}é2
,/_j
Ö
a ,ªJÀÖ Aø_äÕ
{a} ,ku¥}é
S(n, k − 1)_
;C6jÖ
a‹pƒwF˛% A
k_äÕ2íø_
,¥}é
kS(n, k)_
,â‹¶ŸÜ
S(n + 1, k) = S(n, k − 1) + kS(n, k).
4” 2.3.4. P∞ n=k S(n,k) zn+1 = 1 z(z−1)(z−2)···(z−k)
„p
:p
Fk(z) = ∞ X n=k S(n, k) zn+1 ,ku
(z − k)Fk(z) = (z − k) ∞ X n=k−1 S(n + 1, k) zn+2 = ∞ X n=k−1 S(n + 1, k) − kS(n, k) zn+1 = ∞ X n=k−1 S(n, k − 1) zn+1 = Fk−1(z),*7
Fk(z) Fk−1(z) = 1 z − k,FJ
Fk(z) = F0(z) F1(z)F2(z) · · · Fk(z) F0(z)F1(z) · · · Fk−1(z) = 1 z(z − 1) · · · (z − k). (2.39) 4” 2.3.5.ç
n ≥ 1v
, S(n, k) = 1 k Pk j=0(−1)jCjk(k − j)n„p
:ø
(2.39)¬i}jA¶M}(k
1 k!· 1 z − k − 1 1!(k − 1)!· 1 z − k + 1 + · · · + (−1)k−1 (k − 1)!1!· 1 z − 1+ (−1)k k!z ,O
z−1í4Ç
,15?
z−n−1í[b
¹ª
4” 2.3.6. S(n, k)
í
ƒb
P∞ n=0S(n, k)x n= xk (1−x)(1−2x)···(1−kx), k ≥ 1„p
:q
Mk(x) = ∞ X n=0 S(n, k)xn,‚à]RÉ[
S(n, 1) = S(n, n) = 1, S(n + 1, k) = D(n, k − 1) + kS(n, k),·<ƒ
S(0, k) = 0,
Mk(x) = (kx)Mk(x) + xMk−1(x) ⇒ Mk(x) = x 1 − kxMk−1(x),·<ƒ
M0(x) = 1,)
∞ X n=0 S(n, k)xn= x k (1 − x)(1 − 2x) · · · (1 − kx), k ≥ 1. 4” 2.3.7. S(n, k)íNb
ƒb
: P∞ n=0 S(n,k) n! x n= 1 k!(e x− 1)k„p
:õÒ,
,‚à4”
2.3.5ªJ)
∞ X n=0 S(n, k) n! x n = 1 k! ∞ X n=0 " k X j=0 (−1)jCjk(k − j)n # xn n! = 1 k! k X i=0 (−1)k−iCik ∞ X n=0 inxn n! ! = 1 k! k X i=0 (−1)k−iCikeix = 1 k!(e x− 1)k. (2.40)4” 2.3.8. S(n, k) = 4k0n k!
4” 2.3.9.úkL<õb
x
: xn= S(n, 1)x + S(n, 2)x(x − 1) + · · · + S(n, n)x(x − 1) · · · (x − n + 1).„p
:úk
ƒb
F (x) = xn,‚àÏ}t
F (x) = n X k=0 Ckx4kF (0),£
(2.40) ,1·<ƒç
k > n,v
, 4kxn = 0¹ª)|
4” 2.3.10.Jì2
T0 = 1,†
P∞ n=0 Tnxn n! = e ex−1„p
: ∞ X n=0 Tnxn n! = 1 + ∞ X n=1 n X k=1 S(n, k) n! x n = 1 + ∞ X k=1 ∞ X n=k S(n, k) n! x n = ∞ X k=0 (ex− 1)k k! = eex−1. 4” 2.3.11. Tn+1 =Pn k=0C n kTn−k„p
: ex· eex−1 = ∞ X n=0 xn n! ∞ X n=0 Tn n!x n = ∞ X n=0 " n X k=0 CknTn−k # xn n!= eex−1t = ∞ X n=0 Tn n!x n !t = ∞ X n=0 Tn+1 n! x n,
ªœsi
xní[b
¹)
Tn+1 = n X k=0 CknTn−k. 4” 2.3.12.ç
n ≥ 1v
, Tn= 1 e P∞ k=1 kn k!J-†Ñ
2ùéÍ,Šbí4” à-
: 4” 2.3.13. Sr(n, k) = Cn r−1Sr(n, k − 1) + kS(n, k), 1 ≤ k ≤ n, 0 ≤ r ≤ n,w2
Sr(n, 1) = 1, n ≥ r + 1, Sr(n, k) = 0, 0 < (r + 1)k„p
:5?
n + 1_jÖíÕ¯
A ,Ê}¥_Õ¯ÑFb°í
k_äÕíø_}
é2
,/øjÖ
a¸
ÇÕ
r_jÖ AíäÕ
,¥}é
Cn r−1Sr(n, k − 1)_
,C6jÖ
a¸¬
r_jÖ AíäÕ
,¥ší}é
kSr(n, k)_ â‹¶Ÿ
Ü
,
Sr(n, k) = Cr−1n Sr(n, k − 1) + kS(n, k), 1 ≤ k ≤ n, 0 ≤ r ≤ n. (2.41) 4” 2.3.14. ∞ X n=0 Sr(n, k) n! x n= 1 k! ex− 1 − x −x 2 2! − · · · − xr−1 (r − 1)!„p
:‚à
(2.41)¹ª)|
†4J
(2001)ùéÍ,Šb +›‰bD«…
(Euler)bí
j&[ý
ùéÍ,Šbªâ]cÉ[ì2
: S2(m + 1, n) = S2(m, n − 1) + nS2(m, n), (2.42)w2
S2(m, 1) = S2(m, m) = 1, m, n ∈ N.â
(2.42)%¬
m − nŸLH()
S2(m + 1, n) = m−n+1 X i=0 ni· S2(m − i, n − 1). (2.43)-ÞíìÜ#|
S2(m + 1, n)bí
j&[ýt
: ìÜ 2.3.4. S2(m + 1, n) = (−1) n n! Pn j=1(−1) j · Cn j · jm+1, m, n ∈ N.„p
:àbç¦Ñ¶
:ç
n = 1v
,éÍA
ç
n = kv
,éÍA
ç
n = k + 1v
,â
(2.43)
S2(m + 1, k + 1) = m−k X i=0 (k + 1)i(−1) k k! k X j=1 (−1)j · Ck j · jm−i = (−1) k k! k X j=1 (−1)j · Ck j m−k X i=0 jm−i· (k + 1)i = (−1) k k! k X j=1 (−1)j · Cjk· jk m−k X i=0 jm−k−i· (k + 1)i = (−1) k (k + 1)! k X j=1 (−1)j· Ck+1 j · j k·(k + 1)m−k+1− jm−k+1= (−1) k (k + 1)! " (k + 1)m−k+1 k X j=1 (−1)j· Ck+1 j · j k− k X j=1 (−1)j· Ck+1 j · j m+1 # = (−1) k (k + 1)! ( (k + 1)m−k+1 "k+1 X j=0 (−1)j · Ck+1 j · j k− (−1)k+1(k + 1)k # − k X j=1 (−1)j· Cjk+1· jm+1 ) .
@àøíì
k+1 X j=0 (−1)j· Ck+1 j · j k = 0,ª)
S2(m + 1, k + 1) = (−1)k+1 (k + 1)! " k X j=1 (−1)j· Ck+1 j · j m+1+ (−1)k+1· (k + 1)m+1 # = (−1) k+1 (k + 1)! k+1 X j=1 (−1)j · Ck+1 j · j m+1.Ä7ç
n = k + 1v
,ìÜ
2.3.46uA FJìÜ
2.3.4úø~
n, m ∈ NA
úı
3b!‹
ø
+›‰bílt
ÊÇá3b!‹„p5‡
,Ñ7é„p3b!‹2550ßpü“
,-z3bà
V„p3b!‹5½b9õ
,J
ú_ùÜíj×Û
,Ó(nªp3b!‹5„p
ùÜ 3.1.1.úLSõb
x£LSb
T , |T | < 2π, ∞ X k=0 Sk(x) Tk k! = eT (x+1)− eT eT − 1 .„p
:*
Sk(x) = 1 k + 1 ( (x + 1)k+1− k X i=1 Ci+1k+1Sk−i(x) − 1, ) k ≥ 1,)ø
(x + 1)k+1 = 1 + k X i=0 Ci+1k+1Sk−i(x) = 1 + (k + 1)! k X i=0 1 (i + 1)! Sk−i(x) (k − i)!,Ĥ
(x + 1)k+1 (k + 1)! = 1 (k + 1)! + k X i=0 1 (i + 1)! Sk−i(x) (k − i)!,ÛÊ
,ø,í˝¬°
,
Tk+1 ,1/ø
k X i=0 Ti+1 (i + 1)! Sk−i(x)Tk−i (k − i)! ,eÑ
∞ X i=0 Ti+1 (i + 1)!,¸
∞ X i=0 Si(x)Ti i! ,í5a
(Cauchy product),ª)ƒ
∞ X k=0 (x + 1)kT k k! = e T + (eT − 1) ∞ X k=0 Sk(x) Tk k!. ùÜ 3.1.2.cq
kuø_×k
2í£cb
,FJ
Sk0(−1) = Sk0(0).„p
:q
fn(x) = n X k=0 Sk(x) Tk k!, |T | < 2π,†âùÜ
3.1.1¸
{fn}∞ n=0,ª)ƒ
∞ X k=0 Sk0(x)T k k! = T eT (x+1) eT − 1 ,ªø¥¦
x = 0ª)
T eT eT − 1 = ∞ X k=0 Sk0(0)T k k!, T eT − 1 = ∞ X k=0 Sk0(−1)T k k!, (3.1)èt
(3.1)ª)
T = ∞ X k=0 {Sk0(0) − Sk0(−1)} T k k!, S00(0) = S00(−1), S10(0) − S10(−1) = 1, Sk0(0) = Sk0(−1), ∀k ≥ 2. ùÜ 3.1.3.úLS£cb
k ,ª)
S2k0 (x − 1) = −(2k)! 22k−1(πi)2k ∞ X n=1 1 n2kcos(2nπx), ∀x ∈ [0, 1], (3.2) S2k+10 (x − 1) = −(2k + 1)! 22k(πi)2k+1 ∞ X n=1 i n2k+1sin(2nπx), ∀x ∈ [0, 1]. (3.3)„p
:âùÜ
3.1.3ª
“¨|U‚ƒb
Ck(x), k ≥ 2.ì2à-
:Ck(x) = Sk0( x 2π− 1)ú
x ∈ [0, 2π]J£
Ck(x) = Ck(x + 2π)ú
x ∈ [0, 2π] c‚à
Ck(x)í
Z s²
,ª)
Ck(x) =Pn∈Zan,keinx ,/
an,k = 1 2π Z 2π 0 e−inxCk(x)dx.YW‰b‰² }¶
,ª)
an,k = Z 1 0 e−2nπxiSk0(x − 1)dx, n ∈ Z, k ≥ 2.Ñ7bl
an,k, k ≥ 2, n ∈ Z,ø
n}As¶}
,øu
n 6= 0,Çø†u
n = 0.ç
n 6= 0
v
,ÄÑ
Z 1 0 e−2nπxiS00 (x − 1) dx = Z 1 0 e−2nπxidx = 0, Z 1 0 e−2nπxiS10 (x − 1) dx = − 1 2nπi, |T | ≤ 2π,/
T T − 2nπi = Z 1 0 e−2nπxi T e T x eT − 1dx = Z 1 0 e−2nπxi ( ∞ X k=0 Sk0(x − 1)T k k! ) dx = ∞ X k=0 Tk k! Z 1 0 e−2nπxiSk0(x − 1)dx,ª)
Z 1 0 e−2nπxi T e T x eT − 1dx = − T 2nπi+ ∞ X k=2 an,k Tk k!.¤Õ
,ú
|T | < 2π ,ªù|
T T − 2nπi = − ∞ X k=1 T 2nπi k ,<N
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B0 = S00(−1), B1 = S10(−1), B2k = 1 2k + 1 ( C2k2k+1S10(−1) + k X i=1 C2i+12k+1S2k−2i0 (−1) ) , k ∈ N. (3.5)ù
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: 1. B2 k = 1, S00 = 1.FJ
B2 = − 1 3 ( C23· −1 2+ 1 X i=1 C2i+13 S2−2i0 (−1) ) = 1.666666666666667e − 001. 2. B4 k = 2, ζ(2) = 1 6π 2 , S20 = 1.666666666666667e − 001.FJ
B4 = −1 5 ( C45· −1 2+ 2 X i=1 C2i+15 S4−2i0 (−1) ) = −3.333333333333340e − 002. 3. B6 k = 3, ζ(4) = 1 90π 4 , S40 = −3.333333333333340e − 002.FJ
B6 = −1 7 ( C67· −1 2+ 3 X i=1 C2i+17 S6−2i0 (−1) ) = 2.380952380952404e − 002. 4. B8 k = 4, ζ(6) = 1 945π 6, S0 6 = 2.380952380952404e − 002.FJ
B8 = − 1 9 ( C89· −1 2+ 4 X i=1 C2i+19 S8−2i0 (−1) ) = −3.333333333333469e − 002.5. B10 k = 5, ζ(8) = 1 9450π 8, S0 8 = −3.333333333333469e − 002.
FJ
B10 = − 1 11 ( C1011· −1 2+ 5 X i=1 C2i+111 S10−2i0 (−1) ) = 7.575757575758833e − 002. 6. B12 k = 6, ζ(10) = 1 93555π 10, S0 10= 7.575757575758833e − 002.FJ
B12 = − 1 13 ( C1213· −1 2+ 6 X i=1 C2i+113 S12−2i0 (−1) ) = −2.531135531137224e − 001. 7. B14 k = 7, ζ(12) = 691 638512875π 12, S0 12 = −2.531135531137224e − 001.FJ
B14 = − 1 15 ( C1415· −1 2+ 7 X i=1 C2i+115 S14−2i0 (−1) ) = 1.166666666669796e + 000. 8. B16 k = 8, ζ(14) = 2 18243225π 14, S0 14= 1.166666666669796e + 000.FJ
B16 = − 1 17 ( C1617· −1 2+ 8 X i=1 C2i+117 S16−2i0 (−1) ) = −7.092156862821243e + 000. 9. B18 k = 9, ζ(16) = 3617 325641566250π 16, S0 16 = −7.092156862821243e + 000.FJ
B18 = − 1 19 ( C1819· −1 2 + 9 X i=1 C2i+119 S18−2i0 (−1) ) = 5.497117794722328e + 001. 10. B20 k = 10, ζ(18) = 43867 38979295480125π 18 , S180 = 5.497117794722328e + 001.FJ
B20 = − 1 21 ( C2021· −1 2 + 10 X i=1 C2i+121 S20−2i0 (−1) ) = −5.291242425151527e + 002. 11. B22 k = 11, ζ(20) = 174611 1531329465290625π 20, S0 20 = −5.291242425151527e + 002.FJ
B22 = − 1 23 ( C2223· −1 2 + 11 X i=1 C2i+123 S22−2i0 (−1) ) = 6.192123192661362e + 003. 12. B24 k = 12, ζ(22) = 155366 13447856940643125π 22, S0 22 = 6.192123192661362e + 003.FJ
B24 = − 1 25 ( C2425· −1 2 + 12 X i=1 C2i+125 S24−2i0 (−1) ) = −8.658025335156410e + 004. 13. B26 k = 13, ζ(24) = 236364091 201919571963756521875π 24, S240 = −8.658025335156410e + 004.FJ
B26 = − 1 27 ( C2627· −1 2 + 13 X i=1 C2i+127 S26−2i0 (−1) ) = 1.425517182341780e + 006.14. B28 k = 14, ζ(26) = 1315862 11094481976030578125π 26 , S260 = 1.425517182341780e + 006.
FJ
B28 = − 1 29 ( C2829· −1 2+ 14 X i=1 C2i+129 S28−2i0 (−1) ) = −2.729823226851125e + 007. 15. B30 k = 15, ζ(28) = 6785560294 564653660170076273671875π 28, S280 = −2.729823226851125e + 007.FJ
B30 = − 1 31 ( C3031· −1 2+ 15 X i=1 C2i+131 S30−2i0 (−1) ) = 6.015809797412372e + 008. 16. B32 k = 16, ζ(30) = 6892673020804 5660878804669082674070015625π 30, S300 = 6.015809797412372e + 008.FJ
B32 = −1 33 ( C3233· −1 2+ 16 X i=1 C2i+133 S32−2i0 (−1) ) = −1.511632640519539e + 010. 17. B34 k = 17, ζ(32) = 7709321041217 62490220571022341207266406250π 32, S320 = −1.511632640519539e + 010.FJ
B34 = − 1 35 ( C3435· −1 2+ 17 X i=1 C2i+135 S34−2i0 (−1) ) = 4.296158524259357e + 011.18. B36 k = 18, ζ(34) = 151628697551 12130454581433748587292890625π 34 , S340 = 4.296158524259357e + 011.
FJ
B36 = − 1 37 ( C3637· −1 2 + 18 X i=1 C2i+137 S36−2i0 (−1) ) = −1.371180959826842e + 013. 19. B38 k = 19, ζ(36) = 26315271553053477373 20777977561866588586487628662044921875π 36, S360 = −1.371180959826842e + 013.FJ
B38 = − 1 39 ( C3839· −1 2+ 19 X i=1 C2i+139 S38−2i0 (−1) ) = 4.883543134530475e + 014. 20. B40 k = 20, ζ(38) = 308420411983322 2403467618492375776343276883984375π 38, S380 = 4.883543134530475e + 014.FJ
B40 = − 1 41 ( C4041· −1 2 + 20 X i=1 C2i+141 S40−2i0 (−1) ) = −1.930005581237949e + 016. 21. B42 k = 21, ζ(40) = 261082718496449122051 20080431172289638826798401128390556640625π 40, S400 = −1.930005581237949e + 016.FJ
B42 = − 1 43 ( C4243· −1 2+ 21 X i=1 C2i+143 S42−2i0 (−1) ) = 8.422996050255715e + 017.22. B44 k = 22, ζ(42) = 3040195287836141605382 2307789189818960127712594427864667427734375π 42, S420 = 8.422996050255715e + 017.