允許學生個人、非營利性的圖書館或公立學校合理使用
本基金會網站所提供之各項試題及其解答。可直接下載
而不須申請。
重版、系統地複製或大量重製這些資料的任何部分,必
須獲得財團法人臺北市九章數學教育基金會的授權許
可。
申請此項授權請電郵
ccmp@seed.net.tw
Notice:
Individual students, nonprofit libraries, or schools are
permitted to make fair use of the papers and its
solutions. Republication, systematic copying, or
multiple reproduction of any part of this material is
permitted only under license from the Chiuchang
Mathematics Foundation.
Requests for such permission should be made by
e-mailing Mr. Wen-Hsien SUN
ccmp@seed.net.tw
高 級 卷
1-10 3 1. 7 8 (A) 10 (B) 100 (C) 20 (D) 19 (E) 90 708 718 728 738 748 758 768 778 788 798 10 : (A). 2. p = 7 q =−4 p2− 3q2 (A) 49 (B) 48 (C) 0 (D) 97 (E) 1 p2− 3q2 = 72− 3 × (−4)2 = 49− 3 × 16 = 1 : (E). 3. ( 中級卷 8 ) 中 1 P. 1 Q. 1 R. 1 S. 1 (A) P (B) Q (C) R (D) S (E) P Q R S 4√2 8 2√2 4 Q : (B). 4. n 7n + 6≥ 200 n (A) (B) (C) 28 (D) 27 28 (E) 小 27 7n ≥ 194 n ≥ 194 7 = 27 5 7 n 小 28 n≥ 28 : (C).5. 3 m m2 (A) 20 (B) 30 (C) 40 (D) 50 (E) 60 3 m π(3)2 = 9πm2 π 3 9π 27 中 30 : (B). 6. ( 中級卷 11 ) 中 x (A) 120 (B) 108 (C) 105 (D) 135 (E) 112.5 x◦ x◦ x◦ x◦ 1 360 = 90 + 4× (180 − x) 180− x = 2704 = 67.5 x = 180− 67.5 = 112.5 : (E). 2 3× 180 = 90 + 4x x = 4504 = 112.5 : (E). 7. ( 中級卷 12 ) 中 AB (A) 20 (B) 28 (C) 10 + 9√2 (D) 8 + 9√2 (E) 16 4 3 4 4 5 5 3 A B C A B ABC 16 12 x x2 = 162+ 122 = 400 x = 20 : (A). 8. √x2+ 1 = x + 2 (A) x = 22 7 (B) x =− 3 4 (C) x =− 3 2 (D) x = 3 (E)
√ x2+ 1 = x + 2 ⇒ x2+ 1 = x2+ 4x + 4 ⇒ 4x = −3. x = −3 4 中 5 4 : (B). 9. 中 小 中 小 中 (A) 1 3 (B) 4 9 (C) 1 2 (D) 2 3 (E) 1 27 2 3 小 2 3 小 2 3 × 2 3 = 4 9 : (B). : 小 1 3 3 5 2 5 4 9 1 3 2 3 4 9 10. n 3 (A) n3 (B) n3+ 2n (C) 3n3+ 1 (D) n3+ 3n2 (E) n2+ 2 1 n = 1 (A)= 1 (B)= 3 (C)= 4 (D)= 4 (E)= 3 (B)= n3+ 2n (E)= n2+ 2 n = 2 (B)= 12 (E)= 6 n = 3 (B)= 33 (E)= 11 (B) n3 + 2n 3 n3 + 2n = n(n2 + 2) = n(n2 − 1) + 3n = (n− 1)n(n + 1) + 3n n n− 1 n n + 1 中 3 n3+ 2n 3 : (B).
2 (A) (C) (D) (E) Cn = n3+ 2n 3 Cn+1− Cn= (n + 1)3+ 2(n + 1)− n3− 2n = 3n2+ 3n + 3 C1 = 3 3 3 : (B). 11-20 4 11. 22016− 22015 (A) 2 (B) 220162015 (C) 22015 (D) −22016 (E) 0 22016− 22015 = 2× 22015− 22015 = 22015 : (C). 12. • • 45 • 60 • 60 ( ) 中 (A) 60 (B) 20 (C) 45 (D) 5 (E) 40 60 15 + n 45− n n 105− n 15 + 2n n 45− n 60− (45 − n) = 15 + n 60 + 45− n = 105 − n 15 + n + n = 15 + 2n 120 + n 中 120 + n = 5(15 + 2n) = 75 + 10n 9n = 45 n = 5 : (D). 13. y = 6− x2 x-( ) (A) 11 (B) 12 (C) 14 (D) 15 (E) 17 x y
(0, 6) (±1, 5) (±2, 2) 1 + 4 + 5 + 4 + 1 = 15 ◦ • • • • • ◦ • • • • ◦ • ◦ • • • • ◦ • : (D). 14. P QRS P Q QR P X Q RS Q′ SP X 小 (A) 72◦ (B) 45◦ (C) 60◦ (D) 67.5◦ (E) 75◦ S R X P Q′ Q SP Q′ 中 ∠P SQ′ = 90◦ P Q′ = 2P S SP Q′ 30◦–60◦–90◦ ∠SP Q = 60◦ ∠QP Q′ = 30◦ ∠QP X = 15◦ ∠SP X = 75◦ : (E). 15. ( 中級卷 19 ) 20 中 8 9 10 (A) 10 (B) 11 (C) 12 (D) 13 (E) 14 m 20 10 10≤ m ≤ 20 8 + 8 + 9 + 7m 10 = 25 + 7m 10 25 + 7m 10 m 5 m 15 25 + 7× 15 10 = 13 : (D).
16. 中 P QR QST QR = QT = 4 cm QRXT cm2 (A) 16(√2− 1) (C) 16√2− 10 (B) 4√2 (D) 8(√2− 1) (E) 8−√2 R P Q S T X R P Q S T X 4 x x QR = P R = QT = T S = 4 cm x cm = RS = RX QRXT 1 2× 4 2−1 2x 2 = (8−1 2x 2) cm P Q2 = 42 + 42 = 32 cm2 P Q = QS = 4√2 cm x = 4√2− 4 = 4(√2− 1) cm QRXT 8−1 2x 2 = 8− 8(√2− 1)2 = 16(√2− 1) cm2 : (A). 17. x + 2x + 3x + 4x +· · · + 100x x 小 (A) 202 (B) 5050 (C) 1010 (D) 100 (E) 101 S = x + 2x +· · · + 100x = x(1 + 2 + · · · + 100) = 5050x = 2 × 52× 101 × x. S 中 x 小 2× 101 = 202 : (A). 18. 80% 小 小 (A) 12 (B) 20 (C) 8 (D) 15 (E) 19 1 r 小 0.8r 小 4 3π(0.8r) 3 4 3πr3 = (0.8)3 = 0.512
19× 0.512 = 9.728 10 19 小 : (E). 2 小 (4 5) 3 = 64 125 125 64 小 10 1250 64 = 625 32 = 19 17 32 小 19 小 : (E). 19. 1 中 1 (A) 2 (B) 3 (C) 4 (D) 5 (E) 6 中 (h, i, j, k) 中 2 h + i + j + k = 10 h i≥ k (4, 2, 2, 2) (3, 3, 2, 2) (3, 2, 3, 2) 4 2 2 2 3 3 2 2 3 2 3 2 : (B). 20. 1 2 4 · · · 小 2016 (A) 1008 (B) 63 (C) 11 (D) 15 (E) 673 1 2 4 7 10 13 · · · 2 3 1 2016÷ 3 = 672 1 2017 2 小 2016 673 2 3k + 1 n≥ 2 n + 1 2 3k + 1 中 0≤ k ≤ n − 1 n = 2 中 m = 3n− 2 m≥ 4 1 2 m 中 m + 1 m + 2 m + 3 = 3n + 1 3 1 4 中 m 2 + 2 = 4 2 + (3k + 1) = 3(k + 1) (3k + 1) + (3j + 1) = 3(j + k) + 2
中 4 3 1 小 m + 3 m + 3 m + 3 = 3n + 1 n ≥ 2 中 (n + 2) 3n + 1 : (E). 21-25 5 21. 中 小 1 (A) 16 (B) 15 (C) 14 (D) 13 (E) 12 1 A B C D X Y 3x AC =√9x2+ 4x2 = x√13 ABC AXB AY D AX AB = AB AC AX = 9x2 x√13 = 9 √ 13x AY = √6 13x XY = 3 √ 13x 1 XY = 1 x = √ 13 3 3x = √13 13 : (D). 2 A P B C D X Y AXP AY B AX = Y B AP = 23AB AX = 23AY XY = 1 3AY 1 XY = 1 AY = 3 AX = 2 AY B 中 AY = 3 Y B = 2 AY B 12 × 3 × 2 = 3 ABCD AY B 中 小 4× 3 + 1 = 13 : (D).
小 小 小 13 : (D). 22. n2+ n + 34 n (A) 50 (B) 16 (C) 43 (D) 34 (E) 49 1 n2+ n + 34 = (n + k)2 = n2+ 2kn + k2 中 k > 0 n = 34−k2 2k−1 k > 5 n < 0 k 1 2 3 5 n 33 10 5 1 33 + 10 + 5 + 1 = 49 : (E). 2 n2+ n + 34 (2a)2 = n2+ n + 34 中 a > 0 4a2 =(n +1 2 )2 −14 + 34 16a2 = (2n + 1)2+ 135 (4a)2− (2n + 1)2 = 135 (4a + 2n + 1)(4a− 2n − 1) = 33× 5 135 x = 4a + 2n + 1 y = 4a− 2n − 1 x > 0 x > y y = 135 x > 0 135 = xy 中 x > y > 0 a = x + y 8 n = x− y − 2 4 x = 4a + 2n + 1 y = 4a− 2n − 1 a n 135 1 17 33 45 3 6 10 27 5 4 5 15 9 3 1 49 33 + 10 + 5 + 1 = 49 : (E). 23. 2 (A) √2− 1 (B) 2− √ 2 2 (C) √ 6−√2 2 (D) √ 3 3 (E) √ 2 4
中 中 中 B A C D E C D BE = ED = 1 AE = √3 AD =√3− 1 AB =√2 ABE ADC CD = AD× BE AB = √ 3− 1 √ 2 = √ 2× (√3− 1) √ 2×√2 = √ 6−√2 2 : (C). 24. (A) 4 (B) 5 (C) 6 (D) 7 (E) 9 10 小 中 小 中 9 n = −4 n = 5 n 100− n2 −4 ≤ n ≤ 4 y = f (n) = 100− n2 f (n− 1) + f(n + 1) 2 = 100− (n + 1)2+ 100− (n − 1)2 2 = 99− n 2 = f (n)− 1 9 : (E). 25. √x2+ (1− x)2+√(1− x)2+ (1 + x)2 小 (A) 2 (B) √ 2 +√10 2 (C) √ 5 (D) 0 (E) 1 +√2
x y A B C 1 1 2 AB + BC 小 B y = 1− x 小 A B C AC =√5 : (C). 26-30 000-999 26 6 27 7 28 8 29 9 30 10 26. ( 中級卷 29 ) 高中 3 5 小 小 r c rc 3r 5c 3r + 5c rc− 3r − 5c = 0 (r− 5)(c − 3) = 15 (r− 5, c − 3) (1, 15) (3, 5) (5, 3) (15, 1) 15 r≤ 0 c≤ 0 (r, c) (6, 18) (8, 8) (10, 6) (20, 4) rc 108 64 60 80 r = 6 c = 18 r = 8 c = 8 r = 10 c = 6 r = 20 c = 4
小 108 + 64 + 60 + 80 = 312 : (312). 27. a b c m n m < n f (x) = ax2+ bx + c 中 x f (x) (m, 0) (n, 20162) n− m f (n)− f(m) = (an2+ bn + c)− (am2+ bm + c) 20162− 0 = (a(n + m) + b)(n − m) n− m 20162 20162 d m = 0 n = d a = 0 b = 20162 d d n− m 20162 = 210× 34× 72 11× 5 × 3 = 165 n− m 165 : (165). 28. a b 1 100 (a, b) a√b = √ ab a√b = ab/2 a = 1 b 1 100 a ̸= 1 b √b = 2b b > 0 b = 4 a 2 100 199 : (199). 29. ( 中級卷 30 ) 64 64× 63 ÷ 2 = 2016 中 中
64 中 31 64 31 64 + 30 + 2× 31 = 156 n 中 n Mn Mn ≥ n + n 2 − 2 + 2 × ( n 2 − 1) = 5 2n− 4 n Mn = 52n− 4 n = 4 Mn = 6 = 5 2 × 4 − 4 P Q (i) P Q R P R QR (ii) P Q R S P R P S QR QS RS. P Q P R Q (i) (ii) P S R Q
(ii) 4 (i) (ii) (ii) (ii) 6 + 5× 1 2(n− 4) = 5 2 n− 4 (i) (ii) n = 4 n n 中 n (i) (ii) X V Y U P P 5 中 XY U V XY P XU Y V XY U V XU Y V 中 ( ) P 5 XU Y V ̸= P XU Y V P XU XU P P 4 4 (i) (ii) n (ii) Mn= 52n− 4 M64 = 160− 4 = 156 : (156).
2 1 64 + 30 + 2× 31 = 156 64 A B C D X 中 AC BD X AC BD ABCD AB BC CD DA ABCD f + v = e + 2 中 64 64 q t • v = 64 + q 64 • f = 1 + t + 4q 64 t • e 中 2e = 64 + 3 (t + 4q) • c = e− 2q = 32 + 3 2t + 4q f + v = e + 2 0 = (f + v)− (e + 2) = (65 + t + 5q) − (34 +3 2t + 6q) = 31− 1 2t− q c = 32 + 3 2t + 4(31− 1 2t) = 156− 1 2t 156 q = 31 t = 0 : (156). 3 1 64 + 30 + 2× 31 = 156 中 中 64 64 中 64 64 中 4 4 P
A B C X P P BC AX 中 A B C P X P P ABC AB AC 中 P AB AB P AB AB BC BC AX AB 中 中 64 64 62 64 + 61 = 125 中 31 125 + 31 = 156 64 62 31 156 : (156). 30. f n f (f (n)) = 2n f (4n + 1) = 4n + 3 f (2016) 1 f (4n + 1) = 4n + 3 f (4n + 3) = f (f (4n + 1)) = 2(4n + 1) f (2(4n + 1)) = f (f (4n + 3)) = 2(4n + 3) f (2(4n + 3)) = f (f (2(4n + 1))) = 22(4n + 1) f (22(4n + 1))) = f (f (2(4n + 3))) = 22(4n + 3) .. . ... f (2k(4n + 1)) = 2k(4n + 3) f (2k(4n + 3)) = 2k+1(4n + 1) f (2016) = f (63× 32) = f((4 × 15 + 3) × 25) = 61× 26 = 3904 : (904). 2 m f (m) 中 4n + 1 4n + 3 m −→ x x−→ 2m n = 2 4n + 1 = 9 4n + 3 = 11 9 18 36 72 144 11 22 44 88
2016 = 63× 25 中 63 = 2× 15 + 3 61 122 244 25× 61 26× 61 63 126 252 25× 63 · · · f (2016) = 26× 61 = 3904 : (904). 3 f (f (f (n))) = f (2n) f (f (f (n))) = 2f (n) f (2n) = 2f (n) k f (2kn) = 2kf (n) f (2016) = f (25× 63) = 25f (63) f (63) = f (f (61)) = 122 f (2016) = 25× 122 = 3904 : (904).