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1 x + 2x tan x2 Rx2 1 tan tdt 1

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微乙小考四 (2015/11/26)

1. (8分) 令 f (x) = 3x2+ 2x, x ∈ [0, 2]。令 ¯f 為 f(x) 在 [0, 2] 區間上的平均值。求一常數 c ∈ [0, 2]

使得 f (c) = ¯f . sol:

f (c) = ¯f = R2

0 f (x)dx 2 − 0

= R2

0(3x2+ 2x)dx 2

=

(x3+ x2)

2

0

2

= 6

∴ 3c2+ 2c = 6 ⇒ c = −2 +√ 76

6 ∈ [0, 2]

2. 求下列函數的導函數:

(a) (6分) d dx

Z 1 x2

sin t t dt (b) (6分) d

dxln x · Z x2

1

tan tdt

!

sol: (a)

d dx

Z 1 x2

sin t

t dt = 0 − sin x2 x2 · 2x

= −2 sin x2 x (b)

d dxln

 x ·

Z x2 1

tan tdt



= 1

xRx2

1 tan tdt

 Z x2 1

tan tdt + x · tan x2· 2x



= 1

x + 2x tan x2 Rx2

1 tan tdt

1

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