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1. Fubini-Study Metric

Let Pn be the n-dimensional complex projective space and (ζ0 : · · · : ζn) be the homoge- neous coordinates on Pn. For 0 ≤ α ≤ n, we denote the open set

Uα = {(ζ0 : · · · : ζn) : ζα 6= 0}.

Let ϕα: Uα→ Cn be the coordinate chart defined by ϕα0 : · · · : ζn) = ζ0

ζα, · · · ,ζα−1

ζαα+1

ζα , · · · ,ζn

ζα

 .

In other words, we define a local coordinate system zα= (zα1, · · · , zαn) on Uα by ziα0 : · · · : ζn) =

(ζ

i−1

ζα if i < α

ζi

ζα if i > α.

For 1 ≤ i, j ≤ n, we define a function on Cn by hij(z) = (1 +Pn

k=1|zk|2ij− zizj (1 +Pn

k=1|zk|2)2 .

Proposition 1.1. The matrix valued function H(z) = (hij(z))ni,j=1 is smooth and H(z) is a positive definite Hermitian matrix for all z ∈ Cn.

Proof. Since each complex value function hij(z) is smooth on Cn, z 7→ H(z) is smooth.

Moreover,

hij(z) = hji, 1 ≤ i, j ≤ n.

Hence H(z) is Hermitian for all z ∈ Cn.

Let h·, ·i denote the standard inner product on Cn and k · k the norm induced from it.

For each z, w ∈ Cn, we have

hH(z)w, wi = (1 + kzk2)kwk2− |hz, wi|2 (1 + kzk2)2 . By the Cauchy-Schwarz inequality,

|hz, wi|2 ≤ kzk2kwk2. Hence we find

hH(z)w, wi ≥ kwk2

(1 + kzk2)2 ≥ 0.

We find that hH(z)w, wi = 0 implies that kwk2 = 0. Therefore w = 0. This shows that

H(z) is positive definite for each z ∈ Cn. 

Let us define a function K on Cn by

K(z) = log 1 +

n

X

k=1

|zk|2

! . Let us compute ∂K:

∂K = Pn

j=1zjdzj 1 +Pn

k=1|zk|2.

1

(2)

2

Hence ∂∂K is given by

∂∂K =

n

X

i,j=1

δij(1 +Pn

k=1|zk|2) − zizj (1 +Pn

k=1|zk|2)2 dzi∧ dzj

=

n

X

i,j=1

hij(z)dzi∧ dzj.

For each 0 ≤ α ≤ n, we define a (1, 1)-form on Uα by ωα =√

−1

n

X

i,j=1

(hij ◦ ϕα)dzαi ∧ dzjα. This implies that if we denote Kα = K ◦ ϕα on Uα, then

ωα =√

−1∂∂Kα. Lemma 1.1. ∂2 = 0 and ∂2 = 0. We also have ∂∂ = −∂∂.

Proof. This can be proved by direct computation. 

Using the decomposition d = ∂ + ∂, and Lemma 1.1, we find dωα =√

−1∂2∂Kα+√

−1∂∂∂Kα

= −√

−1∂∂2Kα

= 0.

This shows that ωα is a closed (1, 1) one-form on Uα for each α. In fact, we can show that the (1, 1)-form on each Uα can be glued together to obtain a closed global (1, 1)-form ω on Pn.

On Uα, let us rewrite Kα as follows:

Kα0: · · · : ζn) = log 1 +

n

X

k=1

|zαk0: · · · : ζn)|2

!

= log

n

X

i=0

i|2

!

− log |ζα|2. Assume that α < β. Then on Uα∩ Uβ,

Kα0 : · · · : ζn) − Kβ0: · · · : ζn) = log |ζβ|2− log |ζα|2= log

ζβ ζα

2

= log

zαβ0: · · · : ζn)

2

. In other words, on Uα∩ Uβ,

Kα− Kβ = log zαβ

2

. On Uα∩ Uβ,

∂(Kα− Kβ) = 1 zαdzβα

and hence ∂∂(Kα− Kβ) = 0 on Uα∩ Uβ. In other words, on Uα∩ Uβ,

∂∂Kα = ∂∂Kβ.

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3

Hence ωα = ωβ on Uα∩ Uβ. We obtain a global (1, 1)-form ω. Since dωα = 0 on each Uα, the (1, 1)-form ω is a closed form on Pn. Since ω is globally defined, the 2-tensor

(1.1)

n

X

i,j=1

(hij ◦ ϕα)dziα⊗ dzjα

is also globally defined. Since we have already verify that H(z) is a positive definite matrix on Cn, (1.1) defines a Hermitian metric on Pn whose associated (1, 1)-form is ω. Thus we conclude that

Theorem 1.1. Pn is a Kahler manifold.

The Kahler metric on Pn defined in (1.1) is called the Fubini-Study metric.

2. Case for P1.

Let (ζ0, ζ1) be the standard coordinate on C2and (ζ0 : ζ1) be the corresponding coordinate on P1. Denote U = {(ζ0 : ζ1) : ζ0 6= 0} and V = {(ζ0 : ζ1) : ζ1 6= 0}. {U, V } forms an open covering of P1. Let z be the coordinate function on U and w be the coordinate function on V. In other words,

z(ζ0 : ζ1) = ζ1

ζ0

, w(ζ0 : ζ1) = ζ0

ζ1

. Hence on U ∩ V, we have the coordinate transformation

w = 1 z.

Let KU = log(1 + |z|2) on U and KV = log(1 + |w|2) on V. Observe that

KU0 : ζ1) = log(|ζ0|2+ |ζ1|2) − log |ζ0|2, KV0: ζ1) = log(|ζ0|2+ |ζ1|2) − log |ζ1|2. We see that on U ∩ V,

KU0 : ζ1) − KV0: ζ1) = log

ζ1 ζ0

2

= log |z(ζ0: ζ1)|2. Hence we obtain that on U ∩ V

KU− KV = log |z|2. By |z|2 = zz, we have

∂(KU − KV) = 1 zdz.

Hence we find

∂∂(KU− KV) = ∂ 1 z



∧ dz = 0.

This shows that on U ∩ V,

∂∂KU = ∂∂KV.

This {(∂∂KU, U ), (∂∂KV, V )} gives us a globally defined (1, 1)-form ω defined by ω =

(√−1∂∂KU on U ,

√−1∂∂KV on V .

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4

Let us compute ω. We know ∂KU = z

1 + |z|2dz, and hence

∂∂KU = ∂

 z

1 + |z|2



∧ dz

= (1 + |z|2)∂z − z∂(1 + |z|2) (1 + |z|2)2 ∧ dz

= (1 + |z|2)dz − |z|2dz (1 + |z|2)2 ∧ dz

= 1

(1 + |z|2)2dz ∧ dz.

Similarly,

∂∂KV = 1

(1 + |w|2)2dw ∧ dw.

Hence the (1, 1)-form ω is given by ω =

( −1

(1+|z|2)2dz ∧ dz on U ,

−1

(1+|w|2)2dw ∧ dw on V . The Kahler metric ds2 on Pn is given by

ds2 =

( 1

(1+|z|2)2dz ⊗ dz on U ,

1

(1+|w|2)2dw ⊗ dw on V .

Let us verify this metric is globally defined. On U ∩ V, we have w = 1/z and w = 1/z.

Hence on U ∩ V,

dw ⊗ dw = dz z2 ⊗dz

z2 = 1

|z|4dz ⊗ dz.

Moreover, on U ∩ V,

1

(1 + |w|2)2 = 1 (1 +

1z

2)2 = |z|4 (|z|2+ 1)2. On U ∩ V,

1

(1 + |z|2)2dz ⊗ dz = |z|4 (1 + |z|2)2

dz ⊗ dz

|z|4 = 1

(|w|2+ 1)2dw ⊗ dw.

We prove that ds2 is a globally defined Hermitian metric.

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