1. Fubini-Study Metric
Let Pn be the n-dimensional complex projective space and (ζ0 : · · · : ζn) be the homoge- neous coordinates on Pn. For 0 ≤ α ≤ n, we denote the open set
Uα = {(ζ0 : · · · : ζn) : ζα 6= 0}.
Let ϕα: Uα→ Cn be the coordinate chart defined by ϕα(ζ0 : · · · : ζn) = ζ0
ζα, · · · ,ζα−1
ζα ,ζα+1
ζα , · · · ,ζn
ζα
.
In other words, we define a local coordinate system zα= (zα1, · · · , zαn) on Uα by ziα(ζ0 : · · · : ζn) =
(ζ
i−1
ζα if i < α
ζi
ζα if i > α.
For 1 ≤ i, j ≤ n, we define a function on Cn by hij(z) = (1 +Pn
k=1|zk|2)δij− zizj (1 +Pn
k=1|zk|2)2 .
Proposition 1.1. The matrix valued function H(z) = (hij(z))ni,j=1 is smooth and H(z) is a positive definite Hermitian matrix for all z ∈ Cn.
Proof. Since each complex value function hij(z) is smooth on Cn, z 7→ H(z) is smooth.
Moreover,
hij(z) = hji, 1 ≤ i, j ≤ n.
Hence H(z) is Hermitian for all z ∈ Cn.
Let h·, ·i denote the standard inner product on Cn and k · k the norm induced from it.
For each z, w ∈ Cn, we have
hH(z)w, wi = (1 + kzk2)kwk2− |hz, wi|2 (1 + kzk2)2 . By the Cauchy-Schwarz inequality,
|hz, wi|2 ≤ kzk2kwk2. Hence we find
hH(z)w, wi ≥ kwk2
(1 + kzk2)2 ≥ 0.
We find that hH(z)w, wi = 0 implies that kwk2 = 0. Therefore w = 0. This shows that
H(z) is positive definite for each z ∈ Cn.
Let us define a function K on Cn by
K(z) = log 1 +
n
X
k=1
|zk|2
! . Let us compute ∂K:
∂K = Pn
j=1zjdzj 1 +Pn
k=1|zk|2.
1
2
Hence ∂∂K is given by
∂∂K =
n
X
i,j=1
δij(1 +Pn
k=1|zk|2) − zizj (1 +Pn
k=1|zk|2)2 dzi∧ dzj
=
n
X
i,j=1
hij(z)dzi∧ dzj.
For each 0 ≤ α ≤ n, we define a (1, 1)-form on Uα by ωα =√
−1
n
X
i,j=1
(hij ◦ ϕα)dzαi ∧ dzjα. This implies that if we denote Kα = K ◦ ϕα on Uα, then
ωα =√
−1∂∂Kα. Lemma 1.1. ∂2 = 0 and ∂2 = 0. We also have ∂∂ = −∂∂.
Proof. This can be proved by direct computation.
Using the decomposition d = ∂ + ∂, and Lemma 1.1, we find dωα =√
−1∂2∂Kα+√
−1∂∂∂Kα
= −√
−1∂∂2Kα
= 0.
This shows that ωα is a closed (1, 1) one-form on Uα for each α. In fact, we can show that the (1, 1)-form on each Uα can be glued together to obtain a closed global (1, 1)-form ω on Pn.
On Uα, let us rewrite Kα as follows:
Kα(ζ0: · · · : ζn) = log 1 +
n
X
k=1
|zαk(ζ0: · · · : ζn)|2
!
= log
n
X
i=0
|ζi|2
!
− log |ζα|2. Assume that α < β. Then on Uα∩ Uβ,
Kα(ζ0 : · · · : ζn) − Kβ(ζ0: · · · : ζn) = log |ζβ|2− log |ζα|2= log
ζβ ζα
2
= log
zαβ(ζ0: · · · : ζn)
2
. In other words, on Uα∩ Uβ,
Kα− Kβ = log zαβ
2
. On Uα∩ Uβ,
∂(Kα− Kβ) = 1 zαdzβα
and hence ∂∂(Kα− Kβ) = 0 on Uα∩ Uβ. In other words, on Uα∩ Uβ,
∂∂Kα = ∂∂Kβ.
3
Hence ωα = ωβ on Uα∩ Uβ. We obtain a global (1, 1)-form ω. Since dωα = 0 on each Uα, the (1, 1)-form ω is a closed form on Pn. Since ω is globally defined, the 2-tensor
(1.1)
n
X
i,j=1
(hij ◦ ϕα)dziα⊗ dzjα
is also globally defined. Since we have already verify that H(z) is a positive definite matrix on Cn, (1.1) defines a Hermitian metric on Pn whose associated (1, 1)-form is ω. Thus we conclude that
Theorem 1.1. Pn is a Kahler manifold.
The Kahler metric on Pn defined in (1.1) is called the Fubini-Study metric.
2. Case for P1.
Let (ζ0, ζ1) be the standard coordinate on C2and (ζ0 : ζ1) be the corresponding coordinate on P1. Denote U = {(ζ0 : ζ1) : ζ0 6= 0} and V = {(ζ0 : ζ1) : ζ1 6= 0}. {U, V } forms an open covering of P1. Let z be the coordinate function on U and w be the coordinate function on V. In other words,
z(ζ0 : ζ1) = ζ1
ζ0
, w(ζ0 : ζ1) = ζ0
ζ1
. Hence on U ∩ V, we have the coordinate transformation
w = 1 z.
Let KU = log(1 + |z|2) on U and KV = log(1 + |w|2) on V. Observe that
KU(ζ0 : ζ1) = log(|ζ0|2+ |ζ1|2) − log |ζ0|2, KV(ζ0: ζ1) = log(|ζ0|2+ |ζ1|2) − log |ζ1|2. We see that on U ∩ V,
KU(ζ0 : ζ1) − KV(ζ0: ζ1) = log
ζ1 ζ0
2
= log |z(ζ0: ζ1)|2. Hence we obtain that on U ∩ V
KU− KV = log |z|2. By |z|2 = zz, we have
∂(KU − KV) = 1 zdz.
Hence we find
∂∂(KU− KV) = ∂ 1 z
∧ dz = 0.
This shows that on U ∩ V,
∂∂KU = ∂∂KV.
This {(∂∂KU, U ), (∂∂KV, V )} gives us a globally defined (1, 1)-form ω defined by ω =
(√−1∂∂KU on U ,
√−1∂∂KV on V .
4
Let us compute ω. We know ∂KU = z
1 + |z|2dz, and hence
∂∂KU = ∂
z
1 + |z|2
∧ dz
= (1 + |z|2)∂z − z∂(1 + |z|2) (1 + |z|2)2 ∧ dz
= (1 + |z|2)dz − |z|2dz (1 + |z|2)2 ∧ dz
= 1
(1 + |z|2)2dz ∧ dz.
Similarly,
∂∂KV = 1
(1 + |w|2)2dw ∧ dw.
Hence the (1, 1)-form ω is given by ω =
( √−1
(1+|z|2)2dz ∧ dz on U ,
√−1
(1+|w|2)2dw ∧ dw on V . The Kahler metric ds2 on Pn is given by
ds2 =
( 1
(1+|z|2)2dz ⊗ dz on U ,
1
(1+|w|2)2dw ⊗ dw on V .
Let us verify this metric is globally defined. On U ∩ V, we have w = 1/z and w = 1/z.
Hence on U ∩ V,
dw ⊗ dw = dz z2 ⊗dz
z2 = 1
|z|4dz ⊗ dz.
Moreover, on U ∩ V,
1
(1 + |w|2)2 = 1 (1 +
1z
2)2 = |z|4 (|z|2+ 1)2. On U ∩ V,
1
(1 + |z|2)2dz ⊗ dz = |z|4 (1 + |z|2)2
dz ⊗ dz
|z|4 = 1
(|w|2+ 1)2dw ⊗ dw.
We prove that ds2 is a globally defined Hermitian metric.