• 沒有找到結果。

An Elementary Proof that Schoenberg's Space-Filling Curve Is Nowhere Differentiable

N/A
N/A
Protected

Academic year: 2022

Share "An Elementary Proof that Schoenberg's Space-Filling Curve Is Nowhere Differentiable"

Copied!
4
0
0

加載中.... (立即查看全文)

全文

(1)

VOL. 65, NO. 2, APRIL 1992 125

An Elementary Proof that Schoenberg's Space-Filling Curve Is Nowhere Differentiable

HANS SAGAN

North Carolina State University Raleigh, NC 27695

Up to the end of the nineteenth century (and in six, randomly selected, contemporary calculus books) a plane curve was (and is) defined as the "graph of a pair of parametric equations

x=f(t) tEE I

in which the functions f, g are continuous on the interval 1", or by words to that effect. This "conventional wisdom" was shattered in 1890 when G. Peano [1]

demonstrated that this definition embraces what are now called "space-filling curves,"

that is, curves that pass through every point of a two-dimensional region with positive content such as a square. Since one does not ordinarily call a square a curve, one has to place restrictions on f and g for (1) to produce what one might conventionally call a curve. For example, if one assumes that the mapping (f, g): I -> E2 is continuous and injective, one obtains what is generally referred to as a Jordan arc that is, by a theorem of Netto ("a bi-jective map from a line onto a surface is, by necessity, discontinuous" [2]) not space filling.

Peano's pioneering work spawned numerous other examples of space-filling curves, one of which, namely Schoenberg's, will be the object of this discussion.

To produce Schoenberg's curve, let I = [0, 1] and let f, g in (1) be defined by

1 00 1

f(t) = 2

E

p(32kt)/2k, g(t) =- E p(32k+lt)/2k (2)

k=O k=O

where the 2-periodic even function p is defined as in FIGURE 1. (See also [3].)

It is not difficult to demonstrate that f, g are continuous on [0, 1] and that (1), with f, g defined as in (2), represents a space-filling curve (see [3] or [4, p. 365] or [5, p.

438]).

,3 3 3 3 3 ,3 3 3 2 3 3 3

FIGURE I

Some space-filling curves (but not all) are nowhere differentiable and Schoenberg's is one of them. This was not proved until 1981 when J. Alsina published a fairly complicated and laborious proof [6]. (By contrast, Lebesgue's space-filling curve is a.e.

differentiable [4, p. 365].) Schoenberg himself proved in [7] that for 0 < a < 1, b odd, and ab > 4, the function

(2)

126 MATHEMATICS MAGAZINE

oo

F. a E( b t)

k=O

is nowhere differentiable, where E is linear between consecutive integers and E(n) = (-

1)n

for all integers n. He did this by a clever adaptation of Rudin's proof of the nondifferentiability of Weierstrass' first example of such a function ([8, pp.

125-127]). He used this result, in turn, to establish the nowhere differentiability of his curve.

Our proof that Schoenberg's curve is nowhere differentiable is straightforward and does not utilize any advanced notions and techniques. It represents a suitable modification of a proof that the function

00

E

Sk(t)

k=l

with s1l S2, S3,... defined as in FIGURE 2, is nowhere differentiable ([9]) and is based on the following.

LEMMA. If f: [0, 1] -- R is differentiable at t E (0, 1), then, for any two sequences {an} -- t, {bn > t with 0 an < t <bn < 1, by necessity,

lmf(bb) -f(an) f

n oo n

-an

exists.

2 1 2 113 2

FIGURE 2 22

The proof of this lemma consists of the observation that

f(bn) -f (an) f '( t) =

__

t f ( bn)-f ( t) _f '( t)

-f'(t) =

~

(f(b b () (a)

+-a b-a

-

at t f(t)

and that

bn- 1- n

|b

"-a-| an|

are bounded.

We are now ready to establish our main result:

THEOREM. The functions f, g as defined in (2) are nowhere differentiable.

Proof (i) First, let t = 0. Choose bn = 1/9n and consider f(0) =0

1 00

f(1/9n) =

E

P(9k/9n)/2k k2=

(3)

VOL. 65, NO. 2, APRIL 1992 127

Since

p(9k;9n)

=(

for k <

n

1 for k >~n, we have

f(1/9") =

E

1/2k = 1/21,

k = n

and hence

f(bti) _f(o) 9 81l

b = 2 ?

as n -> oo, i.e., f'(O) does not exist.

(ii) Next, let t = 1 and choose all = 1 - 1/91 to obtain

f(l) -f(ta) 9( 9)

as n -> oo, i.e., f'(1) does not exist.

Observe, that we did not need the lemma for these two cases but only the definition of the derivative as the limit of an average rate of change.

(iii) Finally, let t E (0, 1). To achieve our objective, we have to find for every such t two sequences {al}, {bJ} that satisfy the requirements of the lemma so that the limit in (3) does not exist. We will do this for the ftunction f.

Let

kl= [9t], (4)

where [x] denotes the largest integer that is less than or equal to x, and let all = k,/9', b,l = k/9't + 1/911.

It is a simple matter to show that, for sufficiently large n, 0 <a,< t <bl <1 and that {an} -- t, {bJ1 --. t.

From (4), infinitely many k,, are even or infinitely many k,, are odd, or both. We will assume for the sequel that infinitely many of them are even and denote the corresponding subsequence again by k,, in order to avoid double subscripts.

From (2) and (4),

f (a )~kO ~(k) f (b )-kk= (

n e,P n) gn n n )

9

n n

Hence,

(4)

128 MATHEMATICS MAGAZINE

If k <n, then gk;9n, < 1/9 and, in order to obtain a lower estimate for SI, we assume the worst possible situation where (9kl/9n)k + (gk/lgr), as well as (9k/9fl)k

both lie in an interval where p descends with slope -3 (see FIGURE 1). Then,

( kl +

n)

k( .11)> 3(9k/9n).

Hence,

1 11-1 9 k 3 n-I3

1 13 - 3 7F- = - 92 . gn~ [(9/2) 1] (5)

2 k- 9 3 k 37 g

If k > n, then (9k/9n,) > 1, odd. Hence, (9k;9n)k,, is even and (9k9nl)kn + (gkl/g) = even + odd = odd. Therefore,

= 2 E 2k[p(odd)-p(even)]=2

E

?=1/2". (6)

k=n

2

k=n

From (5) and (6),

b' )-a n n( SI + S2) - - + - --> ??

as n -> oo, i.e., f'(t) does not exist.

We assumed for the preceding argument that infinitely many of the k,, are even. If infinitely many of them are odd, we reverse our strategy and seek an upper bound for the difference quotient. We obtain by analogous reasoning that

f(bn) -f(an) 4(9 _9n 3

b~ -a~ <7Y2j - oo Since g(t) =f(3t) by (2), g is also nowhere differentiable.

That the Schoenberg curve is nowhere differentiable as opposed to the Lebesgue curve that is differentiable almost everywhere finds a very graphic expression in the behavior of their approximating polygons [4, FIGURES 2 and 8].

REFERENCES

1. G. Peano, Sur une coui-be qui remplit toute une aire plane, Math. Ann. 36 (1890), 157-160.

2. E. Netto, Beitrag zuI Mannigfaltigkeitslehre, Crelle J. 86 (1879), 263.

3. I. J. Schoenberg, The Peano-Curve of Lebesgue, Bull. Amer. Math. Soc. 44 (1938), 519.

4. H. Sagan, Approximating polygons for Lebesgue's and Schoenberg's space-filling curves, Amer. Math.

Monthly, 93 (1986), 361-368.

5. H. Sagan, Advanced Calculus, Houghton-Mifflin, Boston, 1974.

6. J. Alsina, The Peano Curve of Schoenberg is nowher-e differentiable, J. Approx. Theory 33 (1981), 28-42.

7. I. J. Schoenberg, Mathematical Time Exposures, MAA, Washington, DC, 1982, pp. 135-148.

8. W. Rudin, Principles of Mathematical Analysis, McGr-aw-Hill, New York, 1953.

9. J. F. Randolph, Basic Real and Abstract Analysis, Academic Press, New York, 1968, pp. 365-367.

參考文獻

相關文件

Remark: All the sequences are sequence of real numbers.. Formula that might be useful: Let θ

This shows that q is an interior point

That the sequence is increasing can be shown by induction... If not,

Before proving Proposition 1.2, let us review the following two important facts..

The proof is left to the reader as an exercise.. If f is differentiable at x 0 , its derivative

Here is

To do (9), you need to recall the exercise from hw 1 and hw 2 in Calculus I: (you do not need to turn in the following exercises) If you are not familiar with the exercises below,

[Hint: You may find the following fact useful.. If d is a metric for the topology of X, show that d|A × A is a metric for