ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Pooling designs with d -disjunct property and block weight d + 1
Chih-wen Weng (
翁志文
)(with Yu-pei Huang and Wu, Hsin-Jung)
Department of Applied Mathematics, National Chiao Tung University, Taiwan
July 12, 2010
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Definition
An incidence structure (P, B) is calledd -disjunctif any block in B is not covered by the union of d other blocks.
Assume P = {1, 2, . . . , v }, B = {B1, B2, . . . , Bb} and M is be the incidence matrix of (P, B), i.e.
Mij =
1, i ∈ Bj; 0, i 6∈ Bj
for 1 ≤ i ≤ v and 0 ≤ j ≤ b.
The incidence matrix M of a d -disjunct incidence structure can be used in non-adaptive group testing programming, in which v << b is preferred.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Definition
An incidence structure (P, B) is calledd -disjunctif any block in B is not covered by the union of d other blocks.
Assume P = {1, 2, . . . , v }, B = {B1, B2, . . . , Bb} and M is be the incidence matrix of (P, B), i.e.
Mij =
1, i ∈ Bj; 0, i 6∈ Bj
for 1 ≤ i ≤ v and 0 ≤ j ≤ b.
The incidence matrix M of a d -disjunct incidence structure can be used in non-adaptive group testing programming, in which v << b is preferred.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Definition
An incidence structure (P, B) is calledd -disjunctif any block in B is not covered by the union of d other blocks.
Assume P = {1, 2, . . . , v }, B = {B1, B2, . . . , Bb} and M is be the incidence matrix of (P, B), i.e.
Mij =
1, i ∈ Bj; 0, i 6∈ Bj
for 1 ≤ i ≤ v and 0 ≤ j ≤ b.
The incidence matrix M of a d -disjunct incidence structure can be used in non-adaptive group testing programming, in which v << b is preferred.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
1 Let M be a v × b incidence matrix of an incidence structure and set F2 = {0, 1}. Define theoutput function oM : F2b → F2v by
oM(P) := M ? P = [
Pi=1
Mi,
where ? is the matrix product by using Boolean sum to replace addition.
2 If the incidence structure is d -disjunct, then oM F2b(≤ d ) is known to be injective, where F2b(≤ d ) is the set of binary vectors of length b and Hamming weight at most d .
3 This means that for each element u in the image of oM on F2b(≤ d ), we know which P ∈ F2b to have oM(P) = u.
4 In application, P is interpreted as the unknown infected subset {j | Pj = 1} of a given set of b items, and u is interpreted as the sequence of test results. Then the injective property of oM implies that the infected subset can be determined from the sequence of test results if the number of infected items is known in advance to be at most d .
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
1 Let M be a v × b incidence matrix of an incidence structure and set F2 = {0, 1}. Define theoutput function oM : F2b → F2v by
oM(P) := M ? P = [
Pi=1
Mi,
where ? is the matrix product by using Boolean sum to replace addition.
2 If the incidence structure is d -disjunct, then oM F2b(≤ d ) is known to be injective, where F2b(≤ d ) is the set of binary vectors of length b and Hamming weight at most d .
3 This means that for each element u in the image of oM on F2b(≤ d ), we know which P ∈ F2b to have oM(P) = u.
4 In application, P is interpreted as the unknown infected subset {j | Pj = 1} of a given set of b items, and u is interpreted as the sequence of test results. Then the injective property of oM implies that the infected subset can be determined from the sequence of test results if the number of infected items is known in advance to be at most d .
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
1 Let M be a v × b incidence matrix of an incidence structure and set F2 = {0, 1}. Define theoutput function oM : F2b → F2v by
oM(P) := M ? P = [
Pi=1
Mi,
where ? is the matrix product by using Boolean sum to replace addition.
2 If the incidence structure is d -disjunct, then oM F2b(≤ d ) is known to be injective, where F2b(≤ d ) is the set of binary vectors of length b and Hamming weight at most d .
3 This means that for each element u in the image of oM on F2b(≤ d ), we know which P ∈ F2b to have oM(P) = u.
4 In application, P is interpreted as the unknown infected subset {j | Pj = 1} of a given set of b items, and u is interpreted as the sequence of test results. Then the injective property of oM implies that the infected subset can be determined from the sequence of test results if the number of infected items is known in advance to be at most d .
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
1 Let M be a v × b incidence matrix of an incidence structure and set F2 = {0, 1}. Define theoutput function oM : F2b → F2v by
oM(P) := M ? P = [
Pi=1
Mi,
where ? is the matrix product by using Boolean sum to replace addition.
2 If the incidence structure is d -disjunct, then oM F2b(≤ d ) is known to be injective, where F2b(≤ d ) is the set of binary vectors of length b and Hamming weight at most d .
3 This means that for each element u in the image of oM on F2b(≤ d ), we know which P ∈ F2b to have oM(P) = u.
4 In application, P is interpreted as the unknown infected subset {j | Pj = 1} of a given set of b items, and u is interpreted as the sequence of test results. Then the injective property of oM implies that the infected subset can be determined from the sequence of test results if the number of infected items is known in advance to be at most d .
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Example
The following 4 × 6 binary matrix is used to detect the infected item in {1, 2, 3, 4, 5, 6}, if the infected item is known to be at most one in advance (but do not know which one):
Tests/Items | 1 2 3 4 5 6 oM((0, 0, 1, 0, 0, 0)T)
one | 1 1 1 0 0 0 → 1
Two | 1 0 0 1 1 0 → 0
Three | 0 1 0 1 0 1 → 0
Four | 0 0 1 0 1 1 → 1
If there are two infected items, the above 4 × 6 matrix does not work for detecting them. For example, both the infected sets {3, 4} and {1, 6} have the same output (1, 1, 1, 1)T. So it is impossible to recover the infected set from the output (1, 1, 1, 1)T.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Example
The following 4 × 6 binary matrix is used to detect the infected item in {1, 2, 3, 4, 5, 6}, if the infected item is known to be at most one in advance (but do not know which one):
Tests/Items | 1 2 3 4 5 6 oM((0, 0, 1, 0, 0, 0)T)
one | 1 1 1 0 0 0 → 1
Two | 1 0 0 1 1 0 → 0
Three | 0 1 0 1 0 1 → 0
Four | 0 0 1 0 1 1 → 1
If there are two infected items, the above 4 × 6 matrix does not work for detecting them. For example, both the infected sets {3, 4} and {1, 6} have the same output (1, 1, 1, 1)T. So it is impossible to recover the infected set from the output (1, 1, 1, 1)T.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Relation to t-design
Definition
An incidence structure (P, B) is called a t-(v , k, λ) designif
1 |P| = v ,
2 |B| = k for and B ∈ B, and
3 any t-subset of P is contained in exactly λ blocks in B. Remark
1 A 2-(v , k, 1) design is (k − 1)-disjunct since a block has k points and it intersects another block in at most one point, so k − 1 other blocks can cover at most k − 1 points of a block, leaving at least one point uncovered.
2 If any point is incidence in at least two blocks, then any block in a d -disjunct matrix has size at least d + 1.
3 A d -disjunct incidence structure is called apooling design.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Relation to t-design
Definition
An incidence structure (P, B) is called a t-(v , k, λ) designif
1 |P| = v ,
2 |B| = k for and B ∈ B, and
3 any t-subset of P is contained in exactly λ blocks in B.
Remark
1 A 2-(v , k, 1) design is (k − 1)-disjunct since a block has k points and it intersects another block in at most one point, so k − 1 other blocks can cover at most k − 1 points of a block, leaving at least one point uncovered.
2 If any point is incidence in at least two blocks, then any block in a d -disjunct matrix has size at least d + 1.
3 A d -disjunct incidence structure is called apooling design.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
First result
Theorem
Let (P, B) be a d -disjunct pooling design with constant block size d + 1, and define v = |P| and b = |B|. Then b ≤ max{v (v − 1)/d (d + 1), v − d }. Moreover if v − d ≤ v (v − 1)/d (d + 1), then the above upper bound of b is reached if and only if (P, B) is a 2-(v , d + 1, 1) design.
The v × b incidence matrix
M =
Ib Jd
satisfies the equality b = v − d , where Ib is the b × b identity matrix and Jd is the d × d all 1’s matrix.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
First result
Theorem
Let (P, B) be a d -disjunct pooling design with constant block size d + 1, and define v = |P| and b = |B|. Then b ≤ max{v (v − 1)/d (d + 1), v − d }.
Moreover if v − d ≤ v (v − 1)/d (d + 1), then the above upper bound of b is reached if and only if (P, B) is a 2-(v , d + 1, 1) design.
The v × b incidence matrix
M =
Ib Jd
satisfies the equality b = v − d , where Ib is the b × b identity matrix and Jd is the d × d all 1’s matrix.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
First result
Theorem
Let (P, B) be a d -disjunct pooling design with constant block size d + 1, and define v = |P| and b = |B|. Then b ≤ max{v (v − 1)/d (d + 1), v − d }.
Moreover if v − d ≤ v (v − 1)/d (d + 1), then the above upper bound of b is reached if and only if (P, B) is a 2-(v , d + 1, 1) design.
The v × b incidence matrix
M =
Ib Jd
satisfies the equality b = v − d , where Ib is the b × b identity matrix and Jd is the d × d all 1’s matrix.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
The following example gives the equality in previous theorem for d = q − 1.
Example
(2 − (q2, q, 1) design)Let q be a prime power. The affine plane Fq2 over Fq has q2 points and q2+ q lines. Of course any line has q points and any two lines intersect at at most 1 point. Hence the points-lines incidence matrix is v × b d -disjunct with with constant weight w , where v = q2, b = q2+ q and w = q = d + 1 satisfy
b = q2+ q = v (v − 1)/d (d + 1).
The first q which is not a prime power is when q = 6 = d + 1. In this case the equality does not hold by the Bruck-Ryser-Chowla Theorem. Then there is no 5-disjunct pooling design with 36 points, 42 blocks and constant bock size 6. We will construct a 5-disjunct pooling design with 36 points, 37 blocks and constant block size 6.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
The following example gives the equality in previous theorem for d = q − 1.
Example
(2 − (q2, q, 1) design)Let q be a prime power. The affine plane Fq2 over Fq has q2 points and q2+ q lines. Of course any line has q points and any two lines intersect at at most 1 point. Hence the points-lines incidence matrix is v × b d -disjunct with with constant weight w , where v = q2, b = q2+ q and w = q = d + 1 satisfy
b = q2+ q = v (v − 1)/d (d + 1).
The first q which is not a prime power is when q = 6 = d + 1. In this case the equality does not hold by the Bruck-Ryser-Chowla Theorem. Then there is no 5-disjunct pooling design with 36 points, 42 blocks and constant bock size 6. We will construct a 5-disjunct pooling design with
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Forward difference property
1 Let q be a prime power andm ≥ q be an integer.
2 Let Fq:= {0, a0, a1, . . . , aq−2} denote the finite field of q elements, where a is a generator of the cyclic multiplication group
Fq∗:= Fq− {0}.
3 Let m ≥ q be an integer. Let Zm := {0, 1, . . . , m − 1} be the addition group of integers modulo m. We use the order of integers to order the elements in Zm, e.g. 0 < 1.
4 A subset T ⊆ Zm× Fq is said to have the forward difference distinct propertyin Zm× Fq if the forward difference set
FDT := {(j , y ) − (i , x ) | (i , x ), (j , y ) ∈ T with i < j } consists of |T |(|T |−1)
2 elements.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Forward difference property
1 Let q be a prime power andm ≥ q be an integer.
2 Let Fq:= {0, a0, a1, . . . , aq−2} denote the finite field of q elements, where a is a generator of the cyclic multiplication group
Fq∗:= Fq− {0}.
3 Let m ≥ q be an integer. Let Zm := {0, 1, . . . , m − 1} be the addition group of integers modulo m. We use the order of integers to order the elements in Zm, e.g. 0 < 1.
4 A subset T ⊆ Zm× Fq is said to have the forward difference distinct propertyin Zm× Fq if the forward difference set
FDT := {(j , y ) − (i , x ) | (i , x ), (j , y ) ∈ T with i < j } consists of |T |(|T |−1)
2 elements.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Forward difference property
1 Let q be a prime power andm ≥ q be an integer.
2 Let Fq:= {0, a0, a1, . . . , aq−2} denote the finite field of q elements, where a is a generator of the cyclic multiplication group
Fq∗:= Fq− {0}.
3 Let m ≥ q be an integer. Let Zm := {0, 1, . . . , m − 1} be the addition group of integers modulo m. We use the order of integers to order the elements in Zm, e.g. 0 < 1.
4 A subset T ⊆ Zm× Fq is said to have the forward difference distinct propertyin Zm× Fq if the forward difference set
FDT := {(j , y ) − (i , x ) | (i , x ), (j , y ) ∈ T with i < j } consists of |T |(|T |−1)
2 elements.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Forward difference property
1 Let q be a prime power andm ≥ q be an integer.
2 Let Fq:= {0, a0, a1, . . . , aq−2} denote the finite field of q elements, where a is a generator of the cyclic multiplication group
Fq∗:= Fq− {0}.
3 Let m ≥ q be an integer. Let Zm := {0, 1, . . . , m − 1} be the addition group of integers modulo m. We use the order of integers to order the elements in Zm, e.g. 0 < 1.
4 A subset T ⊆ Zm× Fq is said to have the forward difference distinct propertyin Zm× Fq if the forward difference set
FDT := {(j , y ) − (i , x ) | (i , x ), (j , y ) ∈ T with i < j } consists of |T |(|T |−1)
2 elements.
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The Set
mT
qLet mTq⊆ Zm× Fq be defined by
mTq = {(i , ai) | i ∈ Zm, 0 ≤ i ≤ q − 1}.
` 0
` 1
`
2 · · ·
` `
q − 1
` m − 1
· · · ...
a0 ` a1 ` a2 ` aq−2 `
s s
s
s
s
mTq
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The Set
5T
5For q = 5, a = 2,
5T5 = {(0, 1), (1, 2), (2, 4), (3, 3), (4, 1)}
and
FD5T5 = { (1, 1), (1, 2), (1, 4), (1, 3) (2, 3), (2, 1), (2, 2) (3, 2), (3, 4) (4, 0) }.
Since |FD5T5| = 10, the set 5T5 has the forward difference distinct property in Z5× F5.
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The Set
5T
5For q = 5, a = 2,
5T5 = {(0, 1), (1, 2), (2, 4), (3, 3), (4, 1)}
and
FD5T5 = { (1, 1), (1, 2), (1, 4), (1, 3) (2, 3), (2, 1), (2, 2) (3, 2), (3, 4) (4, 0) }.
Since |FD5T5| = 10, the set 5T5 has the forward difference distinct property in Z5× F5.
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m
T
qhas the forward difference distinct property
Lemma
The set mTq has the forward difference distinct property in Zm× Tq. Proof.
Given any pair (c, d ) ∈ Zm× Fq, solve the equations (c, d ) = (j , aj) − (i , ai)
for 0 ≤ i < j ≤ q − 1. Note that 1 ≤ c ≤ q − 1 to have a solution. If c = q − 1 then j = q − 1 and i = 0. If c 6= q − 1 then
ai = d /(aj −i − 1) = d /(ac− 1) and j = c + i . In each case the pair (i , ai), (j , aj) is unique determined by the element (c, d ) ∈ Zm× Fq.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Difference Property
A subset T ⊆ Zm× Fq is said to have the difference distinct propertyin Zm× Fq if the difference setDT := −FDT∪ FDT consists of |T |(|T | − 1) elements.
Since mTq intersects a vertical line in at most one point, we find (0, x ) 6∈ DmTq for any x ∈ Fq.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Difference Property
A subset T ⊆ Zm× Fq is said to have the difference distinct propertyin Zm× Fq if the difference setDT := −FDT∪ FDT consists of |T |(|T | − 1) elements.
Since mTq intersects a vertical line in at most one point, we find (0, x ) 6∈ DmTq for any x ∈ Fq.
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Non-example (m = q = 5)
We have seen
FD5T5 = { (1, 1), (1, 2), (1, 4), (1, 3) (2, 3), (2, 1), (2, 2) (3, 2), (3, 4) (4, 0) }.
Hence
−FD5T5 = { (4, 4), (4, 3), (4, 1), (4, 2) (3, 2), (3, 4), (3, 3) (2, 3), (2, 1) (1, 0) }.
Since |D5T5| = 16 6= 20, the set 5T5 does not have the difference distinct property in Z5× F5.
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Example (m − 1 = q = 5)
FD6T5 = { (1, 1), (1, 2), (1, 4), (1, 3) (2, 3), (2, 1), (2, 2) (3, 2), (3, 4) (4, 0) }.
Hence considering as the negative in Z6× F5, we have
−FD6T5 = { (5, 4), (5, 3), (5, 1), (5, 2) (4, 2), (4, 4), (4, 3) (3, 3), (3, 1) (2, 0) }.
Since |D | = 20 now, the set T has the difference distinct property in
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
2q−1
T
qhas the difference distinct property
Lemma
For m ≥ 2q − 1, the set mTq has the difference distinct property in Zm× Tq.
Proof.
We have |FDmTq| = | − FDmTq| = q(q − 1)/2. The first coordinate of an element in FD2q−1Tq runs from 1 to q − 1, and the first coordinate of an element in −FD2q−1Tq from m + 1 − q to m − 1. The assumption m ≥ 2q − 1 implies −FD2q−1Tq ∩ FD2q−1Tq = ∅.
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2q−3
T
qhas the difference distinct property
Lemma
The set mTq has the difference distinct property for m = 2q − 3.
Proof.
We have |FDTm,q| = | − FDTm,q| = q(q − 1)/2. Let (c, d ) ∈ FDTm,q. If m = 2q − 3, then 1 ≤ c ≤ q − 1 and q − 2 ≤ −c ≤ 2q − 4. Thus the repetition of differences occurs only when c = q − 2 or c = q − 1. Note that d = 0 iff c = q − 1, and −d = 0 iff −c = q − 2. For c = q − 2, suppose (c0, d0) ∈ −FDmTq and (c0, d0) = (c, d ). Then we have c0= q − 2 and d0= 0. Hence d = 0, a contradiction. Similarly for c = q − 1, we have d = 0 but (q − 1, 0) /∈ −FDTm,q.
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2q−4
T
qhas the difference distinct property
Lemma
The set mTq has the difference distinct property for m = 2q − 4.
Proof.
Let (c, d ) ∈ FDTm,q. Since m = 2q − 4, we have 1 ≤ c ≤ q − 1 and q − 3 ≤ −c ≤ 2q − 5. Thus the repetition of differences occurs only when c = q − 3, q − 2 or q − 1. Note that d = 0 iff c = q − 1, and −d = 0 iff
−c = q − 3. For c = q − 1 or c = q − 3, similar process as the above m = 2q − 3 case can be applied to get contradictions. For c = q − 2,
−c = q − 2. Thus a repetition implies that there are
(q − 2, d1), (q − 2, d2) ∈ FDTm,q such that d1 = −d2. Note that the only two elements of FDTm,q with the first coordinate q − 2 are (q − 2, aq−2− 1) and (q − 2, aq−1− a), where a is the generator chosen for Fq∗. So we have aq−2− 1 = −(aq−1− a) and this implies a = −1, also a contradiction.
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Lines with any two intersecting in at most a point
Proposition
Suppose that mTq ⊆ Zm× Fq has the difference distinct property in Zm× Fq. Set B = {u +mTq | u ∈ Zm× Fq}. Then |L ∩ L0| ≤ 1 for any distinct L, L0 ∈ B.
Proof.
Routine.
1 Note that there are mq lines and mq points in Zm× Fq, and a line has q = |T | points with q different first coordinates.
2 Apparently more lines can be added to B still having the conclusion of the above proposition, for example, adding vertical lines to B.
3 We will add m more points to P, add m + 1 lines to B, and add one more point to each original line in B.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Lines with any two intersecting in at most a point
Proposition
Suppose that mTq ⊆ Zm× Fq has the difference distinct property in Zm× Fq. Set B = {u +mTq | u ∈ Zm× Fq}. Then |L ∩ L0| ≤ 1 for any distinct L, L0 ∈ B.
Proof.
Routine.
1 Note that there are mq lines and mq points in Zm× Fq, and a line has q = |T | points with q different first coordinates.
2 Apparently more lines can be added to B still having the conclusion of the above proposition, for example, adding vertical lines to B.
3 We will add m more points to P, add m + 1 lines to B, and add one more point to each original line in B.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Lines with any two intersecting in at most a point
Proposition
Suppose that mTq ⊆ Zm× Fq has the difference distinct property in Zm× Fq. Set B = {u +mTq | u ∈ Zm× Fq}. Then |L ∩ L0| ≤ 1 for any distinct L, L0 ∈ B.
Proof.
Routine.
1 Note that there are mq lines and mq points in Zm× Fq, and a line has q = |T | points with q different first coordinates.
2 Apparently more lines can be added to B still having the conclusion of the above proposition, for example, adding vertical lines to B.
3 We will add m more points to P, add m + 1 lines to B, and add one more point to each original line in B.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
Lines with any two intersecting in at most a point
Proposition
Suppose that mTq ⊆ Zm× Fq has the difference distinct property in Zm× Fq. Set B = {u +mTq | u ∈ Zm× Fq}. Then |L ∩ L0| ≤ 1 for any distinct L, L0 ∈ B.
Proof.
Routine.
1 Note that there are mq lines and mq points in Zm× Fq, and a line has q = |T | points with q different first coordinates.
2 Apparently more lines can be added to B still having the conclusion of the above proposition, for example, adding vertical lines to B.
3 We will add m more points to P, add m + 1 lines to B, and add one more point to each original line in B.
ALGEBRAIC AND GEOMETRIC COMBINATORICS CONFERENCE 2010
A picture for the finial result
` 0
` 1
`
2 · · ·
` `
q − 1
` q
` m − 1
· · · ...
a0 ` a1 ` a2 ` aq−2 `
s
s s
s
s
s s
s
s s
s
s s s s
s
∞
Lines in Zm× (Fq∪ {∞})
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Second and final result
Theorem
There exists a q-disjunct pooling design (P, B) with |P| = m(q + 1),
|B| = m(q + 1) + 1 and constant block weight q + 1, where q is a prime power, and m is an integer at least three satisfying m = 2q − 4,
m = 2q − 3 or m ≥ 2q − 1.
By choosing q = 5 and m = 2q − 4 = 6, there exists a 5-disjunct pooling design with 36 points, 37 blocks and constant block size 6.
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Second and final result
Theorem
There exists a q-disjunct pooling design (P, B) with |P| = m(q + 1),
|B| = m(q + 1) + 1 and constant block weight q + 1, where q is a prime power, and m is an integer at least three satisfying m = 2q − 4,
m = 2q − 3 or m ≥ 2q − 1.
By choosing q = 5 and m = 2q − 4 = 6, there exists a 5-disjunct pooling design with 36 points, 37 blocks and constant block size 6.
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The end
Thank you for your attention.