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Classroom Capsule: Sphere, Cylinder and Bicone Wong Hang Chi International Christian Quality Music Secondary and Primary School Kwan Shi Pui The Hong Kong Institute of Education Or Chi Ming

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數學教育第三十一期 (6/2011)

72

Classroom Capsule: Sphere, Cylinder and Bicone

Wong Hang Chi

International Christian Quality Music Secondary and Primary School Kwan Shi Pui

The Hong Kong Institute of Education Or Chi Ming

It is well known that circumscribed and inscribed regular polygons could be used to approximate the value of  In the simple case of bounding a circle by its circumscribed and inscribed squares (Figure 1), if we take the arithmetic mean of their areas as an approximation of that of the circle, we would obtain the area of the circle  3r2 , or   3.

Figure 1

A group of pre-service teachers were asked to extend this idea to find upper and lower bounds for the sphere, and estimate its volume using the mean of the volumes of the bounds. One of them suggested using the circumscribed cylinder for the upper bound, and a pair of inscribed joined cones for the lower bound (Figure 2). Surprisingly, the mean of the volumes of these upper and lower bounds is 3

3

4r , which is exactly the volume of the sphere!

r

r Area of Circumscribed Square = 4r2 Area of Inscribed Square = 2r2

Mean =

2 2 4r2r2 = 3r2

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EduMath 31 (6/2011)

73 Figure 2

This happy coincidence could be further illustrated as follows. Let S, C and B be the volumes of the sphere, its circumscribed cylinder and inscribed joined cones (also called bicone) respectively. We invert the two cones and subtract them from the cylinder, as shown in Figure 3. By Pythagoras’

Theorem the areas of the shaded cross-sections at any height are equal, and by Cavalieri’s Principle the sphere and the cylinder minus the inverted cones have equal volumes, that is, S = C – B . Since we also know that the volume of a cone is one-third of that of its circumscribed cylinder, we have C = 3B . Hence

2 B C

= 2B = C – B = S , that is, the mean of the volumes of the circumscribed cylinder and the inscribed joined cones is the volume of the sphere.

Figure 3

Volume of Circumscribed Cylinder = 2r3 Volume of Inscribed Joined Cone =

3 2r3

Mean =

2 2r332r3

= 3 4r3

r

r

r

h r

r

h

h A1 = x2

= r2 – h2) = r2 – h2

= A2

Area: A1

Area: A2

x

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數學教育第三十一期 (6/2011)

74

Finally, it is worthwhile to note that the sphere, cylinder and bicone can be described as the solid of revolution of the superellipse xmym 1 . (http://mathworld.wolfram.com/Superellipse.html) When m = 2 it gives the circle, whose surface of revolution is the sphere. When m = 1 it gives a pair of straight lines of slope 1, whose surface of revolution is the bicone.

When m tends to infinity, we have a pair of horizontal lines which generate the cylinder as the surface of revolution.

Authors’ e-mails: Wong Hang Chi s0945133@s.ied.edu.hk Kwan Shi Pui spkwan@ied.edu.hk Or Chi Ming orchiming@gmail.com

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