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應用電子學()期末考解答

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應用電子學()期末考解答

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1.(25)設計一個基本的npn BJT 差動放大器,差動電晶體對的集極以電阻為負載,以0.5mA的基本電流鏡提供 射極偏壓電流,單端的開路輸出增益要求為30(無輸出負載時),給定的電壓源為±5V。請畫出電路圖,包含電 流鏡的設計。計算出此放大器的共模輸入訊號範圍、差模輸入電阻、輸出阻抗、共模增益(要先算電流鏡的輸 出阻抗)、及CMRRdB

2.(35)(a)如右圖之放大器,要求電晶體的IC為1mA,電壓增益(

o/

s)大約為-40。此外,RL=2k、Rs = 75、VCC =9V。另外假定VB=4V,通過R1的電流約為IB的十倍。找出R1、R2、RC、RE

[Note:建議先由gm、RL估算RC;注意這裡RS很小。]

(b)我們希望此放大器的低頻3dB點大約在20Hz,設計適當的CC1、CC2和CE。 (c)估算此放大器的高頻3dB頻率。(畫出高頻小訊號模型,並使用Miller’s approx.)

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3.(40) Two-stage CMOS op-amp

下頁電路是在作業中做過的。各電晶體的尺寸如下:

Transistor Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8

W/L(m/m) 20/0.8 20/0.8 5/0.8 5/0.8 40/0.8 10/0.8 40/0.8 40/0.8 VDD = VSS = 3V, IREF = 120 A

I.放大器特性的估計

(a)先判定各電晶體的功能。把各級及電流源偏壓電路個別框出來。

(b)估計所有電晶體的ID, |VOV|(|VGS-Vt|), |VGS|, gm, 及ro。(列表)

(c)將輸入級和輸出級小訊號模型簡化成電壓控制電流源電路,包含他的輸出阻抗。估算各級增益和總增益。

(d)估算輸入共模訊號可接受的範圍,及輸出電壓的範圍。

II.用”Miller’s effect”估算”補償電容”CC的影響。假如我們要求此高頻3dB頻率在100Hz,CC應該為多大?若要 增為10kHz,CC應該為多大?

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Transistor Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8

W/L(m/m) 20/0.8 20/0.8 5/0.8 5/0.8 40/0.8 10/0.8 40/0.8 40/0.8

4.(15)解釋何謂cascode configuration?有何好處?為什麼?(以BJT電晶體當作說明例)

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5.(25)(a)請設計出放大器所需要的電流源。

(b)下圖電路是作業中分析過的電路,假如主要極點要 設計在100Hz,請問CC應該為多大?RL=75。先算出第 二級增益。

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6. (20) For each of the differential amplifier module, plot the half circuit for the differential-mode signal input and calculate the differential gain for double-ended output.

7 (20) A common-gate amplifier has the parameters:

(a) Plot the high-frequency small signal model. (Regroup the capacitors in parallel for analysis.) (b) Calculate the midrange gain.

(c) Estimate the high-frequency 3dB point.

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