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Differentiation in Rn

Let U be an open subset of Rn and let f : U → Rm be a map defined on U with values in Rm. 1. f is differentiable at p ∈ U if there exists a linear function L : Rn → Rm such that

x→plim

kf (x) − f (p) − L(x − p)k

kx − pk = 0.

2. If f is differentiable at p, then it is (locally) Lipschitz near p.

3. If the linear function exists at p, then it is unique.

4. If f is differentiable at p, then each of the partial derivatives ∂fi

∂xj(p), 1 ≤ i ≤ m and 1 ≤ j ≤ n, exists and

∂fi

∂xj(p) = the i-th compnent of L(ej) ∀ 1 ≤ i ≤ m, 1 ≤ j ≤ n.

5. If f is differentiable at p and if u is any element of Rn, then the partial derivative Duf (p) of f at p with respect to u exists. Moreover,

Duf (p) = Df (p)(u) = Df (p)(

n

X

i=1

uiei) =

n

X

i=1

uiDf (p)(ei)

and it is called the directional derivative of f at p in the direction of u provided that u is a unit vector of Rn.

Properties of the Derivative

Let U be an open subset of Rn, let f, g : U → Rm be maps defined on U with values in Rm, and let ϕ : U → R a function defined on U.

1. If f and g are differentiable at p ∈ U, and if α, β ∈ R, then h = αf + βg is differentiable at p and

Dh(p) = αDf (p) + βDg(p).

2. If ϕ and f are differentiable at p ∈ U, then k = ϕf : E → Rm is differentiable at p and Dk(p)(u) =Dϕ(p)(u)f (p) + ϕ(p)Df (p)(u) for u ∈ Rn.

3. If f and g are differentiable at p ∈ U, then h = hf, gi =

m

X

i=1

figi : E → R is differentiable at p and

Dh(p) = g(p) · Df (p) + f (p) · Dg(p) =

m

X

i=1

Dfi(p)gi(p) +

m

X

i=1

fi(p)Dgi(p).

Chain Rule Let f have domain E ⊆ Rn and range in Rm, and let g have domain B ⊆ Rm and range in R`. Suppose that f is differentiable at p and that g is differentiable at q = f (p). Then the composition h = g ◦ f is differentiable at p and

Dh(p) = Dg(q) ◦ Df (p).

Alternatively, we write

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Mean Value Theorems

1. Let f be defined on an open subset U of Rn and have values in R. Suppose that the set U contains the points a, b and the line segment S joining them and that f is differentiable at every point of this segment. Then there exists a point c on S such that

f (b) − f (a) = Df (c)(b − a).

2. Let U ⊆ Rn be an open set and let f : U → Rm. Suppose that the set U contains the points a, b and the line segment S joining them and that f is differentiable at every point of this segment. Then there exists a point c on S such that

kf (b) − f (a)k ≤ kDf (c)(b − a)k.

Higher Derivatives

Let U be an open subset in Rn and let f : U → R be a differentiable function on U.

1. If Df : U → Rn is differentiable, we denote the derivative of Df by D2f : U → Rn×n, and we shall refer the n2 functions (entries) of D2f as the second partial derivatives of f denoted by

Dijf or ∂2f

∂xi∂xj

, i, j = 1, 2, . . . , n.

Similarly, if D2f : U → Rn2 is differentiable, we denote the derivative of D2f by D3f : U → Rn3, and we shall refer the n3 functions (entries) of D3f as the third partial derivatives of f denoted by

Dijkf or ∂3f

∂xi∂xj∂xk, i, j, k = 1, 2, . . . , n.

2. Note that if f is differentiable at a point p ∈ U, then Df (p) is a linear map on Rn to R defined by

Df (p)(z) =

n

X

i=1

Dif (p)zi =

n

X

i=1

∂f

∂xi(p)zi for z = (z1, . . . , zn) ∈ Rn.

If Df is differentiable at a point p ∈ U, then D2f (p) is a linear map on Rn2 to R defined by

D2f (p)(y, z) =

n

X

i, j=1

Dijf (p)yjzi =

n

X

i, j=1

2f

∂xi∂xj(p)yjzi for y, z ∈ Rn.

Similarly, if D2f is differentiable at a point p ∈ U, then D3f (p) is a linear map on Rn3 to R defined by

D3f (p)(y, z, w) =

n

X

i, j, k=1

Dijkf (p)ykzjwi =

n

X

i, j, k=1

3f

∂xi∂xj∂xk(p)ykzjwi for y, z, w ∈ Rn.

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3. Taylor’s Theorem Suppose that f has continuous partial derivatives of order m in a neighborhood of every point of a line segment S joining two point a, b = a + u in U. Then there exists a point c on S such that

f (a + u) = f (a) +

m−1

X

k=1

1

k!Dkf (a)(u)k+ 1

m!Dmf (c)(u)m where Dkf (p)(u)k= Dkf (p)(u, u, . . . , u) for k = 1, . . . , m.

The Class C1(U )

Let U be an open subset in Rn, let f : U → Rm be differentiable on U and let Djfi = ∂fi

∂xj

. 1. A function L : Rn → Rm is said to be linear if

L(ax + by) = aL(x) + bL(y) for all a, b ∈ R and x, y ∈ Rn. Note that if L : Rn→ Rm is linear, then L(0) = 0 ∈ Rm.

2. Let L (Rn, Rm) = {L | L : Rn → Rm is linear}. Define (∗) kLknm= sup

z∈Rn, kzk≤1

kL(z)k for each L ∈L (Rn, Rm).

Since L ∈L (Rn, Rm) is linear,

kLknm = sup

z∈Rn, kzk≤1

kL(z)k = sup

z∈Rn, kzk=1

kL(z)k.

If L ∈L (Rn, Rm) is represented by an m × n matrix, then kLknm= sup

z∈Rn, kzk=1

kL(z)k = the maximum length of column vectors of L and the derivative of L equals itself, i.e. DL = L.

3. f ∈ C1(U ) if the derivative Df (x) exists and is continuous under the norm (∗) for all x ∈ U, i.e.

lim

y∈U, y→xkDf (y) − Df (x)knm= 0 for all x ∈ U.

4. For all x, y ∈ U,

kDf (x) − Df (y)knm ≤ ( m

X

i=1 n

X

j=1

|Djfi(x) − Djfi(y)|2 )1/2

≤√

mkDf (x) − Df (y)knm.

5. f ∈ C1(U ) if and only if Djfi is continuous on U for each 1 ≤ i ≤ m, 1 ≤ j ≤ n.

6. If f ∈ C1(U ), then det Df = det[Djfi] : U → R is continuous on U.

7. Suppose that U contains the points a, b and the line segment S joining them, and let p ∈ U.

Then we have

kf (b) − f (a) − Df (p)(b − a)k ≤ kb − ak sup{kDf (x) − Df (p)k }.

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8. If f ∈ C1(U ), p ∈ U and ε > 0, then there exists δ(ε) > 0 such that if kxk− pk ≤ δ(ε), k = 1, 2, then xk ∈ U and

kf (x1) − f (x2) − Df (p)(x1− x2)k ≤ ε kx1− x2k.

9. If L = Df (p) is an injection for some p ∈ U, then there exists r > 0 such that (†) rkuk ≤ kDf (p)(u)k = kL(u)k for all u ∈ Rn.

10. If f ∈ C1(U ) and if L = Df (p) is an injection for some p ∈ U, then there exists a δ > 0 such that

(††)12r kx1− x2k ≤ kf (x1) − f (x2)k for all x1, x2 ∈ ¯Bδ(p) ⊂ U.

This prove that the restriction of f to ¯Bδ(p) is an injection; hence this restriction has an inverse function which we shall denote by g = (fB¯δ(p))−1. Note that g is uniformly continuous on f ( ¯Bδ(p)) by using (††).

11. If f ∈ C1(U ) and if L = Df (p) is a surjection for some p ∈ U, then there exists a bounded linear function M : Rm → Rn such that L ◦ M (y) = y for all y ∈ Rm.

12. If f ∈ C1(U ) and if L = Df (p) is a surjection for some p ∈ U, then there exists numbers d > 0 and α > 0 such that if y ∈ ¯Bα/2d(f (p)) ⊂ Rm, then there exists an x ∈ U ∩ ¯Bα(p) such that f (x) = y.

13. If f ∈ C1(U ) and if L = Df (p) is a surjection for all p ∈ U, then f (U ) is open in Rm. 14. If m = n, f ∈ C1(U ) and if L = Df (p) is a bijection for some p ∈ U, then there exist

open neighborhoods V and W of p and f (p), respectively, such that f : V → W has a differentiable inverse g = f−1 : W → V such that

Df−1(y) = Dg(y) = [Df (g(y))]−1 = [Df (f−1(y))]−1 for y ∈ W.

15. Let W be an open subset of Rn+m, f : W → Rm ∈ C1(W ) and let (a, b) ∈ W be a point at which f (a, b) = 0. Suppose that a ∈ Rn, b ∈ Rm and the m × m matrix

Dyf |(a,b)= ∂fi

∂yj(a, b)



1≤i,j≤m

is invertible.

Then there exist open neighborhoods A ⊂ Rn and B ⊂ Rm of a and b, respectively, and a unique g : A → Rm ∈ C1(A) such that

b = g(a) and F (x, g(x)) = 0 for all x ∈ A and

{(x, y) ∈ A × B ⊂ W | f (x, y) = 0}

= {(x, g(x)) | x ∈ A}

= the graph of g over A.

Extremum problems

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1. Let U ⊆ Rn be open and let f : U → R have continuous second partial derivatives on U. If p ∈ U is a point of relative minimum [respectively, maximum] of f, then

D2f (p)(w)2 = wt  ∂fi

∂xj

(p)



1≤i,j≤n

w =

n

X

i, j=1

Dijf (p)wiwj ≥ 0 for all w ∈ Rn

[respectively, D2f (p)(w)2 =

n

X

i, j=1

Dijf (p)wiwj ≤ 0 for all w ∈ Rn].

2. Lagrange’s Theorem Let U ⊆ Rn be open and suppose that f and g : U → R are real- valued functions in C1(U ). Suppose p ∈ U is such that g(p) = 0 and that there exists an r > 0 such that

f (x) ≤ f (p) or f (x) ≥ f (p) for all x ∈ Br(p) ⊂ U satisfying g(x) = 0.

Then there exist real numbers µ, λ, not both zero, such that µDf (p) = λDg(p).

Moreover, if Dg(p) 6= 0, we can take µ = 1.

Riemann Integrability

1. (Riemann Criterion for Integrability) f is Riemann integrable over K, i.e.

Z

K

f = Z

K

f, if and only if for each ε > 0, there exists a partition Pε of K such that

|U (Pε, f ) − L(Pε, f )| < ε.

2. (Cauchy Criterion for Integrability) f is Riemann integrable over K if and only if for each ε > 0, there exists a partition Pε of K such that if P and Q are refinements of Pε and SP(f, K) and SQ(f, K) are any corresponding Riemann sums, then

|SP(f, K) − SQ(f, K)| < ε.

Convergence and Differentiation

1. Let fn: [a, b] → C be a sequence of continuously differentiable functions defined on I = [a, b].

If fn(x0) converges for some x0 ∈ [a, b] and if fn0 : [a, b] → C converges uniformly on [a, b], then fn converges uniformly on [a, b] to a function f.

2. Term-by-Term Differentiation For each n ∈ N, let fn be a real-valued function on K = [a, b] which has a derivative fn0 on K. Suppose that

(i) P fn converges at x0 ∈ K, (ii) P fn0 converges uniformly on K,

there exists a real-valued function f on K such that (a) P fn converges uniformly on K to f,

(b) f is differentiable on K and f0 =X

fn0 on K.

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Convergence and Integration

1. Let {fn} be a sequence of integrable functions that converges uniformly on a closed cell K ⊂ Rp to a function f. Then f is integrable and

Z

K

f = lim

n→∞

Z

K

fn.

2. Term-by-Term Integration For each n ∈ N, let fn be a real-valued integrable function on K = [a, b]. Suppose that the seriesP fn converges to f uniformly on K.

Then f is integrable on K and

Z

K

f =

X

j=1

Z

K

fn.

3. Bounded Convergence Theorem Let {fn} be a sequence of integrable functions on a closed cell K ⊂ Rp. Suppose that there exists B > 0 such that kfn(x)k ≤ B for all n ∈ N, x ∈ K. If the function f (x) = lim

n→∞fn(x), x ∈ K, exists and is integrable, then Z

K

f = lim

n→∞

Z

K

fn.

4. Monotone Convergence Theorem Let {fn} be a monotone sequence of integrable func- tions on a closed cell K ⊂ Rp. If the function f (x) = lim fn(x), x ∈ K, exists and is integrable, then

Z

K

f = lim

n→∞

Z

K

fn.

參考文獻