Content
Analysis on the HKCEE/HKDSE Questions HKDSE Examination Preparation Guide Points to Note in the Examination
Part 1 Key Stage 4 (S4 – S6)
1. Quadratic Equations 2
2. Functions and Graphs 20
3. Exponential and Logarithmic Functions 42
4. Equations of Straight Lines 60
5. More about Polynomials 80
6. Variations 98
7. More about Equations 118
8. More about Graphs of Functions 138
9. Basic Properties of Circles 164
Part 2 Key Stage 3 (S1 – S3)
10. Percentages 190
11. Polynomials, Indices and Surds 212
12. Rate and Ratio 233
13. Formulas and Equations 248
14. Basic Geometry 266
15. Coordinate Geometry 292
Mock Exam 313
Graph Papers 337
Sample
Analysis on the HKCEE/HKDSE Questions
2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013
1. Quadratic
Equations Q11(b) Q5 Q10(b) Q12(c)
2. Functions and
Graphs Q4 Q10 Q11(a)(b) Q12, Q15 Q11(b) Q17
3. Exponential and
Logarithmic Functions
Q4 Q16(b)
4. Equations of Straight Lines
Q8,
Q17(a) Q12 Q13 Q13 Q12 Q13 Q12(c) Q12
5. More about
Polynomials Q4 Q10(b) Q14(a) Q13 Q12
6. Variations Q11(a) Q10(a) Q10(a) Q10(a) Q15(a) Q14(b) Q10(a) Q11(a) Q11 Q11
7. More about
Equations Q15(b)
8. More about Graphs of Functions
Q11(c) Q16
9. Basic Properties of Circles
Q9,
Q16(a) Q17 Q16(a)(b) Q17(a) Q16(a) Q17(a) Q8
10. Percentages Q6 Q5 Q3 Q6,
Q16(a) Q6 Q6 Q8,
Q16(b) Q7 Q7 Q7 Q4
11. Polynomials, Indices and Surds
Q1 Q3 Q1,Q6 Q2, Q3 Q1,Q3 Q2,Q3 Q1, Q3 Q2,Q3 Q1,Q3 Q2,Q3 Q1 Q1, Q3
12. Rate and Ratio Q5
13. Formulas and Equations
Q1, Q6,
Q16 Q2, Q7 Q1 Q1,Q7 Q6 Q1,Q6 Q5,Q6 Q1,Q6 Q2, Q3,
Q5 Q2, Q4
14. Basic
Geometry Q10 Q8 Q12 Q8 Q5 Q8 Q9 Q11 Q9
Q9
Q12(a)(b) Q7
15. Coordinate
Geometry Q16(b) Q7 Q17(b)(i) Q12(a)(b) Q8,Q9 Q17(a) Q8 Q6
Note: The numbers listed above refer to the question numbers in the HKCEE/HKDSE mathematics Paper 1 that year.
Q.1 represents questions in section A(1), Q.10 represents questions in section A(2), Q.15 represents questions in section B.
Chapter
Year
Sample Sample
In order to prepare for the examination effectively. Candidates are advised to read the instruction of the assessment carefully.
A. Public Assessment Format
The HKDSE Mathematics curriculum consists of a Compulsory Part and an Extended Part (Module 1: Calculus and Statistics, Module 2: Algebra and Calculus). The following table lists out the details of the examination in the compulsory part:
Component Weighting Duration
Paper 1 Conventional questions 65% 135 minutes
Paper 2 Multiple-choice questions 35% 75 minutes
Paper 1 consists of two sections A and B in which all questions are to be attempted. Section A consists of questions on the foundation topics of the compulsory part and the foundation part of S1 – S3 curriculum. Section A is divided into two parts: Section A(1) (35 marks) consists of 8 to 11 elementary questions and Section A(2) (35 marks) will consist of 4 to 7 harder questions. On the other hand, Section B (35 marks) consists of 4 – 7 questions on the compulsory part and the whole curriculum of S1 – S3.
Paper 2 consists of two sections A and B in which all questions are to be attempted. Section A (about 66% of the paper mark) consists of questions on the foundation topics of the compulsory part and the foundation part of the S1 – S3 curriculum, whereas Section B (about 33% of the paper mark) consists of questions of the compulsory part and the whole S1 – S3 curriculum.
B. Standard Referencing
In the HKDSE, standards-referenced reporting will be adopted to report candidates’ results. Candidates’ levels of performance will be reported with reference to a set of standards as defined by cut scores on the variable or scale for a given subject (see the figure below).
There will be five cut scores in each subject to distinguish five levels of performance (1 – 5), with 5 being the highest.
A performance below the threshold cut score for Level 1 will be labelled as “Unclassified” (U). Level 5 candidates with the best performance will have their results annotated with the symbols ‘**’ and the next top group with the symbol ‘*’.
Cut scores
Variable/scale 1
U 2 3 4 5
HKDSE Examination Preparation Guide Sample
A. Instructions Before the Start of the Examination
1. After you have taken your seat, put your essentials on your desk: a pencil, a ball-pen, a correction fluid, a ruler, a pair of compasses, a protractor, a calculator, your ID card and the examination permission. Put other belongings under your seat.
2. Listen carefully to the instructors. When the examination paper is delivered, DO NOT turn over or open the paper until you are told to do so.
3. When you are permitted to check the paper, read the instructions printed on the front page carefully. Then check if there are any missing pages or missing questions.
4. Make sure that your candidate number and seat number are written correctly on the answer book.
5. Put a watch on your desk to remind of the time used.
B. Guidelines in Answering Questions
1. When the examination starts, do not be eager to answer the questions. Scan the questions quickly first and start from the questions that you are most confident with.
2. Read the question carefully before answering it. Look for keywords such as “calculate”, “prove” and “explain”
etc. to find out what you are required to answer.
3. Use ball pens to answer questions. Show your working neatly.
4. When you are stuck in a question, just skip it and answer the next one. You may have time to come back to finish that question later, so do not panic.
5. Manage your time systematically on each question. Here are some suggestions:
Section Number of questions Time spent per question Total time spent
Section A(1) 8 to 11 questions ~ 4 minutes 35 minutes
Section A(2) 4 to 7 questions ~ 7 minutes 40 minutes
Section B 4 to 7 questions ~ 10 minutes 50 minutes
Time left for checking: 10 minutes 6. When applying a formula or geometrical properties, you are advised to show the formula or reasons instead of
substituting the values directly. If you do so, in case you give a wrong answer, you may still get some marks for correct methods used.
7. When drawing figures, always use pencils with appropriate tools such as ruler, pair of compasses and protractor.
8. In application problems, remember to check the units in each step and the answer.
9. Unless otherwise specified, you are advised to give the answers corrected to 3 significant figures. However, the values in the intermediate steps should be corrected to more than 3 significant figures, otherwise the answers obtained would not be accurate.
Points to Note in the Examination Sample
x y
O
y = mx + c
x y
O y = c
x y
O
axis of symmetry
vertex
x y
O x
y
O
x y
O
x y
domain 1 • 2 • 3 •
• 5
• 10
• 15
co-domain
20 21
2 Functions and Graphs
Functions and Graphs
Graphs of Linear Functions
• The graph is a straight line.
• When m 0, the graph goes up from left to right. When m 0, the graph goes down from left to right.
• When m = 0, the function becomes a constant function and the graph is a horizontal line.
• x-intercept = mc
- , where m ≠ 0
• y-intercept = c
Definition of Functions
• If y is a function of x, then for every value of x, there is one and only one corresponding value of y.
• Notation: f(x), g(x), G(x), etc.
• Domain: Values of x such that f(x) is defined.
• Co-domain: All the possible values of f(x).
Linear Functions
In the form f(x) = mx + c, where m and c are constants.
Number of x-intercepts
• The number of x-intercepts is determined by
∆ = b2 – 4ac.
(a) When ∆ 0, there are two x-intercepts.
(b) When ∆ = 0, there is one x-intercept.
(c) When ∆ 0, there is no x-intercept.
Graphs of y = ax
2+ bx + c
• When a 0, the graph opens upwards.
When a 0, the graph opens downwards.
• The graph is symmetric about the axis of symmetry.
• The axis of symmetry must pass through the vertex.
• y-intercept = c
Graphs of y = a(x – h)
2+ k
• Vertex = (h, k)
• If a 0, then (h, k) is the lowest point.
If a 0, then (h, k) is the highest point.
• The axis of symmetry is x = h.
Finding Optimum Values of y = ax
2+ bx + c
Step 1: Rewrite the quadratic function y = ax2 + bx + c into the form y = a(x – h)2 + k by the method of completing the square, where h = a
b
-2 and k = a ac b
4 4 - 2.
Step 2: If a 0, the function attains its minimum value k when x = h.
If a 0, the function attains its maximum value k when x = h.
Quadratic Functions
• In the form f(x) = ax2 + bx + c, where a, b and c are constants with a ≠ 0.
• It can also be expressed in the form of f(x) = a(x – h)2 + k, where a, h and k are constants with a ≠ 0.
Concept Map
x = h (h, k)
vertex
a 0
a 0 a 0
axis of symmetry
NF
(h, k) x = h
a 0
Sample
4
HKDSE Exam Series — Mathematics Conventional Questions (Compulsory Part) (Upgraded Edition) Book A
As x – 5 = ±4, x = 1 is also a root.
(a + bi) + (c + di) = (a + c) + (b + d)i
(a + bi) × (c + di) = (ac – bd) + (ad + bc)i
(a + b) × (a – b) = a2 – b2
Smart Review
A. Complex Numbers
1. Complex numbers(複數)are in the form of a + bi, where a and b are real numbers and i = - . a is called the real part(實部) 1 and b is called the imaginary part(虛部). If a and b are real numbers, then a + bi and a – bi are a pair of conjugate complex numbers(共軛複數).
For example, 4, –2i, 3 + 10i and 7 – 12i are complex numbers.
NF 2. If a + bi = c + di, then a = c and b = d.
NF 3. Operations of complex numbers (a) Addition and subtraction
For example, (i) (2 + 3i) + (7 + 3i) = (2 + 7) + (3 + 3)i
= 9 + 6i
(ii) (2 + 3i) – (7 + 3i) = (2 – 7) + (3 – 3)i
= –5 (b) Multiplication
For example, (5 + 3i) × (2 + 9i) = (10 – 27) + (45 + 6)i
= –17 + 51i (c) Division
For example, i
i 7
4 5
+ + =
i i
i i 7
4 5
7 :7 + +
- -
= i
7 1
28 5
7 1
35 4
2 2 2 2
+
+ + -
+
= 31i
50 33
+50
B. Quadratic Equations
1. An equation in the form ax2 + bx + c = 0, where a ≠ 0, is called a quadratic equation in one unknown(一元二次方程).
2. Solving quadratic equations by taking square root For example, solve (x – 5)2 = 16.
x – 5 = 4 or x – 5 = –4 x = 9 or 1
c di a bi
+ + =
c d
ac bd
2 2
+ + +
c d
bc ad
2 2 i + -
Sample
Concept Builder
1
Quadratic Equations7 Determine whether each of the following is true or false.
1. -25 = 5i
2. 80 is not a complex number.
3. The square of a complex number must be a real number.
4. If bx2 + ax + c = 0, then x =
a
b b ac
2
2 4
- ! - .
5. The equation x2 – x – 4 = 0 has two distinct real roots.
6. The equation 2x2 – x + 3 = 0 has no real roots.
7. If α and β are the roots of the equation 2x2 + 5x + 1 = 0, then α + β =
25 and αβ = 2 - . 1
8. If 2 and 3 are the roots of a quadratic equation, the equation can be x2 – 5x + 6 = 0.
NF
NF NF
Worked Examples
Section A(1)
1. (a) Solve the equation x2 – 3x – 10 = 0.
(b) Hence solve the equation (x – 1)2 – 3(x – 1) – 10 = 0.
(3 marks)
Solution Try Q.1 – 2.
(a) x2 – 3x – 10 = 0
(x + 2)(x – 5) = 0 [1M]
x = –2 or 5 [1A]
(b) Let y = x – 1. The equation becomes y2 – 3y – 10 = 0
y = –2 or 5 (By (a)) ` x – 1 = –2 or x – 1 = 5
x = –1 or 6 [1A]
Concept Builder Ans: 1. T 2. F 3. F 4. F 5. T 6. T 7. F 8. T
Sample
1
Quadratic Equations11
Point to Remember Point to Remember
Try to express the relationship between a and b by considering the real part and the imaginary part.
Point to Remember
Point to Remember
To deal with fraction with complex number as denominator, we should multiply it with the conjugate of that complex number to change it to a real number.
Point to Remember Point to Remember
Write the expression in terms of the sum of roots and the product of roots.
Section B
9. Calculate i
i
4 3
2 11 +
- + (7 – 12i). (3 marks)
Solution Try Q.29 – 30.
i i
4 3
2 11 +
- + (7 – 12i) = i
i
i i
4 3
2 11
4 3
4 3
+ # -
-
- + (7 – 12i) [1M]
= 8 33 6 44 i
42+32
- + - -
] g ] g + (7 – 12i)
= 25 i
25 50
- - + (7 – 12i) [1A]
= (–1 – 2i) + (7 – 12i)
= 6 – 14i [1A]
10. If (a + bi) × (1 – 2i) = 13 – i, where a and b are integers, find the values
of a and b. (5 marks)
Solution Try Q.31 – 32.
L.H.S. = (a + bi) × (1 – 2i)
= (a + 2b) + (b – 2a)i [1M]
By comparing the real part and the imaginary part, ( 20a + 2b = 13 ... (1)
b – 2a = –1 ... (2) [1M]
2 × (1) : 2a + 4b = 26 ... (3)
(3) + (2) : 5b = 25 [1M]
b = 5 [1A]
Substituting b = 5 into (1), we have a + 2(5) = 13
a = 3 [1A]
11. If α and β are the roots of the equation x2 – 4x + 2 = 0, find the values of
(a) α2 – αβ + β2, (3 marks)
(b) α3 + β3. (2 marks)
Solution Try Q.36 – 37.
(a) α + β = 1
4 - -] g = 4,
αβ = 12 = 2 [1A]
α2 – αβ + β2 = (α + β)2 – 3αβ α2 + β2 = (α + β)2 – 2αβ [1M]
= 42 – 3(2)
= 10 [1A]
(b) α3 + β3 = (α + β)(α2 – αβ + β2) [1M]
= (4)(10) (By (a))
= 40 [1A]
NF
NF
NF
Sample
Warm Up Exercise
14
HKDSE Exam Series — Mathematics Conventional Questions (Compulsory Part) (Upgraded Edition) Book A
A B
Answer each of the following questions, each question carries 10 marks.
1. If a + 5i = 7 + (b – 3)i, find the values of a and b.
2. Find (2 + 5i) × (6i – 7).
3. Solve the equation 100 = (2x + 1)2.
4. Solve 2x2 + 5x + 2 = 0 by using the factor method.
5. Solve x2 + 3x – 5 = 0 by using the quadratic formula.
6. By considering the discriminant of each of the following quadratic equations, determine the nature of its roots.
(a) x2 + 4x + 4 = 0 (b) 2x2 + 3x – 7 = 0 (c) 2x2 – 5x + 12 = 0
7. If the equation kx2 + 6x + 3 has two distinct real roots, find the range of values of k.
8. If α and β are the roots of the equation 2x2 – 3x + 1 = 0, find the value of 1a + 1 b. 9. Form a quadratic equation whose roots are –2 and 4.
10. In the figure, the side of square B is 2 cm longer than that of square A. If the sum of the areas of the two squares is 130 cm2, find the side length of square A.
/ 100
NF
NF
NF NF
Sample
1
Quadratic Equations15
Mock Questions
Section A(1)
1. (a) Solve x2 + 5x + 6 = 0.
(b) Hence solve (x + 2)2 + 5(x + 2) + 6 = 0.
(3 marks)
2. (a) Solve 4x2 – 81 = 0.
(b) Hence solve 4(x + 1)2 – 81 = 0.
(3 marks)
3. Solve the equation (x + 3)(x – 5) = 9. (3 marks)
4. Solve the equation 3x2 – 3x – 6 = x – 2. (3 marks)
5. Solve the equation 4(x + 3)(x – 1) = 21x. (3 marks)
6. Solve 3x2 = 9x + 2. Give the answers in surd form if necessary. (3 marks)
7. Solve (x + 3)(1 – 2x) – 6 = 12x. (3 marks)
8. Solve (3x – 4)2 = 6x. (3 marks)
9. Solve (2x – 1)(4x + 5) = (4x + 5)(12x + 5). (3 marks)
10. Suppose 7 is a root of the equation x2 – kx – (2k + 4) = 0.
(a) Find the value of k.
(b) Hence find the other root.
(4 marks)
11. Suppose 3 is a root of the equation k = (x + 1)(2x – 1).
(a) Find the value of k.
(b) Hence find the other root.
(4 marks)
12. Find the number of real roots of the equation (3x + 1)(x + 3) = 2x(x – 8). Reference:HKCEE 07Q5 (3 marks)
13. Find the number of real roots of the equation 5x – 1 = x(3x + 2). (3 marks)
Sample Sample
22 22
HKDSE Exam Series — Mathematics Conventional Questions (Compulsory Part) (Upgraded Edition) Book A Solution Guide
3 Exponential and
Logarithmic Functions
Warm Up Exercise
1.
a a b
4 2 3
3 = ( )
a a b
4 3 1 2 3 2 1
#
= a ab
3 4 2 3
= a1-34b23
= a b-31 23
= a b
3 1 2 3
2. log log
8 16 =
log log 2 2
3 4
= log log
3 2
4 2
= 3 4
3. log a2 + log a3 = 2 log a + 3 log a
= 5 log a 4. (a) log 12 = log (22 × 3) = log 22 + log 3 = 2 log 2 + log 3 = 2a + b
(b) log 15 = log (3 × 10 ÷ 2) = log 3 + log 10 – log 2 = b + 1 – a
5. 42x = 8 (22)2x = 23 24x = 23 4x = 3
x = 4 3
6. 2x – 5 · 2x + 8 = 0 (1 – 5) · 2x + 8 = 0 –4 · 2x + 8 = 0 2x = 2 x = 1
7. log (x + 3) = log (2x + 4) x + 3 = 2x + 4
x = –1
8. log3 (x – 1) = 2.3 x – 1 = 32.3
x = 32.3 + 1
= 13.5 (cor. to 3 sig. fig.) 9. (a) & (b)
x y
0 1 2 3
–1
–2
1
–1 2 3
–2
y = log2 x y = x
y = 2x y = 2–x
10. Sound intensity level = 10 log 10
10
12 8 -
d - n dB
= 10 log 104 dB
= 40 dB
Mock Questions
Section B 1.
p q p q
1 4 3
3 - =
p q p q
1 4 3 1 3
_ - i
[1M]
= p q
p q
3 1
3 4 3
-
= p3 3 q
1 1 3
- -d n -4 [1M]
= p q103 -31
= q p
3 1 3 10
[1A]
Common mistakes
The answer should be expressed with positive indices as required.
Sample
23 23
3
Exponential and Logarithmic Functions2. m
m n n
2
2 2 3 4
- = m24m- -] 2gn3-2 [1M]
= m m n2^ 2 h41 [1M]
= m2+21n41
= m n25 41 [1A]
3. 3ab3 a b2 1 2
3
# -
^ h _ i = ab^ 3h31#^a b2 -1h21#23 [1M]
= a b3 (a b )
1 2 1
4 3
# -
= a b a b 4
3 3
1 3
# 2 - [1M]
= a3 b
1 2 3 1
4 + -3
= a b116 41 [1A]
4.
log
log log x
x x
3 1
2+
= 1
1 log
log log
x
x x
3
2 +2
[1M]
= 1
2 2
1 log
log x
x
3
c + m
[1M]
= 15 2 [1A]
5.
1
log log
log log
x y
x y x y
6 3
2
4 2
+ -
= log log
log log log log
x y
x y
x y
6 3
1 1
2
4 2
+
+ - -
[1M]
= log log
log log log log
x y
x y x y
6 3
2 4 2
+
+ + +
[1M]
= 6log 3log
log log
x y
x y
6 3
+ +
= 1 [1A]
6. log log log
16
1 243 3264
2 - 3 #
c m
= log 2 log
log log
32 3 64
2 4
3 2 5
#
- -
a k [1M]
= log
4 log 2 5
2 2
5 6
# c- - m
= 13
log log
5 2
6 2
2 #
c- m [1M]
= 5
-39 [1A]
Guidelines
Use the change of base formula: loga b = log log a b.
7. log 1 x2-y2
d n
= log 1
x+y x-y
^ h^ h
= G
= log x y
1
c + m + log x y 1
c - m [1M]
= –2log x+y– log (x – y) [1M]
= –2a – b [1A]
Guidelines
log (x + y) = 2 log x+y
8. a2 + b2 = 3ab a2 + b2 – 2ab = ab
(a – b)2 = ab [1A]
log (a – b)2 = log ab [1M]
2 log (a – b) = log a + log b log (a – b) =
21 (log a + log b) [1A]
9. (a) log 21 = log (3 × 7)
= log 3 + log 7 [1M]
= r + s [1A]
(b) log 27
343 = log 27 – log 343
=
21 log 33 –
21 log 73 [1M]
= 3 2log 3 –
23 log 7 = (r s)
2
3 -
[1A]
10. (a) Let y = 0.694444 ...
10y = 6.944444 ...
10y – y = 6.944444 ... – 0.694444 ... [1M]
9y = 6.25 y = .
9 6 25
= 3625 [1A]
Guidelines
To express a recurring decimal into fraction, try to remove the recurring part.