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Solution: y = e–x/2[c1cos(x/2

[r]

For instance, let the set A = {(x, y) ∈ [0, 1] × [0, 1]; 0 ≤ y ≤ 1 2 x}\{(0, 0)}, and g be a real-valued function on [0, 1] × [0, 1], defined by

On some feasible region, the two functions version of minimax theorems does not hold again. However, by restricting to a proper range, the minimax theorem

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