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x + y + z = 1, x + y + z = 1, 1 (2)x + y + z = 1, x + y + z = 1

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(1)

x, y characters; x, y variables, cos operator, not cos variable,

ϵ, ε,

Xα,

x, . . . , z; x +· · · + z,

xlim→c,

k j=1Π

,

∥x∥,

1+x 4 , C, A, G,

R, C,

≡/.

x + y + z = 1,

x + y + z = 1,

1

(2)

x + y + z = 1,

x + y + z = 1.

x + y + z = 1, (4)

2x1− 3y1 = 4, (5)

5x2− 6y2 = 7. (6)

a first b second 1. first 2. second Apple fruit

Bear animal John boy

Mary girl 1 2 3 4 [ 1 2

3 4 ]

{ 2x1− 3y1 = 4 5x2− 6y2 = 7

\left( \right)

2

(3)

title 1 2 3 4 5 6







α1E1 0 · · · 0 −β1A1

−β2A2 α2E2 0

... . .. . .. ...

... . .. . .. 0

0 · · · −βKAK αKAK











 x1 x2 ... ... xK





≡ C

( α1,· · · , αK

β1,· · · , βK

)



 x1

... ... xK



= 0.

(7)

Xj−1 = AHj XjAj − AHj XjBj(Rj + BjHXjBj)−1BjHXjAj + Hj

= AHj Xj(I + GjXj)−1Aj + Hj, (8)

πj(k) =

{ k− j + 1 + p, for k = 1, . . . , j − 1, k− j + 1, for k = j, . . . , p.

Mj =

[ Aj 0

−Hj I ]

, Lj =

[ I Gj 0 AHj

]

. (9)

3

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