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.

...

A few inequalities related to spectral excess theorem

Chih-wen Weng (翁志文)

(joint work with Guang-Siang Lee(李光祥))

Department of Applied Mathematics National Chiao Tung University

August 19, 2012

(2)

f (eigenvalues) ≤ g

(graph parameters eigenvectors

)

h(eigenvalues).

quasi-spectral characterization

?

quasi-spectral characterization

?

spectral characterization

 I

(still working)

(3)

Preliminaries

.

1

..

Throughout let G = (V G, EG) be a simple connected graph of order n and diameter D.

.

2

..

Assume that adjacency matrix A has d + 1 distinct eigenvalues λ

0 >

λ

1 > . . . >

λ

d

with corresponding multiplicities

1 = m

0 , m 1 , ··· ,m d

. d is called the

spectral diameter

of G.

.

3

..

It is well-known that D

≤ d.

.

4

..

Z(x) :=

d i=0

(x

λ

i

) is the

minimal polynomial

of A.

(4)

Inner product

Consider the vector spaceR

d

[x] ∼=R[x]/⟨Z(x)⟩ with the inner product

⟨p(x),q(x)⟩ :=

1

n

tr(p(A)q(A)) =1

n

i, j

(p(A)

◦ q(A)) i j ,

for p(x), q(x)

∈ R d

[x], where

◦ is the entrywise product of matrices.

(5)

Predistance polynomials

.

Definition 1.1

..

...

(i) The orthogonal polynomials 1 = p

0

(x), p

1

(x), . . . , p

d

(x) in R

d

[x] satisfying

deg p

i

(x) = i and

⟨p i

(x), p

j

(x)

⟩ =

δ

i j p i

0

) are called the

predistance polynomials

of G.

(ii) The polynomial

H(x) := n

d i=1

x

λ

i

λ

0

λ

i

is called the

Hoffman polynomial

of G. Moreover, G is regular iff H(A) = J, the all 1’s matrix.

(6)

The sum of all predistance polynomials gives the Hoffman polynomial

H(x) = p 0

(x) + p

1

(x) +

··· + p d

(x) and

H(A) = p 0

(A) + p

1

(A) +

··· + p d

(A).

(7)

Three -term recurrence

The predistance polynomials satisfy a three-term recurrence:

xp i

(x) = c

i+1 p i+1

(x) + a

i p i

(x) + b

i −1 p i−1

(x) 0

≤ i ≤ d,

where c

i+1 , a i , b i−1 ∈ R with b −1

= c

d+1

:= 0.

(8)

Three -term recurrence for bipartite graph

.

1

..

If G is bipartite, then the predistance polynomials satisfy a three-term recurrence of the form

x 2 p i

(x) = X

i+2 p i+2

(x) +Y

i p i

(x) + Z

i −2 p i −2

(x) 0

≤ i ≤ d,

(1) where

X i+2

= c

i+1 c i+2 , Y i

= b

i c i+1

+ b

i−1 c i , Z i −2

= b

i −2 b i −1 . .

2

..

Moreover, if G is bipartite, then for 0

≤ j ≤ d, a j

= 0, and

p j

(x) is even or odd depending on whether j is even or odd.

(9)

Distance polynomials

.

1

..

Let α be the eigenvector of A corresponding to λ

0

such that α

t

α = n and all entries are positive. Note that

α = (1,1,...,1)

t

iff G is regular.

.

2

..

The matrix A

i

, indexed by V G, satisfying (A

i

)

uv

=

{ α

u

α

v ,

if∂(u,v) = i;

0, else. is called the

i-th (weighted) distance matrix

of G.

.

3

.. A 0

= p

0

(A)(= I) iff G is regular.

.

4

.. A 0

+ A

1

+

··· + A D

= H(A) = p

0

(A) + p

1

(A) +

··· + p d

(A).

(10)

The spectral excess and the excess

.

1

.. p d

0

) is called the

spectral excess

of G.

.

2

..

δ

d

:=

1 n

i, j

(A

d ◦ A d

)

i j

is called the

excess

of G, where A

d

:= 0 if D < d.

If G is regular, thenδ

d

is the average number of vertices to have distance d to a vertex.

(11)

The spectral excess theorem (SET)

.

Theorem 1.2

..

...

δ

d ≤ p d

0

) with equality iff G is a distance-regular graph.

[FG1997] M.A. Fiol and E. Garriga, From local adjacency polynomials to local pseudo-distance-regular graphs, J. Combin.

Theory Ser. B 71 (1997), 162–183.

(12)

Related definitions

Define

δ

i

:=1

n

u,v

(A

i ◦ A i

)

uv ,

δ

≥i

:=δ

i

i+1

+

··· ,

p ≥i

0

) := p

i

0

) + p

i+1

0

) +

··· , p even

0

) := p

0

0

) + p

2

0

) +

··· ,

p odd ≥i

0

) := p

i

0

) + p

i+2

0

) +

···

for odd i,

A odd

:= A

1

+ A

3

+

···

...

(13)

Modify the proof of SET

.

Proposition 1.3

..

...

δ

≥i ≤ p ≥i

0

) with equality iff A

≥i

= p

≥i

(A).

.

Proposition 1.4

..

...

δ

≤i ≥ p ≤i

0

) with equality iff A

≤i

= p

≤i

(A).

(14)

G is bipartite

.

Proposition 1.5

..

...

If G is bipartite and

∗ ∈ {even,odd} then

δ

≥i ≤ p ≥i

0

) with equality iff A

≥i

= p

≥i

(A).

.

Proposition 1.6

..If G is bipartite and

∗ ∈ {even,odd} then

δ

≤i ≥ p ≤i

0

) with equality iff A

= p

(A).

(15)

Questions?

δ

i ≤ p i

0

) or δ

i ≥ p i

0

)?

Which graphs have the property thatδ

i

= p

i

0

)?

(16)

The case i = 0

.

Proposition 2.1

..

...

δ

0 ≥ 1(= p 0

0

)) ( i.e. α

1 4

2 4

+

··· +

α

n 4 ≥ n),

and the following are equivalent.

.

1

..

δ

0

= 1. (i.e. α

1 4

2 4

+

··· +

α

n 4

= n.)

.

2

.. A 0

= I.

.

3

.. G is regular.

.

4

..

The entries ofα are all 1.

The above inequality is fromδ

≤0 ≥ p ≤0

0

) which we mentioned earlier, but also follows from the Cauchy-Schwarz inequality

(17)

The case i = 1

A bipartite graph with bipartition V (G) = X

∪Y is biregular

if there exist distinct integers k

̸= k

such that every x

∈ X has degree k,

and every y

∈ Y has degree k .

.

Proposition 3.1

..

...

δ

1 ≥ p 1

0

), and the following statements are equivalent.

(i) δ

1

= p

1

0

) (or equivalently δ

1 k =

λ

0 2

), (ii) A

1

= p

1

(A),

(iii) G is regular or G is bipartite biregular.

(18)

.

Corollary 3.2

..

...

There is no bipartite biregular graph G with exactly four distinct eigenvalues.

The idea of the proof is to modify a proof in

[DDFGG2011] C. Dalfó, E.R. van Dam, M.A. Fiol, E. Garriga and B.L. Gorissen, On almost distance-regular graphs, J. Combin.

Theory Ser. A 118 (2011), 1094–1113.

(19)

The case i = 2

.

1

..

If d = 2 thenδ

2 ≤ p 2

0

).

.

2

..

If G is regular bipartite, thenδ////

0

2 ≥ p

///////// p

0

0

)+

2

0

).

.

3

..

There is no hope to determine the order ofδ

2

and p

2

0

) uniformly.

(20)

.

Definition 4.1

..

...

Let G be a graph and i is a nonnegative integer. We say the numbers c

i , a i , b i

respectively are

well-defined

in G if for any

x, y ∈ V(G) with

∂(x,y) = i, the numbers

c i

:=

|G 1

(x)

∩ G i −1

(y)

|, a i

:=

|G 1

(x)

∩ G i

(y)

|, b i

:=

|G 1

(x)

∩ G i+1

(y)

|,

respectively are independent of the choice of x, y.

d y

d x





 



c i b i

(21)

.

Definition 4.2

..

...

A graph G is

t-partially distance-regular

if for 2

≤ i ≤ t and the

numbers c

i , a i −1 , b i −2

are well-defined.

.

Lemma 4.3

..

...δ

0

= p

0

0

) andδ

2

= p

2

0

) iff G is 2-partially distance-regular.

(22)

.

Definition 4.4

..

...

For a connected bipartite graph G with bipartition X

∪Y, the halved graphs G X

and G

Y

are the two connected components of the distance-2 graph of G.

G :

'

&

$

% G X

'

&

$

% G Y

.

Theorem 4.5 (BCN, Prop 4.2.2, p.141)

..

...

The halved graphs of a bipartite distance-regular graph are again distance-regular and, in the case where G is vertex transitive, the two halved graphs are isomorphic.

(23)

.

Lemma 4.6

..

...

If G = (X,Y ) is a connected regular bipartite graph with

δ

2

= p

2

0

) (so 2–partially distance-regular by previous lemma), then the halved graphs G

X

and G

Y

have the same spectrum.

(24)

Bipartite graphs with δ d −1 = p d −1 ( λ 0 )

.

Lemma 5.1

..

...

Let G be bipartite andδ

d −1

= p

d −1

0

). Then

A d −1

= p

d −1

(A), A

d −3

= p

d −3

(A), A

d −5

= p

d −5

(A), . . . . In particular G is regular (if A

0

= p

0

(A)) or bipartite biregular (if

A 1

= p

1

(A)).

.

Theorem 5.2

..

Let G be a connected bipartite graph with bipartition X

∪Y, odd d.

Then the following are equivalent.

(i)

δ

d −1

= p

d −1

0

);

(ii) G is 2-partially distance-regular and both halved graphs G X

(25)

The following example shows that a bipartite graph satisfying Theorem 5.2(i)-(ii) and D = d needs not to be distance-regular graph.

.

Example 5.3

..

...

Consider the regular bipartite graphs G on 20 vertices obtained from the Desargues graph (the bipartite double of the Petersen graph) by the GM-switching (a way to produce cospectral

nonisomorphic graphs). One can check (by Maple) that D = d = 5, sp G =

{3 1 , 2 4 , 1 5 , (−1) 5 , (−2) 4 , (−3) 1 }, p 0

(x) = 1, p

1

(x) = x,

p 2

(x) = x

2 − 3, p 3

(x) = (x

3 − 5x)/2, p 4

(x) = (x

4 − 9x 2

+ 12)/4,

p 5

(x) = (x

5 − 11x 3

+ 22x)/12, A

i

= p

i

(A) for i

∈ {0,1,2,4}. Hence

δ

0

= p

0

0

) = 1,δ

1

= p

1

0

= 3,δ

2

= p

2

0

) = 6,

δ

4

= p

4

0

) = 3),δ

3

= 32/5,δ

5

= 3/5 , p

3

0

) = 6,

p 5

0

) = 1

̸= 3/5 =

δ

5

. Then G is not distance-regular.

(26)

The following example provides a graph G satisfying Theorem 5.2(i)-(ii) with D = d

− 1.

.

Example 5.4

..Consider the Möbius-Kantor graph G, i.e., the generalized Petersen graph GP(8, 3) with vertex set

{u 0 , u 1 , . . . , u 7 , v 0 , v 1 , . . . , v 7 } and

edge set

{u i v i , u i u i+1 , v i v i+3 |0 ≤ i ≤ 7} with arithmetic modulo 8.

One can check (by Maple) that D = 4 < 5 = d, sp G =

{3 1 ,

3

4 , 1 3 , ( −1) 3 , (

3)

4 , ( −3) 1 }, p 0

(x) = 1, p

1

(x) = x,

p 2

(x) = x

2 − 3, p 3

(x) = 2(x

3 − 5x)/5, p 4

(x) = (x

4 − 10x 2

+ 15)/6,

p 5

(x) = (x

5 − 56x 3 /5 + 21x)/18, A i

= p

i

(A) for i

∈ {0,1,2,4}

0

= p

0

0

) = 1,δ

1

= p

1

0

) = 3, δ

2

= p

2

0

) = 6,

δ

4

= p

4

0

) = 1),δ

3

= 5, p

3

0

) = 24/5, p

5

0

) = 1/5. Note that

G 2

= 2X , where X is the 16-cell graph

(http://mathworld.wolfram.com/16-Cell.html), which is distance-regular with sp X =

{6 1 , 0 4 , ( −2) 3 }.

(27)

The parity of d makes things different

.

Theorem 5.5

..

...

Let G be a connected bipartite graph with bipartition X

∪Y and even d. Then the following are equivalent.

(i) G is distance-regular;

(ii) G is 2-partially distance-regular and both of the halved graphs G X

and G

Y

are distance-regular of diameter d/2.

In the next two pages, we provide two examples of

non-distance-regular graphs that satisfy p

d−1

0

) =δ

d−1

when d is even. The first one is bipartitle biregular and the second one is regular.

(28)

.

Example 5.6

..Consider the bipartite graphs G on 25 vertices obtained from the Petersen graph by subdividing each edge once. One can check (by Maple) that D = d = 6,

sp G =

{

6

1 , 2 5 , 1 4 , 0 5 , ( −1) 4 , ( −2) 5 , (

6)

1 }, the

Perron-Frobenius vectorα = (√

5/4,

··· ,

| {z 5/4}

10

,

5/6,

··· ,

| {z 5/6}

15

)

t

,

p 0

(x) = 1, p

1

(x) = 5

6x/12, p

2

(x) = 15(x

2 − 12/5)/16, p 3

(x) = 5

6(x

3 − 4x)/12, p 4

(x) = 25(x

4 − 21x 2 /4 + 3)/28, p 5

(x) = 5

6(x

5 − 7x 3

+ 10x)/24,

p 6

(x) = 5(x

6 −65x 4 /7 + 22x 2 −48/7)/24, e A i

= p

i

(A) for i

∈ {1,3,5}

1

= p

1

0

) = 5/2,δ

3

= p

3

0

) = 5,δ

5

= p

5

0

) = 5), δ

0

= 25/24, δ

2

= 85/24,δ

4

= 85/12,δ

6

= 5/6, p

0

0

) = 1, p

2

0

) = 27/8,

p 4

0

) = 375/56, p

6

0

) = 10/7. Note that G

2

is the disjoint union of the Petersen graph X and the line graph Y of X. We have

(29)

.

Example 5.7

..

...

Let G be the Hoffman graph (A graph nonisomorphic but cospectral to 4-cube). Then sp G =

{4 1 , 2 4 , 0 6 , ( −2) 4 , ( −4) 1 }, D = d = 4, p 0

(x) = 1, p

1

(x) = x, p

2

(x) = (x

2 − 4)/2,

p 3

(x) = (x

3 − 10x)/6, p 4

(x) = (x

4 − 16x 2

+ 24)/24, and A

3

= p

3

(A).

Note that G

2

is the disjoint union of K

8

and K

2,2,2,2

(= K

8 − 4K 2

), which are both distance-regular (sp K

2,2,2,2

=

{6 1 , 0 4 , ( −2) 3 }).

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