[PDF] Top 20 2014IMAS First Round Middle Primary Division Full Solutions

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... 【Solution】 It is obvious the model is contained in a cube of edge length 3 and contains some of the 27 unit cubes of the large cube. The unit cube in the center has to appear in the model. The cubes at the center of ... See full document

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... the first set when divided by 3 will give a remainder of 1, each number in the second set when divided by 3 will give a remainder of 2 and each number in the third set when divided by 3 or when each of them is ... See full document

... Since 2014 = 335 × 6 + 4, it means that in the first 2014 terms in the sequence, there are 335 complete periods with an incomplete period of four remaining ...The first time both are back ... See full document

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... 【Solution】 If there is no carry when the number is added by 1, sum of digits increases by 1, contradiction to that both sum of digits are divided by 4. If there is a carry, the last digit is 9. Since the sum of all ... See full document

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... Totally there are 20  20 8 4 1 53     isosceles right triangles. Hence (E). Answer： （E） 21. Mike constructs a sequence in the following way: the first two terms are 1 and 2. Starting from the third term, each ... See full document

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... Answer: 45 number sentences 10. An ant starts from the top left corner square of a 3 5  chessboard. It moves from a square to the adjacent square in the same row or column. After visiting every square exactly once, it ... See full document

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... Notice: Individual students, nonprofit libraries, or schools are permitted to make fair use of the papers and its solutions. Republication, systematic copying, or multiple reproduction of any part of this material ... See full document

... Notice: Individual students, nonprofit libraries, or schools are permitted to make fair use of the papers and its solutions. Republication, systematic copying, or multiple reproduction of any part of this material ... See full document