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微積分:級數比較法

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7.4

Comparisons of Series (Positive Series)

Direct Comparison Test:

In the following pairs, the second series cannot be tested by the same convergence test as the first even thougn it is similar to the first.

1. P∞=0 21 is geometric, but P∞ =0  2 is not. 2. P∞=0 13 is a −series, but P∞ =0 1 3+1 is not.

3.  = (2+3) 2 is easily integrated, but  =

2

(2+3)2 is not.

In this section you will study two additional tests for positive -term series.

(1) Dirct Comparison Test. (2) Limit Comparison Test.

Theorem 87 (Dirct Comparison Test) Let 0   ≤  for all  greater

then some integer 

1. If P∞=1 converges, then

P∞

=1 converges. (If the ”larger” series

converges, the ”smaller” series must also converge.) 2. If P∞=1 diverges, then

P

=1 diverges. (If the ”smaller” series

diverges, the ”larger” series must also diverges.)

Example 186 Determine the convergence or divergence of IfP∞=1 2+31

1 2 + 3 

1

3 ≥ 1

Example 187 Determine the convergence or divergence of IfP∞=1 2+1√ 1 2 +√ ≤ 1 √  for  ≥ 1 and 1  ≤ 1 2 +√ for  ≥ 4 103

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Theorem 88 (Limit Compareson Test) Suppose that   0  0 and lim →∞ µ   ¶ = 

where  is finite and positive. Then the two series P and P either

both converges or both diverges.

Example 188 Show that the following series diverges

∞ X =1 1  +    0   0 Use ∞ X =1 1 

Technique: Cancel to lower order term and Comparison −series. Example 189 () ∞ X =1 1 32− 4 + 5 ∞ X =1 1 2 () ∞ X =1 1 √ 3− 2 ∞ X =1 1 √  () ∞ X =1 2 − 10 45+ 3 ∞ X =1 1 3

Example 190 Determine the convergence or divergence of

∞ X =1 √  2+ 1

Example 191 Determine the convergence or divergence of

∞ X =1 2 43+ 1 104

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