Jordan triples in analysis on bounded symmetric
domains
Guy Roos St Petersburg [email protected] Hsinchu, Taiwan 2010/04/08-12Part I. Examples of bounded symmetric domains
1 The unit disc ofC
2 The Hermitian ball ofCn
3 The Lie ball
Riemann’s Mapping Theorem
Unit disc ofC:
∆
=
{
z∈
C| |
z| <
1}
Theorem (Riemann’s Mapping Theorem). Every simply connected
Automorphisms of
∆
G
=
Aut∆, the group of biholomorphic automorphisms of∆.For a
∈
∆, letφa :∆→
∆ φa(
z) =
z+
a 1+
az(
z∈
∆)
. Thenφa∈
Aut∆, φ−a1=
φ−a, φa(
0) =
a.The group Aut∆acts transitively on∆.
Symmetries:
s0
(
z) = −
z(
z∈
∆)
,sa
=
φa◦
s0◦
φ−a.Then sa
∈
Aut∆,Automorphisms of
∆
Let K
=
G0= {
u∈
G|
u(
0) =
0}
.ThenK
=
U(
1) =
{
hλ| |
λ| =
1}
, hλ(
z) =
λz.Eachφ
∈
G may be uniquely writtenφ
(
z) =
λ z+
a1
+
az(
z∈
∆)
,Bergman space of
∆
Flat symplectic formβ0and flat volume formω0for∆:
β0
(
z) =
ω0(
z) =
i 2πd z∧
d z=
1 π d x∧
d y. Bergman space of∆: A2(
∆) =
Hol∆∩
L2(
∆, ω0)
,with the scalar product
(
f|
g) = (
f|
g)
A2(∆)=
Z
∆f gω0
(
f,g∈
A 2(
∆))
and the norm
k
fk
2=
k
fk
2A2(∆)=
Z
∆
|
f|
2Bergman kernel of
∆
The Bergman space is a Hilbert space of holomorphic functions, that is,
A2
(
∆) →
Rf
7→
sup{|
f(
z)| |
z∈
C}
is continuous for every compact subset C
⊂
∆.For z
∈
∆, let Kz∈
A2(
∆)
be the Riesz representative of thecontinuous linear formεz :A2
(
∆) →
C,εz(
f) =
f(
z)
: εz(
f) = (
f|
Kz)
(
f∈
A2(
∆))
.The Bergman kernel of ∆is
Properties of the Bergman kernel
K
(
z,t) =
K(
t,z)
, K(
z,z) =
k
Kzk
2>
0,(
z,t) 7→
K(
z,t)
isholomorphic w.r. to z and antiholomorphic w.r. to t. Reproducing property:
f
(
z) =
Z∆K
(
z,t)
f(
t)
ω0(
t)
(
f∈
A2
(
∆)
, z∈
∆)
.Transformation by automorphisms: forφ
∈
Aut∆,K
(
z,t) =
K(
φ(
z)
, φ(
t))
φ0(
z)
φ0(
t)
(
z,t∈
∆)
, K(
z,z) =
K(
φ(
z)
, φ(
z))
φ0(
z)
2(
z∈
∆)
.Bergman kernel of
∆
The Bergman kernel of ∆is equal to
K
(
z,t) =
1(
1−
zt)
2.Proof
Apply the transformation formula toφa: K
(
0,0) =
K(
a,a)
|
φ0a(
0)|
2.Asφa0
(
0) =
1−
aa, we have K(
a,a) =
K(0,0)(1−aa)2.Hence the Bergman
kernel of∆is
K
(
z,t) =
K(
0,0)
(
1−
zt)
2.K
(
0,t) =
K(
0,0)
for all t∈
∆and the reproducing formula implies1
=
Z ∆K(
0,t)
ω0(
t) =
K(
0,0)
Z ∆ω0. AsR
∆ω0=
1, we have K(
0,0) =
1.Bergman metric of
∆
The Bergman metric of ∆is defined by
hz
(
u,v) =
∂u∂vlog K(
z,z) =
∂2 ∂z∂zlog K
(
z,z)
uv.Computation of the Bergman metric of ∆
hz
(
u,v) =
2(
1−
zz)
2uv.The Bergman metric is an Hermitian metric on∆, invariant by Aut∆:
Forφ
∈
Aut∆such thatφ(
z) =
0,Bergman metric of
∆
The hyperbolic symplectic form βassociated to the Bergman metric is
β
(
z) =
i2∂∂log K
(
z,z)
. It is related to the Bergman metric byβ
(
z)(
u,v) = −
Im hz(
u,v)
.Computation of the hyperbolic symplectic form
β
(
z) =
i d z∧
d z(
1−
zz)
2=
2β0
(
z)
Bergman operator of
∆
The Bergman operator B
(
z,z)
(z∈
∆) is the complex linear operatorB
(
z,z)
:C→
C, such thathz
(
u,v) =
h0(
B(
z,z)
−1u,v)
(
z∈
∆, u,v∈
C)
.The Bergman operator for∆is
Part I. Examples of bounded symmetric domains
1 The unit disc ofC
2 The Hermitian ball ofCn
3 The Lie ball
The Hermitian ball of
C
nV
=
Cn, Hermitian vector space of dimension n, with Hermitianscalar product
(
z|
t) =
n∑
j=1 zjtjand Hermitian norm
k
zk
2= (
z|
z)
.Unit Hermitian ball of V
=
Cn:Ω
=
Bn=
{
z∈
Cn| k
zk <
1}
.G
=
AutΩ, the group of biholomorphic automorphisms ofΩ.Automorphisms of B
n Let M=
A B C d ∈
U(
n,1)
,with A
∈
EndCV , B∈
V , C∈
V0, d∈
C. Then the mapφM definedby
φM
(
z) = (
Az+
B)(
Cz+
d)
−1is a biholomorphic automorphism of Bn.
The condition M
∈
U(
n,1)
writes as MJn,1M∗=
Jn,1, whereJn,1
=
diag(
In,−
1)
. So M∈
U(
n,1)
if and only if AA∗−
BB∗=
In,AC∗
−
dB=
0,Automorphisms of B
nTheorem. The group Aut Bn acts transitively on Bn. Proof. Let a
=
λe∈
Bn, e∈
∂Bn, 0≤
λ<
1.Let
B
=
da, C=
B∗, d=
√
11
−
λ2and let A
∈
EndCV be defined byAe
=
de, Az=
z if(
u|
e) =
0. Thenφa defined by φa(
z) = (
Az+
B)(
Cz+
d)
−1=
Az+
B(
z|
B) +
d(
z∈
Bn)
Derivative of
φ
a Lemma. φ0a(
0) ·
e=
1− k
ak
2e, φa0(
0) ·
u=
1− k
ak
21/2u if(
u|
e) =
0, Jφa(
0) =
1− k
ak
2 n+1 2 . Proof. For z∈
Bn, u∈
V φa0(
z) ·
u=
Au(
z|
aB) +
d−
(
u|
B)(
Az+
B)
((
z|
B) +
d)
2 , φa0(
0) ·
u=
Au d−
(
u|
B)
B d2 . Then φ0a(
0) ·
e=
1−
λ2e, φ0a(
0) ·
u=
√
1−
λ2u if(
u|
e) =
0.Linear automorphisms of B
nLemma (H. Cartan). Let u
∈
Aut Bnsuch that u(
0) =
0 and u0(
0) =
idV. Then u=
idBn.Proposition. K U
(
n)
: u∈
Aut Bn and u(
0) =
0 if and only if u isthe restriction to Bn of a unitary linear endomorphism of V .
Each automorphismφ
∈
Aut Bn may be writtenφ
=
u◦
φa,where a
=
φ(
0)
and u∈
K .Symmetry around 0:
s0
(
z) = −
z(
z∈
Bn)
.Symmetry around a
∈
Bn: takeφ∈
Aut Bnsuch thatφ(
0) =
a andsa
=
φ◦
s0◦
φ−1. Then sa∈
Aut Bn,sa2
=
idBn, sa(
a) =
a, s0
Bergman space of B
nFlat K ¨ahler form for Bn: β0
(
z) =
i 2π∂∂(
z|
z) =
i 2π n∑
j=1 d zj∧
d zj.Flat volume form for Bn:
ω0
=
βn0=
n! n ^ j=1 i 2π d zj∧
d zj . Bergman space of Bn: A2(
Bn) =
Hol Bn∩
L2(
Bn, ω0)
,with scalar product and norm
(
f|
g) = (
f|
g)
A2(B n)=
Z Bn f gω0(
f,g∈
A2(
Bn))
,k
fk
2=
k
fk
2A2(B n)=
Z Bn|
f|
2ω0(
f∈
A2(
Bn))
.Bergman kernel of B
nThe Bergman space A2
(
Bn)
is a Hilbert space of holomorphicfunctions.
The Bergman kernel of Bnis
K
(
z,t) =
Kz(
t)
(
z,t∈
Bn)
,where Kz
∈
A2(
Bn)
is characterized byProperties of the Bergman kernel
K
(
z,t) =
K(
t,z)
, K(
z,z) =
k
Kzk
2>
0,(
z,t) 7→
K(
z,t)
is holomorphic w.r. to z and antiholomorphic w.r. to t.Reproducing property: f
(
z) =
Z
Bn
K
(
z,t)
f(
t)
ω0(
t)
(
f∈
A2(
Bn)
, z∈
Bn)
.Transformation by automorphisms: forφ
∈
Aut Bn,K
(
z,t) =
K(
φ(
z)
, φ(
t))
Jφ(
z)
Jφ(
t)
(
z,t∈
Bn)
,K
(
z,z) =
K(
φ(
z)
, φ(
z))
|
Jφ(
z)|
2(
z∈
Bn)
,where
Jφ
(
z) =
detCφ0(
z)
Bergman kernel of B
nTheorem. The Bergman kernel of Bn is equal to
K
(
z,t) =
1(
1− (
z|
t))
n+1.Proof. Applying the transformation formula to hλ :Bn
→
Bn, hλ(
z) =
λz,where
|
λ| =
1, gives K(
0,a) =
K(
0, λa)
for allλ(|
λ| =
1), henceK
(
0,a) =
K(
0,0)
for all a∈
Bn. By the reproducing formula for the function 1, K(
0,0) =
Z Bn ω0 −1=
1.Letφ
∈
Aut Bn such thatφ(
0) =
a. Then|
Jφ(
0)|
2=
1
− k
ak
2n+1. By the transformation formula,K
(
a,a) =
1|
Jφ(
0)|
2=
1 1− k
ak
2n+1 .Bergman metric of B
nThe Bergman metric of Bnis defined by
hz
(
u,v) =
∂u∂vlog K(
z,z)
.The hyperbolic symplectic form associated to the Bergman metric is
β
(
z) =
i2∂∂log K
(
z,z)
. It is related to the Hermitian metric byβ
(
z)(
u,v) = −
Im hz(
u,v)
.The Bergman metric is an Hermitian metric on Bn, invariant by Aut Bn:
forφ
∈
Aut Bn such thatφ(
z) =
0,Computation of the Bergman metric of B
n K(
z,z) =
1(
1− (
z|
z))
n+1, ∂vlog K(
z,z) = (
n+
1)
(
z|
v)
1− (
z|
z)
, hz(
u,v) =
∂u∂vlog K(
z,z)
= (
n+
1)
(
u|
v)
1− (
z|
z)
+
(
u|
z)(
z|
v)
(
1− (
z|
z))
2 ! .The Bergman metric at z
∈
Bn ishz
(
u,v) = (
n+
1)
(
1− (
z|
z)) (
u|
v) + (
u|
z)(
z|
v)
(
1− (
z|
z))
2 .Bergman metric of B
nh0
(
u,v) = (
n+
1)(
u|
v)
Let a
=
λe∈
Bn, e∈
∂Bn, 0≤
λ<
1. DefineV2
(
e) =
Ce, V1(
e) =
{
z∈
V| (
z|
e) =
0}
.Then the Bergman metric at a is ha
(
e,e) = (
n+
1)
1(1−λ2)2,
ha
(
u,v) = (
n+
1)
11−λ2
(
u|
v)
(
u,v∈
V1(
e))
,Bergman operator of B
nThe Bergman operator B
(
z,z)
(z∈
Bn) is the complex linearoperator, such that
hz
(
u,v) =
h0(
B(
z,z)
−1u,v)
(
z∈
Bn, u,v∈
V=
Cn)
.Let z
=
λe∈
Bn, e∈
∂Bn, 0≤
λ<
1. The Bergman operator for Bnis B
(
z,z)
u=
1−
λ22u(
u∈
V2(
e)
, 1−
λ2u(
u∈
V1(
e)
.Part I. Examples of bounded symmetric domains
1 The unit disc ofC
2 The Hermitian ball ofCn
3 The Lie ball
Notations
V0, real Euclidean vector space of dimension n
>
1, with Euclideanscalar product x
·
y and norm|
x|
2=
x·
x.V
=
C⊗
RV0=
V0⊕
i V0, complexified vector space of V0.Conjugation on V w.r. to V0:
z
=
x+
i y7→
z=
x−
i y(
x,y∈
V0)
.Hermitian scalar product on V :
(
x+
i y|
u+
i v) =
x·
u+
y·
v+
i y·
u−
i x·
v(
x,y,u,v∈
V0)
.The associated Hermitian norm is denoted by
|
z|
. Letρ
(
z) =
|
z|
2= (
z|
z)
(
z∈
V)
.Complex bilinear form on V and associated quadratic form:
(
z:t) =
z|
t(
z,t∈
V)
,Notations
V0, real Euclidean vector space of dimension n
>
1, with Euclideanscalar product x
·
y and norm|
x|
2=
x·
x.V
=
C⊗
RV0=
V0⊕
i V0, complexified vector space of V0.Conjugation on V w.r. to V0:
z
=
x+
i y7→
z=
x−
i y(
x,y∈
V0)
.Hermitian scalar product on V :
(
x+
i y|
u+
i v) =
x·
u+
y·
v+
i y·
u−
i x·
v(
x,y,u,v∈
V0)
.The associated Hermitian norm is denoted by
|
z|
. Letρ
(
z) =
|
z|
2= (
z|
z)
(
z∈
V)
.Complex bilinear form on V and associated quadratic form:
(
z:t) =
z|
t(
z,t∈
V)
,Notations
V0, real Euclidean vector space of dimension n
>
1, with Euclideanscalar product x
·
y and norm|
x|
2=
x·
x.V
=
C⊗
RV0=
V0⊕
i V0, complexified vector space of V0.Conjugation on V w.r. to V0:
z
=
x+
i y7→
z=
x−
i y(
x,y∈
V0)
.Hermitian scalar product on V :
(
x+
i y|
u+
i v) =
x·
u+
y·
v+
i y·
u−
i x·
v(
x,y,u,v∈
V0)
.The associated Hermitian norm is denoted by
|
z|
. Letρ
(
z) =
|
z|
2= (
z|
z)
(
z∈
V)
. Complex bilinear form on V and associated quadratic form:(
z:t) =
z|
t(
z,t∈
V)
,Notations
V0, real Euclidean vector space of dimension n
>
1, with Euclideanscalar product x
·
y and norm|
x|
2=
x·
x.V
=
C⊗
RV0=
V0⊕
i V0, complexified vector space of V0.Conjugation on V w.r. to V0:
z
=
x+
i y7→
z=
x−
i y(
x,y∈
V0)
.Hermitian scalar product on V :
(
x+
i y|
u+
i v) =
x·
u+
y·
v+
i y·
u−
i x·
v(
x,y,u,v∈
V0)
.The associated Hermitian norm is denoted by
|
z|
. Letρ
(
z) =
|
z|
2= (
z|
z)
(
z∈
V)
.Complex bilinear form on V and associated quadratic form:
(
z:t) =
z|
t(
z,t∈
V)
,The Lie norm
Definition. The Lie norm (or maximal norm) on V is the greatest norm
k k
on the complex vector space V , whose restriction to V0is the Euclidean
norm of V0.
k
zk =
inf (∑
j∈J|
λj| |
xj| |
z=
∑
j∈J λjxj, Jfinite, λj∈
C, xj∈
V0 ) .Proposition (L. Dru´zkowski, 1974). Let ν
(
z) =
k
zk
2. Then ν(
z) =
ρ(
z) +
q
ρ2
(
z) −
|
σ(
z)|
2.For z
∈
V ,ν(
z)
is the greatest root of the polynomialm
(
X;z) =
X2−
2ρ(
z)
X+
|
σ(
z)|
2.Definition. The Lie ball Ln is the unit ball of the Lie norm.
Ln
=
nz∈
V|
ρ(
z) <
1, 2ρ(
z) −
|
σ(
z)|
2<
1o .
The Lie norm
Definition. The Lie norm (or maximal norm) on V is the greatest norm
k k
on the complex vector space V , whose restriction to V0is the Euclidean
norm of V0.
k
zk =
inf (∑
j∈J|
λj| |
xj| |
z=
∑
j∈J λjxj, Jfinite, λj∈
C, xj∈
V0 ) .Proposition (L. Dru´zkowski, 1974). Let ν
(
z) =
k
zk
2. Then ν(
z) =
ρ(
z) +
q
ρ2
(
z) −
|
σ(
z)|
2.For z
∈
V ,ν(
z)
is the greatest root of the polynomialm
(
X;z) =
X2−
2ρ(
z)
X+
|
σ(
z)|
2.Definition. The Lie ball Ln is the unit ball of the Lie norm.
Ln
=
nz∈
V|
ρ(
z) <
1, 2ρ(
z) −
|
σ(
z)|
2<
1o .
The Lie norm
Definition. The Lie norm (or maximal norm) on V is the greatest norm
k k
on the complex vector space V , whose restriction to V0is the Euclidean
norm of V0.
k
zk =
inf (∑
j∈J|
λj| |
xj| |
z=
∑
j∈J λjxj, Jfinite, λj∈
C, xj∈
V0 ) .Proposition (L. Dru´zkowski, 1974). Let ν
(
z) =
k
zk
2. Then ν(
z) =
ρ(
z) +
q
ρ2
(
z) −
|
σ(
z)|
2.For z
∈
V ,ν(
z)
is the greatest root of the polynomialm
(
X;z) =
X2−
2ρ(
z)
X+
|
σ(
z)|
2. Definition. The Lie ball Ln is the unit ball of the Lie norm.Ln
=
nz∈
V|
ρ(
z) <
1, 2ρ(
z) −
|
σ(
z)|
2<
1o .
The Lie norm
Definition. The Lie norm (or maximal norm) on V is the greatest norm
k k
on the complex vector space V , whose restriction to V0is the Euclidean
norm of V0.
k
zk =
inf (∑
j∈J|
λj| |
xj| |
z=
∑
j∈J λjxj, Jfinite, λj∈
C, xj∈
V0 ) .Proposition (L. Dru´zkowski, 1974). Let ν
(
z) =
k
zk
2. Then ν(
z) =
ρ(
z) +
q
ρ2
(
z) −
|
σ(
z)|
2.For z
∈
V ,ν(
z)
is the greatest root of the polynomialm
(
X;z) =
X2−
2ρ(
z)
X+
|
σ(
z)|
2. Definition. The Lie ball Ln is the unit ball of the Lie norm.Ln
=
nz∈
V|
ρ(
z) <
1, 2ρ(
z) −
|
σ(
z)|
2<
1o .
Case n
=
2
Let n
=
dimRV0=
dimCV=
2.If
(
e1,e2)
is an orthonormal basis for V0(and V ), the Lie norm of z=
z1e1+
z2e2isk
zk =
max z1+
i z2 , z1−
i z2 .The Lie ball L2is linearly isomorphic to the bidisc ∆
×
∆.Boundary of the Lie ball
Proposition. The boundary ∂Ln of the Lie ball is the disjoint union of a
real analytic hypersurface ∂1Lnand of a compact submanifold ∂2Ln:
∂1Ln
=
n z∈
V|
2ρ(
z) −
|
σ(
z)|
2=
1, ρ(
z) <
1 o , ∂2Ln=
{
z∈
V|
ρ(
z) =
|
σ(
z)| =
1}
=
{
z∈
V|
z=
λx, λ∈
C, x∈
V0,|
λ| = |
x| =
1}
.∂2Ln
(
S1×
Sn−1)
/{±
I}
;∂2Ln is orientable if n is even, nonorientable if n is odd.
∂2Ln
⊂
∂1Ln=
∂LnBoundary of the Lie ball
Proposition. The boundary ∂Ln of the Lie ball is the disjoint union of a
real analytic hypersurface ∂1Lnand of a compact submanifold ∂2Ln:
∂1Ln
=
n z∈
V|
2ρ(
z) −
|
σ(
z)|
2=
1, ρ(
z) <
1 o , ∂2Ln=
{
z∈
V|
ρ(
z) =
|
σ(
z)| =
1}
=
{
z∈
V|
z=
λx, λ∈
C, x∈
V0,|
λ| = |
x| =
1}
.∂2Ln
(
S1×
Sn−1)
/{±
I}
;∂2Ln is orientable if n is even, nonorientable if n is odd.
∂2Ln
⊂
∂1Ln=
∂LnBoundary of the Lie ball
If z
∈
∂Ln, thenρ(
z) =
12(
1+
|
σ(
z)|
2) ∈ [
12,1]
. An element e∈
∂Lnwillbe called minimal ifρ
(
e) =
12, which is equivalent toσ(
e) =
0. The set ofminimal elements M1
=
e∈
V|
ρ(
e) =
1 2, σ(
e) =
0is a real-analytic compact submanifold of V , and dimRM1
=
2n−
3.Proposition. The map
Φ :M1
×
∆→
∂1Ln(
e, λ) 7→
e+
λeis a real-analytic diffeomorphism.
Boundary of the Lie ball
If z
∈
∂Ln, thenρ(
z) =
12(
1+
|
σ(
z)|
2) ∈ [
12,1]
. An element e∈
∂Lnwillbe called minimal ifρ
(
e) =
12, which is equivalent toσ(
e) =
0. The set ofminimal elements M1
=
e∈
V|
ρ(
e) =
1 2, σ(
e) =
0is a real-analytic compact submanifold of V , and dimRM1
=
2n−
3.Proposition. The map
Φ :M1
×
∆→
∂1Ln(
e, λ) 7→
e+
λeis a real-analytic diffeomorphism.
Polar decomposition
Two minimal elements e1,e2are called strongly∂s orthogonal if
e2
=
θe1 with|
θ| =
1; this is equivalent to|(
e1 :e2)| =
12.
A pair
(
e1,e2)
of strongly orthogonal minimal elements is called aframe of V . A frame is a maximal sequence of pairwise strongly orthogonal minimal elements.
The manifold of frames (also called F ¨urstenberg-Satake boundary of Ln)
F =
(
e1,e2) ∈
M1×
M1| |(
e1:e2)| =
1 2Polar decomposition
Two minimal elements e1,e2are called strongly∂s orthogonal if
e2
=
θe1 with|
θ| =
1; this is equivalent to|(
e1 :e2)| =
12.
A pair
(
e1,e2)
of strongly orthogonal minimal elements is called aframe of V . A frame is a maximal sequence of pairwise strongly orthogonal minimal elements.
The manifold of frames (also called F ¨urstenberg-Satake boundary of Ln)
F =
(
e1,e2) ∈
M1×
M1| |(
e1:e2)| =
1 2Polar decomposition
Theorem. Each z
∈
V has a polar decomposition z=
λ1e1+
λ2e2,where
(
e1,e2)
is a frame and λ1≥
λ2≥
0.Proof. Use the decomposition of the boundary∂Ln.
If z
=
λ1e1+
λ2e2is a polar decomposition for z, thenρ
(
z) =
1 2 λ 2 1+
λ22 ,|
σ(
z)|
2=
λ21λ22andλ21,λ22are the roots of
m
(
X;z) =
X2−
2ρ(
z)
X+
|
σ(
z)|
2.The realsλ1,λ2are called singular values of z; in particular,λ1is the Lie
Polar decomposition
Theorem. Each z
∈
V has a polar decomposition z=
λ1e1+
λ2e2,where
(
e1,e2)
is a frame and λ1≥
λ2≥
0.Proof. Use the decomposition of the boundary∂Ln.
If z
=
λ1e1+
λ2e2is a polar decomposition for z, then ρ(
z) =
1 2 λ 2 1+
λ22 ,|
σ(
z)|
2=
λ21λ22andλ21,λ22are the roots of
m
(
X;z) =
X2−
2ρ(
z)
X+
|
σ(
z)|
2.The realsλ1,λ2are called singular values of z; in particular,λ1is the Lie
Polar coordinates
An element z
∈
V is called regular if its singular valuesλ1,λ2 satisfyλ1
>
λ2>
0.The polar decomposition of a regular element is unique.
The set Vregof regular elements
Vreg
=
{
z∈
V|
0<
|
σ(
z)| <
ρ(
z)}
is an open dense subset of V .
Let
C2
=
λ= (
λ1, λ2) ∈
R2|
λ1>
λ2>
0 ,Σ2
=
λ
= (
λ1, λ2) ∈
R2|
1>
λ1>
λ2>
0 .The polar coordinates mapΨ :C2
× F →
Vregdefined by Ψ(
λ1, λ2;e1,e2) =
λ1e1+
λ2e2is a diffeomorphism.Its restrictionΨ : Σ2
× F →
Ln∩
Vregis a diffeomorphism onto the open dense subset of regular points in Ln.Polar coordinates
An element z
∈
V is called regular if its singular valuesλ1,λ2 satisfyλ1
>
λ2>
0.The polar decomposition of a regular element is unique.
The set Vregof regular elements
Vreg
=
{
z∈
V|
0<
|
σ(
z)| <
ρ(
z)}
is an open dense subset of V . Let
C2
=
λ= (
λ1, λ2) ∈
R2|
λ1>
λ2>
0 ,Σ2
=
λ
= (
λ1, λ2) ∈
R2|
1>
λ1>
λ2>
0 .The polar coordinates mapΨ :C2
× F →
Vregdefined byΨ
(
λ1, λ2;e1,e2) =
λ1e1+
λ2e2is a diffeomorphism.Its restrictionΨ : Σ2
× F →
Ln∩
Vregis a diffeomorphism onto theLinear automorphisms of L
nG
=
Aut Ln, the group of biholomorphic automorphisms of Ln.K
=
G0= {
u∈
G|
u(
0) =
0}
.Proposition. The elements of K are the linear endomorphisms
u
∈
EndCV which preserve the Lie norm; u∈
K if and only ifu
(
z) =
αev(
z)
,where αis a complex number,
|
α| =
1, andev is the C-linear extension toCompactification of V
Notations. W=
C2⊕
V, W 0=
R2⊕
V0. An element w∈
W is written w=
w1ε1+
w2ε2+
w0, w1,w2∈
C, w0∈
V . Quadratic form on W : S(
w) =
w12+
w22+
σ(
w0)
(
w∈
W)
.Indefinite Hermitian form with signature
(
2,n)
on W :h
w,ti =
w1t1+
w2t2− (
w0|
t0)
(
w,t∈
W)
, R(
w) =
h
w,wi =
w1 2+
w2 2−
ρ(
w0)
(
w∈
W)
. Complex quadric: Qn=
{[
w] ∈
PC(
W) |
q(
w) =
0}
.Compactification of V
Letξe:V
→
W be the real-analytic mape
ξ
(
z) = (
1+
σ(
z))
ε1+
i(
1−
σ(
z))
ε2+
2 i z(
z∈
V)
. Compactification of V : ξ :V→
Qnξ
(
z) = [
ξe(
z)]
(
z∈
V)
.Proposition. The map ξis a biholomorphism of V onto the open dense
subset ξ
(
V)
of Qnξ
(
V) =
[
w] ∈
Qn|
w2+
i w1 ,0 . The inverse map is given byξ−1
([
w]) =
w0
Compactification of V
Letξe:V
→
W be the real-analytic mape
ξ
(
z) = (
1+
σ(
z))
ε1+
i(
1−
σ(
z))
ε2+
2 i z(
z∈
V)
. Compactification of V : ξ :V→
Qnξ
(
z) = [
ξe(
z)]
(
z∈
V)
.Proposition. The map ξis a biholomorphism of V onto the open dense
subset ξ
(
V)
of Qnξ
(
V) =
[
w] ∈
Qn|
w2+
i w1 ,0 .The inverse map is given by
ξ−1
([
w]) =
w 0Compactification of V
Let z∈
V . Then R e ξ(
z)
=
2 1−
2ρ(
z) +
|
σ(
z)|
2 . Proposition. Let U+⊂
Qn be defined byU
=
{[
w] ∈
Qn|
R(
w) >
0}
.Then U+has two connected components U0+, U+1 such that ξ
(
Ln) =
U+0.If z
∈
V has the polar decomposition z=
λ1e1+
λ2e2, thenRξe
(
z)
=
2(
1−
λ21)(
1−
λ22)
.Compactification of V
Let z∈
V . Then R e ξ(
z)
=
2 1−
2ρ(
z) +
|
σ(
z)|
2 .Proposition. Let U+
⊂
Qn be defined byU
=
{[
w] ∈
Qn|
R(
w) >
0}
.Then U+has two connected components U0+, U+1 such that ξ
(
Ln) =
U+0.If z
∈
V has the polar decomposition z=
λ1e1+
λ2e2, thenRξe
(
z)
=
2(
1−
λ21)(
1−
λ22)
.Compactification of V
Let z∈
V . Then R e ξ(
z)
=
2 1−
2ρ(
z) +
|
σ(
z)|
2 .Proposition. Let U+
⊂
Qn be defined byU
=
{[
w] ∈
Qn|
R(
w) >
0}
.Then U+has two connected components U0+, U+1 such that ξ
(
Ln) =
U+0.If z
∈
V has the polar decomposition z=
λ1e1+
λ2e2, thenRξe
(
z)
=
2(
1−
λ21)(
1−
λ22)
.Automorphisms of L
nLet M:W
→
W be an invertible endomorphism of W . The mapΦM :PC
(
W) →
PC(
W)
defined byΦM
([
w]) = [
Mw]
(
w∈
W)
is then a biholomorphic automorphism ofPC
(
W)
.If M
∈
O(
W,S)
(the complex orthogonal group of S), thenΦMrestricts to a biholomorphism of the quadric Qn.
If moreover M
∈
U(
W,R)
(the unitary group of the indefinite Hermitian form R), thenΦM(
U+) =
U+, andΦM U0+=
U+0 or ΦM U0+=
U1+. Let w0=
ξ(
0)
; ifΦM(([
w0]) ∈
U0+, thenΦM U0+=
U0+and ΨM=
ξ−1◦
ΦM◦
ξ∈
Aut Ln.O
(
W,S) ∩
U(
W,R) '
O(
W0,R0)
(the real orthogonal group of theAutomorphisms of L
nLet M:W
→
W be an invertible endomorphism of W . The mapΦM :PC
(
W) →
PC(
W)
defined byΦM
([
w]) = [
Mw]
(
w∈
W)
is then a biholomorphic automorphism ofPC
(
W)
.If M
∈
O(
W,S)
(the complex orthogonal group of S), thenΦMrestricts to a biholomorphism of the quadric Qn.
If moreover M
∈
U(
W,R)
(the unitary group of the indefinite Hermitian form R), thenΦM(
U+) =
U+, andΦM U0+=
U+0 or ΦM U0+=
U1+. Let w0=
ξ(
0)
; ifΦM(([
w0]) ∈
U0+, thenΦM U0+=
U0+and ΨM=
ξ−1◦
ΦM◦
ξ∈
Aut Ln.O
(
W,S) ∩
U(
W,R) '
O(
W0,R0)
(the real orthogonal group of theAutomorphisms of L
nLet M:W
→
W be an invertible endomorphism of W . The mapΦM :PC
(
W) →
PC(
W)
defined byΦM
([
w]) = [
Mw]
(
w∈
W)
is then a biholomorphic automorphism ofPC
(
W)
.If M
∈
O(
W,S)
(the complex orthogonal group of S), thenΦMrestricts to a biholomorphism of the quadric Qn.
If moreover M
∈
U(
W,R)
(the unitary group of the indefiniteHermitian form R), thenΦM
(
U+) =
U+, andΦM U0+=
U+0 orΦM U0+
=
U1+. Let w0=
ξ(
0)
; ifΦM(([
w0]) ∈
U0+, thenΦM U0+=
U0+and ΨM=
ξ−1◦
ΦM◦
ξ∈
Aut Ln.O
(
W,S) ∩
U(
W,R) '
O(
W0,R0)
(the real orthogonal group of theAutomorphisms of L
nLet M:W
→
W be an invertible endomorphism of W . The mapΦM :PC
(
W) →
PC(
W)
defined byΦM
([
w]) = [
Mw]
(
w∈
W)
is then a biholomorphic automorphism ofPC
(
W)
.If M
∈
O(
W,S)
(the complex orthogonal group of S), thenΦMrestricts to a biholomorphism of the quadric Qn.
If moreover M
∈
U(
W,R)
(the unitary group of the indefiniteHermitian form R), thenΦM
(
U+) =
U+, andΦM U0+=
U+0 orΦM U0+
=
U1+. Let w0=
ξ(
0)
; ifΦM(([
w0]) ∈
U0+, thenΦM U0+=
U0+and ΨM=
ξ−1◦
ΦM◦
ξ∈
Aut Ln.O
(
W,S) ∩
U(
W,R) '
O(
W0,R0)
(the real orthogonal group of theAutomorphisms of L
nLet M:W
→
W be an invertible endomorphism of W . The mapΦM :PC
(
W) →
PC(
W)
defined byΦM
([
w]) = [
Mw]
(
w∈
W)
is then a biholomorphic automorphism ofPC
(
W)
.If M
∈
O(
W,S)
(the complex orthogonal group of S), thenΦMrestricts to a biholomorphism of the quadric Qn.
If moreover M
∈
U(
W,R)
(the unitary group of the indefiniteHermitian form R), thenΦM
(
U+) =
U+, andΦM U0+=
U+0 orΦM U0+
=
U1+. Let w0=
ξ(
0)
; ifΦM(([
w0]) ∈
U0+, thenΦM U0+=
U0+and ΨM=
ξ−1◦
ΦM◦
ξ∈
Aut Ln.O
(
W,S) ∩
U(
W,R) '
O(
W0,R0)
(the real orthogonal group of theAutomorphisms of L
nLet
(
f1,. . . ,fn)
be an orthonormal basis for the Euclidean space V0. Then(
ε1, ε2,f1,. . . ,fn)
is anR-basis for W0and aC-basis for W . Wewill identify an endomorphism of W0 or W with its matrix in this basis.
The matrix of the quadratic form R0in this basis is
I2,n
=
diag(
I2,−
In)
. So M∈
O(
W0,R0)
iff M is real and satisfies MI2,nM0=
I2,n. Write M=
A B C D , with A∈ M
2,2(
R)
, B∈ M
2,n(
R)
, C∈ M
n,2(
R)
, D∈ M
n,n(
R)
. Then M∈
O(
W0,R0)
iff AA0−
BB0=
I2, CA0−
DB0=
0, CC0−
DD0= −
In.Automorphisms of L
nLet M as above. For z
∈
Ln,ΨM
(
z) =
w0 i w1+
w2 , with w1 w2 =
A 1+
σ(
z)
i(
1−
σ(
z))
+
2 i Bz, w0=
C 1+
σ(
z)
i(
1−
σ(
z))
+
2 i Dz.Automorphisms of L
n In particular, ΨM(
0) =
(
i,1)
A 1 i −1 C 1 i . If we write A=
α β γ δ and C
= (
C1,C2)
, this is equivalent toΨM
(
0) =
C1
+
i C2 iα−
β+
γ−
iδ.Automorphisms of L
nBergman kernel of L
nNotations
β0
(
z) =
2πi ∂∂(
z|
z)
,ω0=
βn0A2
(
Ln) =
Hol Ln∩
L2(
Ln, ω0)
, Bergman space of Ln , with Hilbertproduct
(
f|
g)
A2(L n)=
R
Lnf gω0
K
(
z,t)
, Bergman kernel of Ln, reproducing kernel for A2(
Ln)
:f
(
z) =
R
LnK
(
z,t)
f(
t)
ω0(
t)
(f∈
A2
(
L n)
) Transformation law: forφ∈
Aut Ln,Bergman kernel of L
nLet z
∈
Ln andφ∈
Aut Ln such thatφ(
0) =
z. By the transformationlaw, K
(
z,z) =
K(
0,0)
|
Jφ(
0)|
2 . As Ln is circled, K(
0,t) =
K(
0,0) =
Z Ln ω0 −1 .Bergman kernel of L
nProposition. Let φ
∈
Aut Lnsuch that φ(
0) =
z. Then|
Jφ(
0)|
2=
1
−
2ρ(
z) +
|
σ(
z)|
2n .
Theorem. The Bergman kernel of Ln is equal to
K
(
z,t) =
K(
0,0)
1
−
2(
z|
t) +
σ(
z)
σ(
t)
Bergman metric of L
nThe Bergman metric of Ln is defined by
hz
(
u,v) =
∂u∂vlog K(
z,z)
.The hyperbolic symplectic form associated to the Bergman metric is
β
(
z) =
i2∂∂log K
(
z,z)
. It is related to the Hermitian metric byβ
(
z)(
u,v) = −
Im hz(
u,v)
.The Bergman metric is an Hermitian metric on Ln, invariant by Aut Ln:
forφ
∈
Aut Ln such thatφ(
z) =
0,Computation of the Bergman metric of L
n K(
z,z) =
K(
0,0)
1−
2(
z|
z) +
σ(
z)
σ(
z)
n ∂vlog K(
z,z) =
2n(
z|
v) −
σ(
z)(
z:v)
1−
2(
z|
z) +
σ(
z)
σ(
z)
hz(
u,v) =
2n(
u|
v) −
2(
z:u)(
z:v)
1−
2(
z|
z) +
σ(
z)
σ(
z)
+
4n(
z|
v) −
σ(
z)(
z :v)
(
u|
z) − (
z:u)
σ(
z)
1−
2(
z|
z) +
σ(
z)
σ(
z)
2 .Bergman metric of L
nThe Bergman metric at 0 is
h0
(
u,v) =
2n(
u|
v)
. Let z=
λ1e1+
λ2e2∈
Ln. Let V11=
Ce1, V22=
Ce2, V12= (
V11⊕
V22)
⊥. For u=
u1+
u2+
u0, u1∈
Ce1, u2∈
Ce2, u0∈
V12, hz(
u,u) =
2n(
u1|
u1)
(
1−
λ21)
2+
(
u2|
u2)
(
1−
λ22)
2+
(
u 0|
u0)
(
1−
λ21)(
1−
λ22)
.Bergman operator of L
nThe Bergman operator B
(
z,z)
(z∈
Ln) is the complex linearoperator, such that
hz
(
u,v) =
h0(
B(
z,z)
−1u,v)
(
z∈
Ln, u,v∈
V=
Cn)
.The Bergman operator for Ln is
B
(
z,z)
u=
(
1−
λ21)
2u ifu∈
Ce1,(
1−
λ22)
2u ifu∈
Ce2,(
1−
λ21)(
1−
λ22)
u ifu∈
V12.Part I. Examples of bounded symmetric domains
1 The unit disc ofC
2 The Hermitian ball ofCn
3 The Lie ball
Type I
m,nRectangular matrices
Domains of type Im,n
Let 1
≤
m≤
n, V= M
m,n(
C)
(space of m×
n matrices with complexentries) and
Ω
=
{
Z∈
V|
Im−
ZZ∗ 0}
.Lemma. Let Z
∈
V . There exist λ1≥ · · · ≥
λm≥
0 and unitary matricesP
∈
U(
m)
, Q∈
U(
n)
such that Z=
P λ1 0 0 0 0 0 . .. . .. 0 0 λm 0 0 Q−1.Type I
m,nRectangular matrices
Then Z
∈
Ωif and only ifλ1<
1, that is, if.dk d Tk det
(
TIm−
ZZ ∗)
T=1>
0(
0≤
k≤
m−
1)
. Boundary ofΩ: ∂Ω=
m [ j=1 ∂jΩ, where Z∈
∂jΩifλ1= · · · =
λj=
1>
λj+1.Type I
m,nRectangular matrices
Automorphisms. Let M=
A B C D be an(
m+
n) × (
m+
n)
matrix, with A m×
m, B m×
n, . . . If MJm,nM∗=
Jm,n(whereJm,n
=
diag(
Im,−
In)
), thenΦM defined byΦM
(
Z) = (
AZ+
B)(
CZ+
D)
−1provides an automorphism ofΩ.
The automorphism group acts transitively onΩ.
Bergman kernel. The Bergman kernel ofΩis
K(
Z,W) =
K(
0,0)
det
(
Im−
ZZ∗)
m+nType III
nSymmetric matrices
For n
≥
1, V= S
n(
C)
(space of n×
n symmetric matrices),Ω
=
Z
∈
V|
In−
Z Z 0 .Bergman kernel. The Bergman kernel ofΩis
K(
Z,W) =
K(
0,0)
det
(
Im−
Z Z)
n+1Type II
nAlternating matrices
For n
≥
2, V= A
n(
C)
(space of n×
n antisymmetric matrices),Ω
=
Z
∈
V|
In+
Z Z 0 .Bergman kernel. The Bergman kernel ofΩis
K(
Z,W) =
K(
0,0)
det
(
Im+
Z Z)
n−1Jordan triples in analysis on bounded symmetric
domains
Guy Roos St Petersburg [email protected] Hsinchu, Taiwan 2010/04/08-12Part II. Hermitian Jordan triples and bounded symmetric
domains
1 Complex bounded symmetric domains
2 Jordan triple associated to a bounded symmetric domain 3 Spectral theory
4 Minimal polynomial and quasi-inverse 5 Simple Jordan triples
6 Boundary structure 7 Compactification
Bounded symmetric domains
A bounded domainΩ
⊂
V'
Cnis called symmetric if for each x∈
Ωthere is an involutive holomorphic automorphism sx(sx2
=
idΩ) such that xis an isolated fixed point of sx.
Bounded symmetric domains are homogeneous (under the group AutΩof holomorphic automorphisms).
Any bounded symmetric domainΩis biholomorphic to a bounded circled homogeneous domains, which is unique up to linear isomorphisms and is called the circled realization ofΩ.
We will always consider bounded symmetric domains in their circled realization.
A bounded symmetric domain is called irreducible if it is not equivalent to the direct product of two bounded symmetric domains.
Bounded symmetric domains
A bounded domainΩ
⊂
V'
Cnis called symmetric if for each x∈
Ωthere is an involutive holomorphic automorphism sx(sx2
=
idΩ) such that xis an isolated fixed point of sx.
Bounded symmetric domains are homogeneous (under the group AutΩof
holomorphic automorphisms).
Any bounded symmetric domainΩis biholomorphic to a bounded circled homogeneous domains, which is unique up to linear isomorphisms and is called the circled realization ofΩ.
We will always consider bounded symmetric domains in their circled realization.
A bounded symmetric domain is called irreducible if it is not equivalent to the direct product of two bounded symmetric domains.
Bounded symmetric domains
A bounded domainΩ
⊂
V'
Cnis called symmetric if for each x∈
Ωthere is an involutive holomorphic automorphism sx(sx2
=
idΩ) such that xis an isolated fixed point of sx.
Bounded symmetric domains are homogeneous (under the group AutΩof
holomorphic automorphisms).
Any bounded symmetric domainΩis biholomorphic to a bounded circled
homogeneous domains, which is unique up to linear isomorphisms and is
called the circled realization ofΩ.
We will always consider bounded symmetric domains in their circled realization.
A bounded symmetric domain is called irreducible if it is not equivalent to the direct product of two bounded symmetric domains.
Bounded symmetric domains
A bounded domainΩ
⊂
V'
Cnis called symmetric if for each x∈
Ωthere is an involutive holomorphic automorphism sx(sx2
=
idΩ) such that xis an isolated fixed point of sx.
Bounded symmetric domains are homogeneous (under the group AutΩof
holomorphic automorphisms).
Any bounded symmetric domainΩis biholomorphic to a bounded circled
homogeneous domains, which is unique up to linear isomorphisms and is
called the circled realization ofΩ.
We will always consider bounded symmetric domains in their circled realization.
A bounded symmetric domain is called irreducible if it is not equivalent to the direct product of two bounded symmetric domains.
Classification of bounded symmetric domains
Type Im,n
(
1≤
m≤
n)
. V= M
m,n(
C)
(space of m×
n matrices withcomplex entries).
Ω
=
x
∈
V|
Im−
xtx 0 .Type IIn
(
n≥
2)
V= A
n(
C)
(space of n×
n alternating matrices).Ω
=
{
x∈
V|
In+
xx 0}
.Type IIIn
(
n≥
1)
. V= S
n(
C)
(space of n×
n symmetric matrices).Ω
=
{
x∈
V|
In−
xx 0}
.Type IVn
(
n>
2)
. V=
Cn,σ(
x) =
∑xi2, ρ(
x) =
∑|
xi|
2. The domainΩisdefined by
1
−
2ρ(
x) +
|
σ(
x)|
2>
0, 1−
ρ(
x) >
0.Type V . V
= M
2,1(
OC) '
C16, exceptional type.References
Cartan, ´Elie. Sur les domaines born ´es homog `enes de l’espace de n variables complexes. Abh. Math. Sem. Univ. Hamburg, 11 (1935), 1–114.
Helgason, Sigurdur. Differential geometry, Lie groups, and symmetric spaces. Pure and Applied Mathematics, 80. Academic Press, Inc. [Harcourt Brace Jovanovich, Publishers], New York-London, 1978. xv+628 pp. ISBN: 0-12-338460-5 MR0514561 (80k:53081)
Satake I. Algebraic Structures of Symmetric Domains, Iwanami Shoten and Princeton University Press, 1980.
References
Loos, Ottmar. Bounded symmetric domains and Jordan pairs, Math. Lectures, Univ. of California, Irvine, 1977.
Roos, Guy. Jordan triple systems, pp. 425–534, in J. Faraut,
S. Kaneyuki, A. Kor ´anyi, Q.k. Lu, G. Roos, Analysis and geometry on complex homogeneous domains, Progress in Mathematics, vol.185, Birkh ¨auser, Boston, 2000.
Roos, Guy. Exceptional symmetric domains. Symmetries in complex analysis, 157–189, Contemp. Math., 468, Amer. Math. Soc.,
Part II. Hermitian Jordan triples and bounded symmetric
domains
1 Complex bounded symmetric domains
2 Jordan triple associated to a bounded symmetric domain 3 Spectral theory
4 Minimal polynomial and quasi-inverse 5 Simple Jordan triples
6 Boundary structure 7 Compactification
Automorphism group
LetΩbe a bounded circled homogeneous domain in a complex vector
space V .
Then the automorphism group AutΩis a real Lie group. Denote by
G
= (
AutΩ)
0its identity component and byK
=
G0=
{
g∈
G|
g(
0) =
0}
.Automorphism group
Letω be a volume form on V , invariant by K and by translations. Let
K(
z)
be the Bergman kernel ofΩwith respect toωand let
hz
(
u,v) =
∂u∂vlogK(
z)
be its Bergman metric at z
∈
Ω. The Bergman metric is invariant by theautomorphisms ofΩ: for g
∈
G,hz
(
u,v) =
hg(z)(
g0(
z) ·
u,g0(
z) ·
v)
(
u,v∈
V, z∈
Ω)
.For g
∈
K , this impliesh0
(
u,v) =
h0(
gu,gv)
(
u,v∈
V)
.Infinitesimal automorphisms
A vector field onΩis a mapξ :Ω
→
V . The Lie bracket of two suchvector fields is defined by
[
ξ, η](
z) =
ξ0(
z) ·
η(
z) −
η0(
z) ·
ξ(
z)
.A one parameter subgroup
(
gt)
t∈Rof G will be identified with theholomorphic vector field
ξ
(
z) =
d d t(
gt(
z)
t=0 .These vector fields form the Lie algebragof G.
Theorem. The elements ξ of gare the vector fieds
ξ
(
z) =
Uz+
v−
Q(
z)
v,where U
∈
Lie K , v∈
V and Q:V→
EndCV is a quadratic map withvalues inC-linear endomorphisms of V .
Jordan triple associated to a bounded symmetric domain
Let Q
(
x,z) =
Q(
x+
z) −
Q(
x) −
Q(
z)
and define the triple product{
x,y,z} =
Q(
x,y)
z(
x,y,z∈
V)
.For x,y
∈
V , denote by D(
x,y)
theC-linear operator defined byD
(
x,y)
z= {
xyz}
(
z∈
V)
.For v
∈
V , denote byξvthe vector fieldJordan triple associated to a bounded symmetric domain
Proposition. The following identities hold:
[
ξu, ξv] =
D(
u,v) −
D(
v,u)
,[[
ξu, ξv]
, ξw] =
ξ{u,v,w}−{v,u,w},[
D(
u,v)
,D(
x,y)] =
D({
uvx}
,y) −
D(
x,{
vuy}
,Hermitian Jordan triples
The triple product
(
x,y,z) 7→ {
xyz}
is complex bilinear and symmetricwith respect to
(
x,z)
, complex antilinear with respect to y. It satisfies the Jordan identity{
xy{
uvw}} − {
uv{
xyw}} = {{
xyu}
vw} − {
u{
vxy}
w}
. (J)Definition. The space V endowed with the triple product
{
xyz}
verifying the identity (J) is called an Hermitian Jordan triple.Bergman operator
Let
(
V,{
, ,})
be an Hermitian Jordan triple. The mapQ :V
−→
EndR(
V)
defined by Q(
x)
y=
12{
xyx}
is called.quadraticrepresentation . The Bergman operator B is defined by
B
(
x,y) =
idV−
D(
x,y) +
Q(
x)
Q(
y)
(
x,y∈
V)
.The quadratic representation and the Bergman operator satisfy to many identities; the most important of these are
Q
(
Q(
x)
y) =
Q(
x)
Q(
y)
Q(
x)
,Bergman operator
Theorem. Let Ω
⊂
V be a bounded circled homogeneous domain and let(
V,{
, ,})
be the associated Jordan triple. ThenThe Bergman kernel of Ωis
K(
z) =
1volΩ
1 det B
(
z,z)
.The Bergman metric at 0 is h0
(
u,v) =
tr D(
u,v)
.The Bergman metric at z
∈
Ωishz
(
u,v) =
h0(
B(
z,z)
−1u,v)
(
z∈
Ω; u,v∈
V)
.The Jordan triple product on V is characterized by h0
({
uvw}
,t) =
∂u∂v∂w∂tlogK(
z)
|
z=0 . Definition. A Jordan triple system is called Hermitian positive if(
u|
v) =
tr D(
u,v)
is positive definite.As the Bergman metric of a bounded domain is always definite positive, the Jordan triple associated to a bounded symmetric domain is Hermitian positive.