Advanced Engineering Mathematics, by Erwin Kreyszig 10th. Ed.
Problem Set 6.7
No. 1
No. 2
y1'−y2=0, y1+y2'=2cos t , y1(0)=1, y2(0)=0
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s) sY1(s)−y1(0)−Y2(s)=1
Y1(s)+sY2(s)−y2(0)= 2 s
s2+1 Replace y1(0)=1, y2(0)=0 sY1(s)−Y2(s)=1
Y1(s)+sY2(s)= 2 s
s2+1
× s+ (s2+1)Y1( s)=s+ 2s
s2+1
Y1(s )= s
s2+1+ 2 s
(s2+1)2
Then from Y2(s)=sY1(s )−1= s2
s2+1+ 2s2
(s2+1)2−1=−
1
s2+1+ 2s2
(s2+1)2
Using (3) of sec.6.6 ℒ-1
{
(s2+βs 2)2}
=2βt sin βty1(t )=cost +2 t2 sin t=cost+t sin t In this case β=1
And using (4) of sec.6.6 ℒ-1
{
(s2+s2β2)2}
=2 β1 (sin βt+βt cosβt)y2(t )=−sin t+22(sin t+t cost )=−sin t+sin t+t cost=t cost In this case β=1
No. 3
y1'−2 y1+3 y2=0, y2'−y1+2 y2=0, y1(0)=1, y2(0)=0
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s) sY1(s)−y1(0)−2 Y1(s)+3 Y2(s)=0 sY2(s)−y2(0)−Y1(s)+2 Y2(s)=0
Replace y1(0)=1, y2(0)=0 (s−2)Y1(s)+3 Y2(s)=1
−Y1(s)+(s+2)Y2(s)=0
×( s+2)- × 3 (s2−4 +3)Y1( s)=s+ 2
Y1(s)= s+2
s2−1 Then from Y2(s)=s+21 Y1(s)= 1
s2−1
Furthermore Y1(s)=s+2
s2−1=
3 2
s−1−
1 2
s+1
Y2(s)= 1
s2−1=
1 2
s−1−
1 2
s+1
y1(t )=32et−12e−t=12et+12e−t+2(12et−12e−t)=cosht +2 sinh t
y2(t)=12et−12e−t=sinht
No. 4
y1'=4 y2−8cos 4t , y2'=−3 y1−9sin 4t , y1(0)=0, y2(0)=3
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s)
sY1(s)−y1(0)=4Y2(s)− 8 s
s2+16
sY2(s)−y2(0)=−3Y1(s)− 36
s2+16 Replace y1(0)=0, y2(0)=3
sY1(s)−4Y2(s)=− 8 s
s2+16
3Y1(s)+sY2(s)=3− 36
s2+16
× s+ × 4 (s2+12)Y1( s)=− 8 s2
s2+16+12−144 s2+16
(s2+12)Y1( s)=−8s2+12 s2+192−144
s2+16 (s2+12)Y1(s)=4 s2+48
s2+16=4(s2+12)
s2+16
Y1(s)= 4
s2+16
×3- × s
(−12−s2)Y2(s)=− 24 s
s2+16−3 s+36 s
s2+16=−24 s−3 s3−48s+36s
s2+16 =−36 s−3s3
s2+16 =3s(−12−s2)
s2+16 Y2(s)= 3 s
s2+16 y1(t)=sin 4 t y2(t)=3 cos4 t No. 5
y1'=y2+2−u(t−1) , y2'=−y1+1−u(t−1), y1(0)=1, y2(0)=0
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s)
sY1(s )− y1(0 )=Y2( s)+2s−e−s s sY2(s )− y2(0 )=−Y1( s)+1s−e−s
s Replace y1(0)=1, y2(0)=0
sY1(s )−Y2(s )=1+2s−e−s s Y1(s )+ sY2(s )=1s−e−s
s
× s+ (s2+1)Y1(s)=s +2−e−s+1s−e−s
s =2+s2+1
s −(s+1s )e−s
Y1(s)= 2
s2+1+1
s− s+1 s(s2+1)e
−s
= 2
s2+1+1
s−
(
1s−ss−12+1)
e−s=s22+1+1s−
(
1s−s2s+1+ 1 s2+1)
e−s- × s
(−1−s2)Y2(s)=1+2s−e−s
s −1+e−s=2 s−e−s
s +e−s
Y2(s)=− 2
s(s2+1)+
[
−s21+1+s(s12+1)]
e−s=−2s +s2s2+1+(
−s21+1+1s−s2s+1)
e−sy1(t)=1+2 sint−[1−cos(t−1)+sin(t−1)]u(t−1)
y2(t)=−2+2 cos t+[1−sin(t −1)−cos(t−1)]u(t−1)
No. 6
y1'=5 y1+y2, y2'=y1+5 y2, y1(0)=1, y2(0)=−3
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s) sY1(s)−y1(0)=5 Y1(s)+Y2(s)
sY2(s)−y2(0)=Y1(s)+5 Y2(s)
Replace y1(0)=1, y2(0)=−3 sY1(s)−5 Y1(s)−Y2(s)=1 (s−5)Y1(s)−Y2(s)=1
−Y1(s)+sY2(s)−5 Y2(s)=−3 −Y1(s)+(s−5)Y2(s)=−3
×( s-5)+ [(s−5)2−1]Y1(s)=s−5−3
Y1(s)= s−8
(s2−10s+24)= 2
s−4− 1 s−6
+ ×( s-5)
[−1+(s−5)2]Y2(s)=1−3s+15=−3 s+16
Y2(s)= −3 s+16
(s2−10 s+24)= −2 s−4− 1
s−6 y1(t )=2e4t−e6t
y2(t )=−2e4 t−e6t
No. 7
y1'=2 y1−4 y2+u(t−1) et, y2'=y1−3 y2−u(t−1) et, y1(0)=3, y2(0)=0
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s)
sY1(s )− y1(0 )=2 Y1(s )−4 Y2( s)+e e−s s−1 sY2(s )− y2(0 )=Y1(s )−3 Y2( s )−e e−s
s−1 Replace y1(0)=3, y2(0)=0
sY1(s )−2 Y1( s)+4 Y2(s )=3+e e−s
s−1 (s−2) Y1( s)+4 Y2(s)=3+ e e−s s−1
−Y1(s )+sY2(s )+3 Y2(s )=−e e−s
s−1 −Y1(s )+( s+3) Y2( s)=−e e−s s−1
× (s+3)-×4 [(s−2) ( s+3)+ 4]Y1( s)=
(
3+es−1e−s)
( s+3 )+ 4 e e−s s−1(s2+s−2)Y1(s )=3 s+9+(s−1s+7)ee−s
Y1(s )= 3 s+9
(s−1) (s+2)+ (s+7)
(s−1)2(s+2)ee−s= 4
s−1− 1
s+2+
[
−(s−1)59s+2299 +s+259]
ee−s=s−14 −s+21 +
[
(s−1)−59 +(s−1)83 2+s+259]
ee−s+×( s-2) [4 +(s +3) (s−2)]Y2(s)=3+es−1e−s −(s−2)e e
−s
s−1
(s2+s−2)Y2(s)=3−(s−3)e e−s s−1
Y2(s)=(s−13) (s+2)− s−3
(s−1)2(s+2)ee−s= 1
s−1− 1
s+2−
[
( s−1)59s−1192−s+259]
ee−s=s−11 −s+21 −
[
s−159 −( s−1)23 2−s+259]
ee−sy1(t )=4 et−e−2t+[−59ee(t−1)+83(t−1)ee( t−1)+59ee−2(t−1)]u(t−1)
=4 et−e−2t+[(83t−299 )et+59e(−2t +3)]u (t−1)
y2(t)=et−e−2t−[59eet−1−23(t−1)eet−1−59ee−2 (t−1)]u(t−1)
=et−e−2 t−[(−23t+119 )et−59e(−2 t+3)]u (t−1)
=et−e−2 t+[(23t−119 )et+59e(−2t+3)]u(t−1 )
No. 8
y1'=−2 y1+3 y2, y2'=4 y1−y2, y1(0)=4 , y2(0)=3
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s) sY1(s)−y1(0)=−2 Y1(s)+3 Y2(s) sY2(s)−y2(0)=4 Y1(s)−Y2(s)
Replace y1(0)=4, y2(0)=3 sY1(s)+2 Y1(s)−3 Y2(s)=4 (s +2)Y1(s)−3 Y2(s)=4
−4 Y1(s)+sY2(s)+Y2(s)=3 −4 Y1(s)+(s +1)Y2(s)=3
×( s+1)+×3 [(s +2) (s+ 1)−12]Y1(s)=4 s +4 +9
Y1(s)= 4 s+13
(s2+3 s−10)= 3 s−2+ 1
s+5
×4+×( s+2)
[−12+(s +2) (s+ 1)]Y2(s)=16+3 s+6=3 s +22
Y2(s)= 3 s+22
(s2+3 s−10)= 4
s−2− 1 s+5 y1(t )=3e2t+e−5t
y2(t )=4 e2 t−e−5 t
No. 9
y1'=y1+y2, y2'=−y1+3 y2, y1(0)=1, y2(0)=0
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s) sY1(s)−y1(0)=Y1(s)+Y2(s)
sY2(s)−y2(0)=−Y1(s)+3 Y2(s)
Replace y1(0)=1, y2(0)=0 sY1(s)−Y1(s)−Y2(s)=1 (s−1)Y1(s)−Y2(s)=1 Y1(s)+sY2(s)−3 Y2(s)=0 Y1(s)+(s−3)Y2(s)=0
×( s-3)+ [(s−1) (s−3)+1]Y1(s)=s−3
Y1(s)= s−3
(s2−4 s+4)=(s−2)−1 (s−2)2 =
1
s−2− 1 (s−2)2
-×( s-1)
[−1−(s−3) (s−1)]Y2(s)=1 Y2(s )=− 1
(s2−4 s+4)=− 1 (s−2)2= y1(t )=e2t−te2 t
y2(t )=−te2t
No. 10
y1'=−y2, y2'=−y1+2[1−u(t−2π )]cost , y1(0)=1, y2(0)=0
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s)
2[1−u (t−2 π )]cost=2 cost−2 u (t−2 π ) cos(t−2 π ) sY1(s)−y1(0)=−Y2(s)
sY2(s )− y2(0 )=−Y1( s)+ 2 s
s2+1−2 se−2 πs
s2+1 Replace y1(0)=1, y2(0)=0
sY1(s)+Y2(s)=1 Y1(s )+ sY2(s )= 2 s
s2+1−2 se−2 πs s2+1
×s- (s2−1)Y1(s )=s− 2 s
s2+1+2 se−2 πs s2+1
Y1(s)= s
(s2−1)− 2 s
(s2−1)(s2+1)+
2se−2 πs
(s2−1) (s2+1)
=
1 2
s−1+
1 2
s+1− s
s2−1+ s
s2+1+
(
s2−1s − ss2+1
)
e−2πs=
1 2
s−1+
1 2
s+1−
1 2
s−1−
1 2
s+1+ s
s2+1+
(
s−112 +s+112 −s2s+1)
e−2πs= s
s2+1+
(
s−112 +s+112 −s2s+1)
e−2 πs-×s
(1−s2)Y2(s)=1− 2s2
s2+1+2 s2e−2 πs
s2+1 =−(s2−1)
s2+1 +2s2e−2πs s2+1
Y2(s)= 1
s2+1− 2s2e−2 πs
(s2−1)(s2+1)
= 1
s2+1−
(
s2−11 + 1s2+1
)
e−2 πs= 1
s2+1−
(
s−112 −s+112 +s21+1)
e−2πsy1(t )=cos t +[12e( t−2 π)+12e−(t −2 π )−cos(t−2 π )]u (t−2 π )
=cos t+[cosh (t−2 π )−cos t]u (t−2 π )
y2(t )=14et−14e−t+12sint−[12e( t −2 π )−12e−(t−2 π )+sin (t−2 π )]u (t−2 π )
=sin t−[sinh (t−2 π )+sin t]u (t−2 π )
No. 11
y1} } =y rSub { size 8{1} } +3y rSub { size 8{2} } ,y rSub { size 8{2} } rSup { size 8{
=4 y1−4et, y1(0)=2, y1'(0)=3, y2(0)=1, y2'(0)=2
Writing ℒ {y1}=Y1(s),
ℒ {y2}=Y2(s)
s2Y1(s)−sy1(0)− y1'(0)=Y1(s)+3Y2(s)
s2Y2(s)−sy2(0)−y2'(0)=4Y1(s)−s−14 Replace
y1(0)=2, y1'(0)=3, y2(0)=1, y2'(0)=2 (s2−1)Y1(s)−3 Y2( s)=2 s+3
−4Y1(s)+s2Y2(s)=s+2−s−14
× s2 +×3
[s2(s2−1)−12]Y1(s)=(2s+3)s2+3s+6−s−112 =2 s3+3s2+3s+6−s−112
Y1(s)=2 s3+3 s2+3 s+6 s4−s2−12−12
(s4−s2−12)(s−1)
= 2 s3+3 s2+3 s+6
(s2−4)(s2+3)−
12
(s2−4)(s2+3)(s−1)
=
11 7s+187
s2−4+
3 7s+37
s2+3 −
(
47s2s+−447+3 7s+37 s2+3 − 1
s−1
)
= s+2
s2−4+ 1 s−1= 1
s−2+ 1 s−1
×4+× (s2−1) [−12+s2(s2−1)]Y2( s )=8 s +12+(s2−1)(s+2−s−14 )
(s4−s2−12)Y2(s)=8s+12+s3−s+2s2−2−4(s2−1) s−1