Jhen-Syuan Huang, Prof. Chin-Hsiang Cheng Date : 2016/08/25
Department of Aeronautics and Astronautics,
National Cheng Kung University, Tainan, Taiwan
Introduction
Prototypes and experimental apparatus
Theoretical model
Results and discussion
Conclusions
Ringbom Beta-type
Alpha-type Thermal-lag Free-piston
Stirling cooler
Stirling engine
Rotation Speed (r.p.m.)
Power(W) Temperature(°C)
1000 1500 2000
400 600 800 1000 1200 1400 1600
0 200 400 600 800 1000 1200 1400 1600
Power Heating Temp.
Expansion chamber Temp.
Reg. chamber entrance Temp.
Reg. chamber exit Temp.
Cooler Temp.
Solar tracker
10.75 kW@1000 W/m
2Diameter:3.7m
1.5 kW beta-type Stirling engine
CFD analysis
(Temperature variation) Stress analysis
(Von-Mises stress)
Volume [cm3]
Pressure[atm]
0 100 200 300 400 500 600
6 8 10 12 14
16 ω = 600 rpm
ω = 800 rpm ω = 900 rpm ω = 950 rpm ω = 1000 rpm ω = 1050 rpm ω = 1200 rpm
Volume [cm3]
Pressure[atm]
0 100 200 300 400 500
6 8 10 12 14 16
ω = 600 rpm ω = 800 rpm ω = 900 rpm ω = 950 rpm ω = 1000 rpm ω = 1050 rpm ω = 1200 rpm
Time (s)
EquivalentStress(MPa)
0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 0.22 0.24 0
100 200 300 400 500 600
700 Allowable Stress
Piston
90K
t (sec) Twe1,Twe2(K)
0 1000 2000 3000
50 100 150 200 250 300
Exp.
Num.
Twe2=82K Twe1=156K (ζ1=12,ζ2=17)
Two-stage beta-type Stirling cooler
One-stage beta-type Stirling cooler
t (sec)
T(K)
0 200 400 600 800 1000
100 150 200 250 300
Split Stirling cooler
(Helium、5atm、2000rpm)
103K
Twe(K)
C.O.P.
50 100 150 200 250
0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2
Exp.
Num.
Ikuda et al. [23] (FPSC)
Park et al. [24] (FPSC/12.5atm,50Hz) present (STSC/3atm,1600rpm)
Heating power
Engine
Cooling power
Cooler
Stirling engine Stirling cooler
Mechanical power
Engine speed (rpm)
Shaftpower(W)
0 500 1000 1500 2000 2500 3000 3500
0 100 200 300 400 500 600 700 800
Th=800°C Th=700°C Th=600°C Helium, 8 atm
Parameter Value
Bore size × Stroke 35.22 mm × 70 mm Displacer swept volume 135 c.c.
Swept volume ratio 1 Dead volume ratio 1.478 Compression ratio 1.364
Cooling temperature 300 K(liquid cooling)
550 W
Experimental data of shaft power
time (s) Twe(K)
0 50 100 150 200 250 300
50 100 150 200 250 300
Exp.
Num.
Helium, 5atm, 1000rpm
73 K
Parameter Value
Stroke of displacer 20.3 mm Displacer swept volume 5.2 c.c.
Diameter of cold cylinder 19 mm Dead volume ratio 0.35 Compression ratio 2.7
Cooling temperature 300 K(liquid cooling)
Stirling cooler Stiling engine PID controller Vacuum pump
Thermocouple Electric heater
Water circuit
Cold head
Schematic diagram of beta-type Stirling engine Schematic diagram of beta-type Stirling cooler
Ld,c
L1,c
L2,c
Rc
L3,c
L4,c
Lc
Yd,c
Yp,c
θc
Regenerator
Cold head Expansion
chamber
Compression chamber
Dp,c
Dd,c
L2,e
Re L3,e
L4,e
Le
Yd,e
Yp,e
θe
Piston
Displacer Ld,e Expansion
chamber
Compression chamber Regenerator
Heater
Cooler
L1,e Dd,e
Parameters of engine
θe 0 degree
Charged pressure, Pe 5 atm Cooling temperature 300 K Heating temperature 1100 K
Parameters of cooler
θe 0 degree
Charged pressure, Pc 1 atm Cooling temperature 300 K Initial speed 200 rpm
( )
( )
1 2 2 4,
2
, , 3,
1 2 2 1,
2
, , 2,
Position of displacer :
sin cos
2 2
Position of piston :
sin cos
2 2
Volume of expansion chamber :
e e
d e dt e e e e e e
e e
p e pt e e e e e e
ex
L L
Y t L R L R
L L
Y t L R L R
V
θ θ
θ θ
= + − − − −
= + + − − −
2 ,
, , ,
2 ,
, , , ,
( )
4
Volume of compression chamber :
( )
4
d e
e t e d e
p e
co e d e d e p e
D L Y
V D Y L Y
π
π
= −
= − −
For Stirling engine For Stirling cooler
( )
( )
1 2 2 4,
2
, , 3,
1 2 2 1,
2
, , 2,
Position of displacer :
sin cos
2 2
Position of piston :
sin cos
2 2
Volume of expansion chamber :
c c
d c dt c c c c c c
c c
p c pt c c c c c c
ex
L L
Y t L R L R
L L
Y t L R L R
V
θ θ
θ θ
= + − − − −
= + + − − −
2 ,
, , ,
2 2
, ,
, , , , , ,
( )
4
Volume of compression chamber :
( ) ( )
4 4
d c
c t c d c
p c d c
co c cy c p c d c cy c d c
D L Y
D D
V L Y Y L L
π
π π
= −
= − + − −
( )
(
, , , ,)
, , , , , , , , , ,
, , , , , , ,
Pressure variation :
Mass flow rate : , ,
e co e col e ex e hex e
e
co e col e l e l e r e r e h e h e ex e hex e
l e l e e const l e r e r e e const r e l e h
P dV T dV T
dP V T V T V T V T V T
dm V dP R T dm V dP R T dm V
γ γ
− +
= + + + +
= = =
( ) ( )
, ,
, , , , , , , ,
1
, , ,
,
Temperature of expansion chamber : (
e e const h e
ex e e ex e ex e e const hex e co e e co e co e e const col e
i i i e ex
ex e ex e ex e i
e
dP R T
dm P dV V dP R T dm P dV V dP R T
dP dV
T T T
P
γ γ
+
= + = +
= + +
, ,, ,
, ,
1
, , ,
, ,
)
Temperature of compression chamber : ( )
e ex e
i i
ex e ex e
co e co e
i i i e
co e co e co e i i i
e co e co e
dm
V m
dV dm T T T dP
P V m
+
−
= + + −
, , ,
, ,
, , , , , ,
, , , , ,
, ,
, ,
,
Pressure drop across the regenerator :
39.52
, 0.01
2 Re
ex c c r c
tol c const c
co c c r c
ex c ex c r c r c co c co c
r c d c f c r c r c
r c r c
hy c r c
P P P
m R
P V T V T V T P P P
f L u u
P f
D ρ
= − ∆
= + + = + ∆
∆ = = +
( )( ) ( )
,
1 1
, , , ,
, ,
1
, 1 1 1 , ,
, , ,
, 0 Re 100
Temperature of expansion and compression chambers :
2
r c
i i i i
i i
ex c ex c ex c ex c
ex c ex c
i i i i i i i
ex c i i i p in j out ex c ex c sh
ex c ex c v ex c v
p p V V
m T dt
T c m T m T Q Q Q
m m c m c
+ +
+
+ + +
< ≤
+ −
= − + − + + +
( )( ) ( )
( )
1 1
, , , ,
, ,
1
, 1 1 1 , ,
, , ,
1
2
Energy variation of cold head :
i i
pu p
i i i i
i i
co c co c co c co c
co c co c
i i i i i i
co c i i i p in co c out i co c
co c co c v co c v
i i i i
head head ex k
Q
p p V V
m T dt
T c m T m T Q
m m c m c
E E Q Q dt
+ +
+
+ + +
+
+
+ −
= − + − +
= − −
1 1
Temperature of cold head :
i
i head
we
head head
T E
m c ζ
+
=
+1
2 1
1
3 1 2
4 3
1
5 3 4
6 5
Angles :
cos ( cos )
sin ( cos )
e
e
e
z z
z z θ θ
θ π θ
θ θ
θ π θ
θ θ
θ π θ
−
−
=
= −
= +
= −
= +
= −
3
1 2
7
5
4
6 8
θ1
θ5
θ3
θ2
θ6
θ4
displacer
piston y
x
L1,e
L2,e
L3,e
L4,e
Re
Lpt,e
Ldt,e
Lp,e
Ld,e
Le
1 1, 2,
2 2,
3 4, 3,
4 3,
Geometrical variables :
( ) 2
( ) 2
e e e
e e
e e e
e e
z L L L
z R L
z L L L
z R L
= −
= −
= −
= −
1 2
2 2
2 1 1 2 1 1 2 1 1 1 2 1
3 2 2 1.5
1 2 1 1 2 1
4 3
2
4 1 1
4 1 1 4 1 1
5 2
3 4 1
Angular acceleration : ,
cos( ) sin( ) ( sin( ) ) (z z cos( )) 1 (z cos( )) 1 (z z cos( ))
( sin( ) cos( ) sin( )
1 (z cos( ))
e e
z z z
z
z
z z
z
α α α α
θ ω θ α θ ω θ
α θ θ
α α
θ ω θ α θ ω
α θ
= = −
+ +
= −
− + − +
= −
= − + +
− +
2
3 4 1
2 1.5
3 4 1
6 5
) (z z cos( )) 1 (z z cos( ))
θ θ
α α
+
− +
= −
Kinematics :
3
1 2
7
5
4
6 8
θ1
θ5
θ3
θ2
θ6
θ4
displacer
piston y
x
L1,e
L2,e
L3,e
L4,e
Re
Lpt,e
Ldt,e
Lp,e
Ld,e
Le
, , 56 78
2 2
37 1 1 1 1 2, 3 3 3 3
2 2
35 1 1 1 1 3, 5 5 5 5
x-direction :
0 , 0 , 0 , 0
sin( ) cos( ) 1 sin( ) cos( )
2
sin( ) cos( ) 1 cos( ) sin( )
2
dis x pis x x x
x e e e
x e e e
a a a a
a R R L
a R R L
θ θ θ θ θ θ θ θ
θ θ θ θ θ θ θ θ
= = = =
= − − − +
= − − − − +
48 37 46 35
2 2
, 1 1 1 1 2, 3 3 2, 3 3
2 2
, 1 1 1 1 3, 5 5 3, 5 5
56 , 78
,
y-direction :
cos( ) sin( ) sin( ) cos( )
cos( ) sin( ) sin( ) cos( )
,
x x x x
pis y e e e e
dis y e e e e
y dis y y pi
a a a a
a R R L L
a R R L L
a a a a
θ θ θ θ θ θ θ θ
θ θ θ θ θ θ θ θ
= − = −
= − − +
= − + −
= =
,
2 2
37 1 1 1 1 2, 3 3 3 3
2 2
35 1 1 1 1 3, 5 5 5 5
48 37 46 35
cos( ) sin( ) 1 sin( ) cos( )
2
cos( ) sin( ) 1 sin( ) cos( )
2 ,
s y
y e e e
y e e e
y y y y
a R R L
a R R L
a a a a
θ θ θ θ θ θ θ θ
θ θ θ θ θ θ θ θ
= − + − +
= − + −
= =
Mass center acceleration :
, , ,
Force balance in y-direction :
ex e co e dis dis dis dis y
P P Y m g m a
− + + − =
5 6 56 56
dis 5 6 56 56 56
4, 4,
5 6
Force balance in x-direction :
-X X
Force balance in y-direction :
Y Y Y
Moment balance :
Y Y 0
2 2
x
y
e e
m a
m g m a
L L
+ =
− − − − =
− =
, , ,
Force balance in y-direction :
co e b e pis pis pis pis y
P P Y m g m a
− + + − =
7 8
Ypis
X7
Y7
X8
Y8 m78g
5 6
Ydis
X5 X6
Y5 Y6
m56g
7 8 78 78
pis 7 8 78 78 78
1, 1,
7 8
Force balance in x-direction :
-X X
Force balance in y-direction :
Y Y Y
Moment balance :
Y Y 0
2 2
x
y
e e
m a
m g m a
L L
+ =
− − − − =
− =
P
co,em
pisg P
b,eY
pisPex,e
Pco,e Ydis
mdisg
35 5 35 35
35 5 35 35 35
3, 5 5 3, 5 5
3,
5 35 35 35
Force balance in x-direction :
X X
Force balance in y-direction :
Y Y
Moment balance :
sin( ) X cos( ) Y
cos( ) 2
x
y
e e
e
m a
m g m a
L L
L m g I
π θ π θ
π θ α
+ =
+ − =
− + −
− − =
4 8
Y8 X8
Y48
X48 m48g θ4
4
6
Y46 X46
Y6 X6
m46g θ6
3 7
Y7 X7
Y37
X37 m37g
θ3
3
5
m35g Y35
X35
Y5 X5 θ5
7 37 37 37
7 37 37 37 37
2, 3 7 2, 3 7
2,
3 37 37 37
Force balance in x-direction :
X X
Force balance in y-direction :
Y Y
Moment balance :
sin X cos Y
cos 2
x
y
e e
e
m a
m g m a
L L
L m g I
θ θ
θ α
+ =
+ − =
− +
− =
46 6 46 46
46 6 46 46 46
3, 6 6 3, 6 6
3,
6 46 46 46
Force balance in x-direction :
X X
Force balance in y-direction :
Y Y
Moment balance :
sin X cos Y
cos 2
x
y
e e
e
m a
m g m a
L L
L m g I
θ θ
θ α
− =
+ − =
− −
+ =
8 48 48 48
8 48 48 48 48
2, 4 8 2, 4 8
2,
4 48 48 48
Force balance in x-direction :
X X
Force balance in y-direction :
Y Y
Moment balance :
sin( ) X cos( ) Y
cos( ) 2
x
y
e e
e
m a
m g m a
L L
L m g I
π θ π θ
π θ α
− + =
+ − =
− − −
+ − =
1 35 37 1 35 37 12 1 1
1 46 48 1 46 48 12 2 2
Moment balance :
sin (X X ) cos (Y Y ) Y
2
sin( )(X X ) cos( )(Y Y ) Y
2 Torques exerted on the engine :
Frictional torque :
e
e e
e
e e e
e c fri
fri f e
R R L I
R R L I
c
θ θ α
π θ π θ α τ
τ τ τ
τ ω
+ − + − =
− + + − + − = =
− −
=
( )
2
Angular speed is updated as :
ei 1 eidt
e c friω
+= ω + I τ τ τ − −
3 1
Y35
X35
Y37
X37
θ1
Y12 2
4
Y46
X46
Y48
X48
θ2
Y12
Start
Initial conditions
t = t + dt θe = θe + dθe
θc = θc + dθc
Thermodynamic model
P,m,T Converge?
Dynamic model
Torques (τe , τc , τfri)
dθ =ωi+1dt
t = tmax ?
End
No
Yes
No
Time (s)
Position(mm)
400 400.1 400.2 400.3 400.4 400.5 400.6 100
150 200 250 300
Yd,e Yp,e
Time (s)
Position(mm)
400 400.2 400.4 400.6
40 60 80 100 120 140 160 180
Yd,c
Yp,c
Time (s)
Volume(c.c.)
400 400.1 400.2 400.3 400.4 400.5 400.6
0 10 20 30 40 50 60
Vco,c Vex,c
Time (s)
Volume(c.c.)
400 400.1 400.2 400.3 400.4
0 20 40 60 80 100 120 140 160 180
Vco,e Vex,e
Position variation of the engine Position variation of the cooler
Volume variation of the engine Volume variation of the cooler
Instantaneous rotation speed and cold head temperature
Temperature of expansion and compression chamber in engine and cooler
Time (s)
Instantaneousrotationspeed(rpm) T we(K)
0 100 200 300 400
200 400 600 800 1000
230 240 250 260 270 280 290 300
Instantaneous rotation speed Twe
Time (s)
Instaneousrotationspeed(rpm)
300 300.1 300.2 300.3 300.4 510
520 530 540 550 560
Time (s) Tex,e,Tco,e,Tco,c,Tex,c(K)
400 400.1 400.2 400.3 400.4 400.5 400.6
200 250 300 350 400 450 500 550 600 650 700 750 800 850
Tex,e Tco,e Tco,c Tex,c
Volume (c.c.)
Pressure(kPa)
0 20 40 60 80 100 120 140
600 700 800 900 1000 1100 1200 1300 1400
Pc,e- Vc,e Pe,e- Ve,e
Volume (c.c.)
Pressure(kPa)
0 10 20 30 40 50
50 60 70 80 90 100 110 120 130 140 150 160 170
Pc,c- Vc,c Pe,c- Ve,c
P-V diagram for engine P-V diagram for cooler
Time (s)
Averagerotationspeed(rpm)
0 10 20 30 40 50 60
100 200 300 400 500 600 700 800 900
cf= 0.001 cf= 0.0015 cf= 0.002
Time (s) Twe(K)
0 100 200 300 400 500
220 240 260 280 300
cf= 0.001 cf= 0.0015 cf= 0.002
Average rotation speed Cold head temperature
Time (s) Twe(K)
0 100 200 300 400 500
200 220 240 260 280 300 320
Pengine= 5 atm Pengine= 6 atm Pengine= 7 atm Pengine= 8 atm
Time (s) Twe(K)
0 100 200 300 400 500
100 120 140 160 180 200 220 240 260 280 300 320
Pcooler= 1 atm Pcooler= 2 atm Pcooler= 3 atm
Effect of charged pressure of Stirling engine Effect of charged pressure of Stirling cooler
Time (s) Twe(K)
0 100 200 300 400 500 600 700 800 900
50 100 150 200 250 300
Pcooler= 3atm (Num.) Pcooler= 4atm (Num.) Pcooler= 5atm (Num.) Pcooler= 3atm (Exp.) Pcooler= 4atm (Exp.) Pcooler= 5atm (Exp.)
Numerical and experimental results of temperature with different cooler pressure when the engine is charged with 8 atm and the heating temperature is 1100 K.