Progress in
String Field Theory
Syoji Zeze
Yokote Seiryo Gakuin High School
2 April, 2010 National Taiwan U.
• A very simple solution for tachyon condensation in string field theory is found
[Erler-Schnabl, arXiv: 0906.0979]
• We apply their solution to various problems of tachyon condensation
[S.Z., JPS in Okayama, 2010, to appear in arXiv]
• Classical potential
• Effective potential
• Interpretation from world sheet geometry
They are exact result
Claim
Tachyon
Condensation
in SFT
Sen s conjecture
unstable D-brane no open string
1998
t V
tension of unstable
D-brane t0
V (t0) SFT can derive
this potential
10 yeas history
year brane tension
(ratio) method authors
1999 0.9864 level 4 Sen-Zwiebach, (Kostelecky-
Samuel)
2000 0.9912 level 10 Moeller-Taylor
2002 1.00049 level 18 Gaiotto-Rastelli
2005 1 exact Schnabl
2009 1 exact Erler-Schnabl
Exact era
Level truncation era
Ψ = t1 + t2 + · · ·Erler-Shnabl solution
• Analytic solution of the classical SFT
• Lorentz invariant, i.e. scalar field
with no space time dependence
Schnabl Erler Schnabl form of the
solution
Infinite
sum Integral
`Phantom
term exists none
D-brane
tension OK OK
Homotopy
operator exists exists
Gauge equivalent
K B c subalgebra
B, c, K: string fields (identity based)
{B, c} = 1 [K, B] = 0
Q B c = cKc
Q
BK = 0
Q
BB = K
c = 2π c(1) |I�
B = π
2 BL |I�
K = π
2 KL |I�
Okawa
= �
∞0
dt e
−tc(1 + K)BcΩ
t= �
∞0
dt c(1 + K)Bce
−t(1+K)Ψ = c(1 + K)Bc 1
1 + K
Ω
midpoint
π 2
Ω t
π 2 t
Level expansion in
dressed gauge
Level expansion
Ψ = cf(K)Bc 1
1 + K
f (K) = 1 + K
Erler-Schnabl
f (K) = t0 + t1K + t2K2 + · · ·
S[Ψ] = T r[ 1
2 ΨQ
BΨ + 1
3 Ψ
3]
Dressed gauge condition
[B0−{Ψ(1 + K)}] 1
1 + K = 0
3 The Tachyon Potential
In this section, we evaluate the tachyon potential V = 1
2Tr[ΨQBΨ] + 1
3Tr[Ψ3] (10)
for the string field (8). All of the calculation can be preformed by employing a procedure developed in Ref. [1]. We evaluate the tachyon potential order by order with respect to the expansion (9). We assign ‘level’ n to the nth order term in f (K), since the corresponding string field is an eigenstate of ‘dressed’ L0 operator with eigenvalue n − 1.1 Let us write the potential up to level N as
V = 1
2tmKmntn + 1
3Vmnptmtntp, (11) where the sum over m,n, p is taken from 0 to N. The coefficients Kmn and Vmnp can be obtained by plugging the level n field
ψn = cKnBc 1
1 + K (12)
= lim
s→0(∂s)n ! ∞
0 e−tdt cΩsBcΩt. (13) into the classical action. It is easily found that both Kmn and Vmnp can be evaluated in terms of the the well-known trace[2, 3]
g(r1,r2, r3,r4) ≡ Tr[BcΩr1cΩr2cΩr3cΩr4]. (14) More explicitly,
Kmn = lim
s1→0,s2→0(−∂s1)m(−∂s2)n ! ∞
0 dt1 ! ∞
0 dt2e−t1−t2h2(t1,t2, s1,s2), (15) where
h2(t1,t2, s1,s2) = − lim
u→0∂u"g(t2,s1 +t1,u,s2) − g(t2, s1,t1 + u,s2) + g(t2,s1,t1, u + s2) − g(t1,s2 + u,t2, s1)
+ g(u,t2,s1 +t1, s2) − g(u,t2,s1,t1 + s2)#
(16)
1The ‘dressed’ L0 is given by L Ψ = 12L0− {Ψ(1 + K)}, where L0− = L0 − L0†.
3
and
Vmnp = lim
s1→0,s2→0,s3→0(−∂s1)m(−∂s2)n(−∂s3)p ! ∞
0 dt1 ! ∞
0 dt2 ! ∞
0 dt3
e−t1−t2−t3h3(t1,t2,t3, s1,s2,s3), (17) where
h3(t1,t2,t3,s1,s2,s3) = g(t3,s1 +t1, s2 +t2,s3) − g(t3, s1 +t1,s2,t2 + s3)
− g(t3, s1,t1 +t2 + s2,s3) + g(t3, s1,t1 + s2,t2 + s3). (18) In [1], the integrals in the kinetic term (which corresponds to Kmn in our paper) is performed with the help of the reparametrization
t1 = uv, t2 = u(1 − v) (19)
where u = t1 +t2 parametrize the width of the strip world sheet in the sliver frame.
Under this reparametrization, the masure of the integral is transformed as
! ∞
0 dt1 ! ∞
0 dt2 →
! ∞
0 du ! 1
0 dvu. (20)
While the qubic term is not calculated in [1], we find that similar reparametrization also works. Thus the integrals in Vmnp can be preformed with the replacement
t1 = uv1, t2 = uv2, t3 = u(1 − v1 − v2). (21) where u = t1 +t2 +t3 also represents the width of the world sheet. The integration mesure is also be rewritten into
! ∞
0 dt1 ! ∞
0 dt2 ! ∞
0 dt3 →
! ∞
0 du! 1
0 dv1 ! 1−v1
0 dv2 u2. (22) After integrating out v1, v2 and v3, we obtain the potentail as an integral with respetct to the width u as
V = ! ∞
0 due−uA(u,tn), (23)
where A(u,tn) is finite order in u, possibly includes negative powers of u. This prescription in terms of world sheet width u helps us to understand the relation between world sheet fluctuation and the tachyon potential.
4
Tr[ψmQBψn]
Tr[ψmψnψp]
3 The Tachyon Potential
In this section, we evaluate the tachyon potential V = 1
2Tr[ΨQBΨ] + 1
3Tr[Ψ3] (10)
for the string field (8). All of the calculation can be preformed by employing a procedure developed in Ref. [1]. We evaluate the tachyon potential order by order with respect to the expansion (9). We assign ‘level’ n to the nth order term in f (K), since the corresponding string field is an eigenstate of ‘dressed’ L0 operator with eigenvalue n − 1.1 Let us write the potential up to level N as
V = 1
2tmKmntn + 1
3Vmnptmtntp, (11) where the sum over m,n, p is taken from 0 to N. The coefficients Kmn and Vmnp can be obtained by plugging the level n field
ψn = cKnBc 1
1 + K (12)
= lim
s→0(∂s)n ! ∞
0 e−tdt cΩsBcΩt. (13) into the classical action. It is easily found that both Kmn and Vmnp can be evaluated in terms of the the well-known trace[2, 3]
g(r1, r2, r3, r4) ≡ Tr[BcΩr1cΩr2cΩr3cΩr4]. (14) More explicitly,
Kmn = lim
s1→0,s2→0(−∂s1)m(−∂s2)n ! ∞
0 dt1 ! ∞
0 dt2e−t1−t2h2(t1,t2, s1, s2), (15) where
h2(t1,t2, s1, s2) = − lim
u→0 ∂u"
g(t2, s1 +t1, u,s2) − g(t2, s1,t1 + u,s2) + g(t2,s1,t1, u + s2) − g(t1, s2 + u,t2, s1)
+ g(u,t2, s1 +t1,s2) − g(u,t2, s1,t1 + s2)#
(16)
1The ‘dressed’ L0 is given by L Ψ = 12L0− {Ψ(1 + K)}, where L0− = L0 − L0†.
3
Level expansion terminates at level 3 because
tr[K · · · ] → lim
s→0
∂
ssin t
iu + s ∼ t
iu
2cos t
iu
higher order of K higher rank derivative integrand contains sin(s/u) factor
(Erler-Shnabl: solution of EOM terminates at level 1)
(m,n, p) vm,n,p(u) (m,n, p) vm,n,p(u) (0,0,0) 4π3u54 (0,0,1) (−15+π2)u4
6π4
(0,1,1) −(−15+π2)u3
3π4 (0,0,2) −(−15+4π2)u3
3π4
(1,1,2) 2(−15+π2)u
π4 (0,2,2) 2(−15+4π2)u
π4
(1,2,2) −4(−15+π2)
π4 (0,0,3) −2(−6+π2)u2
3π2
(0,1,3) −2(45−9π2+π4)u
3π4 (1,1,3) −4(−45+6π2+π4)
3π4
(0,2,3) 4(45−15π2+2π4)
3π4
Table 1: A complete list of vm,n,p(u) up to level 3. Other coefficients are zero.
swer for the tachyon potential is obtained by performing integration with respect to u, together with the e−u factor. We present the final expression below.
V = 1 π2
! 15
64π2t03 −
15t1
16π2t02 + 1
16t1t02 + 15
16π2t2t02 − 1
4t2t02 − 1
12π2t3t02 + 1
2t3t02 − 3
32t02 + 15
16π2t12t0 − 1
16t12t0 − 15
4π2t22t0 +t22t0 + 3
4t2t0 − 1
6 π2t1t3t0
− 15
2π2t1t3t0 + 3
2t1t3t0 + 4
3π2t2t3t0 + 30
π2t2t3t0 − 10t2t3t0 + π2t3t0 − 3t3t0 + 15
π2t1t22 −t1t22 −
15
4π2t12t2 + 1
4t12t2 − 1
3π2t12t3 + 15
π2t12t3 − 2t12t3
"
(28)
3.2 The instability of the classical potential
In last section, we have seen that the level expansion in the dressed B0 gauge termnates at level 3 within the KBc subalgegra. This implies that any result ob- tained from the potential (28) is exact within our setup, although the KBc subalge- bra covers very limited part of the whole spcae of the string fields. Therefore we can expect some exact result for the tachyon potential from our analysis. Since the potential is completely known, we only need to follow the proceder as in Ref. [5].
The closed string vacuum is given by the configuration (t0,t1,t2,t3) = (1,1,0,0).
We have cheked that it is a stationary point of (28), and furthermore gives correct D-brane tension −1/2π2. To see whether the vacuum is stable or not, we evaluate
6
Level 3 potential
exact !
fields:
t0, t1, t2, t3Is closed string vacuum stable ?
(t0, t1, t2, t3) = (1, 1, 0, 0)
Eigenvalues of Hessian
Hessian matrix at the closed string vacuum
Hi j = ∂ 2V
∂ti∂t j . (29)
The closed string vacuum is stable(unstable) if all eigenvalues of Hi j is posi- tive(negative). Otherwise, it is a saddle point.
The Hessian matrix for this configuration is
180 + 6π2 −180 + 12π2 180 − 30π2 −180 + 48π2
−180 + 12π2 180 − 12π2 −180 + 12π2 180 − 12π2 − 12π4 180 − 30π2 −180 + 12π2 180 + 24π2 360 − 120π2 + 16π4
−180 + 48π2 180 − 12π2 − 12π4 360 − 120π2 + 16π4 0
, and eigenvalues is found to be (30)
1487.14, −1261.59, 412.919, 79.1831. (31) Hessian matrix has a negative eigenvalue while others are positive. This con- cludes that the closed string vacuum of Erler and Schnabl is a suddle point. It should be stressed that the four eigenvalues obtained here do not change even if we include other field outside KBc subalgebra or outside the dressed B0 gauge, since such fields are set to zero on the closed string vacuum. Therefore our result is completely exact and does not depend on choice of basis for string fields.
3.3 Effective Potential
The effective potential for tachyon can be obtained by eliminating fields other than tahyon field from the classical potential by solving equations of motion. In this paper, we identified t0 as the tachyon mode, also such choice is ad-hoc, but seems to be natural. Therefore we have to solve
∂V
∂ ti = 0 (i = 0,1,2,3) (32)
for fields t1,t2,t3. In general, there appear many branches since the equations of motion is cubic in each ti. However, one can see that (28) is linear in t3. Therefore, t3 is an auxiliary field and can be eliminated by imposing
∂V
∂ t3 = 0. (33)
7
Hessian matrix at the closed string vacuum
H
i j= ∂
2V
∂ t
i∂ t
j. (29)
The closed string vacuum is stable(unstable) if all eigenvalues of H
i jis posi- tive(negative). Otherwise, it is a saddle point.
The Hessian matrix for this configuration is
180 + 6 π
2−180 + 12 π
2180 − 30 π
2−180 + 48 π
2−180 + 12 π
2180 − 12 π
2−180 + 12 π
2180 − 12 π
2− 12 π
4180 − 30 π
2−180 + 12 π
2180 + 24 π
2360 − 120 π
2+ 16 π
4−180 + 48 π
2180 − 12 π
2− 12 π
4360 − 120 π
2+ 16 π
40
, (30)
and eigenvalues is found to be
1487.14, −1261.59, 412.919, 79.1831. (31) Hessian matrix has a negative eigenvalue while others are positive. This con- cludes that the closed string vacuum of Erler and Schnabl is a suddle point. It should be stressed that the four eigenvalues obtained here do not change even if we include other field outside KBc subalgebra or outside the dressed B
0gauge, since such fields are set to zero on the closed string vacuum. Therefore our result is completely exact and does not depend on choice of basis for string fields.
3.3 Effective Potential
The effective potential for tachyon can be obtained by eliminating fields other than tahyon field from the classical potential by solving equations of motion. In this paper, we identified t
0as the tachyon mode, also such choice is ad-hoc, but seems to be natural. Therefore we have to solve
∂ V
∂ t
i= 0 (i = 0,1,2,3) (32)
for fields t
1, t
2, t
3. In general, there appear many branches since the equations of motion is cubic in each t
i. However, one can see that (28) is linear in t
3. Therefore, t
3is an auxiliary field and can be eliminated by imposing
∂ V
∂ t
3= 0. (33)
7
Unstable (classically)
Arroyo (2009)
�1.0 �0.5 0.0 0.5 1.0
�1.0
�0.5 0.0 0.5 1.0
t0 t1
Effective Potential
• t_3 and t_2 can be integrated out without specifying branch
closed string vacuum
V = −Tp
Fake
vacuum ?
V = −0.71Tp
Effective potential
•
Integrate out t_1•
Obtained analytically, but too long to present here0.5 1.0 1.5 2.0 t0
�0.05 0.05 0.10
V1
• Closed string vacuum only
• Stable, no fall-off
• defined for positive
t_0
How identity
based solution
fails?
4 Analysys in terms of width of the strip 5 Identity based solution
Ψ = −cK (34)
= lim
s→0
∂
scΩ
s. (35)
asd f (36)
A Formlas
B Summary and Discussion References
[1] T. Erler and M. Schnabl, JHEP 0910, 066 (2009) [arXiv:0906.0979 [hep- th]].
[2] Y. Okawa, JHEP 0604, 055 (2006) [arXiv:hep-th/0603159].
[3] T. Erler, JHEP 0705, 083 (2007) [arXiv:hep-th/0611200].
[4] T. Erler, JHEP 0705, 084 (2007) [arXiv:hep-th/0612050].
[5] E. Aldo Arroyo, JHEP 0910, 056 (2009) [arXiv:0907.4939 [hep-th]].
10
Equation of motion contracted with itself
4 Analysys in terms of width of the strip 5 Identity based solution
Ψ = −cK (34)
= lim
s→0 ∂scΩs. (35)
TrΨQBΨ = − lim
s→0 lim
u→0Tr[cΩscΩucΩs] (36) TrΨ3 = − lim
s→0 Tr[cΩsΩscΩs] (37)
A Formlas
B Summary and Discussion References
[1] T. Erler and M. Schnabl, JHEP 0910, 066 (2009) [arXiv:0906.0979 [hep- th]].
[2] Y. Okawa, JHEP 0604, 055 (2006) [arXiv:hep-th/0603159].
[3] T. Erler, JHEP 0705, 083 (2007) [arXiv:hep-th/0611200].
[4] T. Erler, JHEP 0705, 084 (2007) [arXiv:hep-th/0612050].
[5] E. Aldo Arroyo, JHEP 0910, 056 (2009) [arXiv:0907.4939 [hep-th]].
10
take this first
They differ at finite s because width are different
4 Analysys in terms of width of the strip 5 Identity based solution
Ψ = −cK (34)
= lim
s→0
∂
scΩ
s. (35)
TrΨQ
BΨ = − lim
s→0
lim
u→0
Tr[cΩ
scΩ
ucΩ
s] (36) TrΨ
3= − lim
s→0
Tr[cΩ
scΩ
scΩ
s] (37)
A Formlas
B Summary and Discussion References
[1] T. Erler and M. Schnabl, JHEP 0910, 066 (2009) [arXiv:0906.0979 [hep- th]].
[2] Y. Okawa, JHEP 0604, 055 (2006) [arXiv:hep-th/0603159].
[3] T. Erler, JHEP 0705, 083 (2007) [arXiv:hep-th/0611200].
[4] T. Erler, JHEP 0705, 084 (2007) [arXiv:hep-th/0612050].
[5] E. Aldo Arroyo, JHEP 0910, 056 (2009) [arXiv:0907.4939 [hep-th]].
10
Tr[cΩs1 cΩs2 cΩs3]
different limits of
4 Analysys in terms of width of the strip 5 Identity based solution
Ψ = −cK (34)
= lim
s→0
∂
scΩ
s. (35)
TrΨQ
BΨ = − lim
s→0
lim
u→0
Tr[cΩ
scΩ
ucΩ
s] (36) Tr Ψ
3= − lim
s→0
Tr[c Ω
sc Ω
sc Ω
s] (37) TrΨQ
BΨ = 1
2 + 2
π
2(38)
TrΨ
3= 2
9 + 9 √ 3
4 π
3+
√ 3
2 π (39)
A Formlas
B Summary and Discussion References
[1] T. Erler and M. Schnabl, JHEP 0910, 066 (2009) [arXiv:0906.0979 [hep- th]].
[2] Y. Okawa, JHEP 0604, 055 (2006) [arXiv:hep-th/0603159].
[3] T. Erler, JHEP 0705, 083 (2007) [arXiv:hep-th/0611200].
[4] T. Erler, JHEP 0705, 084 (2007) [arXiv:hep-th/0612050].
[5] E. Aldo Arroyo, JHEP 0910, 056 (2009) [arXiv:0907.4939 [hep-th]].
10
4 Analysys in terms of width of the strip 5 Identity based solution
Ψ = −cK (34)
= lim
s→0
∂
scΩ
s. (35)
TrΨQ
BΨ = − lim
s→0
lim
u→0
Tr[cΩ
scΩ
ucΩ
s] (36) TrΨ
3= − lim
s→0
Tr[cΩ
scΩ
scΩ
s] (37) TrΨQ
BΨ = 1
2 + 2
π
2(38)
TrΨ
3= 2
9 + 9 √ 3
4 π
3+
√ 3
2 π (39)
A Formlas
B Summary and Discussion References
[1] T. Erler and M. Schnabl, JHEP 0910, 066 (2009) [arXiv:0906.0979 [hep- th]].
[2] Y. Okawa, JHEP 0604, 055 (2006) [arXiv:hep-th/0603159].
[3] T. Erler, JHEP 0705, 083 (2007) [arXiv:hep-th/0611200].
[4] T. Erler, JHEP 0705, 084 (2007) [arXiv:hep-th/0612050].
[5] E. Aldo Arroyo, JHEP 0910, 056 (2009) [arXiv:0907.4939 [hep-th]].
10
Not a solution !
Finite value of action (D-brane tension) But they doesn t depend of s !
Tr[Ψ(QBΨ + Ψ2)] �= 0
Summary
•
Tachyon potential in dressed Schnabl gauge is obtained•
Potential terminates at level 3•
Closed string vacuum: saddle point (classically)stable in the effective potential
•
Explanation for identity based solutionSpeculation
V =
�
∞0
du e
−uA(u)
* u is length of the
boundaries of an open string
* small u divergence corresponds to
zero momentum closed string ?