General Physics (Lecture Notes)
Textbook: Essential University Physics by
Richard Wolfson
2
Chapter 1
Doing Physics
1.1 Realms of Physics
Physics:
• Mechanics ( Chs. 2 12)
• Oscillations, Waves, and Fluids ( Chs. 13 15)
• Thermodynamics ( Chs. 20 29)
• Electromagnetism ( Chs. 20 29)
• Optics ( Chs. 30 32)
• Modern Physics (Chs. 33 39)
1.2 Measurements and Units
SI unit system: (International System of Units)
• Length: meter (m)
• Time: second (s)
• Mass: kilogram (kg)
• Temperate: kelvin (K)
• Electric current: ampere (A)
• Amount: mole (mol)
• Luminosity: candela (cd)
3
4 CHAPTER 1. DOING PHYSICS
1.3 Working with Numbers
Scientific notation:
e.g.,
4.185 =⇒ 4.185 × 103 (four significant figures)
1.4 Strategies for Learning Physics
An IDEA strategy:
• Intepret: know the problem.
• Develop: draw a diagram and choose eqs.
• Evaluate: in symbolic form, then plug in numbers at the end.
• Assess: make sense? or reasonable?
Chapter 2
Motion in a Straight Line
2.1 Average Motion
∆x = x2− x1 (displacement), d = |x2− x2| (distance), and
¯ v = ∆x
∆t (average velocity), ∆t = t2− t1, S = d
∆t (average speed).
2.2 Instantaneous Velocity
v = lim∆t→0
∆x
∆t = dx
dt (inst. vel.) Math: (taking derivatives)
e.g.,
x = b tn =⇒ dx
dt = b n tn−1.
2.3 Acceleration
¯ a = ∆v
∆t (ave. acc.), and
a = lim∆t→0∆v
∆t = dv
dt (inst. acc.) 5
6 CHAPTER 2. MOTION IN A STRAIGHT LINE
2.4 Constant Acc.
a = ¯a = ∆v
∆t = v2− v1
t2− t1
= v − v0
t
=⇒ v = v0+ at (for const acc. only) · · · (1)
¯
v = 12(v0+ v)
¯
v = ∆x∆t = xt22−−xt11 = x−xt 0
=⇒ x − x0
t = 1
2(v0+ v)
=⇒ x = x0+12(v0+ v)t · · · (2) (1), = x0+12(v0+ v0+ a t) t
= x0+ v0t + 12a t2 (a = const) · · · (3)
(1) =⇒ t = (v − v0)/a · · · (4) (4)(2) =⇒ x = x0+1
2(v0+ v)(v − v0)/a
=⇒ v2= v20+ 2a(x − x0)
2.5 The Acceleration of Gravity
(a = const) =⇒
v = v0+ at
x = x0+ v0t +12a t2 v2 = v02+ 2a(x − x0) x → y and a → (−g),
(free fall, g = 9.8 m/s2) =⇒
v = v0− gt
y = y0+ v0t −12g t2 v2 = v02− 2g(y − y0)
Chapter 3
Motion in Two and Three Dimensions
3.1 Vectors
Quantities :
Scalars: no direction
Vectors: magnitude and direction
Vector Components:
A~ = A~x+ ~Ay, A~x = A cos θ ˆi(or ˆx), A~y = A sin θ ˆj(or ˆy), and
A =q
A2x+ A2y, tan θ = Ay
Ax
.
Vector Arithmetic with Unit Vectors:
A = ~~ Ax+ ~Ay, B = ~~ Bx+ ~By,
=⇒ ~A + ~B = (Axˆi + Ayˆj) + (Bxˆi + Byˆj) = (Ax+ Bx)ˆi + (Ay+ By)ˆj
3.2 Velocity and Acceleration Vectors (in 2 or 3-dim.)
~vave =∆r
∆t (ave. velocity vector) 7
8 CHAPTER 3. MOTION IN TWO AND THREE DIMENSIONS
~v = lim∆t→0∆~r
∆t = dr
dt (inst. velocity velocity) If ~r = xˆi + yˆj,
=⇒ ~v = dr dt =dx
dtˆi + dy
dtˆj = vxˆi + vyˆj, and
~aave= ∆~v
∆t (ave. acc. vector),
~a = lim∆t→0∆~v
∆t = dv dt = dvx
dtˆi + dvy
dt ˆj = axˆi + ayˆj. (inst. acc. vector)
3.3 Relative Motion
If ~V = V , V = const ( relative vel.), and x = x0+ V t,
=⇒ dx dt = dx0
dt + V =⇒ vx= vx0 + V · · · (1) Since y = y0,
=⇒ dy dt =dy0
dt or vy= v0y· · · (2)
(1)(2) =⇒ ~v = vxˆi + vyˆj = (vx0 + V )ˆi + v0yˆj = (v0xˆi + vy0 ˆj)
| {z }
~v0
+V ˆi,
=⇒ ~v = ~v0+ ~V #.
3.4 Constant Acceleration (~a = const.)
1-dim. (Ch. 1):
v = v0+ a t
x = x0+ v0t + 12a t2
~a = const, 2 or 3-dim.:
~v = ~v0+ ~a t
~r = ~r0+ ~v0t +12~a t2
or
x = x0+ v0xt +12axt2 y = y0+ v0yt +12ayt2 z = z0+ v0zt + 12azt2
3.5. PROJECTION MOTION 9
3.5 Projection Motion
~v = ~v0+ ~a t,
~a = ax
|{z}
0
ˆi + ay
|{z}
−g
ˆj = −g y.
=⇒
vx = v0x+ axt = v0x, vy = v0y+ ayt = v0y− g t.
Since ~r = ~r0+ ~v0t + 12~a t2,
=⇒
x = x0+ v0xt +12axt2= x0+ v0xt#· · · (1) y = y0+ v0yt +12ayt2= y0+ v0yt −12g t2
#· · · (2)
(1) =⇒ x − x0= v0x
|{z}
v0cos θ0
t =⇒ t = x − x0
v0cos θ0· · · (3)
(2)(3), v0y = v0sinθ0=⇒ y − y0= v0sinθ0
x − x0
v0cos θ0
−1
2g x − x0
v0cos θ0
2
= (x − x0) tan θ0− g
2v02cos θ20(x − x0)2
#
· · · (∗)
The Range of a Projectile:
y = y0in (*),
=⇒ 0 = (x − x0) tan θ0− g
2v20 cos θ02(x − x0)2
=⇒ x − x0= tan θ0
| {z }
sin θ0 cos θ0
×2v20 cos θ02 g = 2v20
g sin θ0cos θ0, sin 2θ0= 2 sin θ0cos θ0
=⇒ x − x0=2v02 g sin 2θ0
#
(horizontal range)
Since sin 2θ0|max= 1,
=⇒ (x − x0)max=2v02
g (at 2θ0= 900or θ0= 450)
#
10 CHAPTER 3. MOTION IN TWO AND THREE DIMENSIONS
3.6 Uniform Circular Motion
∆v v =∆r
r · · · (1) If θ ↓ =⇒ ∆r = v∆t,
(1) =⇒ ∆v
v =v ∆t
r =⇒ ∆v
|{z}∆t
a
= v2
r =⇒ a =v2 r #
Chapter 4
Force and Motion
4.1 The Wrong Question ( =⇒ What keeps things moving?)
The Right Question =⇒ What causes changes in moving?
4.2 Newton’s First and Second Laws
Ans.: =⇒ Force causes change in moving.
Newton’s 1st Law: A body in uniform motion remains in uniform motion, and a body at rest remains at rest, unless acted on by a nonzero net force.
Newton’s 2ndLaw: force ↔ changing in motion.
=⇒ ~p(def.)= m ~v (momentum)
=⇒ ~Fnet= d~p
dt# (2nd law) If m = const,
=⇒ ~Fnet= d~p
dt = d (mv)
dt = m d~v
|{z}dt
~ a
=⇒ ~Fnet = m ~a# (m = const, 2ndlaw)
If ~Fnet = 0, =⇒ ~a = 0 =⇒ ~v = const# (=⇒ 1st law) Mass, Inertia, and Force:
1st law = law of inertia (=⇒ resists changes in motion) 11
12 CHAPTER 4. FORCE AND MOTION If F = m amand F = M aM,
=⇒ m am= M aM
=⇒ m
M =aM
am # (definition of mass) Inertial Reference Frames: (where Newton’s laws are valid)
=⇒ Test: check whether Newton’s 1st law is obeyed.
Noninertial Reference Frames: e.g., Earth, an accelerating car, · · ·
4.3 Forces
The Fundamental Forces:
Theory of Everything:
• Gravity
• Grand Unified Force:
1. Strong 2. Electroweak:
(a) Weak
(b) Electromagnetism:
i. Electricity ii. Magnetism
4.4 The Force of Gravity
Mass: a measure of a body’s resistance to change in motion.
Weight: the force that gravity exerts on a body.
=⇒ ~W = m ~g (weight)
Weightlessness: (a) a falling elevator (b) an orbiting spacecraft.
4.5 Using Newton’s 2nd Law
Draw a Free-Body Diagram:
1. Identify the object of interest and all the forces acting on it.
2. Reprent the object as a dot.
3. Draw the vectors for only those forces acting on the object, with their tails all starting on the dot.
4.6. NEWTON’S3RD LAW 13
4.6 Newton’s 3rd Law
3rdlaw: If object A exerts a force on object B, then object B exerts an oppositely directed force of equal magnitude on A.
Measuring Force:
=⇒ ~Fsp= −k x (Hooke’s law), k : spring const
14 CHAPTER 4. FORCE AND MOTION
Chapter 5
Using Newton’s Laws
5.1 Using Newton’s 2nd Law 5.2 Multiple Objects
Understanding tension forces:
5.3 Circular Motion 5.4 Friction
Applications of Friction: e.g., walking, stopping a car, · · ·
5.5 Drag Forces
=⇒ terminal speed (e.g., rain drops of a falling cat)
Objects moving through fluids like water or air experience drag forces that oppose the relative motion of object and fluid.
15
16 CHAPTER 5. USING NEWTON’S LAWS
Chapter 6
Work, Energy, and Power
6.1 Work
1-dim. displacement:
=⇒ W = Fx∆x
Work and the Scalar Product Scalar Product: (or dot product)
A · ~~ B(def.)= A B cos θ, A = | ~A|, B = | ~B|.
If ~A = Axˆi + Ayˆj + Azˆk and ~B = Bxˆi + Byˆj + Bzˆk, A · ~~ B = AxBx+ AyBy+ AzBz.
For an arbitryry displacement ∆~r,
F · ∆~r = F ∆r cos θ~ # (const force)
6.2 Forces That Vary
If F 6= const, =⇒ W 6= F ∆x.
=⇒ W ' F (x1)∆x + F (x2)∆x + · · · + F (xN)∆x = XN i=1
F (xi)∆x
=⇒ W = lim
∆x→0
X∞ i=1
F (xi)∆x = Z x2
x1
F (x) dx
formula:
17
18 CHAPTER 6. WORK, ENERGY, AND POWER
Z x2
x1
xndx = xn+1 n + 1
x2
x1
= xn+12
n + 1− xn+11 n + 1 Stretching a Spring
F = − ~~ Fsp, Fsp= −kx (Eq. 4.9)
=⇒ F = kx
=⇒ W = Z x
0
F (x) dx = Z x
0
k x dx = k Z x
0
x dx
| {z }
x2 2
x
0=x22
=1 2k x2
#
Force and Work in Two and Three Dimensions
∆W = ~F · ∆~r =⇒ dw = ~F · d~r
=⇒ W = Z
dW = Z ~r2
~r1
F · d~r~
#
Work Done Against Gravity
∆W = Fy∆y, Fy= mg,
=⇒ W = Z h
0
Fydy = mg inth0dy = mgh#
6.3 Kinetics Energy
K.E. =⇒ K = 1
2m v2, m : mass, v = speed.
Work-energy thm: (1-dim.)
=⇒ Wnet= Z
Fnetdx, Fnet = m a ( = mdv dt)
= Z
mdv
dt dx, v = dx dt
= Z v2
v1
m v dv = m Z v2
v1
v dv = m
2 v22−m
2 v22= ∆K =⇒ Wnet = ∆K#
6.4. POWER 19
Energy Units
1joule = 1 newton-meter 1 erg = 10−7J
electron-volt (eV), calorie, foot-pound, British thermal unit (Btu), kilowatt-hours (kw · h).
See App. C.
6.4 Power
Ave. power: ¯P = ∆W
∆t Inst. power: P = lim
∆t→0
∆W
∆t = dW
d t (J/s = Watt) Since dW = P dt,
=⇒ W = Z t2
t1
P dt
#
If P = const,
=⇒ W = P Z t2
t1
dt = P ∆t, ∆t = t2− t1.
Power and Velocity Since dW = ~F · d~r,
=⇒ P = dW
d t = ~F · d~r
d t = ~F · ~v#
20 CHAPTER 6. WORK, ENERGY, AND POWER
Chapter 7
Conservation of Energy
7.1 Conservative and Nonconservative Forces
Conservative force: When the total work done by a force ~F acting as an object moves over any closed path is zero, the force is conservative, i.e.,
H ~F · d~r = 0
=⇒ The work done by a conservative force is path-independent.
Pf:
WAB,1+ WBA,2= 0 =⇒ WAB,1= −WBA,2· · · (1) Since WAB,2= −WBA,2,
(1) =⇒ WAB,1= WAB,2
#
7.2 Potential Energy
Potential energyU :
∆UAB
| {z }
UB−UA
= − Z B
A
F · d~r =⇒ ∆U = −W~
If W > 0 =⇒ ∆U < 0 If W < 0 =⇒ ∆U > 0
1-dim.: ∆U = − Z x2
x1
F (x) dx
Gravitational P.E.: ∆U = mgh Elastic P.E.:
=⇒ ∆U = − Z x2
x1
F (x) dx = − Z x2
x1
(−k x) dx = 1
2k x22−1 2k x21
If choose U = 0 as x = 0 (i.e., the spring is neither stretched nor compressed),
=⇒ ∆U = 1 2k x2
#
(elastic P.E.)
21
22 CHAPTER 7. CONSERVATION OF ENERGY
7.3 Conservation of Mechanical Energy
In Ch. 6,
∆K = Wnet
| {z }
Wc+Wnc
· · · Eq. (6.14)
Since Wc = −∆U ,
=⇒ ∆K = −∆U + Wnc =⇒ ∆K + ∆U = Wnc · · · (∗) If Wnc= 0,
(∗) =⇒ ∆K + ∆U = 0
=⇒ K + U
| {z }
E(mech)
= Const
or E(mech)= Const
# (Conservation of mech. energy)
7.4 Potential-Energy Curves
Force and P.E.:
Since ∆U = −W ,
1-dim. : =⇒ ∆U = −Fx∆x (for small displacement)
=⇒ Fx = −∆U∆x
∆x → 0 =⇒ Fx = −dUdx(x)
#
3 dim.:
Fx= −∂U (x, y, z)
∂x , Fy= −∂U (x, y, z)
∂y , Fz= −∂U (x, y, z)
∂z .
Chapter 8
Gravity
8.1 Toward a Law of Gravity
Kepler’s laws: (based on observation, no theoretical explanation) (See Fig. 8.1)
1st law: The orbit is elliptical, with the Sun at one focus.
2ndlaw: If the shaded areas are equal, so is the time to go from A to B and from C to D.
3rd law: The square of the orbital
T
z }| {
period is proportional to the cube of the semimajor axis
| {z }
a
. (=⇒ T3 ∝ a3)
8.2 Universal Gravitation
=⇒ F = G m1m2
r2 , (attractive)
where G = 6.67 × 10−11N · m2/kg2 (the const of universal gravitation) The Cavendish Experiment: Weighing the Earth
(See Fig. 8.4)
Since F = G m Mr2 , measure F and given m, M , and r,
=⇒ calculate G#
In Example 8.1, use g = G ME/RE2 =⇒ ME # (i.e., weighing the Earth) 23
24 CHAPTER 8. GRAVITY
8.3 Orbital Motion
(See Fig. 8.5)
G M m
r2 = mv2
r =⇒ v =
rG M
r # (circular orbit) · · · (1)
Since T = 2π r
v =⇒ v = 2π r
T · · · (2)
(1)(2) =⇒ 2π r T =
rG M
r =⇒ 2π r T
2
=G M
r =⇒ T2=4π2r3
G M # (or T2∝ r3) Elliptical Orbits (see Fig. 8.7)
=⇒ Projectile trajectories are actually elliptical (if no air resistance).
Open orbits (see Fig. 8.8)
8.4 Gravitational Energy
(See Fig. 8.9)
∆U12= − Z r2
r1
F · d~r,~ F · d~r = −~
GM m
r2
dr
=⇒ ∆U12= Z r2
r1
GM m
r2 dr = GM m 1 r1 − 1
r2
#
· · · (∗)
The Zero of Potential Energy: (Choose r1= ∞, r2= r) (∗) =⇒ U (r) = −GM m
r # Escape Speed:
E = K + U = 1
2mv2−GM m r If E = 0,
=⇒ 0 = 12mv2−GM mr ,
=⇒ vesc=q
2GM r #
(escape speed)
At r = RE, =⇒ vesc= 11.2 km/s.
8.5. THE GRAVITATIONAL FIELD 25
Energy in Circular Orbits:
For a circular orbit,
GM m
r2 = mv2
r =⇒ v2= GM r
=⇒ K = 1
2mv2= GM m
2r , U = −GM m
r = −2K and
E = U + K = −2K + K = −K# or
E = U
2 = −GM m 2r #
8.5 The Gravitational Field
Action at a distance:
F = G~ M m r2 (−ˆr) Gravitational field:
~g = −GM r2 r,ˆ
=⇒ ~F = m ~g = −GM m r2 (ˆr) Near Earth’s surface, ~g ' −g ˆy, where g = 9.8 m/s2.